Explanation
The actual molecular mass of chlorine is :
The molecular formula of metal carbonate is $${MCO}_{3}$$ as it is isomorphous with $${MgCO}_{3}$$.
Let the mass of metal be $$M$$. Molecular weight of this carbonate $$= (M+12+48)$$. Mass percentage of carbon in this compound $$= 6.091%$$
$$\dfrac{6.091}{100}\times(M+12+48) = 12$$
$$M = \dfrac{12\times100}{6.091} - 60$$
$$M = 137$$
Atomic wt. of the element is 137.01 amu which is Barium and the metal carbonate is BaCO$$_3$$
Hence, the correct option is $$C$$
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