Explanation
Hint: In the oxides, the oxidation number of oxygen is $$-2$$
Correct Answer: Option A
Explanation:
Let the oxidation number of the central atom be $$x$$
$$CrO^{-}_{2}$$:
$$\therefore$$ $$x=+3$$
$$CrO_{4}^{2-}$$:
$$\therefore$$ $$x=+6$$
$$ClO^{-}_{3} $$:
$$\therefore$$ $$x = +5$$
$$MnO_{4}^{-}$$:
$$\therefore$$ $$x = +7$$
Hence, correct answer is $$CrO^{-}_{2}$$, $$ClO^{-}_{3} $$ , $$CrO_{4}^{2-}$$, $$MnO_{4}^{-}$$
Hint
The total number of electrons that an atom acquires or loses in order to form a chemical connection with another atom is known as the oxidation number.
Let the central oxidation number is $$x$$.
The oxidation number of $$O$$ is $$2$$.
Step 1: the oxidation state of $$CrO_{2}^{-}$$
Thus, the oxidation state if $$Cr$$ in $$CrO_{2}^{-}$$.
$$x+2\times \left( -2 \right)=-1$$
$$x-4=-1$$
$$x=-1+4$$
$$x=3$$
Step 2 : the oxidation state of $$CrO_{4}^{2-}$$,
$$x+4\times \left( -2 \right)=-2$$
$$x-8=-2$$
$$x=8-2$$
$$x=6$$
Step 3 : the oxidation state of $$ClO_{3}^{-}$$,
$$x+3\times \left( -2 \right)=-1$$
$$x-6=-1$$
$$x=6-1=5$$
Step 4: the oxidation state of $$MnO_{4}^{-}$$,
$$x+4\times \left( -2 \right)=-1$$
$$x-8=-1$$
$$x=8-1=+7$$
Hence, the increasing order of the central atom is $$CrO_{2}^{-}<ClO_{3}^{-}<CrO_{4}^{2-}<MnO_{4}^{-}$$.
Final answer
The correct answer is option (A).
In $$Ni{(CO) }_{ 4 }$$ the oxidation state of Ni is:
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