alcoholic KOH and $${\text{NaN}}{{\text{H}}_{\text{2}}}$$

$${\text{NaN}}{{\text{H}}_{\text{2}}}$$ and alcoholic KOH

$${\text{NaN}}{{\text{H}}_{\text{2}}}$$ and lindlar

Lindlar and $${\text{NaN}}{{\text{H}}_{\text{2}}}$$

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Both Assertion and Reason are incorrect

MCQ Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 14

How many plane of symmetry in given molecule (Benzene) ?

0%
3
0%
5
0%
7
0%
9

The correct IUPAC name of the hydrocarbon X:

0%
2 - Methyl - 3 -ethyl pentane
0%
3 - Ethyl-2-methyl pentane
0%
3-Isopropyl pentane
0%
1,1-Diethyl-2-methyl propane.

Addition of one equivalent of

$HCl$ on but-

$1-en-3-yne$ gives mainly?

0%
$3-$ chlorobut- $1-yne$
0%
$3-$ chlorobut- $1-ene$
0%
$2-$ chlorobuta- $1,3-diene$
0%
$1-$ chlorobuta- $1,3-diene$

The gases (B), (C) and (D), respectively are:

0%
$HC\equiv CH$ , ${ CO }_{ 2 }$ and ${ H }_{ 2 }$
0%
$HC\equiv CH$ , ${ H }_{ 2 }$ and $CO_{ 2 }$
0%
$CH_{ 3 }-C\equiv C-CH_{ 3 }$ , $CO_{ 2 }$ and $H_{ 2 }$
0%
$CH_{ 3 }-C\equiv C-H$ , $H_{ 2 }$ and $CO_{ 2 }$

$Al_4C_3 \xrightarrow{Hydrolysis } A \xrightarrow[HNO_3(vapour)]{400^o-479^oc}B$ ;

A and B are?

0%
$C_2H_2$ and $C_2H_3NO_2$
0%
$CH_4$ and $CH_3NO_2$
0%
$CH_4$ and $CH_3NO_3$
0%
$C_2H_2$ and $CH_3CN$

The IUPAC name of the compound having the formula

$Ch \equiv C-CH = CH_2$ is

0%
1-butyn-3-ene
0%
but-1-yne-3-ene
0%
1-buten-3-yne
0%
3-buten-1-yne

The number of primary, secondary and tertiary carbons in 3,4-dimethylheptane are respectively

0%
4, 3 and 2
0%
2, 3 and 4
0%
4, 2 and 3
0%
3, 4 and 2

A and B are-

0%
alcoholic KOH and ${\text{NaN}}{{\text{H}}_{\text{2}}}$
0%
${\text{NaN}}{{\text{H}}_{\text{2}}}$ and alcoholic KOH
0%
${\text{NaN}}{{\text{H}}_{\text{2}}}$ and lindlar
0%
Lindlar and ${\text{NaN}}{{\text{H}}_{\text{2}}}$

$RCH=CH_{2}$ can be obtained by:

0%
$R - \overset{O}{\overset{||}{C}} - H$ and $(C_{6}H_{5})_{3}P=CH_{2}$
0%
By heating $RCH_{2}CH_{2}CH_{2}OCOCH_{3}$
0%
By heating $RCH_2 CH_2 \underset{O}{\underset{\downarrow}{N}} (CH_3)_2$
0%
All of these

${ CH }_{ 3 }-{ CH }_{ 2 }-OH\xrightarrow [ ]{ PCC } A\xrightarrow [ OH^{ - } ]{ } B$
Then 'B' is

0%
$CH_2 = CH_2$
0%
$CH_3CHO$
0%
$CH_3-CH_2-OH$
0%
${ CH }_{ 3 }-\overset { \overset { \displaystyle \,\,\,\,\,\, OH }{ | } }{ \underset { \underset {\displaystyle H }{ | } }{ C } } -CH_{ 2 }-CHO$

The alkene which will have the lowest heat of hydrogenation value will be

0%
$(CH_{3})_{2}C=CHCH_{3}$
0%
$CH_{3}CH_{2}CH_{2}CH=CH_{2}$
0%
0%

Promination of alkanes is carried in the presence of

0%
$AlB{r_3}$
0%
$CaB{r_2}$
0%
$NaBr$
0%
$Zn$

Which of the following has maximum boiling point

0%
$C_4H_{10}$
0%
$C_5H_{12}$
0%
$C_6H_{14}$
0%
$C_7H_{16}$

The most volatile compound is

0%
$2, 2-$ dimethyl propane
0%
$2-$ methyl butane
0%
Isobutane
0%
$n-$ pentane

Which of the following has the maximum melting point?

0%
$C_4H_{10}$
0%
$C_5H_{12}$
0%
$C_6H_{14}$
0%
$C_7H_{16}$

Major product "P" obtained in the given reaction is:

Propane

$\xrightarrow{{Dehydrogenation}}$ A+B Major product 'A' is

0%
Propene
0%
Ethene & methane
0%
Propene & ${H_2}$ gas
0%
${H_2}$ gas

Catalytic hydrogenation of the above compound produces saturated hydrocarbon(s). The number of stereoisomers formed is

0%
$1$
0%
$2$
0%
$3$
0%
$4$

During halogenation of methane, methylene dichloride reacts with chlorine to form:

0%
trichloro methane
0%
chloro methane
0%
tetra chloro methane
0%
dichloro methane

Compound P is

What type of bonding is most important in

$\mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 3 }$ ?

0%
ionic
0%
hydrogen
0%
covalent
0%
polar

The given compounds show______isomerism.

0%
Chain
0%
Position
0%
Functional
0%
None of these

An alkyne on reaction with alk. and subsequent acidiflcation with HCl yields mixture of
The alkyne is-

0%
3-Methyl-Hexyne
0%
2-Methyl -3-hexyne
0%
2-Methyl-2-hexyne
0%
2-Methyl- 2- hexene

Which of the following is the weakest acid?

Which of the following is most stable?

0%
$CH_{4}$
0%
$CH_{2}= CH_2$
0%
$HC\equiv CH$
0%
$CH_{3}-CH = CH_2$

In the given structure, the type of carbon atoms present are

0%
One primary, two secondary and one tertiary
0%
Four primary, one secondary and two tertiary
0%
One primary, one secondary, one tertiary and one quaternary
0%
Five primary, one secondary, one tertiary and one quaternary

When water vapours are passed over aluminium carbide, we get:

0%
acetaldehyde
0%
ethylene
0%
methane
0%
ethane

A concentrated solution of sodium butyrate is electrolysed, the product obtained at anode is:

0%
Butane
0%
Propane
0%
Hexane
0%
Pentane

Identify A.

Which of the following reagents can be used for above conversion?

0%
$Zn$
0%
$Mg$
0%
$NaI/acetone$
0%
$Alc.KOH$

Neopentyl bromide, undergoes dehydrohalogenaton to give alkenes even though it has no hydrogen. This is due to:

0%
$E_2$ mechanism
0%
$E_1$ mechanism
0%
Rearrangement of carbocations by $E_1$ mechanism
0%
$E_1cB$ mechanism
0%
$E_1$ mechanism

Explanation

Neopentyl bromide gives a carbocation as an intermediate which undergoes for rearrangement and shows a

$E_1$ mechanism (even has no

$\beta$ -H atom).

Thus rearrangement of carbocations by

$E_1$ mechanism is the correct option.

1491605_1698712_ans_1f805d1b3d504d618c2d426839eccec6.png

The IUPAC name of the given compound is:

0%
2,5,6-trimethylheptane
0%
1,3-isopropyl-3-methylpropane
0%
2,6,3-trimethylheptane
0%
2,3,6-trimethylheptane

Which of the following compounds will give the maximum yield of alkane on hydrogenation?

0%
$H_{2}C=CH_{2}$
0%
$CH_{3}-CH=CH_{2}$
0%
0%

Explanation

Maximum yield of alkane on hydrogenation will be in the compound with the least steric hinderance.

Of all the given options, least steric hinderance is in case of

$\mathrm{CH_2=CH_2}$ .

Hence, Option "A" is the correct answer.

The highest boiling point is expected for

0%
iso-octane
0%
n-octane
0%
n-butane
0%
neo-heptane

Explanation

Boiling point

$\propto$ Molecular weight

Boiling point

$\propto$ Branching.

Of all options, iso-octane has the highest branching and molecular weight.

So, it has the highest boiling point of all the given options.

Hence, Options "A" is the correct answer.

Which among the following carbides on hydrolysis give alkane?

0%
$Al_{4}C_{3}$
0%
$CaC_{2}$
0%
$Be_{2}C$
0%
$SiC$

Explanation

$Al_4C_3+12H_2O\rightarrow 4Al(OH)_3+3CH_4$

Hydrolysis is a reaction that takes place between a substance and water, as a result of which the substance and water break down and new compounds form.

Aluminium carbide on hydrolysis produces methane, and aluminium hydroxide.

Hence the correct answer is option A.

Following are the isomers of molecular formula for

$C_{5}H_{12}$ :
Decreasing order of their boiling points is:

0%
$I < II < III$
0%
$I>II>III$
0%
$II>I>III$
0%
$III>I>II$

Explanation

The given structures are isomers of

$C_5H_{12}$ , which means all the compounds have the same number of carbon atoms. So, the boiling point of the compounds cannot be compared considering the number of carbon atoms of the compound.

Now we have to observe the branching of the compounds. More branching in a compound, less its boiling point. In structure I, no branching present. In structure II, one branching present and in structure III, two branching present. So, structure I has the highest boiling point, then structure II and then structure III.

So, decreasing order of boiling point is,

$I>II>III$

Product formed in the below reaction is

$\mathrm{CH_3I +Na \xrightarrow{Dry \ Ether}}$

0%
$CH_{4}$
0%
$CH_{3}CH_{3}$
0%
$CH_{3}-CH_2-CH_2-CH_3$
0%
$CH_{2}C_2H_{5}CH_3$

Explanation

The given reaction is wurtz reaction and the complete reaction is:

$\mathrm{CH_3I +Na \xrightarrow{Dry \ Ether}CH_3-CH_3}$

So, the product formed is

$\mathrm{CH_3-CH_3}$

Hence, Option "B" is the correct answer.

Consider the following reaction,
Identify the structure of major product X:

Explanation

Order of stability of free radicals:

$\mathrm{3^{\circ} > 2^{\circ} > 1^{\circ}}$

So, structure of major product X of the given reaction will be a compound with free radical at tertiary carbon.

In, option "B", radical is at tertiary carbon.

Hence, Option "B" is the correct answer.

Which one of the following statements is wrong?

0%
Aromatic compounds are richer in carbon content
0%
Aromatic compounds burn with sooty flame
0%
Aromatic compounds are generally unstable
0%
Aromatic compounds show substitution reactions

The ring structure of benzene was first proposed by:

0%
Wohler
0%
Faraday
0%
Kekule
0%
Baeyer

Aqueous solution of which of the following compounds is electrolysed, when acetylene gas is obtained?

0%
Sodium fumerate
0%
Sodium maleate
0%
Sodium acetate
0%
Calcium carbide

Explanation

Kolbe's electrolysis: acetylene can be produced by electrolysis of

$\text{aq. solution of sodium/potassium maleate or}$

$\text{fumarate.}$

Options A,B are correct.

1793213_1719211_ans_0f550ffd2fa947d890c0fe494d548e13.png

Which of the following is the correct sequence of steps in the halogenation of an alkane?

0%
Propagation, initiation, termination
0%
Initiation, termination, propagation
0%
Initiation, propagation, termination
0%
Propagation, termination, initiation

In the given reactions:

0%
A is an aldehyde; B is ketone and C is an alkene
0%
A, B and C are alkenes
0%
A, B and C are alkanes
0%
A and B are alkenes while C is an alkane

Possible products are :

Disubstituted derivatives of benzene are of ________ type/ types.

0%
$1$
0%
$2$
0%
$3$
0%
$6$

The number of

$\pi-electrons$ in benzene molecule are:

0%
$6$
0%
$3$
0%
$5$
0%
$4$

0%
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
0%
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
0%
Assertion is correct but Reason is incorrect
0%
Both Assertion and Reason are incorrect

Explanation

In naming cycloalkenes, number the ring to give the double-bonded carbons

$1$ and

$2$ and choose the direction of numbering so that the substituents get the lowest numbers. The position of the double bond is not indicated because it is known to bond between

$C-1$ and

$C-2$ .

So, its IUPAC name is 3-methyl cyclopentene.

1675896_1761062_ans_201425ddde784ed4b3219bb0b6304d15.png

Benzene gives mainly:

0%
Substitution reaction
0%
Addition reaction
0%
Elimination reaction
0%
All of these

$IUPAC$ came of

$(CH_3)_2CHCH(CH_3)_2$ is

0%
$1,1,2,3-$ tertamethylethane
0%
$1,2-$ di-isotropylethane
0%
$2,3-$ dimethylbutane
0%
$2,3,3-$ trimethylbutane

An aromatic compound

$X (C_{9}H_{8}0_{3})$ turns blue litmus to red. It gives yellow precipitate with

$I_{2}/NaOH$ and forms

$Y(C_{8}H_{6}O_{4}$ .

$Y$ forms three mononitro isometric products. Identify

$X$ .

0%
0%
0%
0%
None of these

CBSE Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 14 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Hydrocarbons Quiz 14 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

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