Explanation
pure water is a very good insulator, but if we add sodium chloride we create ions to form an electrolytic solution.
$$NaCl(s) + H_2O(l) \longrightarrow Na^+(aq) + Cl^-(aq) + H_2O(l)$$
Therefore, $$NaCl$$ is an electrolyte.
Correct Answer: Options C and D.
Explanation:
1. $$BaCl_{2}$$ and $$Ba(NO_{3})_{2}$$Both have $$Ba^{2+}$$ as a common ion.$$BaCl_{2}$$ is a salt of $$Ba(OH)_{2}$$ and $$HCl$$. $$Ba(NO_{3})_{2}$$ is a salt of $$Ba(OH)_{2}$$ and $$HNO_{3}$$. Since all of these are strong acids and bases, these two species don’t exhibit the common ion effect.
2. $$NaCl$$ and $$HCl$$Both have $$Cl^{-}$$ as a common ion.$$NaCl$$ is a salt of $$Na(OH)$$ and $$HCl$$. $$HCl$$ is a strong acid itself. Since all of these are strong acids and bases, these two species don’t exhibit the common ion effect.
3. $$NH_{4}OH$$ and $$NH_{4}Cl$$Both have $$NH_{4}^{+}$$ as a common ion.$$NH_{4}OH$$ and $$NH_{4}Cl$$ are both weak species since $$NH_{4}^{+}$$ is a weak species. Therefore, these two can exhibit the common ion effect.
4. $$AgCN$$ and $$KCN$$Both have $$CN^{-}$$ as a common ion.$$KCN$$ is a salt of a weak acid and strong base and $$AgCN$$ is a sparingly soluble salt, they have $$CN^-$$ ion in common. So they will show the common ion effect.
Hence, Options $$C$$ and $$D$$ will show the common ion effect.
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