MCQ Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 1

Acetylene reacts with excess of hypochiorous acid to produce

0%
Acetylene tetrachloride
0%
Acetylene chlorohydrin
0%
Acetaldehyde
0%
Dichloroacetaldehyde.

In which case butane is formed ?

0%
$2C_2H_5 -CI+Na$
0%
$C_2H_5COOH+Na_2CO_3$
0%
${ CH }_{ 3 }{ CH }_{ 2 }\overset { \overset { O }{ || } }{ C } -OH+H_{ 2 }O$
0%
$CH_2=CH_2+H_2SO_4$

$CH_3CH=CH-CH_2-CO_2H\xrightarrow[\Delta]{}(X)$ (major); Product (X) is :

0%
$CH_3CH=CH-CH_3$
0%
$CH_3-\underset{\,\,\,\,CH_3}{\underset{|}{C}}=CH_2$
0%
$CH_3-CH_2-CH=CH_2$
0%
$CH_3-CH=CH_2$

Electromagnetic radiation with maximum wavelength is

0%
ultraviolet
0%
radio waves
0%
x-rays
0%
infrared

$IUPAC$ name of the following compound is:

0%
4 - ethyl - 7 methyl nonane
0%
3,3, 4- trimethyl - 7- ethyl decane
0%
3 - propyl - 7 - methyl octane
0%
7- ethyl- 3,3, 4- trimethyl decane

Which of the following alkane gives only two mono chloro-derivatives?

0%
propane
0%
n-butane
0%
isobutane
0%
All

Alkanes can be obtained by the hydrolysis of

0%
$\mathrm{CaC}_{2}$
0%
$\mathrm{Mg}_{2} \mathrm{C}_{3}$
0%
$\mathrm{Be}_{2} \mathrm{C}_{3}$
0%
$\mathrm{Al}_{4} \mathrm{C}_{3}$

Methane is obtained from among the following:

0%
$A{ l }_{ 4 }{ C }_{ 3 }$
0%
$Be_{ 2 }{ C }$
0%
${ Mg }_{ 2 }{ C }_{ 3 }$
0%
Both A and B

When the given compound undergoes Hoffmann methylation, the major product of the reaction:

Which of the following is not a pair of isomers:

0%
Propyne and Cyclopropene
0%
Propyne and Propadiene
0%
Propene and Cyclopropene
0%
$1$ - Propanol and Methoxy ethane

The molecular formula of Ethyne is ______

0%
$C_3H_6$
0%
$C_2H_4$
0%
$C_2H_2$
0%
$C_2H_6$

Explanation

The molecular formula of Ethyne is

$C_2H_2$ and it is the simplest alkyne with a carbon-carbon triple bond.

Rank the following substances in decreasing order of heats of combustion ( most exothermic

$\rightarrow$ east exothermic)

0%
2 > 1> 3
0%
2 > 3 >1
0%
3 > 1 > 2
0%
3 > 2 > 1

The smallest possible alkane with ethyl group as substituent possess molecular mass

0%
16
0%
72
0%
84
0%
100

The product of the following reaction is

An alkane

${ C }_{ 7 }{ H }_{ 16 }$ is produced by the reaction of lithium di(3-pentyl) cuprate with ethyl bromide. The alkane produced is

0%
3-methylhexane
0%
2-ethylpentane
0%
heptane
0%
3-ethylpentane
0%
2-methylpentane

Meso - dibromobutane on debromination gives

0%
Trans -2-butene
0%
Cis-2-butene
0%
1 - Butene
0%
1 - Butyne

Compound having open chain is-

0%
Pentane
0%
Isopentane
0%
Neopentane
0%
All of the above

Number of monochloroderivatives formed on chlorinating n-butane is

0%
1
0%
2
0%
3
0%
4

On disubstitution of propane with chlorine, gives _____ number of possible products

0%
$2$
0%
$3$
0%
$4$
0%
$5$

IUPAC name of the compound shown above is:

0%
3,3-Bis(1,1-dimethylethyl) pentane
0%
3,3-Bis(isopropyl)pentane
0%
3-Ethyl-3-isopropyl-2,2-dimethyl pentane
0%
3,3-Diethyl-2,2,4 4-tetramethyl pentane

Which of the following reaction will not give methane?

0%
$\mathrm { CH } _ { 3 } \mathrm { COONa } \frac { \mathrm { NaOH } + \mathrm { CaO } } { \Delta }$
0%
$\mathrm { BeC } _ { 2 } + \mathrm { H } _ { 2 } \mathrm { O } \stackrel { \Delta } { \longrightarrow }$
0%
$\mathrm { Al } _ { 4 } \mathrm { C } _ { 3 } + \mathrm { H } _ { 2 } \mathrm { O } \stackrel { \Delta } { \longrightarrow }$
0%
All of these

What is degree of unsaturation ?

0%
8
0%
7
0%
10
0%
9

A and B are -

0%
alcoholic KOH and $NaNH_{2}$
0%
$NaNH_{2}$ and alcoholic KOH
0%
$NaNH_{2}$ and Lindlar
0%
Lindlar and $NaNH_{2}$

$CH_3CH_2CH_3 \xrightarrow[hv]{Cl_2} \underset {(monochlorination\, product)}{A+B}$

The approximate ratio of percentage yields of A and B formed in the above reaction is:

0%
$56:44$
0%
$72:28$
0%
$50:50$
0%
$75:25$

Wet ether is not used as a solvent in Wurtz reaction because of the water present in it_____________.

0%
hydrolyses RX to ROH
0%
reduces RX to RH
0%
oxidize RX to RH
0%
reacts with R-R

Explanation

If water is used instead of ether, hydrolysis of RX will happen and ROH will be formed as product.
Wurtz reaction:

$RX+2Na+XR\rightarrow R-R+2NaX$

C- H bond type in benzene is:

0%
$\sigma$ $sp-s$
0%
$\sigma$ $sp^{2}-s$
0%
$\sigma$ $sp^{3}-s$
0%
$\sigma$ $p-p$

Explanation

In benzene molecule, six carbon atoms are in

$sp^2$ hybridization and hydrogen atoms have pure 's' orbitals. Overlap is

$sp^2-s$ overlap with formation of a sigma bond.

Common name of alkenes is :

0%
Olefins
0%
Paraffins
0%
Acetylene
0%
Arenes

Explanation

Olefin also called alkene, with the general formula

$C_nH_{2n}$

R in RMgX is :

0%
${ C }_{ 3 }{ H }_{ 7 }$
0%
$C{ H }_{ 3 }$
0%
${ C }_{ 2 }{ H }_{ 5 }$
0%
${ C }_{ 4 }{ H }_{ 9 }$

Product (C) obtained in the above reaction sequence is

0%
Mixture of n-butane, ethane
0%
Only propane
0%
Only ethane
0%
n-hexane

The major product

$X$ and

$Y$ in the following sequence of transformations are:

A mixture of

$1-chlorobutane$ and

$2-chlorobutane$ when treated with alcoholic

$KOH$ , gives:

0%
$1-butene$
0%
$2-butene$
0%
Isobutylene
0%
a mixture of $1-butene$ and $2-butene$

Among the following the number of aromatic compound(s) is/are:

0%
2
0%
4
0%
1
0%
3

The IUPAC name of the following compound is:

0%
$3$ -ethyl- $4$ -methylhex- $4$ -ene
0%
$4, 4$ -diethyl- $3$ -methylbut- $2$ -ene
0%
$4$ -Ethyl- $3$ -methylhex- $2$ -ene
0%
$4$ -methyl- $3$ -ethylhex- $4$ -ene

IUPAC name of the compound is:

0%
2,2,3-Trimethyl hexane
0%
2-propyl -3,3-dimethyl butane
0%
2,2 dimethyl -3-methyl butane
0%
2-propyl 3,3-dimethyl hexane

Explanation

$\text { IUPAC name is } 2,2,3 \text {-trimethyl }\text {hexane.}$
1993960_244381_ans_9dce65b460f94aa89c1004d51b045cbe.PNG

In the reaction,

$CH_{3}COOH\xrightarrow{LiAlH_{4}}A\xrightarrow{PCl_{5}}B\xrightarrow{Alc.KOH}C,$ the product

$C$ is:

0%
Ethylene
0%
Acetyl chloride
0%
Acetaldehyde
0%
Acetylene

Explanation

$CH_{3}COOH\xrightarrow{LiAlH_{4}}CH_{3}CH_{2}OH\xrightarrow{PCl_{5}}CH_{3}CH_{2}Cl\xrightarrow{alc.KOH}H_{2}C=CH_{2}$
(ethylene)

The compound

$Y$ is:

Explanation

Hence, the answer is option

$C$ .

Cyclohexene is best prepared from cyclohexanol by which of the following?

0%
Conc. $H_3PO_4$
0%
Conc. $HCl/ ZnCl_2$
0%
Conc. $HCl$
0%
Conc. $HBr$

A fuel has the same knocking property as a mixture of 70% iso-octane (2, 2, 4-trimethylpentane) and 30% n-heptane by volume. The octane number of the fuel is:

0%
100
0%
70
0%
50
0%
40

A compound X is obtained by the reaction of alkaline

$KMnO_3$ with another compound Y followed by acidification. Compound X also reacts with compound Y in presence of few drops of

$H_2SO_4$ to form a sweet smelling compound Z. The compound X, Y and Z are respectively.

0%
Ethanol, Ethene, Ethanoic acid
0%
Ethanoic acid, Ethanol, Ethylethanoate
0%
Ethanoic Acid, Ethanal, Ethene
0%
Ethanol, Ethanoic Acid, Sodium Ethanoate

Explanation

Ethanoic acid is obtained by the reaction of alkaline KMnO4

$_4$ with ethanol followed by acidification.

$CH_3-CH_2-OH \xrightarrow [\text {ii. acidification}]{\text {i. alkaline KMnO}_4} CH_3-COOH$

Ethanoic acid also reacts with ethanol in presence of few drops of H

$_2$ SO

$_4$ to form a sweet smelling ethyl ethanoate.

$CH_3-COOH+CH_3-CH_2-OH \xrightarrow {H_2SO_4} CH_3-COOCH_2-CH_3$

The compound

$X$ ,

$Y$ and

$Z$ are ethanoic acid, ethanol, ethylethanoate respectively.

Hence, option (B) is the correct answer.

When chloro-benzene reacts with sodium in presence of ether than the major product formed is.

which compound is geometrical isomers showing

0%
methane
0%
ethane
0%
1 butane
0%
2-butene

The IUPAC name of

$H_{3}CH_{2}C-C(CH_{3})_{2}-C\equiv CH$ is:

0%
3,3 - dimethyl -1- pentyne
0%
Propyne
0%
Butyne
0%
2-pentyne

Choose the correct IUPAC name of the following compound from the given-below options

0%
$3,4-Dimethyl$ $Pent-1-ene$ $3-Sulphonic Acid$
0%
$3,4-Dimethyl$ $Pent-1-ene$ $2- Sulphonic Acid$
0%
$3 -Methyl$ $4-Ethyl$ $Pent-1-ene$ $3- Sulphonic Acid$
0%
$None$ $of$ $the$ $above$

Correct naming of the given compound is:

0%
ethane
0%
ethene
0%
ethyne
0%
2-ethene

$CH_3CH_2CH_2CH_3 \, \xrightarrow {Br_2 \, / \, hv}$
Major product in the above reaction is:

0%
racemic mixture
0%
meso
0%
diastereomers
0%
constitutional isomers

Explanation

$Br$

$CH_3CH_2CH_2CH_3 \xrightarrow []{Br_2/h\nu} CH_3CH_2CH_2Br+CH_3\overset {|}{CH}CH_2CH_3$

Thus, a racemic mixture is obtained. A racemic mixture is one that has equal amount of left and right handed enantiomers of a chiral molecule.

Alkane with more boiling point is:

0%
${ C }_{ 2 }{ H }_{ 6 }$
0%
${ C }_{ 4 }{ H }_{ 10 }$
0%
${ C }_{ 5 }{ H }_{ 12 }$
0%
${ C }_{ 6 }{ H }_{ 14 }$

In which of the following methods, the number of carbon atoms in alkane (forms as a product) is less than that of the parent compound (reactant)?

0%
Reduction of alkyl halide
0%
Wurtz reaction
0%
Decarboxylation of alkali salt of a fatty acid
0%
Hydrolysis of Griganard reagent

Explanation

A) In reduction of alkyl halide, the number of carbon atoms in alkane formed as product is same as the reactant.

$R-X \xrightarrow {[2H]} R-H+H-X$
B) In Wurtz reaction, coupling of R takes place without any loss of carbon atoms.

$2R-X +2Na\rightarrow R-R+2NaX$
C) In decarboxylation of alkali salt of a fatty acid, the reaction occurs at anode is:

$2CH_3COO^{\bullet} \rightarrow 2CH_3^{\bullet}+2CO_2$

$2CH_3^{\bullet} \rightarrow C_2H_6$
Here, one carbon escapes as carbon dioxide. So, alkane (product) has one carbon less than reactant.
D) In hydrolysis of Grignard reagent, the number of carbon atoms in reactant (Grignard reagent) remains same in product (alkane).

$RMgX+H_2O\rightarrow RH+Mg(OH)X$

The energy barrier to free rotation about carbon carbon bond of ethane is about:

0%
${ 30\ kJ\ mol }^{ -1 }$
0%
${ 3\ kJ\ mol }^{ -1 }$
0%
${ 3\ kcal\ mol }^{ -1 }$
0%
${ 40\ kJ\ mol }^{ -1 }$

Calcium heptane dioate on distillation produces :

0%
cyclo hexanal
0%
cyclohexene
0%
cyclohexanone
0%
cyclohexanoic acid

Sodium acetate can be converted to ethane by which of the following method?

0%
Wurtz reaction
0%
Kolbe's electrolysis
0%
Decarboxylation in presence of soda lime
0%
Hydrogenation

Explanation

$2CH_3COO-Na+ + 2H_2O\rightarrow CH_3CH_3+ 2CO_2+ H_2+2NaOH$

This reaction is called Kolbe's electrolysis.

Option B is correct.

CBSE Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 1 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 1 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

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