Explanation
$${\textbf{Step - 1: Find 7th term of the AP}}$$
$${a_7} = a + (n - 1)d$$
$$ = a + (7 - 1)d$$
$$ = a + 6d$$
$${\text{The 11th term of the AP,}}$$
$${a_{11}} = a + (n - 1)d$$
$$ = a + (11 - 1)d$$
$$ = a + 10d$$
$${\textbf{Step - 2: According to the question 7 times of 7th term is equal to 11 times of 11th term}}$$
$$7(a + 6d) = 11(a + 10d)$$
$$\Rightarrow 7a + 42d = 11a + 110d$$
$$\Rightarrow 4a + 68d = 0$$
$${\textbf{Step - 3: Find value for a}}$$
$${\text{a = }}\dfrac{{ - 68}}{4}d$$
$${\textbf{Step - 4: Find value of 18th term }}$$
$$a_{18} = a + (18 - 1)d$$
$$ = a + 17d$$
$${\textbf{Step - 5: Substitute the value of a in equation of }}{{\textbf{a}}_\textbf{18}}$$
$${a_{18}} = \dfrac{{ - 68}}{4}d + 17d$$
$$ = \dfrac{{ - 68d + 68d}}{4} = 0$$
$${\textbf{Hence , the required value is (D) 0}}$$
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