Explanation
So reactivity and reducing power decreases on going from group 1 to group 2 as size decreases from group 1 to group 2.
So given statement is true.
1) $$Be^{2+}$$ and $$Al^{3+}$$ have almost same and smaller size and thus favour for covalent bonding.
2) Both these form covalent compounds having low melting point and soluble in organic solvent.
3) Both have same value of electronegativity.
4) Their oxides are soluble in alkali solution forming $$[Be(OH)_4]^{3-}$$
5) Both form many stable complexes for example $$BeH_3^-, \ AlH_4^-$$.
6) They form complex anion $$BeF_4^{2-}$$ and $$AlF_6^{3-}$$.
7) $$BeCl_2$$ and $$AlCl_3$$ are Lewis acid.
Hence options A,B & C are correct.
The two structures involve the only movement of electrons and not of atoms or groups, hence these are resonating structures. Both metals have the tendency to form covalent compounds Diagonal relationship of Be with Al Because of its small size. Be differs from other earth alkaline earth metals but resembles in many of its properties with Al on account of the diagonal relationship.
The correct option is that $$Be (OH)_{2} $$ like $$Al (OH)_{3}$$ both are basic in nature.
$$BeSO_4 < MgSO_4 < CaSO_4$$(increasing stability)
Temp.of Decomposition of $$BeSO_4 , MgSO_4 , CaSO_4$$ are 773K ,11681 K and 1422K respectively.
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