Explanation
Hint: The minimum amount of energy required to remove an electron from an isolated gaseous atom is called its ionization potential.
Correct Answer: Option C
Explanation:
Electronic configuration of the below elements are-
$$N=1s^22s^22p^3$$
$$O=1s^22s^22p^4$$
$$O^+=1s^22s^22p^3$$
$$Na=1s^22s^22p^63s^1$$
In option $$C$$, oxygen has already released one electron and it shows a half-filled configuration. So, it will require higher energy than the other elements to remove an electron from it.
Final Answer: $$O^+$$ shows maximum ionization potential.
$$Ne>Cl>P>S>Mg>Al$$.
Hence, the correct answer is option $$B$$.
Which members of each of the following pairs of atoms has higher first ionisation enthalpy and why?
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