Explanation
Given: Height $$= 150$$ m
Angle of depression $$= 30^o$$
Consider the diagram,
In $$\Delta ABC$$,
Let, distance of the car from tower $$BC = x$$ m,
In $$\Delta ABC, \tan 30^o = \dfrac{AC}{AB}$$
So, $$\tan 30^o = \dfrac{1}{\sqrt{3}}$$
Therefore, $$AC = 150\sqrt{3}$$
So, distance between the tower and car is $$150\sqrt{3}$$ m
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