Explanation
Explanation:
Molar mass of ethanol = $$46\ grams/(mole)$$
Molar mass of water = $$18\ gram/(mole)$$
The sum of all mole fractions is $$1$$.
The mole fraction of:
Ethanol = $$0.25$$ and water = $$0.75$$
Let the 10 moles of mixture are present.
Moles of ethanol $$=\dfrac {0.25}{10}\times 100$$ = $$2.5$$
Moles of water $$=\dfrac {0.75}{10}\times 100$$= $$7.5$$
Given mass of ethanol $$=2.5 \times 46 = 115\ grams$$
Given mass of water $$7.5 \times 18 = 135\ grams$$
The percentage concentration of ethanol by weight in the mixture $$=\dfrac {115}{115+135}\times 100$$
The percentage concentration of ethanol by weight in the mixture $$=46\%$$.
Hence, the correct answer is option $$C$$.
Let us assume that the mass of compound is $$10$$ grams.
$$X$$ and $$ Y$$ both are $$50\%$$ of the mass of compound.
Therefore, mass of $$X$$ = mass of $$Y$$ = $$5$$ grams.
The atomic mass of $$X$$ = $$10$$ grams.
The atomic mass of $$Y$$ = $$20$$ grams.
$$Number \space of\space moles = \dfrac {given \space mass }{atomic \space mass}$$
$$Number \space of\space moles\ of \space X= \dfrac {5 }{10 }$$=$$0.5$$
$$Number \space of\space moles\ of \space Y= \dfrac {5}{20}$$ =$$0.25$$
The formula of compound is $$X_{0.5}Y_{0.25}$$ i.e. in simple form it is $$X_2Y$$.
Hence, the correct answer is option $$B$$.
Both statement 1 and statement 2 are correct and statement 2 is the correct explanation of statement 1
Both statement 1 and statement 2 are correct but Statement 2 is not the correct explanation of Statement 1
Statement 1 is correct but statement 2 is incorrect
Statement 1 is incorrect but statement 2 is correct
Both the statement 1 and statement 2 are incorrect
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