MCQ Questions for Class 12 Medical Chemistry Alcohols, Phenols And Ethers Quiz 2

The number of dihydric phenols possible with the molecular formula

$C_6H_6O_2$ is

0%
2
0%
3
0%
4
0%
5

Alkyl halides can be converted to ethers through:

0%
Frankland reaction
0%
Williamson synthesis
0%
Fitting reaction
0%
Grignard reaction

In the dehydration reaction ,

$^{18}O$ will be in

0%
$H_2O$
0%
A
0%
Both (A) and (B)
0%
None of these

Correct order of basic strength:

0%
$C{ H }_{ 3 }N{ H }_{ 2 } > C{ H }_{ 3 }-\overset { \oplus }{ N } { H }_{ 3 }>C{ H }_{ 3 }-\overset { \circleddash }{ N } H$
0%
$\overset { \circleddash }{ O } H > C{ H }_{ 3 }CO\overset { \circleddash }{ _2 } >C{ l }^{ \circleddash }$
0%
$C{ H }_{ 3 }N{ H }_{ 2 } > C{ H }_{ 3 }-\overset { \oplus }{ N } { H }_{ 3 }>C{ H }_{ 3 }-CH_2-\overset { \circleddash }{ N } H$
0%
$CH_{3}CH_{2}NH_{2} > CH_{2}=CH-NH_{2} > HC \equiv C-\overset{ \circleddash }{ N }H$

$(a)\quad Secondary\quad alcohol\quad \xrightarrow [ \Delta ]{ H_{ 3 }PO_{ 4 } }$

$(b)\quad Tertiary\quad alcohol\quad \xrightarrow [ \Delta ]{ H_{ 3 }PO_{ 4 } }$
For the above dehydration reaction rate of reaction will be:

0%
a > b
0%
a < b
0%
a = b
0%
None

Substrate that readily do not show

$E_1$ reaction is:

During steam distillation of a mixture of o- nitrophenol and p- nitrophenol, which of the statement is false?

0%
Vapours of o-nitrophenol are carried by steam because of its lower boiling point due to chelation
0%
vapours of o- nitrophenols are carried by steam because of its lower boiling point and solubility in steam
0%
Vapours of p-nitrophenol are carried by steam because of its lower boiling point
0%
both 2 and 3

The IUPAC name of the given acid is:

0%
1, 2, 3-propane tricarboxylic acid
0%
3-hydroxy-1, 5-pentanendioic acid
0%
3-hydroxy-3-keto-1, 5-pentanedioic acid
0%
1, 3, 5-trihydroxypentane-1, 5-dione

Identify the compound

$'Y"$ in the following sequence of reaction:

$HC \equiv CH \xrightarrow[ii) H_2O/Zn]{i) O_3} X \xrightarrow{Zn/CH_3COOH} Y$

0%
0%
0%
0%
$CH_{3}COOH$

Consider the given reaction
Identify alkene.

0%
$CH_{3} - CH_{2} - CH = CH_{2}$
0%
$CH_{3} - CH = CH - CH_{3}$
0%
$(CH_{3})_{2}C = C(CH_{3})_{2}$
0%
$CH_{3} - CH = \underset {\underset {CH_{3}}{|}}{C} - CH_{3}$

IUPAC name of compound is:

0%
5-ethyl-3,3-dimethyl cyclohex-en-6-ol
0%
6-Ethyl-4,4-dimethyl cyclohex-2-en-1-ol
0%
2-ethyl-4,4-dimethyl cyclohex-en--enol
0%
6-ethyl-4,4-dimethyl cyclohexenol

.How many number of compounds, which have same IUPAC name?

0%
$0$
0%
$1$
0%
$2$
0%
$3$

The structure of compound P is :

_____________ is prepared on a large seals from water gas.

0%
Methanol
0%
Ethanal
0%
Methane
0%
Ethanol

Explanation

Methanol is generally prepared on a large scale using water gas. Water gas is also called syn gas is the mixture of

$(CO+{ H }_{ 2 }).$

The_____ ethers are highly volatile and flammable.

0%
Higher
0%
Lower
0%
Both A and B
0%
None of these

Methanol cannot be prepared by the hydration of an alkene.

0%
True
0%
False

Rate of dehydration when given compound is treated with conc,

${ H }_{ 2 }{ SO }_{ 4 }$ .

0%
P > Q > R > S
0%
Q > P > R > S
0%
R > Q > P > S
0%
R > Q > S > P

The compounds A and B in the following reaction are ________ respectively.

0%
A = Benzyl alcohol, B = Benzyl cyaninde
0%
A = Benzyl chloride, B = benzyl cyanide
0%
A = benzyl alcohol, B = Benzyl isocyanide
0%
none of these

Find the product:

Identify major products

$r_1,r_2$ and

$r_3$ in the given reaction.

In the reaction sequence,

$2CH_{3}CHO \xrightarrow []{OH^{-}}A\xrightarrow []{\Delta}B\ ;$

the product

$B$ is:

0%
$CH_{3}-CH_{2}-CH_{2}-CH_{2}-OH$
0%
$CH_{3}-CH=CH-CHO$
0%
$CH_{3}-CH_{2}-CH_{2}-CH_{3}$
0%
$CH_3-\overset {\displaystyle {\overset {\displaystyle O} {||}}}{C}-CH_3$

In the above reaction X is

0%
phenol
0%
benzoic acid
0%
salicylaldehyde
0%
carbonic acid

$(CH_{3})_{2}CHCH_{3}$

$\underrightarrow { HN{ O }_{ 2 } }$ ?

0%
$n-$ butyl alcohol
0%
isobutyl alcohol
0%
tetiary butyl alcohol
0%
secondary butyl alcohol

ortho-Nitrophenol is less soluble in water than p- and m-Nitrophenol because:

0%
Melting point of o-nitrophenol is lower than of m- and p- isomers
0%
o-Nitrophenol is more volatile in steam than those of m- and p- isomers
0%
o- Nitrophenol shows intramolecular H- bonding
0%
o- Nitrophenol shows intermolecular H- bonding

Molecule which does not oxidise using PCC

Which one of the following compounds will be most readily dehydrated?

Dehydration of following alcohols follows the order:

0%
$I<II<III<IV$
0%
$II<III<I<IV$
0%
$I<II<IV<III$
0%
$III<I<II<IV$

Predict

$B$ :

0%
0%
0%
0%
All of these

Identify the dehydration product in the following compound?

0%
0%
0%
both (a) and (b)
0%
None of these

Which of the following alcohols can be prepared by direct hydration of the corresponding alkene in presence of 50% sulphuric acid?

0%
Butan-1-ol
0%
Butan-2-ol
0%
2-Methylpropan -1-ol
0%
2-Methylpropan-2-ol

Which of the following compounds will most readily be dehydrated to give alkene under acidic condition?

0%
2-Hydroxycyclopentanone
0%
1-Pentanol
0%
3-Hydroxypentan-2-one
0%
4-Hydroxypentan-2-one

Explanation

3-Hydroxypentan-2-one and 4-Hydroxypentan-2-one will most readily be dehydrated to give alkene under acidic condition. This will lead to formation of

$\alpha - \beta$ unsaturated ketone. But out of both 4-Hydroxypentan-2-one will most readily be dehydrate to give alkene under acidic condition.
Note: Dehydration of 2-Hydroxycyclopentanone will lead to

$C=C$ double bond in 5 member ring that will cause strain and product is less likely to be formed.

The organic compound that gives the following qualitative analysis is:

Test	Inference
(a) Dil. $HCl$	Insoluble
(b) $NaOH$ solution	soluble
(c) ${Br}_{2}$ /water	Decolourization

Explanation

Given is insoluble in dil.

$HCl$ but soluble in

$NaOH$ to form the given
1247767_1614178_ans_dcebf480be9a485e86fbe68975e64378.PNG

Which of the following is not the product of dehydration of :

Compound

$A, C_{8}H_{10}O$ , is found to react with

$NaOI$ (produced by reacting

$Y$ with

$NaOH$ ) and yields a yellow precipitate with characteristic smell.

$A$ and

$Y$ are respectively are:

Explanation

A and Y are 1-phenylethanol and iodine respectively.
NaOI oxidizes 1-phenylethanol to methyl ketone (acetophenone) which gives positive iodoform test. The yellow precipitate is of iodoform

$(CHI_3)$

The compound

$A$ on treatment with

$Na$ gives

$B$ , and with

$PCl_{5}$ gives

$C. B$ and

$C$ react together to give diethyl ether.

$A, B$ and

$C$ are in the order.

0%
$C_{2}H_{5}Cl, C_{2}H_{6}, C_{2}H_{5}OH$
0%
$C_{2}H_{5}OH, C_{2}H_{6}, C_{2}H_{5}Cl$
0%
$C_{2}H_{5}OH, C_{2}H_{5}ONa, C_{2}H_{5}Cl$
0%
$C_{2}H_{5}OH, C_{2}H_{5}Cl, C_{2}H_{5}ONa$

Explanation

The compound A is ethanol

$\displaystyle C_{2}H_{5}OH$ . The compound A on treatment with

$Na$ gives sodium ethoxide

$\displaystyle (C_{2}H_{5}ONa)$ which is compound B.

$\displaystyle C_{2}H_{5}OH \xrightarrow [-H_2]{Na} C_{2}H_{5}ONa$

The compound A on treatment with

$PCl_5$ gives ethyl chloride

$\displaystyle ( C_{2}H_{5}-Cl)$ which is compound C.

$\displaystyle C_{2}H_{5}OH \xrightarrow {PCl_5} C_{2}H_{5}-Cl+HCl+POCl_3$

B and C react together to give diethyl ether.

$\displaystyle C_{2}H_{5}ONa+C_{2}H_{5}Cl \rightarrow C_{2}H_{5}OC_{2}H_{5}+NaCl$

A,B and C are in the order

$\displaystyle C_{2}H_{5}OH, C_{2}H_{5}ONa, C_{2}H_{5}Cl$ .

Option C is correct.

Degree of unsaturation of

$A=2$ and it contains no double or triple bonds. Identify the structure of A.

0%
0%
0%
0%
None of these

Explanation

The degree of unsaturation of

${C}_{10}{H}_{18}O=2$ but it contains no double or triple bond. Hence, there are two rings-one six-membered as indicated by product and the other three-membered which is cleaved by

$HCl$ due to strain. Hence

$A$ has given structure.