Explanation
Hint: Common oxidation number for $$H$$ is $$+1$$ and for $$O$$ is $$-2$$.
Explanation:
The compound given is $${{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}.$$ The oxidation numbers of $$H$$ and $$O$$ are + 1 and $$ - 2$$ respectively.
Let the oxidation number for $$C$$ be $$x$$. The sum of oxidation numbers of all the atoms in an uncharged compound is equal to zero.
So, the oxidation number of $$C$$ can be calculated as:
$$ (2 \times H) + (1 \times C) + (3 \times O) = 0$$
$$ (2 \times 1) + (1 \times x) + (3 \times (- 2)) = 0$$
$$2 + x - 6 = 0$$
$$x = + 4$$
Thus, the oxidation number of carbon in $${{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}$$ is $$+4.$$
Final Answer: Hence, the correct option is (D).
Please disable the adBlock and continue. Thank you.