MCQ Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 9

In the structure, the number of functional groups present is :

0%
2
0%
4
0%
5
0%
3

How is -X group replaced by following functional groups.

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-OH
0%
-CN
0%
-NC
0%
$-NH_2$

$M{e_2}CCl\,C{H_2}CH = CH - CH = CH - COOH$

$I.U.P.A.C$ name of this is :-

0%
$7-Chloro-7-methyloctan-2,4-dienoic$ $acid.$
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$7-Chloro-7,7-dimethyl-2,-3-heptadienoic$ $acid.$
0%
$2-Chloro-2-methyl-4,5-octadiene-7-oic$ $acid.$
0%
$7-Chloro-7-methyl oct-2,-3-heptadienoic$ $acid.$

In the given compound the correct lowest set of locants are :

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3,3,4,5
0%
3,4,5,5
0%
4,5,3,3
0%
None of these

Give the IUPAC name of the alkene

0%
$Z-3 methyl-4-propyl-3-octene$
0%
$E-3 methyl-4-propyl-3-octene$
0%
$E-4 butyl-3-methyl-3- heptene$
0%
$E-2 ethyl-3-propyl-3- heptene$
0%
$Z-2-ethyl-2-propyl-2-heptene$

The IUPAC name of given compound is:

0%
4-Ethylcyclobut-2-en-l-ol
0%
4-ethylcyclobut-2-en-3-ol
0%
3-ethylcyclobut-1-en-2-ol
0%
2-ethylcyclobut-3-en-l-ol

Correct IUPAC name is

0%
3-ethylhex-2-ene
0%
3-ethypent-2-ene
0%
3-ethylpent-3-ene
0%
3-propylpent-2-ene

The correct IUPAC name

0%
2-ethoxy-5-chloropentane
0%
1-chloro-4-ethoxy-4-methylbutane
0%
1-chloro-4-ethoxypentane
0%
ethyl-1-chloropentyl ether

IUPAC name for the compound is:

0%
$\alpha$ -methyl cyclohexanone
0%
2-Methyl cyclohexanone
0%
heptanone-2
0%
methyl cyclohexanone

The correct IUPAC name of

$CH_3CH_2CH(CH_3)CH(CH_3)CH(C_2H_5)_2$ is :

0%
4-Ethyl-3-methylhexane
0%
3-Ethyl-4,5-dimethylheptane
0%
4-Methyl-3-ethylhexane
0%
2,4-Diethylpentane

$IUPAC$ Name of is :

0%
$2-Ethyl-3-methyl epoxy\ butane$
0%
$4-Ethyl-4-methyl\ oxetane$
0%
$2-Ethyl-4-methyl\ oxetane$
0%
$2-Ethyl-2-methyl\ oxetane$

In which of the following pair of elements the pi-bond formation tendency is maximum

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S and O
0%
Si and O
0%
P and O
0%
Cl and O

The correct IUPAC of the following
compound -

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7 -nitro-4-(carboxmethyl) heptanoic acid
0%
6-nitro-3-(carboxy ethyl) hexanoic acid
0%
4-(3-nitro propyl) hexane -1, 6-odioic acid
0%
3-(3-nitro propyl) hexane-1, 6-dioic acid

The IUPAC name of

0%
N,N-dimethylmethanal
0%
N,N-dimethylmethanamide
0%
N,N-dimethylcarbaldehyde
0%
None of these

Two compounds X and Y have the same molecular formula

$C_3H_6O$ . Identify the functional groups and structural formula of X and Y.

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-CHO and -CO, X = $CH_3CH_2CHO$ , Y = $CH_3COCH_3$
0%
-CHO and -CO, X = $CH_3CH_2OCH_3$ , Y = $CH_3COCH_3$
0%
-CO and -COOH, X = $CH_3COCH_3$ , Y = $CH_3COOH$
0%
-CHO and -COOH, X = $CH_3CH_2OCH_3$ , Y = $CH_3CH_2COOH$

How many bonds are there in

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$14\sigma,\ 8\pi$
0%
$18\sigma,\ 8\pi$
0%
$19\sigma,\ 4\pi$
0%
$14\sigma,\ 2\pi$

Explanation

Here there are

$4$

$C=C$ bond. So the number of pi bond is

$4$ .

Alos, there are

$10$

$C-H$ sigma bond and

$9$

$C-C$ sigma bond. So in total, there are

$19$ sigma bonds.

Hence correct answer is option C.

1552777_1367295_ans_e21ad630b14e4718bd40159e9c8cc0c8.PNG

Ethyl alcohol containing 9.5 % methyl alcohol land 0.5 % pyridine is called :

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spirt
0%
denaturated spirit
0%
rectified spirit
0%
absolute alcohol

In the given compound which functional group is absent ?

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Ketone
0%
Ether
0%
Amide
0%
Ester

Which of the following is correct for hydbridization of C-atom?

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$CH_{4}-SP^{3}$
0%
$C_{2}H_{4}-sp^{2}$
0%
$C_{2}H_{2}-sp$
0%
All of these

Carbon and hydrogen are estimated in organic compounds by:

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Kjeldahl's method
0%
Duma's method
0%
Liebig's method
0%
Carius method

Explanation

Liebig's method is used for the estimation of "Carbon and hydrogen". Principle: A known mass of the organic compound is heated in the presence of pure oxygen. The carbon dioxide and water formed are collected and weighed.

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (C).}$

Which of the following molecule have both

$P \pi - p \pi$ and

$p \pi -d \pi$ bonding?

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$CIO^+_ 2$
0%
$NO^+_2$
0%
$SO^{2-}_3$
0%
$CIO^-_4$

In which of the following func-tional group isomerism is not possible?

1) Alcohols
2) Aldehydes
3) Alkyl halides
4) Cyanides

0%
$1, 2, 3$ and $4$ are correct
0%
$1$ and $2$ only are correct
0%
$2$ and $3$ only are correct
0%
$3$ only is correct

Explanation

$\text{Alkyl halides does not have any functional group.}$

Which of the following has highest bond strength?

0%
$2 p \pi-2 p \pi$
0%
$2 p \pi-3 p \pi$
0%
$3 d \pi-3 d \pi$
0%
$1 s-2 p$

Prussian blue colour is obtained by mixing together an aqueous solution of

$Fe^{3+}$ salt with:

0%
ferricyanide
0%
ferrocyanide
0%
hydrogen cyanide
0%
sodium cyanide

Explanation

Potassium ferricyanide reacts with ferrous iron in an acidic solution to produce the insoluble blue pigment, commonly referred to as Turnbull's blue or Prussian blue. To detect ferric

$(Fe^{+3})$ iron, potassium ferrocyanide is used instead in the Perls' Prussian blue staining method.

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (B).}$

In the estimation of carbon and hydrogen, if the substance also contains nitrogen, then near the exit, it is placed:

0%
a roll of silver
0%
a bright copper gauge spiral
0%
ammonium sulphate
0%
a layer of lead chromate

Explanation

Carbon and hydrogen are detected by heating the organic compound with cupric oxide (CuO) strongly, where carbon is oxidized to carbon dioxide and hydrogen to water. Carbon dioxide is tested by a lime water test, whereas water is tested by the anhydrous copper sulphate test.

where CuO can be formed by heating copper wire(copper gauge spiral) in the air at around .

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (B).}$

The first organic compound prepared from inorganic compounds was.

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Acetic acid
0%
Methane
0%
Urea
0%
Ethyl alcohol

The first organic compound synthesised in the laboratory from its elements.

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Urea
0%
Methane
0%
Ethylene
0%
Acetic acid

Which of the following reagents is used for the separation of acetaldehyde from acetophenone?

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$NH_2OH$
0%
$NaOHI_2$
0%
$NaHSO_3$
0%
$C_6H_5NHNH_2$

Explanation

$Acetaldehyde (CH_{3}CHO)$

$Acetophenone(C_{6}H_{5}C(O)CH_{3})$

$A)NH_{2}OH$ is Hydroxylamine which is a derivative of ammonia which gives nuclear fuse addition reaction with the elimination of water. It reacts with both Acetaldehyde and Acetophenone.

$B)NaOHI_{2}$ is a carbon compound test which gives the carbon compound having

$COCH_{3}$ group. Both Acetaldehyde and Acetophenone has

$COCH_{3}$ group

$C)NaHSO_{3}$ reacts with acetaldehyde to form an addition compound which is precipitated. Acetaldehyde can be recovered with dilute

$HCl$ . Acetophenone does not react.

$D)C_{6}H_{5}NHNH_{2}$ is an ammonium derivative known as phenylhydrazine

which gives nuclear fuse addition reaction with the elimination of water. It reacts with both Acetaldehyde and Acetophenone.

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (C).}$

Correct IUPAC name of compound is:

0%
$3-$ trimethyl hexane
0%
$3-$ Methyl hexane
0%
$4-$ methyl hexane
0%
$4-$ Methyl pentane

Explanation

The IUPAC name of this compound is:

$3-$ Methyl hexane.
1706566_1807094_ans_79fd5d66646340d7906179dc920e2221.png

In carbon and hydrogen estimation, the saphnolite (a resin) absorbs:

0%
$N_2$
0%
Water vapours
0%
both $CO_2$ and $H_2 O$
0%
Only $CO_2$

Explanation

A small quantity

$(0.2\ to\ 0.3\ g)$ of the organic compound is placed in a porcelain/platinum boat. The boat is placed in the combustion tube and is heated at

$400^{\circ}\ to\ 450^{\circ}C$ . Pure dry oxygen is slowly passed through the tube. Combustion is complete in

$8\ to\ 10\ hours$ . It results in the formation of

$CO_{2}\ and\ H_{2}O$ from the carbon and hydrogen in the compound. They are absorbed in the absorption tubes at the end.

The absorption tubes are removed and weighed to determine the amount of

$CO_{2}\ and\ H_{2}O$ formed in the reaction. The masses and the percentages of

$C$ and

$H$ in the compound are calculated as follows. But saphnolite resin is high carbon observing resin so it only observes

$CO_{2}$ .

$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (D).}$

How many sigma and pi-bonds are there in the molecule of dicyanoethene

$(CN-CH=CH-CN)?$

0%
$3$ sigma and $3$ pi
0%
$5$ sigma and $2$ pi
0%
$7$ sigma and $5$ pi
0%
$2$ sigma and $3$ pi

Number of pi bonds in

$H_2C=CH-CH=CH-C\equiv CH$ is?

0%
$2$
0%
$3$
0%
$4$
0%
$5$

Number of pi-electrons present in naphthalene is?

0%
$4$
0%
$6$
0%
$10$
0%
$14$

The correct IUPAC name for

${H}_{2}C=CH-C\equiv CH$ is

0%
but-3-en-1-yne
0%
but-1-en-3-yne
0%
but-1-yn-3-ene
0%
but-3-yn-1-ene

The IUPAC name of 4-isopropyl m-xylene is:

0%
1-isopropyl 2,4-dimethylbenzene
0%
4-isopropyl-m-xylene
0%
1-isopropyl-3,5-dimethylbenzene
0%
4-isopropyl-3,5-dimethylbenzene

The IUPAC name of the given is

0%
2-ethyl-3-methyl-butanoyl chloride
0%
2,3-dimethyl pentanoyl chloride
0%
3,4-dimethyl pentanoyl chloride
0%
1-chloro-1-oxo-2,3-dimethyl pentane

The grouping >CO is present in:

0%
ethers
0%
alcohols
0%
ketones
0%
None of these

Explanation

Ketones are having

$>C=O$ group. Ex-

$CH_3-\overset {\overset {\displaystyle O }{||}}C-CH_3$

$CH_2 COCI$ is used to detect the number of amino group in the organic compounds. When a compound of molecular mass 180 is acetylated,gives a compound of molecular massThe number group in the compounds is

0%
1
0%
5
0%
2
0%
4

Explanation

$NH_2 + CH_3 -\overset { \overset { O }{ parallel } }{ C } -CI\rightarrow \underset { \underset { H }{ | } }{ N } -\overset { \overset { O }{ parallel } }{ C } -CH_ 3+HCl$
Let the amino compound has n

$(-NH_2)$ group Molecular mass of the product will be.

$180-n \times 1 + n\times 143 = 390$
42n = 210
n = 5 ]

The IUPAC name of tertiary butyl iodide is:

0%
1-iodo-3-methyl propane
0%
2-iodo-2-methyl propane
0%
4-iodobutane
0%
2-iodobutane

Which of the following names are correct for the compound?

${ \left( { CH }_{ 3 } \right) }_{ 2 }CHCN$

0%
2-Methyl propane nitrile
0%
Isobutyronitrile
0%
Isopropyl cyanide
0%
All are correct

State whether the following statement is True or False.

Ethyl alcohol and dimethyl ether are position isomers.

0%
True
0%
False

Explanation

False

Ethers are isomeric with alcohol. They have the same molecular formula but different functional groups. hence, Ethyl alcohol and dimethyl ether are

$functional\ isomers$

The IUPAC name for diglyme is

${CH}_{3}O{CH}_{2}{CH}_{2}O{CH}_{2}O{CH}_{3}$

0%
2,5,8 trioxanonane
0%
bis(2-methoxy ethyl) ether
0%
$\beta,\beta'$ -dimethoxy-diethyl ether
0%
diethylene glycol dimethyl ether

The chemical name of DDT is

0%
Dichloro dinitrotoluene
0%
Dichloro dimethyl toluene
0%
$p,p-dichloro$ diphenyl trichloroethane
0%
None of the above

Explanation

$p,p-dichloro$ diphenyl trichloroethane

1737311_1723018_ans_dffb444d5bc7401fa2c7e19da653c152.png

The number of

$\pi$ -bonds in the following compound

$O_2N-C\equiv C-NO_2$ is:

0%
$2$
0%
$3$
0%
$4$
0%
$1$

The functional groups present in 'salol' are

0%
$-NH_{2}$ and $-OR$
0%
$-OH$ and $-COR$
0%
$-NH_{2}$ and $-COOH$
0%
$-OH$ and $-COOR$

Explanation

The functional groups present in 'salol' are "-

$OH$ and -

$COOR$ ".

1668200_1726270_ans_00fa4817aef24754b8d475a4e42c50fc.png

The sigma and

$\pi-bonds$ present in benzene ring are:

0%
Three sigma and three pi
0%
Twelve sigma and three pi
0%
Six pi and three sigma
0%
Nine sigma and three pi

In which of the following method of purification, metal is converted to its volatile compound which is decomposed to give pure metal?

0%
Heating with stream of carbon monoxide
0%
Heating with iodine
0%
Liquation
0%
Distillation

Explanation

Vapor phase refining or purification method includes:

(i) Mond's process - Heating of metal with stream of

$CO$ :

$Ni+4CO\rightarrow Ni(CO)_4 \xrightarrow{\text{450-470 K}}Ni+4CO$

(ii) Van Arkel method - Heating with iodine:

$Zr+2I_2 \xrightarrow{\text{870K}}ZrI_4 \xrightarrow{\text{2000 K}} Zr+2I_2$

Hence, the correct options are (A) and (B).

Which of the following has

$\pi-d\pi$ bonding?

0%
$NO_{3}^{-}$
0%
$SO_{3}^{2-}$
0%
$BO_{3}^{2-}$
0%
$CO_{3}^{2-}$

The compound formed in the positive test for nitrogen with the Lassaigne solution of an organic compound is

0%
$Fe_{4}[Fe(CN)_{6}]_{3}$
0%
$Na_{3}[Fe(CN)_{6}]$
0%
$Fe(CN)_{3}$
0%
$Na_4[Fe(CN)_{5}NOS]$

Explanation

The carbon and nitrogen present in the organic compound on fusion with sodium metal gives sodium cyanide. This is converted in to sodium ferrocyanide by the addition of sufficient amount of ferrous sulphate

$(FeSO_{4})$ . Ferric ion

$(Fe^{+3})$ generated during the process reacts with ferrocyanide to form prussian blue coloured ppt of ferric ferrocyanide.

$Na+C+N\rightarrow NaCN$ .

$6NaCN+FeSO_{4}\rightarrow Na_{4}[Fe(CN)_{6}]+Na_{2}SO_{4}$

sodium ferrocyanide

$Na_{4}[Fe(CN)_{6}]+Fe^{+3}\rightarrow Fe_{4}[Fe(CN)_{6}]_{3}$

ferric ferrocyanide prussian blue ppt.

The functional group present in propanol and propanal respectively are

0%
$-OH$ and $-CHO$
0%
$-OH$ and $-COOH$
0%
$-CHO$ and $-COOH$
0%
$-CHO$ and $-CO$

Explanation

propanol is

$CH_3CH_2CH_2-OH$ and propanal is

$CH_3CH_2-CHO$ .

Hence in propanol

$-OH$ (alcohol) group is present and in propanal

$-CHO$ (aldehyde) group is present.

Option A is correct.

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 9 - MCQExams.com

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Practice Class 11 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 11 Medical Chemistry Organic Chemistry Some Basic Principles And Techniques Quiz 9 - MCQExams.com

0:0:1

Practice Class 11 Medical Chemistry Quiz Questions and Answers

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