Explanation
Explanation:
Molar mass of ethanol = 46\ grams/(mole)
Molar mass of water = 18\ gram/(mole)
The sum of all mole fractions is 1.
The mole fraction of:
Ethanol = 0.25 and water = 0.75
Let the 10 moles of mixture are present.
Moles of ethanol =\dfrac {0.25}{10}\times 100 = 2.5
Moles of water =\dfrac {0.75}{10}\times 100= 7.5
Given mass of ethanol =2.5 \times 46 = 115\ grams
Given mass of water 7.5 \times 18 = 135\ grams
The percentage concentration of ethanol by weight in the mixture =\dfrac {115}{115+135}\times 100
The percentage concentration of ethanol by weight in the mixture =46\%.
Hence, the correct answer is option C.
Let us assume that the mass of compound is 10 grams.
X and Y both are 50\% of the mass of compound.
Therefore, mass of X = mass of Y = 5 grams.
The atomic mass of X = 10 grams.
The atomic mass of Y = 20 grams.
Number \space of\space moles = \dfrac {given \space mass }{atomic \space mass}
Number \space of\space moles\ of \space X= \dfrac {5 }{10 }=0.5
Number \space of\space moles\ of \space Y= \dfrac {5}{20} =0.25
The formula of compound is X_{0.5}Y_{0.25} i.e. in simple form it is X_2Y.
Hence, the correct answer is option B.
Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
Both statement 1 and statement 2 are correct but Statement 2 is not the correct explanation of Statement 1
Statement 1 is correct but statement 2 is incorrect
Statement 1 is incorrect but statement 2 is correct
Both the statement 1 and statement 2 are incorrect
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