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CBSE Questions for Class 10 Maths Introduction To Trigonometry Quiz 4 - MCQExams.com

The value of sin2600+tan450cosec2450 is
  • 12
  • 14
  • 14
  • 12
tanθ(1+tan2θ)2+cotθ(1+cot2θ)2 is equal to

  • 2sinθ.cosθ
  • cosecθ.secθ
  • sinθ.cosθ
  • 2cosecθ.sinθ
Let x=(1+sinA)(1+sinB)(1+sinC),y=(1sinA)(1sinB)(1sinC) and If x=y then
  • x=cosAcosBcosC
  • y=sinAsinBsinC
  • y=cosAcosBcosC
  • x=sinAsinBsinC
If acosθbsinθ=c, then asinθ+bcosθ equals-
  • a2+b2+c2
  • a2b2c2
  • a2+b2+c2
  • ±a2+b2c2
If sin4x2+cos4x3=15, then:
  • tan2x=23
  • sin8x8+cos8x27=1125
  • tan2x=13
  • sin8x8+cos8x27=2125
If \displaystyle x=r\sin \theta \cdot \cos \phi,  y=r\sin \theta \cdot \sin \phi and \displaystyle z= r\cos \theta, then the value of \displaystyle x^{2}+y^{2}+z^{2} is independent of: 
  • \displaystyle \theta ,\phi
  • \displaystyle r,\theta
  • \displaystyle r,\phi
  • r
If \sin { A } =a\cos { B } and \cos { A } =b\sin { B } , then \left( { a }^{ 2 }-1 \right) \tan ^{ 2 }{ A } +\left( 1-{ b }^{ 2 } \right) \tan ^{ 2 }{ B }   is equal to
  • \displaystyle \frac { { a }^{ 2 }-{ b }^{ 2 } }{ { b }^{ 2 } }
  • \displaystyle \frac { { a }^{ 2 }-{ b }^{ 2 } }{ { a }^{ 2 } }
  • \displaystyle \frac { { a }^{ 2 }+{ b }^{ 2 } }{ { b }^{ 2 } }
  • \displaystyle \frac { { a }^{ 2 }+{ b }^{ 2 } }{ { a }^{ 2 } }
If \displaystyle  \sin\theta + cosec \theta= 2,  then the value of \displaystyle \sin ^{8}\theta + cosec ^{8}\theta is equal to
  • 2
  • \displaystyle 2^{8}
  • \displaystyle 2^{4}
  • none of these
If \tan A+\cot A=4, then \tan^2A+\cot^2A is equal to
  • 10
  • 11
  • 12
  • 14
If \sin A, \cos A and \tan A are in G.P., then \cot^6 A- \cot^2A is equal to
  • -1
  • 0
  • 1
  • \cfrac {1}{2}
The value of \tan 5^{\circ}\tan 10^{\circ}\tan 15^{\circ}\cdots \tan 85^{\circ} is
  • 0
  • Not defined
  • 1
  • -1
The expression \displaystyle f\left ( \theta \right )= \frac{1}{\tan \theta+\sec \theta+\cot \theta+\text{cosec} \theta} is equivalent to
  • \displaystyle \frac{\text{cosec} \theta +\sec \theta+\text{cosec} \theta\sec \theta}{2\text{cosec} \theta\sec\theta}
  • \displaystyle \frac{\text{cosec} \theta -\sec \theta-\text{cosec} \theta\sec \theta}{2\text{cosec}\theta\sec\theta}
  • \displaystyle \frac{\text{cosec} \theta +\sec \theta-\text{cosec} \theta\sec \theta}{2\text{cosec}\theta\sec\theta}
  • None of these
ABC is an isosceles right-angled triangle. Assuming AB= BC= x, find the value of each of the following trigonometric ratios:
\sin 45^{0} is \displaystyle \dfrac{1}{\sqrt{m}}, the value of m is 

184308.jpg
  • 1
  • 3
  • 2
  • 4
Choose the correct option for the following.
The value of \displaystyle \frac{\cos 3A-2\cos 4A}{\sin 3A+2\sin 4A} is \displaystyle \frac{1-\sqrt{2}}{1+\sqrt{6}}, when A= 15^{0}.
  • True
  • False
  • Ambiguous
  • Data insufficient
If \tan \angle ADC= 1 and \sin \angle ABC=4:5, then measure of CD is: 

187003_c05f539d2d244f3c89e48a8d7c71aa9d.png
  • 10
  • 20
  • 30
  • 40
Find the length of AB in cm
187593_5777284f055742489e1e2697b2823e96.png
  • 39.25
  • 81.96
  • 46.32
  • 85.34
The length of AD (in cm.) is
187428.png
  • 10
  • 100
  • 75
  • 50
In the given figure; BC= 15 cm  and \displaystyle \sin B= \frac{4}{5}.
The measure of AC in cm is

186999_7bd76132660f466cb6fef0a54ce15e26.png
  • 10
  • 15
  • 20
  • 19
Find PQ, if \displaystyle AB = 150\ m, \angle P = 30^{\circ} and \displaystyle \angle Q = 45^{\circ}
187681_4cbfe876b614462b89d6b7d01f3d0ce6.png
  • 978.8
  • 524.4
  • 279.9
  • 409.8
If in given figure AD= 2 cm, then value of AB ( in cm )  is 
187601_352714e8102e4942922bc4252dd6c9f9.png
  • 2
  • 3
  • 7
  • 1
In the given figure, \displaystyle \angle B = 60^{\circ}, \angle C =30^{\circ}, AB=8\ cm and \displaystyle BC=25\ cm
Calculate BE in cm.

187620_b16418eb3e3a40c4862d7d01397dbc82.png
  • 4
  • 2
  • 5
  • 7
Find :
AD

187639.bmp
  • 2
  • 6
  • 4
  • 1
If \sin x+\sin^2x+\sin^3x=1, then \cos^6x-4\cos^4x+8 \cos^2x is equal to
  • 0
  • 2
  • 4
  • 8
If \cos 1^o \cos 2^o \cos 3^o ... \cos {179}^o=x+1, then x is equal to
  • -1
  • 0
  • 1
  • none of these
For all values of \alpha the given expression is equal to:
 (sin\alpha+cosec \alpha)^2+(cos\alpha+sec\alpha)^2-(tan^2\alpha+cot^2\alpha) 
  • 0
  • 2
  • 4
  • 7
If 0 < A < \pi /2 the value of the expression \dfrac {tan A}{1-cot A}+\dfrac {cot A}{1-tan A}-sec A cosec A is equal to
  • -1
  • 0
  • 1
  • sin A + cos A
If \displaystyle \tan A=1 and \displaystyle \tan B=\sqrt{3} evaluate:\displaystyle \cos A\cos B-\sin A\sin B
  • \displaystyle \frac{\sqrt{2}+\sqrt{6}}{4}
  • \displaystyle \frac{\sqrt{2}-\sqrt{6}}{6}
  • \displaystyle \frac{1-\sqrt{3}}{2\sqrt2}
  • \displaystyle \frac{\sqrt{2}+\sqrt{6}}{6}
If cos x+sin x=\sqrt 2 cos x, then tan^2x+2 tan x is equal to
  • 0
  • 1
  • 2
  • 3
If \sec C is \displaystyle \frac{m}{2\sqrt{2}}, then m is: 
196004.png
  • 1
  • 3
  • 7
  • 5
In the following figure, cosec A is \displaystyle \frac{5}{m}, m is 
196004.png
  • 1
  • 4
  • 3
  • 2
0:0:2


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