Explanation
$$Be^{+3}$$ is isoelectronic with $$Li^{+2}$$. Both the ions are having 1 electron only in their valence shells. So they are isoelectronic with each other.
So the option A is the correct statement for $$Be^{+3}$$.
Hence option A is correct.
It has only one electron in its valence shell and can only take the +1 oxidation state.
Now, in $$KO_2$$, let oxidation number of oxygen be x.
Therefore, $$1+2x=0$$ as $$K=+1$$ and $$KO_2$$ is a neutral molecule.
The oxidation number of oxygen in $$KO_2$$ is $$\cfrac{-1}{2}$$
$$LiAlH_4$$ is obtained by reacting an excess of $${LiH}$$ with an ethereal solution of $$AlCl_3$$.
$$LiAlH_4$$ is prepared from the reaction between lithium hydride $$(LiH)$$ and aluminium chloride.
$$4LiH + AlCl_3 \rightarrow LiAlH_4 + 3 LiCl$$
So the correct option is B
Similarities of lithium with magnesium and dissimilarities with that of the other members of the group
Lithium is a very strong element and is equally strong as magnesium.
Li forms $$Li_3N$$ with nitrogen.
It has high melting and boiling points. The boiling point of lithium is $$1330$$ degree centigrade that is comparable to that of magnesium which is $$1100$$ degrees.
Due to small size, the lithium atom has high ionization energy. Hence, it remains inactive to dry air, slowly reactivity with water, liquid bromine and forms a highly stable hydride unlike other alkali metals.
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