Explanation
The sum of $$n$$ terms of arithmetic sequence can be calculated by the formula
$$ S_n =\dfrac{n}{2}(a_1+a_n)$$Sn=n2(a1+an)
is the first term and the last term.$$n=10$$
Given,
First term $$a_1=2$$
Tenth term $$a_{10}=22$$
$$\Rightarrow S_n=\dfrac{10}{2}(22+2)$$
$$\Rightarrow S_n=10(12)=120$$
Hence, option $$B$$ is correct
The sum of first n terms of arithmetic series formula can be written as,
$$S_n = \dfrac{n}{2} [2a + (n -1)d]$$
Where n = number of terms $$\Rightarrow$$ 20
a = first odd number $$\Rightarrow$$ 2
d = common difference of A.P. $$\Rightarrow$$ 2
Apply the given data in the formula,
$$S_{20} = \dfrac{20}{2} [2 \times 2 + (20- 1)2]$$
$$= 10[4 + (19)2]$$
$$= 10 [4 + 38]$$
$$= 10 [42]$$
$$= 420$$
So, the sum of first 20 multiples of 2 is 420.
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