MCQ Questions for Class 11 Medical Chemistry Hydrogen Quiz 13

The strength of

$\mathrm{H}_{2} \mathrm{O}_{2}$ (in

$g/litre$ ) in

$11.2$ volume solution of

$\mathrm{H}_{2} \mathrm{O}_{2}$ is

0%
$17$
0%
$15$
0%
$34$
0%
$85$

The dihedral angle in gaseous

${ H }_{ 2 }{ O }_{ 2 }$ is

0%
${ 180 }^{ 0 }$
0%
${ 90 }^{ 0 }$
0%
$111.{ 5 }^{ 0 }$
0%
${ 109 }^{ 0 }{ 28 }^{ ' }$

Which of the following represents the formula of water gas?

0%
$CO+{ H }_{ 2 }$
0%
$CO+{ N }_{ 2 }$
0%
$CO+{ H }_{ 2 }O$
0%
$CO_{ 2 }+{ H }_{ 2 }$

Volume strength of hydrogen peroxide is

$22.4V$ . What volume of this sample is required for the oxidation of 3.4 g of hydrogen sulphide?

0%
50 ml
0%
200 ml
0%
100 ml
0%
5 ml

Which of the following is not correct regarding electrolytic preparation of

$H_2O_2$ ?

0%
50 % concentrated $H_2SO_4$ is used
0%
$S_2O^{2-}_8$ ion is deposited at anode
0%
Dilute $H_2SO_4$ is used
0%
Sulphuric acid undergoes oxidation

The dipole moment of

${ H }_{ 2 }{ O }_{ 2 }$ is 2.1D. This indicates that the structure of

${ H }_{ 2 }{ O }_{ 2 }$ is:

0%
Linear
0%
Non-linear
0%
Symmetrical
0%
none of these

Statement (I): Position of Hydrogen is still uncertain in the modern periodic table.
Statement (II): The Long form of the periodic table reflects the exact distribution of electrons among all the orbitals of an atom.

0%
A statement I is correct, II is incorrect.
0%
Statement II is correct, I is incorrect.
0%
Both statements I and II are correct.
0%
Both statements I and II are incorrect.

Hydride which has polymeric structure :

0%
$CaH_2$
0%
$NaH$
0%
$B_2H_6$
0%
$BeH_2$

Which is accepted structure of

$\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }$ in gas phase?

0%
0%
0%
Both (A) and (B)
0%
None of these

The correct statements among (a) to (d) are:
(a) saline hydrides produce

$H_{2}$ gas when reacted with

$H_{2}O$ .
(b) Reaction of

$LiAlH_{4}$ with

$BF_{3}$ leads to

$B_{2}H_{6}$ .
(c)

$PH_{3}$ and

$CH_{4}$ are electron - rich and electron - precise hydrides, respectively.
(d)

$HF$ and

$CH_{4}$ are called as molecular hydrides.

0%
(c) and (d) only
0%
(a), (b) and (c) only
0%
(a), (b), (c) and (d)
0%
(a), (c) and (d) only

Explanation

(a)

$\underset {Ionic\ hydride/ saline\ hydride}{\overset {\oplus}{M} \overset {\ominus}{H} + HOH} \rightarrow MOH + H_{2}$

(b)

$4BF_{3} + 3LiAlH_{4}\rightarrow 2B_{2}H_{6} + 3LiF + 3AlF_{3}$

(d)

$HF$ and

$CH_{4}$ are molecular hydride because they are covalent molecules.

1246685_1614773_ans_026a692faf5c43d08b82d62471caba1d.png

In water-gas shift reaction, hydrogen gas is produced from the reaction of steam with:

0%
methane
0%
coke
0%
carbon monoxide
0%
carbon dioxide

Explanation

Water-gas shift reaction explains the reaction of carbon monoxide and water vapour to form carbon dioxide and hydrogen:

$CO+H_2O\rightarrow CO_2 + H_2$

Hence option C is correct.

The hydride ion

$H^{-}$ is a stronger base than its hydroxide ion

$OH^{-}$ . Which of the following reactions will occur if sodium hydride (

$NaH$ ) is dissolved in water

0%
$H^{-}(aq)+H_{2}O\rightarrow H_{3}O^{-}(aq)$
0%
$H^{-}(aq)+H_{2}O(l)\rightarrow OH^{-}(aq)+H_{2}(g)$
0%
$H^{-}(aq)+H_{2}O(l)\rightarrow$ No reaction
0%
None of these

Explanation

If sodium hydride (NaH) is dissolved in water the following reaction occurs:

$NaH\to Na^+(aq)+H^-(aq)$

$H^{-}(aq)+H_{2}O(l)\rightarrow OH^{-}(aq)+H_{2}(g)$

A cell contains two hydrogen electrodes. The negative electrode is in contact with a solution of

$10^{-6}$ M hydrogen ions. The EMF of the cell is 0.118 V at

$25^{\circ}C$ . The concentration of hydrogen ions at the positive electrode is

0%
$10^{-6}M$
0%
$10^{-3}M$
0%
$10^{-4}M$
0%
$10^{-5}M$

Explanation

For a Concentration cell Nernst Equation is

$Ecell= \frac{0.059}{n}log\frac{C_2}{C_1}$

Given

$Ecell= 0.118V$

Concentration of hydrogen ion at the positive electrode

$\left [ C_2 \right ]=Unknown$

Concentration of hydrogen ion at the negetive elctrode

$\left [ C_1 \right ]=10^{-6}M$

$Ecell= \frac{0.059}{n}log\frac{C_2}{C_1}$

25∘C

$0.118= \frac{0.059}{1}log\frac{C_2}{C_1}$

$log\frac{C_2}{C_1}=\frac{0.118}{0.059}$

$\frac{C_2}{C_1}= 10^{2}= 100$

$C_2=100\times 10^{-6}M=10^{-4}M$

Hence the correct answer is [C]

A solution of

$H_{2} O_{2}$ is titrated with a solution of

$KMnO_{4}.$ The reaction is

$2MnO_{4}-+5H_{2}O_{2}+6H^{+}$

$\rightarrow 2Mn^{2+}+5O_{2}+8H_{2}O$
It requires

$50$ ml of

$0.1$

$M - KMnO_{4}$ to oxidize

$10$ ml of

$H_{2}O_{2}.$ The strength of

$H_{2}O_{2}$ solution is

0%
$4.25 (w/v)$ %
0%
$8.5 (w/v)$ %
0%
$0.85 (w/v)$ %
0%
$1.7 (w/v)$ %

Explanation

we have balanced equation

$2MnO_{4}^{\circleddash} + 5H_{2}O_{2}+ 6H^{\oplus } \rightarrow 2Mn^{2+}+5O_{2}+8H_{2}O$

moles of oxidizing agent = moles of reducing

$\times$ stoichiometric Ratio

$0.05 \times 0.1 = 0.01 \times M \times \left ( \dfrac{2}{5} \right )$

$M = 1.25 \, molar$

(ml.wt. of

$H_{2}O_{2} = 34$ )

wt. of

$H_{2}O_{2} = 1.25 \times 34 = 42.5 gm$

strength (gm/m)

$= \dfrac{42.5 gm}{1000 ml} \times 100 = 4.25 \%$

$= 4.25\%$

Ans- option (A)

Hydrogen can be prepared by mixing steam and water gas at

$673 K$ in the presence of

$Fe_2O_3$ and

$Cr_2O_3$ . This process is called:

0%
Nelson's process
0%
Bosch's process
0%
Serpeck's process
0%
Parke's process

Explanation

$CO_{(g)}+H_2O_{(g)}\xrightarrow[Fe_2O_3/Cr_2O_3]{673K}CO_{2_{(g)}}+H_{2_{(g)}}$

(Catalyst)

This is called water-gas shift reaction or Bosch's process.

Which of the following compound are the soluble in water?

0%
$CaC_{2}O_{4}$
0%
$SrSO_{4}$
0%
$BaCl_{2}$
0%
$(NH_{4})_{2}C_{2}O_{4}$

Explanation

$BaCl_{2}$ and

$(NH_{4})_{2}C_{2}O_{4}$ are soluble in water as these can be dissociated into constituents ions in water.

but

$CaC_{2}O_{4}$ and

$SrSO_{4}$ remain insoluble.

Hence , Option C and D are correct .

Which of the following statement is correct for ionic hydrides?

0%
The ionic hydrides are crystalline
0%
The ionic hydrides are non-volatile
0%
The ionic hydrides are non-conducting in solid state
0%
All the correct

Which of the following properties of water leads in comparison to

$H_2S$ and

$H_2Se$ due to H-bonding?

0%
Low freezing point
0%
Low boiling point
0%
Low heat of vaporization
0%
High heat of fusion

$H_2O_2$ is manufactured these days...

0%
By the action of $H_2SO_4$ on $Na_2O_2$
0%
By the action of $H_2O_2$ on $BaO_2$
0%
By electrolysis of $50\%\ H_2SO_4$
0%
By burning hydrogen in excess of oxygen

Explanation

Electrolysis of

$50\%$ sulphuric acid gives per disulphuric acid, represented as

$H_2S_2O_8$ , which on distillation with water yields

$30\%$ solution of hydrogen peroxide as follows :

$H_2S_2O_8 + 2H_2O\rightarrow 2H_2SO_4 + H_2O_2$

Hence, option (C) is correct.

A good quality of water will have
A) high DO
B) high BOD
C) high COD

0%
A
0%
B & C
0%
C & A
0%
A, B, C

High purity

$(>99.95\%)$ dihydrogen is obtained by:

0%
Electrolysis of acidified water using platinum electrodes
0%
Electrolyzing warm aqueous barium hydroxide solution between nickel electrodes
0%
Electrolysis of brine solution
0%
Reaction of steam on hydrocarbons or coke at high temperature in the presence of catalyst

$H_2$ gas is usually prepared by the reaction of

0%
$Zn+dil.HCl$
0%
$Zn+dil.H_2SO_4$
0%
$Zn+NaOH$
0%
All of these

Which of the following statements is correct?

0%
Metallic hydrides are deficient of hydrogen
0%
Metallic- hydrides conduct heat and electricity
0%
Ionic hydrides do not conduct electricity in solid state
0%
Ionic hydrides arc very good conductors of electricity in solid state

Which represent only amphiprotic species ?

0%
${ H }_{ 3 }^{ + }O,{ H }PO_{ 4 }^{ 2- },{ H }CO_{ 3 }^{ - }$
0%
$H_2O,{ HPO }_{ 3 }^{ 2- },{ H_{ 2 }PO }_{ 2 }^{ - }$
0%
${ HSO }_{ 4 }^{ - },{ H }_{ 2 }{ PO }_{ 4 }^{ - },{ H }_{ 2 }{ PO }_{ 3 }^{ - }$
0%
All of these

Pair of amphiprotic species is :

0%
$H_2CO_3$ and ${ HCO }_{ 3 }^{ - }$
0%
$H_2CO_3$ and $H_2O$
0%
${ CO }_{ 3 }^{ 2- }$ and $H_3O^+$
0%
${ HCO }_{ 3 }^{ - }$ and $H_2O$

An oxide of a non-metal has the following properties:
(i) acts both as a proton donor as well as proton acceptor
(ii) it reacts readily with basic and acidic oxides
(iii) it oxidises

$Fe$ at its boiling point.
The oxide is:

0%
$P_{2}O_{5}$
0%
$SiO_{2}$
0%
$H_{2}O$
0%
$CO_{2}$

Which of the following is a true structure of

$H_2O_2$ ?

In which of the properties listed below, hydrogen does not show similarity with halogens?
I. Nature of the oxide
II. Electropositive character
III. Combination with alkali metals
IV. Atomicity

0%
$I$ and $II$
0%
$III$ and $IV$
0%
$II$ only
0%
$I$ and $III$

Explanation

Hydrogen forms a neutral oxide, ie.,

$H_2O$ ( water) while the oxides of halogens are acidic.

Hydrogen shows electropositive nature also while halogens are mostly electronegative in nature.

Option A is correct.

Which one of the following pairs of substances on reaction will not evolve

$H_2$ gas?

0%
Iron and dil $H_2SO_4$
0%
Iron and steam
0%
Copper and $HCl(g)$
0%
Sodium and ethyl alcohol

Explanation

Ans.

$(C)Copper$ and

$HCl(gas)$

A.Iron metal dissolves readily in dilute sulphuric acid in the absence of oxygen to form solutions containing the aquated Fe(II) ion together with evolution of hydrogen.

$Fe(s) + H_{2}SO_{4}(aq) \rightarrow Fe^{2+} + SO^{2-}_{4}(aq) + H_{2}(g)$

B. Iron on reaction with steam creating a layer of hydrated iron oxide over the iron and release hydrogen.

$3Fe + 4H_{2}O \rightarrow Fe_{3}O_{4} + 4H_{2}$

C. Copper reacts with HCl in aqueous form not reacts if it is in gas form.So,this reaction is not possible.

D.Ethanol react with Sodium to produce sodium ethoxide and hydrogen gas.

$CH_{3}CH_{2}OH + Na \rightarrow CH_{3}CH_{2}O^{-}Na^{+} + H_{2}$

Water is a :

0%
protophobic solvent
0%
protophilic solvent
0%
amphiprotic solvent
0%
aprotic solvent

When electric current is supplied through an ionic hydride of fused state, then:

0%
Hydrogen is obtained at anode
0%
Hydrogen is obtained at cathode
0%
No change
0%
Hydride ion moves towards cathode
0%
Hydride ion present in solution

Explanation

On electrolysis of fused ionic hydride

$(LiH)$ , hydrogen obtained at anode.

$MH+H_2O \to MOH +H_2 \uparrow$

Option A is correct.

Which of the following statements do not define the characteristic property of water "Water is a universal solvent".

0%
It can be dissolve maximum number of compounds
0%
It has very low dielectric constant
0%
It has high liquid range
0%
None of these

$H_2O_2$ is obtained when dilute

$H_2SO_4$ reacts with:

0%
$BaO_2$
0%
$MnO_2$
0%
$PbO_2$
0%
$Na_2O_2$

Explanation

Barium peroxide reacts with sulfuric acid to produce hydrogen peroxide and barium sulfate.

$BaO_2 + H_2SO_4 \rightarrow H_2O_2 + BaSO_4$

Manganese

$(IV)$ oxide reacts with sulfuric acid to produce manganese

$(II)$ sulfate oxygen and water.

$MnO_2 + H_2SO_4 \rightarrow MnSO_4 + O_2 + H_2O$

Lead

$(IV)$ oxide reacts with sulfuric acid to produce lead

$(II)$ sulfate, oxygen, and water.

$PbO_2 + H_2SO_4 \rightarrow PbSO_4 + O_2 + H_2O$

Sodium peroxide reacts with sulfuric acid to produce hydrogen peroxide and Sodium sulfate

$Na_2O_2 + H_2SO_4 \rightarrow Na_2SO_4 + H_2O_2$

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ A \ and\ D}.$

What is true about ice?

0%
Its density is more than water
0%
It is a good conductor of heat
0%
It is a thermal insulator
0%
Its density is less than water

Hydrogen can be obtained from water, by the action of water on

0%
Calcium carbide
0%
Calcium hydride
0%
Calcium oxide
0%
Calcium

Explanation

Hydrogen can be obtained from water, by the action of water on calcium hydride and calcium metal.

$CaH_{2}+2H_{2}O\rightarrow Ca(OH)_{2}+2H_{2}\uparrow$

$Ca+2H_{2}O\rightarrow Ca(OH)_{2}+H_{2}\uparrow$

In lab

$H_{2}O_{2}$ is prepared by

0%
Cold $H_{2}SO_{4}+BaO_{2}$
0%
$HCl+BaO_{2}$
0%
Conc. $H_{2}SO_{4}+Na_{2}O_{2}$
0%
$H_{2}+O_{2}$

Explanation

Hydrogen peroxide can be prepared in the laboratory by the action of ice cold, dilute sulphuric acid on hydrated barium peroxide.

$H_{2}SO_{4}+BaO_{2}\rightarrow BaSO_{4}+H_{2}O_{2}$

Plumbosolvency is a health hazard in the transportation of

0%
Hard water only
0%
Soft water only
0%
Both (A) and (B)
0%
Water containing plum juice

Explanation

Presence of

$CO^{2-}_{3}$ and

$SO^{2-}_{4}$ ions in water reduce the tendency of dissolution of

$Pb$ in water as

$Pb(OH)_{2} .$ So, Plumbosolvency is a health hazard in the transportation of soft water.

Lead pipes are not used for carrying drinking water because

0%
They are covered with a coating of lead carbonate
0%
They are corroded by air and moisture
0%
Water containing dissolved air attacks lead forming soluble hydroxide
0%
None of these

$H_{2}O_{2}$ is manufactured these days

0%
By the action of $H_{2}O_{2}$ and $BaO_{2}$
0%
By the action of $H_{2}SO_{4}$ on $Na_{2}O_{2}$
0%
By electrolysis of 50% $H_{2}SO_{4}$
0%
By burning hydrogen in excess of oxygen

Explanation

Electrolysis of 50% sulphuric acid gives per disulphuric acid

$\left ( H_{2}S_{2}O_{8} \right )$ which on distillation yields 30% solution of hydrogen peroxide.

$H_2S_2O_8 + 2H_2O \xrightarrow{Electrolysis} 2H_2SO_4 + H_2O_2$

Saline hydrides react explosively with water, such fires can be extinguished by

0%
Water
0%
Carbon dioxide
0%
Sand
0%
None of these

Explanation

Fire due to action of water on saline hydrides cannot be extinguished with water or

$CO_{2}$ . These hydrides can reduce

$CO_{2}$ at high temperature to produce

$O_{2}$ . So, sand is used to extinguish the fire.

HCl is added to following oxides. Which one would give

$H_{2}O_{2}$ ?

0%
$MnO_{2}$
0%
$PbO_{2}$
0%
$BaO$
0%
None of these

Explanation

$MnO_{2},\ PbO_{2}$ and

$BaO$ will not give

$H_{2}O_{2}$ with

$HCl.$

$MnO_{2}$ and

$PbO_{2}$ will give

$H_2O_2$ with

$Cl_{2}$ and

$BaO$ will react with

$HCl$ to give

$BaCl_{2}$ and water.

Which of the following pair will not produce dihydrogen gas?

0%
$Cu+HCl \text{(dil)}$
0%
$Fe+H_{2}SO_{4}$
0%
$Mg\ +$ steam
0%
$Na\ +$ alcohol

Explanation

Cu and dil.HCl will not produce

$H_{2}$ as Cu is less reactive than hydrogen.

$Cu+HCl \to$ No reaction

Hydrogen can be produced by heating

0%
Cu with $H_{2}SO_{4}$
0%
Sodium formate
0%
Sodium oxalate
0%
None of these

which if the following statements is correct?

0%
Metallic hydrides are deficient of hydrogen.
0%
Metallic hydrides conduct heat and electricity.
0%
Ionic hydrides do not conduct electricity in solid state.
0%
Ionic hydrides are very good conductors of electricity in solid state.

The oxide that gives H

$_2$ O

$_2$ on treatment with dilute H

$_2$ SO

$_4$ is -

0%
PbO $_2$
0%
BaO $_2$ .8H $_2$ O $+$ O $_2$
0%
MnO $_2$
0%
TiO $_2$

Fill in the blanks:
Every nine parts of water by weight contains eight parts by weight of ______.

0%
oxygen
0%
helium
0%
carbonic
0%
sulphur dioxide gas

Which of the following melts in boiling water ?

0%
Gun metal
0%
Wood's metal
0%
Monel metal
0%
Bell metal
0%
None of these

Which of the following is not true about

$H_{2} O$ molecule?

0%
The molecule has $\mu= 0.$
0%
The molecule can act as a base.
0%
Shows abnormally high boiling point in comparison to the hydrides of other elements of the oxygen group.
0%
The molecule has a bent shape.

In ice, the length of H-bonds :

0%
is less than that of covalent bonds
0%
is greater than that of covalent bonds
0%
is same as that of covalent bonds
0%
can be less greater or same as that of covalent bonds

Which of the following hydrides is least stable to hydrolysis ?

0%
$CH_{4}$
0%
$SiH_{4}$
0%
$SnH_{4}$
0%
$PbH_{4}$

Explanation

Silicon hydrides are most easily hydrolysed.

$SiH_{4} + 3H_{2}O \rightarrow H_{2}SiO_{3} + 4H_{2}$

$SiH_{4} + 2NaOh + H_{2}O \rightarrow Na_{2}SiO_{3} + 4H_{2}$

CBSE Questions for Class 11 Medical Chemistry Hydrogen Quiz 13 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Hydrogen Quiz 13 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

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