Explanation
We know
$$\Delta G=-RT\ln K$$
$$\because \Delta G=-nFE$$
$$\therefore -nFE=-RT\ln K$$
$$\therefore -1\times 96500\times E=-8.314\times 298\ln (10^{-14})$$
$$\therefore E=-0.828$$ $$V$$
1. $$K^+$$ ion will form most water soluble hydroxide because it is the most reactive of these metals and thus forms strong alkali $$KOH$$ which will undergo complete dissociation in water, thus making it highly soluble.
Barium peroxide react with sulfuric acid to produce Hydrogen peroxide and Barium sulfate.
Isopropyl Alcohol oxidises to Acetone and water, and not hydrogen peroxide.
$$CO_{2}$$ reacts with water to form carbonic acid. It then reacts with barium peroxide to form barium carbonate and hydrogen peroxide. Barium carbonate is insoluble and is easy to remove by filtration. This process is widely used to manufacture $$H_{2}O_{2}$$.
Barium phosphate reacts with Sulphuric acid to form Barium sulfate and Phosphoric acid.
The correct option is C.
Correct Answer: Option C
Explanation:
By reacting carbon monoxide from syngas mixture with steam in the presence of iron chromate as a catalyst, the production of dihydrogen gas can be boosted.
$$CO\left( g \right)+{{H}_{2}}O\left( g \right)\xrightarrow[catalyst]{673K}C{{O}_{2}}\left( g \right)+{{H}_{2}}\left( g \right)$$
This is called the water-gas shift reaction.
Final Answer:
The correct answer is option $$(C).$$
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