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CBSE Questions for Class 11 Medical Chemistry Classification Of Elements And Periodicity In Properties Quiz 13 - MCQExams.com
CBSE
Class 11 Medical Chemistry
Classification Of Elements And Periodicity In Properties
Quiz 13
An element Y has the proton number 18 .The next element of the periodic table is an element Z.
Which statement is correct?
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Element Z has 1 more electron in its outer shell than element Y.
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Element Z has 1 more electron shell than element Y.
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Element Z is in the same group of the periodic table as element Y.
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Element Z is in the same period of the periodic table as element Y.
The IUPAC name of the element having atomic number 109 is
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Unniloctium
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Unnilquadium
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Unnilennium
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Ununseptium
The electronic configuration of an element is $$1{ s }^{ 2 }2{ s }^{ 2 }2{ p }^{ 6 }3{ s }^{ 2 }3{ p }^{ 6 }3{ d }^{ 5 }4{ s }^{ 1 }.$$ This represents its:
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excited state
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ground state
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cationic form
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none
The correct order of second I. E. of C, N, O and F are in the order :
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F > O > N > C
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C > N > O > F
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O > N > F > C
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O > F > N > C
Which of the following is not correct increasing order of ionisation energy
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$$Cl^{-} < Ar < K^{+}$$
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Au < Ag < Cu
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Cs < Rb < K
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K < Ca < Sc
Explanation
Ionization energy of gold is more than copper and silver because of poor shielding of 4f electrons nucleus has more attraction on s-orbital electrons.
so correct order is $$Au > Cu> Ag$$
The elements with the lowest number that has a ground state electronic configuration of $$\left( {n - 1} \right){d^6}n{s^2}$$ is located in the :
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fifth period
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sixth period
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fourth period
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third period
Explanation
For d, minimum orbital is $$3d$$ , which is in the fourth period {Option C}
Group I elements of the periodic table are known as:
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Alkali metals
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Alkaline earth metals
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Inert gases
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None of these
Which of the following atoms has the highest first ionisation energy?
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$$Na$$
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$$K$$
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$$Cs$$
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$$Rb$$
Which of the following has maximum ionization potential?
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$$Al$$
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$$P$$
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$$Si$$
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$$Mg$$
General electronic configuration of outermost and penultimate shell is $$(n-1) s^2(n - 1)p^6(n - 1)d^x ns^2$$. If $$n = 4$$ and $$x = 5$$, then the number of protons in the nucleus will be:
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$$> 25$$
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$$< 24$$
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$$25$$
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$$30$$
Which one of the following is not a monoatomic element ?
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Copper
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Helium
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Iodine
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Barium
Explanation
Iodine is not a monoatomic elements. It is diatomic element. Rest are all monoatomic elements.
Select the correct order of first ionization potential :
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$$ N > O_2 $$
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$$ O_2 > N $$
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$$ O_2 = N $$
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None of these
Which of the following is incorrect ?
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Among $$Cl, Ar$$ and $$K,K$$ has the smallest ionization potential
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Among $$ CH_4 ,NH_3$$ and $$ HF, HF$$ has the highest boiling point
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Among $$ Cl_2, Br_2$$ and $$I_2 , Br_ 2 $$ has the lowest boiling point
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Among $$HOl$$ and $$HOBr$$ and $$HOCl, HOl$$ is the weakest
Sodium has, as compared to potassium:
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less electronegativity
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more ionisation potential
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larger atomic radius
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lower melting point
Explanation
Element
$$Na$$
$$K$$
$$IE_1$$ $$496$$
$$419$$
$$IE_2$$
$$4562$$
$$3051$$
sodium has higher $$I.E$$ because of smaller atomic size.
Option B is correct.
An element having electronic configuration $$1s^{2}, 2s^{2}, 2p^{6}, 3s^{2},3p^{6}, 4s^{1}$$ will form:
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Acidic oxide
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Basic oxide
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Amphoteric oxide
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Neutral oxide
The ionisation enthalpy of isotopes of an element will be:
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same
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different
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dependent on atomic masses
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dependent on the number of neutrons present in the nucleus
Explanation
Ionisation enthalpy is the minimum amount of energy required to remove an electron from the outermost shell of a neutral isolated gaseous atom in its ground state. Since the isotopes of the same element have the same atomic number, they have the same number of electrons (and protons) and differ only in the number of neutrons.
Hence the ionisation energy for two isotopes of an element will be the same.
The set representing the correct order of first ionisation enthalpy is :
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K > Na > Li
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Be > Mg > Ca
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B > C > N
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Ge > Si > C
In which of the following arrangements, the order is not according to the property indicated against it?
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$$ Al^{3+} < Mg^{2+} < Na^+ < F^- $$ increasing ionic size
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B < C < N < O increasing first ionisation enthalpy
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I < Br < F < Cl increasing electron gain enthalpy (with negative sign)
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Li < Na < K < Rb increasing metallic radius
Explanation
First $$IE$$ of N will be maximum as it has a half filled orbital providing it extra stability.
Potassium forms $$K^+$$ ion but it does not form $$K^{2+}$$ because of
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Very low value of $$(I.E.)_1$$ and $$(I.E.)_2$$
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Very high value of $$(I.E.)_1$$ and $$(I.E.)_2$$
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Low value of $$(I.E.)_1$$ and low value of $$(I.E.)_2$$
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Low value of $$(I.E.)_1$$ and high value of $$(I.E.)_2$$
Explanation
$$K \xrightarrow {I.E._1} K^+ \xrightarrow {I.E._2} K^{2+}$$
$$I.E._2 > > I.E._1$$
$$\therefore$$ Potassium gets ionized only once after which it attains inert gas configuration.
$$K^+ = 1s^2, 2s^2 2p^6, 3s^23p^6$$
In the following, the element with the highest ionisation energy is :
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$$ [Ne] 3s^2 3p^1 $$
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$$ [Ne] 3s^23p^3 $$
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$$ [Ne] 3s^2 3p^2 $$
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$$ [Ne]3s^2 3p^4 $$
Explanation
$$ [Ne]3s^23p^3 $$ is a symmetrical configuration or half-filled stability thus, this atom has extra stability. So, this element will have the highest ionisation energy.
For the process
$$A_{(g)} + e^- \longrightarrow A_{(g)}; \quad \Delta H = x$$
and $$A^- _{(g)} \longrightarrow A_{(g)} + e^-; \quad \Delta H = y$$
Select correct alternate:
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Ionization energy of $$A^-_{(g)}$$ is $$y.$$
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Electron affinity of $$A_{(g)}$$ is $$x.$$
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Electron affinity of $$A_{(g)}$$ is $$-y.$$
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All are correct statements
In which of the following arrangements, the order is NOT according to the property indicated against it?
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$$Li < Na < K < Rb$$: increasing metallic radius
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$$I < Br < F < Cl$$: increasing electron gain enthalpy
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$$B < C < N < O$$: increasing first ionization enthalpy
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$$Al^{3+} < Mg^{2+} < Na^+< F^-:$$ increasing ionic size
Explanation
Ionisation energy of $$N$$ is greater than $$O$$ due to its half-filled 2p - subshell.
So, the correct order is:
$$B < C < O < N$$: increasing first ionization enthalpy.
The element with atomic number 3 to 10 belong to the second period. Identify the most electropositive and most electronegative element in this period.
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$$F, Li$$
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$$Li, F$$
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$$Li, Ne$$
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$$Ne, Li$$
Explanation
Li having atomic number 3 is most electropositive and F having atomic number 9 is most electronegative in this period.
Assign the position of the element having outer electronic configuration,
(A) $$ns^2np^2\,(n =6)$$
(B) $$(n - 1)d^2ns^2\,(n=4)$$
(C) $$(n-2)f^7(n-1)d^{1}ns^2\,(n=6)$$
Which of the following statement(s) is/are correct?
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The element A belongs to $$3^{rd}$$ periods and $$16^{th}$$ groups.
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The element ‘A belongs to $$6^{th}$$ periods and $$14^{th}$$ groups.
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The element 'C’ belongs to $$6^{th}$$ period and is a lanthanide element
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All A, B, C elements are metals
Explanation
The ground state electron configuration of A is $$[Xe]\; 4f^{14}.\;5d^{10}.\;6s^2\;6p^2$$.
Group: 14, Period : 6
The electronic configuration of B is $$[Ar]\;3d^2\;4s^2$$.
Group : 4, Period : 4
The electronic configuration of C is $$[Xe]\; 4f^7 \;5d^1\; 6s^2$$
Group :Lanthanide, Period : 6
Which of the following atomic species has maximum ionization energy?
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$$O^-$$
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$$S^-$$
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$$Se^-$$
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$$Te^-$$
Which of the following pairs of elements have the same number of electrons in their outermost shell
?
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Mn, Fe
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Na, Sr
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As, Bi
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Se, Te
Explanation
C) $$As: 4s^2\;4p^3$$
$$Bi: 6s^2\;6p^3$$
D) $$Se: 4s^2\;4p^4$$
$$Te: 5s^2\;5p^3$$
Hence option C and D are correct
An element of the $$4th$$ period which has maximum number of unpaired electrons is :
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$$_{20} Ca $$
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$$_{24}Cr $$
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$$_{30}Zn$$
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$$_{33} As$$
The first ionization potential of $$Mg , Al , P $$ and $$S$$ follows the order:
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$$Mg < Al < P < S $$
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$$Al < Mg < P < S $$
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$$Al < Mg < S < P $$
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$$Mg < Al < S < P $$
Explanation
Because of extra stability of exactly half-filled electronic configuration of P its $$IE_{1}$$ is higher than that of S. Further the $$IE_{1}$$ of Mg is higher than that of Al because in case of Mg , electron is to be removed from a $$3s$$- orbital while in case of Al, the electron is to be removed from a $$3p$$ orbital. Thus option (c), i.e., $$Al < Mg < S < P $$ is correct.
Hence option C is correct
The first ionization enthalpies of the given elements are in the order of:
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$$C < N < Si < P$$
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$$N < Si < C < P$$
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$$Si < P < C < N$$
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$$P < Si < N < C$$
If there were 10 periods in the periodic table and each orbital could have maximum 4 electrons, then how many maximum number of elements would be present in period 9?
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100
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125
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150
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90
The first ionization energies of $$Na , Mg , Al $$ and $$Si$$ are in the order :
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$$ Na < Mg > Al < Si $$
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$$Na > Mg > Al < Si $$
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$$Na > Mg > Al > Si $$
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$$Na < Mg < Al < Si $$
The highly metallic element will have the configuration of :
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$$ 2 , 8 , 7 $$
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$$ 2 , 8 , 8 , 5 $$
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$$ 2 , 8 , 8 , 1 $$
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$$ 2 , 8 , 2 $$
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Practice Class 11 Medical Chemistry Quiz Questions and Answers
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