Explanation
Multiplying equation $$ (2) $$ with $$ 3 $$ we get, $$ 15x - 9y = 12 $$ ....$$(4)$$
Subtracting equations $$ (3) $$ from $$ (4) $$, we get,
$$ -9y-(-10y) = 12-(-5) $$
$$y=17$$
Substituting $$ y = 17 $$ in the equation $$ (2) $$, we get,
$$ 5x - 3(17) = 4$$
$$ 5x = 55$$
$$\Longrightarrow x = 11 $$Hence, the fraction is $$ \dfrac {11}{17}. $$
Multiplying equation $$ (1) $$ with $$ 3 $$ we get, $$ \dfrac {60}{x+y} + \dfrac {9}{x-y} = 21 $$ ----- equation $$ (3) $$
Multiplying equation $$ (2) $$ with $$ 4 $$ we get, $$ \cfrac {32}{x-y} - \dfrac {60}{x+y} = 20 $$ ----- equation $$ (4) $$
Adding equations $$ 3 $$ and $$ 4 $$, we get $$ \dfrac {41}{x-y} = 41=> x - y = 1 $$ ---- (5)
Substituting $$ x-y = 1 $$ in the equation $$ (1) $$, we get $$ \dfrac {20}{x+y} + \dfrac {3}{1} = 7 => \dfrac {20}{x+y} = 4$$
=>$$ x +y= 5 $$ --- (6)
Adding equations $$ 5 $$ and $$ 6 $$, we get $$ 2x = 6 => x = 3 $$ ---- (5)
Substituting $$ x = 3 $$ in the equation $$ (5) $$, we get $$ 3-y = 1 => y = 2 $$
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