Explanation
Given: Height = 150 m
Angle of depression = 30^o
Consider the diagram,
In \Delta ABC,
Let, distance of the car from tower BC = x m,
In \Delta ABC, \tan 30^o = \dfrac{AC}{AB}
So, \tan 30^o = \dfrac{1}{\sqrt{3}}
Therefore, AC = 150\sqrt{3}
So, distance between the tower and car is 150\sqrt{3} m
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