Both phenolic and alcoholic groups

MCQ Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 12

The functional groups present in the compound

$(A)$ is

0%
Aldehydic $(-CHO)$
0%
Ketonic $(-\overset {\overset {O}{\parallel}}{C}-)$
0%
Alcoholic $(-OH)$
0%
Alkoxy group $(-OR)$

The molecular mass of a non-volatile organic compound is determined either by the Victor Meyer's.
method or Duma's method.

0%
True
0%
False

Which of the following molecules is not having

$d \pi - p \pi$ bonding?

0%
$BCl_3$
0%
$P_4O_{10}$
0%
$PF_3$
0%
$B_3N_3H_6$

How many bonds are there in

0%
$14 \sigma , 8 \pi$
0%
$18 \sigma , 8 \pi$
0%
$14 \sigma , 2 \pi$
0%
$19 \sigma , 4 \pi$

Explanation

There are

$9$ carbon-carbon

$\sigma$ bond and

$10$ carbon-hydrogen

$\sigma$ bond. So in total, there are

$19\sigma$ bonds.

Also, there are

$4$ cabon-carbon

$\pi$ bond.

So the given molecule contains

$19\sigma$ bond

$4\pi$ bond.

1560358_1725787_ans_14d23fb0bb354313b93a3da5e6f477b8.PNG

Molecular mass of a volatile organic solid can be determined by :

0%
Silver salt method
0%
Platinichloride method
0%
Victor Meyer's method
0%
Kjeldahl's method

Explanation

$\text{The molecular mass of a volatile organic solid can be determined by }Victor Meyer’s \ method.$

In Victor Meyer’s method a known mass of a volatile liquid or solid is converted into its vapour by heating in a Victor-Meyer's tube. The vapour displaces its own volume of air. The volume of air displaced by the vapour is measured at the experimental temperature and pressure. The volume of the vapour at s.t.p is then calculated. From this, the mass of

$2.24\times10^{−2}m^3$ of the vapour at S.T.P. is calculated. This value represents the molecular mass of the substance.

Option C is correct.

In Lassaigne's test of nitrogen, the final product formed is sodium ferrocyanide.

0%
True
0%
False

Which of the following molecule(s) has /have

$d \pi- p \pi$ bonding?

0%
$H_2S_2O_3$
0%
$P_4O_{10}$
0%
$SO_3$
0%
$SO_2$

Select the correct priority for citation as principal group

Explanation

$\text{According to IUPAC convention, Carboxylic Acids and their derivatives have the highest priority then carbonyls}$

$\text{then alcohols, amines, alkenes, alkynes, and alkanes, so in this case the correct answer is the correct answer is D}$

Which of the following functional groups is not present in vanillin?

0%
$-COOH$
0%
$-CHO$
0%
$-OH$
0%
$-OCH_{3}$

Which of the following has

$p\pi -d\pi$ bonding?

0%
$NO_3^{-}$
0%
$CO_3^{-2}$
0%
$BO_3^{-3}$
0%
$SO_3^{-2}$

Explanation

ANSWER is Option

$D$

$SO_3^{2−}$

$dπ-pπ$ back bonding involves d-orbitals. Hence it is possible only in case of elements which belong to the 3rd period, where d-orbitals are present (though unoccupied in ground state). Out of all the options, only

$SO_3^{2−}$ can have dπ-pπ back bonding because sulphur belongs to the 3rd period.

Vanillin contains.

0%
$-Cl$
0%
$-CONH_{2}$
0%
$-CHO$
0%
$-COOH$

Explanation

Vanillin is an organic compound with the molecular formula

$C_8H_8O_3$ . It is a phenolic aldehyde. Its functional groups include aldehyde, hydroxyl, and ether. Vanillin contains

$-CHO$ group.

Option B is correct.

1824367_1727332_ans_a4f72a930d7d42fc9f1e91158c9adaa3.PNG

A distinctive and characteristic functional group of fats is

0%
An ester group
0%
A peptide group
0%
A ketonic group
0%
An alcoholic group

Explanation

$\text{Fats are the basically Higher order Ester}$ which are formed by by the combination of higher acids and alcohol.

thus, Ester group is the distinctive and characterstic group of fats.

Identify the correct sequence of increasing number of

$\pi-$ bonds in structures of the following molecules.
(i)

$H_{2}S_{2}O_{6}$
(ii)

$H_{2}SO_{3}$
(iii)

$H_{2}S_{2}O_{5}$

0%
$I, II, III$
0%
$II, III, I$
0%
$II, I, III$
0%
$I, III, II$

Which of the following elements forms

$p\pi-d\pi$ bonding in its oxide?

0%
Lithium
0%
Boron
0%
Sulphur
0%
Nitrogen

Which of the following orbitals can from

$\pi$ bond if internuclear axis is y axis ?

0%
$P_{x}+d_{xy}$
0%
$P_{z}+d_{xz}$
0%
$d_{yz}+d_{yz}$
0%
$P_{x}z+d_{xz}$

Vanillin contains:

0%
A phenolic group
0%
An alcoholic group
0%
Both phenolic and alcoholic groups
0%
Two phenolic groups

Explanation

Vanillin is an organic compound with the molecular formula

$C_8H_8O_3$ . It is a phenolic aldehyde. Its functional groups include aldehyde, hydroxyl, and ether. Vanillin contains

$phenolic \ group$ not alcoholic.

Option A is correct.

1824372_1727336_ans_a75b572010fd4b7e8fa08ef1ea06ba14.PNG

When propionic acid is treated with aqueous sodium bicarbonate,

${CO}_{2}$ is liberated. The

$C$ of

${CO}_{2}$ comes from:

0%
Methyl group
0%
Carboxylic acid group
0%
Methylene group
0%
Bicarbonate group

Quantitative estimation of

$C$ ,

$H$ and extra elements (e.g.

$N$ ,

$S$ ,

$P$ and halogens) is carried out by Liebig’s combustion, Carius, Dumas, and Kjeldahl’s method.
Liebig’s combustion method is used for the quantitative estimation of:

0%
$C$ and $H$
0%
Halogens
0%
$S$ and $P$
0%
$N$

Explanation

Estimation of carbon and Hydrogen by Liebig's method:

A known mass of an organic compound is heated in the presence of pure oxygen. The carbon dioxide and water formed are collected and weighed. The percentages of carbon and hydrogen in the compound are calculated from the masses of carbon dioxide and water. Estimation of carbon and hydrogen in an organic compound is based on their conversion to

$CO_2$ and

$H_{2}O$ respectively.

The percentage of carbon and hydrogen is calculated from the masses of

$CO_{2}$ and

$H_{2}O$ .

Hence, option A is correct.

A chemist has 4 samples of artificial sweetener P, Q, R and S. To identify these samples, he performed certain experiments and noted the following observations.

(i) Q and R both form a blue-violet colour with ninhydrin.
(ii) Lassaigne extract of P gives positive

$AgNO_3$ test and negative

$Fe_4[Fe(CN)_6]_3$ test.
(iii) Lassaigne extract of R and S gives positive sodium nitroprusside test.

Based on these observations which option is correct?

0%
P: Alitame; Q: Saccharine;
R: Aspartame; S: Sucralose
0%
P: Aspartame; Q: Saccharine;
R: Sucralose; S: Alitame
0%
P: Sucralose; Q:Aspartame;
R:Alitame ; S: Saccharine
0%
P: Saccharine; Q: Alitame;
R: Sucralose; S: Aspartame

Explanation

$\text{Ninhydrin test : -}$ Amino acid-containing

$NH_2$ or

$COOH$ group gives this test. So, Alitame and Aspartame response for this test.

$AgNO_3\ \text{test}:-$ Halides like

$Br, Cl$ and

$I$ reacts with

$AgNO_3$ and gives respective precipitates. Compound

$P$ would be sucralose as it contains

$Cl$ .

$AgNO_3 + Cl^- \to AgCl (ppt.) + NO_3$

$\text{Sodium nitroprusside test : -}$ Only the thiol group gives this test. So, possible compound

$R$ is alitame or

$S$ (Saccharine).

The correct answer is option

$C$ .

2010784_1954931_ans_ac02730010c54b9ab2dcd7381c36780e.png

Which among the following is

$(R,Z)$ -

$7$ -ethoxy -

$2,7$ -dimethyl -

$4$ - propyl nona-

$1,4$ -diene ?

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 12 - MCQExams.com

0:0:1

Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 12 - MCQExams.com

0:0:1

Practice Class 11 Medical Chemistry Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.