2-Ethyl-3-menthyl-1-penten-4-yne

2-Ethyl-3-methyl-4-pentyne-1-ene

MCQ Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 11

Arrange the following in increasing order of their acidic strength.

0%
$III < I < IV < II$
0%
$II < I < IV < III$
0%
$I < III < IV < II$
0%
$II < III < I < IV$

Explanation

Acidic strength of a compound is increased due to presence of groups showing

$-I$ effect. So,

$IV$ , having the strongest

$-I$ effect, will be the most acidic, followed by

$I$ .

Between

$II$ and

$III$ ,

$III$ will be more acidic as the removal of adjacent to

$-C=O$ group is favored due to stronger

$-I$ effect by

$-C=O$ group as well as ether group. The

$-I$ effect is comparatively less in case of

$II$ .

Hence, the required order is:

$II<III<I<IV$

The IUPAC name of

0%
2-Ethyl-3-menthyl-1-penten-4-yne
0%
2-Ethyl-3-methyl-4-pentyne-1-ene
0%

2-Methyl-1-penten-4-yne
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4-Ethyl-3-methy-1-pentyn-4-ene

The blue compound is formed in the positive test for nitrogen with Lassaigne's solution of an organic compound is:

0%
${ Na }_{ 4 }[Fe({ CN) }_{ 5 }(NOS)]$
0%
${ Na }_{ 3 }[Fe({ CN) }_{ 6 }$
0%
$[Fe({ CN) }_{ 3 }$
0%
$Fe_4[Fe(CN)_6]_3$

Explanation

If Nitrogen is present in the organic compound, then sodium extract contains

${Na}_{4}[Fe{(CN)}_{6}]$ .

$Na + C + N \xrightarrow{Fuse} NaCN$

$FeS{O}_{4} +6NaCN \longrightarrow {Na}_{4}[Fe{(CN)}_{6}] + {Na}_{2}S{O}_{4}$

This

${Fe{(CN)}_{6}}^{-4}$ turns to

${Fe}_{4}{[Fe{(CN)}_{6}]}_{3}$ (Prussian blue) on reaction with

$Fe{Cl}_{3}$

$3{Na}_{4}[Fe{(CN)}_{6}] + 4Fe{Cl}_{3} \longrightarrow \underset{\text{Prussian Blue}}{{Fe}_{4}{[Fe{(CN)}_{6}]}_{3}} + 12NaCl$

Hence, the blue compound is

${Fe}_{4}{[Fe{(CN)}_{6}]}_{3}$ .

What are reactant

$X$ and product

$Y$ in the following sequence of reactions ?

Which of the following compounds will have the highest percentage of enol content at equilibrium condition at the same temperature?

0%
$CH_{3}COCH_{3}$
0%
$CH_{3}COCH_{2}COOC_{2}H_{5}$
0%
$CH_{3}COCH_{2}COCH_{3}$
0%
$CH_{3}CHO$

Which statements (s) is (are)correct?

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A $\pi$ - bond is weaker then $\sigma$ -bond
0%
A $\sigma -$ bond is weaker then $\pi-$ bond
0%
A double bond stronger then H-bond
0%
A covelent bond stronger then H-bond

Explanation

$\pi-$ bonds are weaker than

$\sigma-$ bonds due to less overlapping as a result of parallel orbitals.

Hydrogen bonds are due to electrostatic forces of attraction, whereas covalent/ double bonds are a result of the sharing of electrons between the atoms. Since hydrogen bonds involve mere dipole-dipole interactions, it is weaker than covalent/ double bonds. Hence A, C, and D are the correct answer

Choose the correct statement regarding the preparation of Lassaigne's extract of a given organic compound.

0%
Li can be used on the place of Na
0%
Li cannot be used on the place of Na because its compound are covalent in nature
0%
Both A and B
0%
None of these

How many number of enolic form are possible for the compound

0%
1
0%
2
0%
3
0%
4

The correct sequence of decreasing number of

$\pi$ - bonds in the structure of

$H_2SO_3, H_2SO_4$ and

$H_2S_2O_7$ is:

0%
$H_2SO_3 > H_2SO_4 > H_2S_2O_7$
0%
$H_2SO_4 > H_2S_2O_7 > H_2SO_3$
0%
$H_2S_2O_7 > H_2SO_4 > H_2SO_3$
0%
$H_2S_2O_7 > H_2SO_3 > H_2SO_4$

The correct IUPAC name of the following alkane is:

0%
3 ,6-diethyl-2-methyloctane
0%
5-isopropyl-3-ethylocante
0%
3-ethyl-5-isopropylocatane
0%
3-isopropyl-6-ethyloctane

Explanation

IUPAC Name

$\rightarrow 3,6-Diethyl-2-methyloctane$ .
1381003_1164826_ans_2d13104c151a432589000aba12bf564f.png

The species having no p

$\pi$ - p

$\pi$ bond is:

0%
ClO $_3$
0%
SO $_3$
0%
COCl $_2$
0%
NO $_2$

Which of the following orbital combination does not from

$\pi$ -bond?

0%
${ p }_{ x }+{ p }_{ x }$ sideways overlapping
0%
${ d }_{ { x }^{ 2 }-{ y }^{ 2 } }+{ p }_{ x }$ sideways overlapping
0%
${ d }_{ xy }+{ d }_{ xy }$ sideways overlapping
0%
${ d }_{ yz }+{ p }_{ y }$ sideways overlapping

Main axis of diatomic molecule is z. The orbitals

${p_x}$ and

${p_y}$ overlap to form

0%
$\pi$ molecular orbital
0%
$\sigma$ molecular orbital
0%
$\delta$ molecular orbital
0%
No bond will be formed.

In Lassaigne's test when both N and S are present, blood-red colour is due to the formation of____

0%
ferric sulphocyanide
0%
ferric cyanide
0%
ferric ferrocyanide
0%
none of these

Identity the correct sequence of increasing number of

$\pi-$ bonds in structure of the following molecules:
I)

$H_{2}S_{2}O_{6}$
II)

$H_{2}SO_{3}$
III)

$H_{2}S_{2}O_{5}$

0%
$I,II,III$
0%
$II,III,I$
0%
$II,I,III$
0%
$I,III,II$

How many pi (n) electrons are there in the following molecules?

0%
4
0%
6
0%
8
0%
10

IUPAC name of the compound,

${ CH }_{ 3 }-\overset { \overset { O }{ || } }{ C } -\underset { \underset { { CH }_{ 3 } }{ | } }{ CH } -\overset { \overset { CH=CH_{ 2 } }{ | } }{ CH } -{ CH }_{ 2 }{ CH }_{ 2 }{ CH }_{ 3 }$ is -

0%
4-propyl-3-methylhex-5-en-2-one
0%
3-propyl-5-methylhex-1-en-5-one
0%
3-methyl-4-propylhex-5-en-2-one
0%
3-methyl-4-vinylheptan-2-one

In the given compound, the number of

$\sigma$ and

$\pi$ bonds, respectively, are:

0%
$19, 11$
0%
$19, 5$
0%
$13, 11$
0%
$7, 3$

The

$IUPAC$ name of given compound is:

0%
Ethanoic propanoic anhydride
0%
Propanoic ethanoic anhydride
0%
1-Ethanoyloxypropanone
0%
3-Ethanoyloxypropanone-3-one

The number of

$\sigma$ and

$\pi$ bonds present in a molecule of tetracyanoethane

$(CN)_{2}C=C(CN)_{2}$ are

0%
$5\sigma$ and $9\pi$
0%
$5\sigma$ and $8\pi$
0%
$9\sigma$ and $9\pi$
0%
$9\sigma$ and $7\pi$

Functional group order for Cahn Ingold Prelog preference is

0%
I>II>III>IV
0%
I>III>II>IV
0%
IV>II>III>I
0%
I>IV>III>II

Write the IUPAC name of given compound ?

0%
1 - Chloro- 2- methylbenzene
0%
o - chlorotoluene
0%
2 - chlorotoluene
0%
both A and C

The correct statement related to

$IUPAC$ nomenclature is:

0%
If 2 or more chains of equal length are seen in the compound then the chain with the minimum number of side chains is preferred.
0%
If double and triple bonds are at symmetrical positions in a compound then triple bond gets lower preference.
0%
The correct $IUPAC$ name of $CH_{3}COC_{2}H_{5}$ is ethyl ketone.
0%
As far as possible, the $IUPAC$ name of a compound is written as a single word.

How many different type of functional group are present in this compound?

0%
$7$
0%
$6$
0%
$5$
0%
$4$

The IUPAC name of the following compound is:

0%
N,N-dimethylmethanal
0%
N,N-dimethylmethanamide
0%
N,N-dimethylcarbaldehyde
0%
None

$IUPAC$ name of (see figure) is :

0%
Cyclobutane-1 carbaldehyde-2-carboxylate
0%
2-Formylcyclobutane carboxylate
0%
2-formylcyclobutyl methanoate
0%
2-Methanoyloxy cyclobutane carbaldyde

The correct comparison in B.P's of different carbon compounds of similar molar masses is:

0%
$Propan-1-ol > Propanal > Propanone > Methoxymethane$
0%
$Propan-1-ol > Propanone > Propanal > Methoxy \ ethane$
0%
$Propan -1-ol>Methoxy\ ethane >Propanone >Propanal$
0%
$Propanal>Propanol >Methoxy ethane >Propanone$

In which of the following pair of elements the pi-bond formation tendency is maximum.

0%
S and O
0%
Si and O
0%
P and O
0%
Cl and O

The decreasing order of priority for the following functional groups according to IUPAC is
i)

$-C \equiv N$
(ii)

$-CHO$
(iii)

$-CONH_2$
(iv)

$-OH$

0%
i > ii > iv > iii
0%
ii > i > iv > iii
0%
iii > ii > iv > i
0%
iii > i > ii > iv

Which of the following is the correct priority order of functional groups:

0%
$-SO_{3} H>-COR > -CHO > -OH$
0%
$-COOH >-SO_{3}H > -CN >-CONH_{2}$
0%
$-CN >- CHO >- COR >-OH$
0%
$-COOR > -COX > -CHO >-CN$

Stability of

π−bondπ−bond in following in the increasing order is :

0%
I < III < IV < II
0%
I < II < III < IV
0%
IV < III < II < I
0%
II < III < IV < I

Quinine is the most important alkaloid obtained from Cinchona bark. It's molecular formula is

$C_{20}H_{24}N_2O_2$ . It may contain

0%
5 double bond & 6 ring
0%
6 double bond & 4 ring
0%
6 double bond & 3 ring
0%
7 double bond & 5 ring

Which functional group has 'anol' suffix?

0%
$- C H O$
0%
$- OH$
0%
$- C OOH$
0%
none of these

The number of

$\pi$ - bonds and

$\sigma$ bonds in the above structure respectively are:

0%
8, 5
0%
8, 6
0%
5, 8
0%
5, 13

The IUPAC name of compound

0%
3-carbonyl methoxy -5- ethanoyl oxy cyclogexanoic aicd
0%
3-ethanoyl oxy -5- methoxy carbonyl cyclohexane carboxylic acid
0%
5-ethanoyl oxy -5- methoxy carbonyl cyclohexane acid
0%
3-methoxy carbonyl -5- ethanoyl oxy cyclohexane carboxylic aicd

Two complexes

$\left[ Cr\left( { H }_{ 2 }O \right) _{ 6 } \right] { C }I_{ 3 }\left( A \right)$ and

$\left[ Cr\left( { NH }_{ 3 } \right) _{ 6 } \right] { C }I_{ 3 }\left( B \right)$ are violet and yellow coloured, respectively. The incorrect statement regarding them is:

0%
$\triangle _{ 0 }$ values of $(A)$ and $(B)$ are calculated from the energies of violet and yellow light, respectively.
0%
$\triangle _{ 0 }$ value of $(A)$ is less than that of $(B)$ .
0%
both absorb energies corresponding to their complementary colors.
0%
both are paramagnetic with three unpaired electrons.

The correct order of +M effect of 'N' containing functional group on benzene ring amongst the given compounds is:

0%
$I > II > IV > III$
0%
$II > I > III > IV$
0%
$I > II > III > IV$
0%
$IV > III > II > I$

In which of the following

$p\pi -d\pi$ bonding is observed ?

0%
$NO^-_3$
0%
$SO^{2-}_3$
0%
$BO^{3-}_3$
0%
$CO^{2-}_3$

Which of the following substrates is an electron donating group overall ?

0%
$- Br$
0%
$- \underset{O}{\underset{||}{C}}CH_3$
0%
$-OCH_3$
0%
$-\overset{\bigoplus}{N} (CH_3)_3$

IUPAC name of the given compound is:-

$CH_2=C(Me)-CH_2-COOMe$

0%
Methyl-3-methyl but -3-en-oate
0%
2-Methyl-3-methoxy carbonyl propene
0%
Dimethyl but-3- enoate
0%
1-methyoxy-3- methyl but-3- enone

The systematic name of

$(CH_3)_2 CH-COOH$ is:

0%
2-propanoic acid
0%
Isobutanoic acid
0%
2-Methylpropanoic aid
0%
2-methylbutanoic acid

Which of the following has

$p \pi-d \pi$ bonding?

0%
${ \mathrm{NO}_{3}}^{-}$
0%
${ \mathrm{BO}_{3}}^{3-}$
0%
${ \mathrm{SO}_{3}}^{2-}$
0%
${ \mathrm{CO}_{3}}^{2-}$

Number of

$\pi$ electrons in conjugation for these compounds will be respectively:

0%
$8, 6, 6, 6$
0%
$6, 4, 6, 6$
0%
$6, 6, 6, 6$
0%
None of the above

Which of these functional groups is not present in the below compound given

0%
Nitrile
0%
Acid
0%
Amine
0%
Ester

Which among the following is not correctly matched with their colour?

$\text {Compound}$

$\text {Colour}$

0%
$Na_4[Fe(CN)_5NOS ]$ purple
0%
$Fe_4[Fe(CN)_6]_3$ blue
0%
$Fe(CNS)_3$ blood red
0%
$AgCl$ light yellow

Explanation

$A)\underset{from\ sodium\ extracted}{Na_{2}S}+Na_{2}[Fe(CN)_{5}NO]\rightarrow \underset{purple\ colouration}{Na_{4}[Fe(CN)_{5}NOS]}$

$B) Na_{4}[Fe(CN)_{6}]+Fe^{+3}\rightarrow \underset{Ferric\ ferrocynid\\ \\ (blue\ colour)}{Fe_{4}[Fe(CN)_{6}]_{3}}$

$C)Fe^{+3}+3NaSCN \rightarrow \underset{\ \ Ferric\ thiocynate\\ \\ (Blood\ red\ colouration)}{Fe(SCN)_{3}}$

$D)Na+Cl\xrightarrow[From\ o.c]{\Delta }NaCl\xrightarrow[]{AgNO_{3}}\underset{white\ ppt}{AgCl}+NaNO_{3}$

$\therefore AgCl$ is incorrect match with its colour

$\mathbf{Hence\ correct\ answer\ is\ option\ (D)}$

A person is suffering from Diabetes, which get confirmed by testing his urine with Benedict's reagent. The organic compound and functional group present in the urine of suffering person is :

0%
$sucrose - COOH$
0%
Glucose, $- \overset{O}{\overset{||}{C}} -$
0%
Glucose, $- \overset{O}{\overset{||}{C}} - H$
0%
sucrose $- \overset{O}{\overset{||}{C}} -$

Chromyl chloride gives yellow ppt. when it reacts with respectively_________

0%
$Cu(OH)_2,PbNO_3$
0%
$NaOH,(CH_2COO)_2Ca$
0%
$NaOH,(CH_3COOO)_2Pb$
0%
$KOH,PbSO_4$

Explanation

$CrO_2Cl_2+4NaOH\rightarrow Na_2CrO_4+2NaCl+2H_2O$
Chromyl chloride

$Na_2CrO_4+(CH_3COO)_2Pb\rightarrow PbCrO_4+2CH_3COONa$
yellow ppt

Option C is correct.

Which functional group is there in methyl ethanoate?

0%
Alcohol
0%
Halide
0%
Ketone
0%
Ester

The number of

$\sigma$ bonds and

$\pi$ bonds in the following structure respectively are:

0%
$8,5$
0%
$8,6$
0%
$3,8$
0%
$5,13$

Which compound cannot give a precipitate with an ammoniacal silver nitrate solution?

0%
$CH_3-C\equiv C-CH_3$
0%
$CH_3-C(Me)C\equiv CH$
0%
$C_2H_5-C\equiv CH$
0%
$CH_3-C\equiv CH$

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 11 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 11 - MCQExams.com

0:0:1

Practice Class 11 Medical Chemistry Quiz Questions and Answers

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