Explanation
There are two planes in this structure and each plane has one O-H pair, the angle between both the planes is 90.2°, The O-O bond length is 145.8 pm and the O-H bond length is 98.8 pm.
Hence option B is correct.
$$\textbf{Hint: The shape of a molecule depends on the number of lone pairs and the bond pairs present}\\\;\;\;\;\;\;\;\;\;\;\;\textbf{around the central atom.}$$
$$\textbf{Step-1: Find shape of }$$$$\mathbf{H_2O}$$
In $$H_2O$$, the oxygen atom is the central atom which is surrounded with two hydrogen atoms and hence will
have two bond pairs. The oxygen atoms will also consist of two lone pairs in $$H_2O$.
Hence the shape of $$H_2O$$ will be bent and the geometry will be tetrahedral.
$$\textbf{Step-2: Find shape of }$$$$\mathbf{H_2O_2}$$
A $$ H_2O_2$$ molecule consists of two hydrogen atoms and two oxygen atoms. Each oxygen atom in $$H_2O_2$$ is
surrounded with two other atoms and two lone pairs. Hence the shape around each oxygen atom
in $$H_2O_2$$will be bent.
$$\textbf{Step-3: Find shape of }$$$$\mathbf{D_2O}$$
In $$D_2O$$, the oxygen atom is the central atom which is surrounded with two deuterium
atoms and hence will have two bond pairs. The oxygen atoms will also consist of two lone
pairs in $$D_2O$$. Hence the shape of $$D_2O$$ will be bent and the geometry will be tetrahedral.
$$\textbf{Step-4: Find shape of }$$$$\mathbf{N_2O}$$
$$N_2O$$, has below structure. The central nitrogen atom is forming two $$\mathbf{\sigma}$$ bonds and two
$$\mathbf{\pi}$$ bonds. So it is $$\mathbf{sp}$$ hybridized. So the shape is linear..
Hence, the correct answer is option $$\textbf{(D)}$$ $$N_2O$$.
Please disable the adBlock and continue. Thank you.