Explanation
The -OH group in alcohols and phenols contain a hydrogen bonded to an electronegative oxygen atom. Thus they form hydrogen bonds with water molecules.
Phenol on reaction with ammonia gives aniline. In this reaction, -OH group is replaced with $$-NH_2$$ group.
Carbinol is a trivial name of methanol $$CH_3OH$$.
Phenol is a very weak acid and the position of equilibrium lies well to the left.
Phenol can lose a hydrogen ion because the phenoxide ion formed is stabilised to some extent. The negative charge on the oxygen atom is delocalised around the ring. The more stable the ion is, the more likely it is to form.
One of the lone pairs on the oxygen atom overlaps with the delocalised electrons on the benzene ring.
This overlap leads to a delocalisation which extends from the ring out over the oxygen atom. As a result, the negative charge is no longer entirely localised on the oxygen, but is spread out around the whole ion.
Due to delocalization of electrons, the keto-form of the phenol is stable.
Hence, option A and D are correct
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