2-carbocyethyl benzoyl chloride

ethyl-2-(chlorocarbarbonyl) benzoate

ethyl-1-(chlorocarbarbonyl) benzoate

MCQ Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 7

What is IUPAC name for isophthalic acid?

0%
Benzene- 1,3 dicarboxylic acid
0%
Benzene- 1,2 dicarboxylic acid
0%
Benzene- 1,4 dicarboxylic acid
0%
Benzene- 1,5 dicarboxylic acid

Explanation

IUPAC name is benzene

$-1,3-$ dicarboxylic acid.
1157728_855613_ans_d76b3bb0ea5e4773b0f92b9e10447872.PNG

Correct IUPAC name of l-chloropent-l-yn-4-ol.

0%
Chloropentyne-2-ol
0%
5-Chloropent-4-yn-2-ol
0%
2-Hydroxypent-4-yn-2-ol
0%
4-Hydroxypent-l-yne

Explanation

$\Rightarrow$ Alcohol is given

${ 1 }^{ st }$ prefence.

$\Rightarrow$

$S-$ chloropent

$-1-yn-4-01$ .

Ans :- B

The correct IUPAC name of the compound is:

0%
$1,2,3-triaminobutan-1,3-one$
0%
$2,4-diamino-3-oxobutanamide$
0%
$1,3-dioxobutane-1,2,4-triamine$
0%
$1,3,4-triaminobutane-2,4-one$

Explanation

IUPAC name is

$2,4-diamino$

$3-oxobutanamide$
1380833_833150_ans_f8a76f1bd3d8441f9b8a968d5eaa89ec.png

Which of the following compound gives only one monochloro product on its chlorirnation in presence of sunlight?

0%
n-butane
0%
Iso pentane
0%
Neo pentane
0%
n-pentane

Which is the most aromatic in character?

0%
0%
0%
0%
All having same aromatic character

The IUPAC name of the product obtained by the oxidation of phenol with the help of chromic acid is__________.

0%
cyclo-hexa-2,4-diene-1,4-diol
0%
cyclo-hexa-2,4-diene-1,4-dione
0%
cyclo-hexa-2,5-diene-1,4-diol
0%
cyclo-hexa-2,5-diene-1,4-dione

Explanation

(Refer to Image)

$cyclo-hexa-2,5-diene-1,4-dione$

1158154_854302_ans_a0a825e321704ecb96a506ccb15ce7d4.png

IUPAC name of the following compound:

${ CH }_{ 3 }-{ CH }_{ 2 }-\underset { CH_2CH_3 }{\underset{|}{ C}H -}C{ H }_{ 2 }-\underset{CH_3}{\underset{|}{C}H}-C{ H }_{ 2 }-C{ H }_{ 3 }$

0%
3-Ethyl-5-methylheptane
0%
5-Ethyl-3-methylheptane
0%
1,1-Diethyl-3-methylpentane
0%
3-Methyl-5,5-diethylpentane

Explanation

The given structure formula can be written as:

As per rule numbering will start from the end, giving the lowest number to an ethyl group.

Thus we have, $Ethyl (C_{2}H_{5})$ is at number 3 , $methyl (CH_{3})$ is at number 5, with a total 7 C in the chain giving heptane.

Thus, its IUPAC will be:

$3- Ethyl-5-methyl heptane.$

Thus option A is correct.
1499124_927090_ans_d32169975f3143dfbd1015b927dfc7e7.jpg

Which of the following is the correct IUPAC name for the following compound?

0%
2-(1,1-dimethyl ethyl)-5-(1-methyl ethyl) heptane
0%
2-(1,2-dimethyl ethyl)-5-ethyl-6-methyl heptane
0%
3-ethyl-2,6,7,7-tetramethyl octane
0%
6-ethyl-2,2,3,7-tetramethyl octane

Explanation

Rules for Naming Hydrocarbons:-

Rule-I Selection of the longest carbon chain.

Rule-II Numbering the longest chain: Longest chain is numbered starting from a terminal carbon. Numbering is done is such a way that lowest possible number is given to the side cahin or a functional group.

Rule-III Writing names of branched, saturated hydrocarbons, locants are written first in alphabetical order followed by name of parent chain.

Rule-IV Some common names are retained in $IUPAC$ system for unsubstituted hydrocarbon only.

Option (D) 6-ethyl-2,2,3,7-tetramethyl octane is the answer.

(Refer to Image)

For

$8$ -carbon atom

$\longrightarrow$ Octane.

For

$-CH_3$ group

$\longrightarrow$ Methyl.

1002734_863918_ans_98ee8b6e9ea740ffbcd7f6b3b14eaf9d.png

IUPAC name of the product obtained when

$2$ - Chloropropane reacts with Na metal -

0%
n- Hexane
0%
$2, 3$ - Dimethylbutane
0%
Butane
0%
$3, 4$ - Dimethylhexane

The IUPAC name of the compound :

0%
3,3-dimethyl-1-hydroxy cyclohexane
0%
1, 1-dimethyl-3-hydroxy cyclohexane
0%
3,3-dimethyl-1 -cyclohexane
0%
1,1-dimethyl 1-3-cyclohexane

Explanation

$3,3 \text { -dimethyl-1-hydroxy cyclohexane }$
2005005_874878_ans_6787bf590f494de2b691d00775a98d80.PNG

The IUPAC name of the compound given is :

$\underset{\!\!\!\!\!{\displaystyle \text {OH}}}{\underset{|}{C}H_2} - \underset{{\displaystyle \text {NH}}_2}{\underset{|}{C}H} - COOH$

0%
2-amino-3-hydroxypropanoic acid
0%
1-hydroxy-2-aminopropan-3-oic acid
0%
1-amino-2-hydroxypropanoic acid
0%
3-hydroxy-2-aminopropanoic acid

Explanation

Answer:-

Since the given compound has a carboxylic acid group as the main group, thus numbering will start from that side.

$\therefore$ The correct IUPAC name of the given compound is - 2-amino-3-hydroxypropanoic acid.

Lassaigne's test for the detection of nitrogen fails in:

0%
${ NH }_{ 2 }CONH{ NH }_{ 2 }.HCl$
0%
${ NH }_{ 2 }{ NH }_{ 2 }.HCl$
0%
${ NH }_{ 2 }CO{ NH }_{ 2 }$
0%
${ C }_{ 6 }{ H }_{ 5 }{ NH }{ NH }_{ 2 }.HCl$

Explanation

In the absence of carbon in the organic compound in Lassaigne's test,

$NaCN$ is not formed as a product.

$N{H}_{2}N{H}_{2}.HCl$ does not have any carbon, it does not respond to the Lassaigne's test.

Silt in water remains suspended. It is removed by sedimentation and filtration. For increasing its sedimentation aluminium sulphates and calcium hydroxide (slaked lime) are added. As a result sticky aluminium hydroxide.

0%
Destroys slit particles
0%
Attracts the particles of slit
0%
Mixes with slit particles
0%
Makes slit particles increases in size and deposit at the bottom

Explanation

The silt in

$H_2O$ remains suspended. To attract some more silt particles,

$Al(OH)_3$ is used. It is used to absorb the silt particles and make the liquid more pure.

The correct

$IUPAC$ name of the following alkane is:

0%
$3,6-diethyl-2-methyloctane$
0%
$5-isopropyl-3-ethyloctane$
0%
$3-ethyl-5-isopropyloctane$
0%
$3-isopropyl-6-ethyloctane.$

Explanation

Correct Answer: Option A

Explanation:

Numbering should be such that substituent gets the least positions.

Considering that substituents should be given lowest numbering and selecting the longest chain, the compounds IUPAC name will be,

$3,6 - diethyl - 2 - methyloctane$ .

Hence option $A$ is correct answer.

If an adding of

$FeCl_3$ solution to acidified Lassaigne s solution, a red colouration is produced, it indicates the presence of:

0%
$S$
0%
$N$
0%
$N$ and $S$
0%
$S$ and $Cl$

Explanation

The red colour is due to the formation of

$Fe{(CNS)}_{3}$ which indicates the presence of both,

$N$ and

$S$ and the extract used will be

$NaCNS$ .

$Fe{Cl}_{3} + 3NaCNS \longrightarrow \underset{\text{Blood red colour}}{Fe{(CNS)}_{3}} + 3NaCl$

In lassaigne's test for

$N,\ S$ and halogen, the organic compound is:

0%
fused with sodium
0%
dissolved with sodamide
0%
extracted with sodamide
0%
fused with calium

The correct structure for triphenylbromomethane is :

The IUPAC name for compound ?

0%
1-Chloro-2 nitro-4-methylbenzene
0%
1-Chloro-4 methyl-2- nitrobenzene
0%
2-Chloro-1 nitro-5- methylbenzene
0%
m-nitro-p-chlorotoluene

Explanation

(Refer to Image)

$1-chloro-4-methyl-2-nitrobenzene$

1158305_930503_ans_d4772e7501b74d698f91382b7a9cd596.png

The process of separation of an organic compound from its aqueous solution by shaking with a suitable solvent is termed solvent extraction or differential extraction.
The organic compound present in aqueous layer moves to the organic solvent because:

0%
the organic substance is more soluble in the organic solvent
0%
organic compound being lighter moves in the upper layer
0%
organic solvent is insoluble in water hence organic compound moves up
0%
from the supersaturated aqueous solution the solute starts diffusing

The synthetic steroid ethynylestardiol (1) is a compound used in the birth control pill.
Which of the following functional group is contained in compound (1)?

0%
A ketone
0%
An alcohol
0%
A carboxylic acid
0%
An ester

Explanation

In the above compound

$-OH$ group is present only which is an alcohol group.

Hydroboration of 1- methylcyclopentene using

$B_2D_6$ , followed by treatment with alkaline hydrogen peroxide, gives

Explanation

As refer to the above image addition reaction using hydroboration follow Anti-Markovnikov’s rule. Hence, $D$ attaches to the first carbon.

1099138_989596_ans_55076b3b5cdf4d6b91b14baf49165c4a.PNG

Prostaglandin

$E_1$ 1 is a compound produced by the body to regulate a variety of processes including blood clotting, fever, pain and inflammation.
Which of the following functional groups is not contained in 1 ?

0%
A ketone
0%
An alcohol
0%
A carboxylic acid
0%
An alkene
0%
A nitrile

Which of the following substances is not of 3-ethyl 2-methyl pentane?

0%
0%
0%
0%
All are isomers

Explanation

The above compound is not an isomers of

$3-ethyl$

$2-methyl$

$pentane$
As this compound has

$7$ carbon while

$3-ethyl$

$2-methyl$

$pentane$ has

$8$ carbons.

1053334_988881_ans_ec8115da18ae44b597db7a1035e32ee4.png

The functional groups present in Cortisone are:

0%
Ether, alkene, alchohol
0%
Alcohol, ketone, alkene, ether
0%
Alcohol, ketone, ammine
0%
Ether, amine, ketone

Explanation

$a$ is alcoholic group,

$b$ is ether,

$c$ is ketone group and

$d$ is the alkene group.
1157435_988183_ans_1ecdebc3dedf4e5c9b79889862f176e3.png

The synthetic steroid ethynylestardiol (1) is a compuond used in the birth control pill.
How many asymmetric (stereogenic) centres are present in compound (1) ?

0%
2
0%
3
0%
4
0%
5

Explanation

Stereogenic centres are those centre which are attached to the different group with single bond.

There are

$5$ stereogenic centre.

1187342_988747_ans_c1a274a6ef21463cabdedca89a6a78fa.JPG

IUPAC name of 4-iso-propyl-m-xylene is:

0%
1-iso-propyl-2,4-dimethylbenzene
0%
4-iso-propyl-m-xylene
0%
4-iso-propyl-2,3-dimethylbenzene
0%
4-iso-propyl-3,5-dimethylbenzene

Explanation

According to IUPAC convention, least number should be given to the substituent on parent molecule.

Name is:

$1-iso-propyl-2,4-dimethylbenzene$

Identify which functional group are not present in the given compound?

0%
ketone
0%
Ester
0%
Amide
0%
Ether

Explanation

Box

$a$ encloses ester group,

$b$ encloses ketone group while

$c$ encloses amide group.
Here ether group is not present.
1172754_988113_ans_bf86103e9bfc44e198a8582b5f4ab11f.png

The IUPAC name of the compound is

0%
$4$ -ethoxycarbonylpent- $3$ -enoic acid
0%
$4$ -ethanoyloxypent- $3$ -enoic acid
0%
$3$ -ethoxycarbonylbut- $2$ -enecarboxylic acid
0%
$3$ -ethoxycarbonylpent - $3$ - enoic acid

Explanation

Priority of

$-COOH$ is greater than an ester group and numbering is always made from

$-C^1OOH$ .

IUPAC name:

$4-ethoxycarbonylpent-3-enoic$

$acid$ .

1116719_996508_ans_bc4c43bc12ae4279b4b33a2280fad628.png

Nitrene is a/an:

0%
nucleophile
0%
electrophile
0%
charged species
0%
free atom

Which of the following would be expected to be most highly ionised in water?

0%
${\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{COOH}}$
0%
${\text{C}}{{\text{H}}_{\text{3}}}{\text{CHClC}}{{\text{H}}_{\text{2}}}{\text{COOH}}$
0%
${\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_2}{\text{CC}}{{\text{l}}_2}{\text{COOH}}$
0%
${\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_2}{\text{CHClCOOH}}$

Explanation

Fast ionization is shown by strong acids. Chlorine atom has high

$-I$ effect so when attached to nearly carbon, it increases acidity thus is more acidic.

Therefore option C is correct .

How many total numbers of

$\pi$ -bonds are present in complex

$K_3[Fe(CN)_5O_2]Fe$ having

$t_{2g}^{6}e_g{^0}$ ?

0%
$11$ $\pi$ bond
0%
$10$ $\pi$ bond
0%
$10.5$ $\pi$ bond
0%
None of these

Calculate the amount of NaOH required to neutralise 100 mL 0.1 M H2SO4

0%
0.8
0%
0.5
0%
0.6
0%
0.7

IUPAC name of the bond line structure is:

0%
trimethyl propane
0%
pent-1-yne
0%
pent-2-ene
0%
1, 3-pentadiene

Explanation

According to IUPAC convention, numbering should be done such that minimum number should be given on groups or parent chain.

Name is:

$Pentyne$ or

$Pent-1-yne$ or

$1-pentyne$

988935_1006386_ans_739973c18f5c47299997603b76d38727.PNG

The IUPAC name of the compound is:

0%
1-hydroxy-4-methylpentan-3-one
0%
2-methyl-5-hydroxypentan-3-one
0%
4-methyl-3-oopentan-1-ol
0%
hexan-1-ol-3-one

Explanation

According to IUPAC convention, numbering is done in such a way that heto group and

$-OH$ group get less numbering with highest priority .

So, the name is:

$1-hydroxy-4-methylpentan-3-one$

990111_1007614_ans_63f5d87d45314155a0b578fcabda1838.PNG

IUPAC name of the given compound is:

0%
(2 - chlorocyclopropenyl ) - 4 - chloro - 2 - fluoro -3 [ 2 - oxoformyl ] cyclohex - 5 - enecarboxylate
0%
(2 - chlorocyclopropenyl ) - 4 - chloro - 6 - fluoro -5 [ oxoethyl] cyclohex-2-enecarboxylate
0%
(2 - chlorocyclopropenyl ) - 4 - chloro - 2 - fluoro -3 [ formylmethyl ] cyclohex - 5 - enecarboxylate
0%
(2 - chlorocyclopropenyl ) - 4 - chloro - 2 - fluoro -3 [ 2 - formylmethyl ] cyclohex - 5 - enecarboxylate

Explanation

$\begin{array}{l} \text { - Find and name the longest continues carbon chain } \\ \text { - Identify and name groups attached to this chain. } \\ \text { - Number the chain consecutively, starting at the } \\ \text { end nearest a substituent group. } \\ \text { - Designate the location of each substituent group } \\ \text { by an appopriate number and name. } \end{array}$
2004756_1026791_ans_3d977a14b319426d8c5f915254abf893.jpeg

2004756_1026791_ans_3d977a14b319426d8c5f915254abf893.jpeg

Correct name for the given compound, is ?

$CH_3-CH_2-CH(C_2H_5)-CH_2-CH(CH_3)-C_2H_5$

0%
3-ethyl-5-methylheptane
0%
5-ethyl-3-methylheptane
0%
1,1-diethyl-3-methylpentane
0%
3-methyl-5,5-diethylpentane

Which of the following reacts with an aqueous solution of

$\left[ {{\text{Ag}}\left( {{\text{NH}}_{\text{3}} } \right)_{\text{2}} } \right]^ + {\text{OH}}^{\text{ - }}$ ?

0%
$CH_3 - C \equiv C - CH_3$
0%
$CH_3 - CH = CH_2$
0%
$CH_3 - C \equiv CH$
0%
None of these

Explanation

Only terminal alkyne reacts with tollen's reagent since these are basic reagent require more acidic proton

$(sp-H)$ .
1171523_1006411_ans_6b667df8563a46a79758a9aaafabbc9f.PNG

The IUPAC name of the compound is:

0%
2 - Amino - 3 - chloro - 2 - methylpent - 2 - enoic acid
0%
3 - Amino - 4 - chloro - 2 - methylpent - 2 - enoic acid
0%
4- Amino -3 - chloro - 2 - methylpent - 2 - enoic acid
0%
All of the above

Isopropylamine can be obtained by

0%
${\left( {C{H_3}} \right)_2}C = O + N{H_3} \to ?$
0%
${\left( {C{H_3}} \right)_2}CO + N{H_3}$
0%
${\left( {C{H_3}} \right)_2}CH - Br + NaN{H_2} \to$
0%
${\left( {C{H_3}} \right)_2}CH - Br?$

Which of the following compounds has wrong IUPAC name ?

0%
$CH_ 3-CH_ 2-CH_ 2-COO-{\underset{ethyl\,butanote}{CH_ 2CH_ 3\rightarrow}}$
0%
$CH_3-\underset{CH_3}{\underset{|}{C}H}-CH_2-CHO\rightarrow 3- methyl - butanal$
0%
$CH_3-\underset{OH}{\underset{|}{C}H}-\underset{CH_3}{\underset{|}{C}H}-CH_3 \rightarrow 2- methyl - 3 - butanal$
0%
$CH_3 -\underset{CH_3}{\underset{|}{C}H} -\overset{O}{\overset{||}{ C}} -CH_2 -CH_3 \rightarrow 2- methyl -3 - pentanone$

Explanation

According to IUPAC convention alcohols are having more priority than saturated carbons.

As the IUPAC name of compound shown above is:

$3-methyl$

$butan-2-ol$

990372_1028215_ans_bea45f7f593a46cd8ca6141588c87892.PNG

Dumas method is used for estimation of:

0%
carbon
0%
nitrogen
0%
oxygen
0%
sulphur

Which of the following names is IUPAC name for the given compound?

$\underset{\underset{\,\,\,\,CHO}{|}}{C}H_2\underset{\underset{\,\,\,\,\,CHO}{|}}{C}H-\underset{\underset{\,\,\,\,\,CHO}{\,\,|}}{C}H_2$

0%
2- Formyl pentane -1, 5-dial
0%
1,2,3-Triformyl - propane
0%
2 - formylbutane - 1, 4 - dial
0%
Propane -1,2,3 - tricarbaldehyde

Explanation

The

$IUPAC$ name of the following compound is propane

$-1,2,3-$ tricarbaldehyde.
1381146_1048096_ans_29ac7e1ed9404b7c81307d480a62c4f2.jpg

The IUPAC name of the compound is:

0%
$1$ -amino- $1$ -phenyl- $2$ -methyl propane
0%
$2$ -methyl- $1$ -phenyl propane- $1$ -amine
0%
$2$ -methyl- $1$ -amino- $1$ -phenyl propane
0%
$1$ -isopropyl- $1$ phenyl methyl amine

Explanation

According to

$IPUAC$ nomendatus ir has

$3$ carbon long, long chain and on position

$2$ a methyl group is attached. Then on position

$1$ a phenyl and an amino group is attached. So its

$IUPAC$ name will be,

$1-$ amino

$-1-$ phenyl

$-2-$ methyl propane.

According to the IUPAC system,

${ CH }_{ 3 }{ CH }_{ 2 }COCl$ is named as:

0%
chloropropane
0%
propanoyl chloride
0%
chloropropanyl
0%
none of these

Which of the following is not the correct

$IUPAC$ name?

0%
$2$ -ethyl- $3$ -methyl pentane
0%
$4$ -formyl pentan- $2$ -ol
0%
$3$ -Carboxy pentanoic acid
0%
Cyclohexanoic acid

The number of carbon atoms in the principal carbon chain of the given compound in its IUPAC name will be:

0%
5
0%
4
0%
3
0%
none of these

Explanation

Here, there are

$4$ carbon atoms in the principal carbon chain.

1184795_1067669_ans_184de1807f814cab8d21b87dcdd14482.png

Which of the following is/are incorrect

$IUPAC$ name?

0%
$4$ -Chloro- $3$ -methyl cyclopentanol- $1$
0%
$1$ -Amino- $3$ -bromo hexan- $2$ -one
0%
$4$ -Chloro- $3$ -methyl cyclohexanoic acid
0%
$3$ -Bromo- $1$ -methyl hexan- $1$ -ol

Explanation

$4-Chloro-3-methyl-cyclopentanol-1$ is an incorrect

$IUPAC$ name because

$1$ should not come at last. As

$1$ defines position of

$-OH$ group so it should be written as

$4-Chloro-3-methyl-cyclopentan-1-ol$ .

The IUPAC name of:

0%
phenyl ethanone
0%
methyl phenyl ketone
0%
acetophenone
0%
phenyl emethyl ketone

Explanation

IUPAC name is Phenyl ethanone.

functional group of ketone is

$R'-C^{=O}-R"$

The IUPAC name of:

0%
2-chlorocarbony ethylbenzoate
0%
2-carbocyethyl benzoyl chloride
0%
ethyl-2-(chlorocarbarbonyl) benzoate
0%
ethyl-1-(chlorocarbarbonyl) benzoate

The

$IUPAC$ name of the following structure

${ (CH }_{ 3 })_2C=CH-C\equiv C-CH{\left( C{H}_{ 3 } \right)}_{2}$ is:

0%
$2,6$ -dimethylhept- $4$ -yn- $2$ -ene
0%
$3$ -Methylhept- $2$ -yn- $4$ -ene
0%
$4$ -Methylhex- $4$ -yn- $4$ -ene
0%
all are correct

Explanation

The IUPAC name of the compound is

$2,6$ -dimethyl hept-

$2$ -en-

$4$ -yne

1007095_1067134_ans_e839f1267b44403ca1e701bea3876f31.png

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 7 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 7 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

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