Explanation
$$18.0\ g$$ of glucose$$\left( {{C_6}{H_{12}}{O_6}} \right)$$ is added to $$178.2\ g$$ of water. The vapour pressure of water for this aqueous solution at $${100^o}\ C$$ is :
$$\textbf{Correct Option A}$$
$$\textbf{Solution}$$
Diffusion process is explained as the movement of substance from a region of higher concentration to a region of lower concentration.Diffusion occurs in three physical states namely solids, liquids and gas
So, the correct option is A.
Given
Colorless gas - $$X$$
Brown gas - $$Y$$
The bromine does not change its color at a given temperature, but nitrogen dioxide and dinitrogen tetraoxide change their color at a given temperature and give the same color as given in the question.
Heat dinitrogen tetroxide
$${N_2}{O_4}$$ $$\xrightarrow{{{{160}^{\rm O}}C}}$$ $$2N{O_2}$$ $$\xrightarrow{{{{600}^{\rm O}}C}}$$ $$2NO$$ $$ + $$ $${O_2}$$
In this reaction,
$${N_2}{O_4}$$ - dinitrogen tetroxide (colorless)
$$2N{O_2}$$ - nitrogen dioxide (brown)
$$2NO$$ - Nitric oxide (colorless)
Therefore, the name of $$Y$$ gas is dinitrogen tetroxide that is brown.
Hence, option (C) is the correct answer.
Given,
heat dinitrogen tetraoxide
in this reaction,
$${N_2}{O_4}$$ - dinitrogen tetraoxide (colorless)
Therefore, the name of $$X$$gas is nitric oxide that is colorless.
Hence, option(d) is the correct answer.
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