$$CH_3CH (OH)_2, CH_3CH(OH)COOH$$

Assertion is correct but Reason is incorrect

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Both Assertion and Reason are incorrect

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

Assertion is correct but Reason is incorrect

Both Assertion and Reason are incorrect

MCQ Questions for Class 12 Medical Chemistry Aldehydes, Ketones And Carboxylic Acids Quiz 14

An aldehyde can give nucleophilic addition reaction with:

0%
$HCN$
0%
$NaHSO_3$
0%
$R-MG-X$
0%
$NH_2NH_2$

Which of the following statements is not correct?

0%
Aldehydes and ketones contain polar carbonyl group
0%
Aldehydes and ketones undergo nucleophilic addition
0%
Aldehydes and ketones undergo electrophilic substitution
0%
Lower members of aldehydes and ketones are soluble in water due to hydrogen bonding

Which gives nucleophilic addition reactions?

0%
Methanal
0%
Ethanal
0%
Propanone
0%
None of these

Acetone gives addition elimination reaction with:

0%
$NH_2OH$
0%
$NaHSO_3$
0%
$NH_2NHCONH_2$
0%
$NH_2NHC_6H_5$

Acetaldehyde reacts with both nucleophiles and electrophiles.

0%
True
0%
False

Which of the following compounds will give carboxylic acid with nitrous acid

$(HNO_2)?$

0%
R-COCl
0%
$R-CONH_2$
0%
R-COOR
0%
$(RCO)_2O$

Explanation

$RCONH_2 + HNO_2 \rightarrow RCOOH$

Hence option (B) is correct.

Oil of vanilla bean is

Explanation

Vanillin is an organic compound with the molecular formula

$C_8H_8O_3$ . It is a phenolic aldehyde. Its functional groups include aldehyde, hydroxyl, and ether. It is the primary component of the extract of the vanilla bean.

Option A is correct

1821509_1727018_ans_4ba4cc029c9247c2ab879e1702236708.png

The structures of the products

$Q$ and

$R$ , respectively, are

The structure of the carbonyl compound

$P$ is

The structure of the product

$S$ is

Which of the following compund(s) is/are peroxy-acids?

0%
$HClO_4$
0%
$H_2SO_5$
0%
$H_2S_2O_8$
0%
$H_3PO_5$

By the action of malonic acid in ethanolic ammonia on benzaldehyde in the presence of pyridine, it forms:

0%
Benzoic acid
0%
Phenyl acetic acid
0%
Cinnamic acid
0%
Phthalic acid

In the following reaction sequence
What is X.

Which carbonyl group is protonated most readily in acidic solution, but gives nucleophilic addition by

$NH_{2}NH-Ph$ least readily?

The following conversion reaction can be carried out by using reaction sequence/s.

0%
0%
0%
0%
$KMnO_4 / OH^{\circleddash } / Heat$

Compound ' P ' of the following reaction sequence can be:

$CH_3 - \underset{O}{\underset{||}{C}} - OH \xrightarrow[]{NaH{\overset{14}{C}O_3}} (P \,gas) \xrightarrow[(2) H_3O^{\oplus}]{(1)PhCH_2MgBr} (Q)$

$CH_{ 3 }-\overset { O }{ \overset { || }{ \underset { O }{ \underset { || }{ S } } } } -OH\xrightarrow [ ]{ NaH{ \overset { 14 }{ C } O_{ 3 } } } (R\, gas)\xrightarrow [ (2)H_{ 3 }O^{ \oplus } ]{ (1)Ph{ \overset { 14 }{ C } }H_{ 2 }MgBr } (S)$
Product (Q) and (S) in the aove reactions are respectively:

0%
$PhCH_2COOH, Ph - \overset{14}{C}H_2 - \overset{O}{\overset{||}{\underset{O}{\underset{||}{S}}}} - OH$
0%
$PhCH_2\overset{14}{C}OOH, Ph \overset{14}{C}H_2COOH$
0%
$PhCH_2\overset{14}{C}OOH, Ph\overset{14}{C}H_2 \overset{14}{C}OOH$
0%
$PhCH_2COOH, Ph\overset{14}{C}H_2 \overset{14}{C}OOH$

Explanation

$CH_3 - \underset{O}{\underset{||}{C}} - OH \xrightarrow[]{NaH\overset{14}{C}O_3} CH_3CO\overset{-}{O} \overset{+}{N}a + H_2O + \overset{14}{C}O_2$

$\overset{14}{C}O_2 \xrightarrow[(2) H_3O^{\oplus}]{(1) PhCH_2MgBr} \underset{(Q)}{PhCH_2\overset{14}{C}OOH}$

$CH_3 - \overset{O}{\overset{||}{\underset{O}{\underset{||}{S}}}} - OH \xrightarrow[]{NaH\overset{14}{C}O_3} CH_3SO_3Na + H_2O + \overset{14}{C}O_2$

$\overset{14}{C}O_2 \xrightarrow[(2) H_3O^{\oplus}]{(1) Ph\overset{14}{C}H_2MgBr} \underset{(S)} {Ph\overset{14}{C}H_2 \overset{14}{C}OOH.}$

Option C.

The correct statement is

0%
If $(x)$ is $PhCH = O$ , then $(z)$ is also $PhCH = O$
0%
If $(x)$ is $PhCH = O$ , then $(y)$ is $Ph - CH = CH - CH = CH - COOH$
0%
0%
$x$ can be $CH_3 - CH = O$

0%
$CH_3CH (OH)_2, CH_3CH(OH)COOH$
0%
$CH_3CHO, CH_3CH(OH)COOH$
0%
$CH_3CH_2COOH, CH_3CH_2OH$
0%
$CH_3CH(OH)COOH, CH_3CH_2OH$

In which of the following reactions correct major product is mentioned?

What is the compound called if remaining two valencies of a carbonyl group are satisfied by two alkyl groups

0%
Aldehyde
0%
Ketone
0%
Acid
0%
Acid chloride

Explanation

The compound formed is known as

$Ketone.$ And according to question, the compound so formed has a structure,

$R_2C=O.$ And this is the general structure of ketones.

What is the correct

$IUPAC$ name for

0%
5-methyl-3-hexenoic acid
0%
5-carboxy-2-methylpentene
0%
4-isotropyl-3-butenoic acid
0%
None of these

The

$IUPAC$ name for

$\begin{matrix} { CH }_{ 3 }CH={ CH }{ CH }_{ 2 }{ CH }{ CH }_{ 2 }COOH \\ \quad \quad| \\ \quad \quad{ CH }_{ 2 } \end{matrix}$ is

0%
$5-$ aminohex $-2-$ ene carboxylic acid
0%
$5-$ amino $-2-$ heptenoic acid
0%
$3-$ amino $-5-$ heptenoic acid
0%
$\beta -$ amini $-\delta -$ heptenoic acid

Explanation

$\begin{matrix} \overset { 7 }{ { CH }_{ 3 } } & - & \overset { 6 }{ CH } & = & \overset { 5 }{ CH } & - & \overset { 4 }{ { CH }_{ 2 } } & - & \overset { 3 }{ CH } & - & \overset { 2 }{ { CH }_{ 2 } } & - & \overset { 1 }{ COOH } \\ & & & & & & & & | & & & & \\ & & & & & & & & { NH }_{ 2 } & & & & \end{matrix}$

$3-$ amino

$-5-$ heptenoice acid

Addition of alcohols to aldehydes in presence of anhydrous acid yield

0%
Carboxylic acids
0%
Ethers
0%
Cyclic ethers
0%
Acetals

$CH_3CONH_2\xrightarrow[]{NaNO_2IHCI}X$

0%
$CH_3COOH$
0%
$CH_3CO \overset{+}{N}H_3CI^{-}$
0%
$CH_3NH_2$
0%
$CH_3CHO$

Explanation

Amide, on treating with

$HNO_2$ give acids.

$CH_3CONH_2\xrightarrow[(h\nu)]{NaNO_2/HCl}CH_3COOH+N_2+H_2O$

acetic acid

Addition of alcohols to aldehydes in presence of anhydrous acid yield:

0%
Carboxylic acids
0%
Ethers
0%
Cyclic ethers
0%
Acetals

Explanation

Alcohols are added to aldehydes and ketones in the presence of dry hydrogen chloride to form hemiacetals. This reaction can continue by adding another alcohol to form an acetal.

Hence, option

$D$ is correct.

1644028_1763780_ans_add2daf1ef0a4e3db72738f59196dabf.png

0%
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
0%
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
0%
Assertion is correct but Reason is incorrect
0%
Both Assertion and Reason are incorrect

Explanation

As, the functional group is

$-COOH$ , the numbering is done from RHS to give minimum number to carbon atom bearing the functional group. Rewriting the above structure. The chain consists of four carbon atoms. Hence its a derivative of butane.

The substituent is the methyl group. So the above compound is

$3-$ methyl butanoic acid.

Carboxylic acid

$(A)$ is:

0%
0%
0%
0%
Both (a) and (c)

Explanation

Formation of

$(E)$ suggests monosubstituted acid and reaction of 1 mol of

${H}_{2}$ with (A) and (B) shows one

$(C=C)$ bond. There are 6 D.U (4 D.U for

$(Ph)$ group, 1 D.U for

$(COOH)$ and 1 D.U for

$(C=C)$ in both (A) and (B)

Chiral compound with nine

$C$ atoms would be (given figure)

Here

$(C)$ and

$(D)$ can be distinguished quantitatively by H.V.Z reaction.

$(C)$ has one

$\alpha$ - H atoms and would give dichlorinated product. The chlorine content in the chlorinated derivaties of

$(C)$ and

$(D)$ is determined by quantitative methods

1774741_1767788_ans_095eef2ada444fcabcaa824e8f8b6e3e.PNG

Compound

$(A)$ is:

${CH}_{3}CH=CHCHO$ is oxidised to

${CH}_{3}CH=CHCOOH$ using:

0%
Alkaline $KMn{O}_{4}$
0%
Selenium dioxide
0%
Ammoniacal $Ag{NO}_{3}$
0%
All

Explanation

Since alkaline

$KMnO_4$ are powerful oxidizing agents, they can oxidize double bond also, to protect double bond, we use a mild oxidizing agent as

$Tollen's\ [Ag(NH_3)_2]+OH−$ oxidizes

$CHO$ to

$COOH$ without affecting the

$(C=C)$ bond. and

$Ag(0)$ (mirror) is precipitated.
1777309_1768382_ans_5da4edd36a324a559e587b6651ab80aa.png

Which of the following statements are correct?

0%
Oximes are stronger acids than hydroxylamine
0%
$p{K}_{a}$ of maleic acid is less than $p{K}_{a}$ of fumaric acid
0%
${Me}_{3}Si{CH}_{2}COOH$ is a stronger acid than ${Me}_{3}C-{CH}_{2}COOH$
0%
o-Nitrobenzoic acid is a weaker acid than 3,5-dinitrobenzoic acid

Five isomeric p-substituted aromatic compounds (A) to (E) with molecular formula

$C_8H_8O_2$ are given for identification. Based on the following observation, give the structures of the compounds.
i. Both (A) and (B) form a silver mirror with Tollens reagent. (B) also gives a positive test with neutral

$FeCl_3$ solution.
ii. (C) gives positive iodoform test.
iii. (D) is readily extracted in aqueous

$NaHCO_3$ solution.
iv. (E) on acid hydrolysis gives 1,4 - dihydroxy benzene.
Compound (D) is:

0%
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
0%
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
0%
Assertion is correct but Reason is incorrect
0%
Both Assertion and Reason are incorrect

Explanation

Since 3-phenol propanoic acid is

${1}^{o}RX$ , preparation by both methods can occur.

Option A is correct.

1778774_1768422_ans_575bb3c9ae7f4a49b33beb8c20b83d19.jpg

Which of the following reactions are correct?

Select the correct order in sequence in order to get the final product (E).

0%
$(X)\, (U) \, (Z) \, (W) \, (U/X),(Y)$
0%
$(X) \,(U) \,(Z) \,(V) \,(U/X),(Y)$
0%
$(X) \,(Z) \,(W) \, (U/X),(Y) \,(V)$
0%
$(X) \,(Z) \,(W) \,(U) \,(V)$

Which of the following is the correct repeseentaation for intermediate of nucleophilic addition reaction to the given carbonyl compound (A):

Aldehyde and ketones do not react with

0%
Sodium bisulphide
0%
Phenylhydrazine
0%
Dihydrogen sodium phosphate
0%
Semicarbazide

Which of the following reagent are not correctly matched with the reaction ?

0%
$CH_{3}CH = CHCHO \rightarrow CH_{3}CH = CHCOOH :$ Ammonical $AgNO_{3}$
0%
$CH_{3}CH = CHCHO \rightarrow CH_{3}CH =CHCH_{2}OH : H_{2}/Pt$
0%
$R - COOH \rightarrow R - CH_{2}OH : NaBH_{4}$
0%
$CH_{3}CH_{2}COCl \rightarrow CH_{3}CH_{2}CHO : H_{2}CH_{2}CHO : H_{2}, PD /NASO_{4}$

Explanation

The incorrect reaction from the given reactions is reaction"B"

Corrected Reaction:

$\mathrm{CH_{3}CH = CHCHO \overset{H_{2}/{Pt}}{\rightarrow} CH_{3}CH_{2}CH_{2}CH_{2}OH}$

Hence, Option "B" is the correct answer.

Match column I with column II and mark the appropriate choice.

0%
$(A) \rightarrow (i) , (B) \rightarrow (ii) , (C) \rightarrow (iii) , (D) \rightarrow (iv)$
0%
$(A) \rightarrow (iv) , (B) \rightarrow (iii) , (C) \rightarrow (ii) , (D) \rightarrow (i)$
0%
$(A) \rightarrow (ii) , (B) \rightarrow (iv) , (C) \rightarrow (iii) , (D) \rightarrow (i)$
0%
$(A) \rightarrow (iii) , (B) \rightarrow (i) , (C) \rightarrow (ii) , (D) \rightarrow (iv)$

Explanation

Hint: Aldehydes and ketones can undergo both oxidation and reduction reduction.

Step 1: Oxidation and reduction reaction of aldehydes and ketones.

Carbonyl compounds are the ones that consist of a carbonyl group ( $-C=O$ ) in their structure. Aldehydes and ketones are examples of carbonyl compounds. Carbonyl compounds like aldehydes and ketones can undergo oxidation reactions to form carboxylic acid and sodium salt of carboxylic acid. Also, it can undergo reduction reactions to form alkanes and alcohols.

Step 2: Given oxidation and reduction reactions of aldehydes and ketones.

Aldehyde and ketones undergo reduction reactions in the presence of reducing agent $LiAlH_4$ to form alcohols. In this, the carbonyl group $-C=O$ gets converted into $-CH_2OH$ . Aldehyde and ketones can also be reduced to alkanes in the presence of Zn/HCl and conc. HCl. During this reaction, $-C=O$ group gets converted into $-CH_2$ group.

Oxidation reaction of aldehyde and ketones in the presence of $Ag_2O/OH^-$ leads to the formation of carboxylic acid. In this oxidation reaction, $-C=O$ group is converted into $-COOH$ . Similarly, the oxidation of aldehyde and ketones can also occur in the presence of NaOX but the product formed in this reaction is sodium salt of carboxylic acid. The carbonyl group $-C=O$ in this reaction is changed into $-COONa$ .

Final step:

Hence, the option B is correct.

2116788_1847166_ans_feb7e12e5f4e465c9ee8baa055b54d09.JPG

$\alpha$ - Hydroxypropanoic acid can be prepared from ethanal by following the steps given in the sequence .

0%
Treat with HCN followed by acidic hydrolysis
0%
Treat with $NaHSO_{3}$ followed by reaction with $Na_{2}CO_{3}$
0%
Treat with $H_{2}SO{4}$ followed by hydrolysis
0%
Treat with $K_{2}Cr_{2}O_{7}$ in presence of sulphurilic acid .

Explanation

Reaction for obtaining

$\mathrm{\alpha}$ -Hydroxypropanoic acid from ethanal is:

$\mathrm{\underset{Ethanal}{H_3C-CHO} + HCN \xrightarrow{\ \ \ \ } H_3C-C(OH)-CN \xrightarrow{H_3O^+} \underset{\alpha- Hydroxy \ Propnoic \ Acid}{H_3C-CH(OH)-COOH}}$

Hence, Option "A" is the correct answer.

Identity reactant (X) in the given reaction sequence .

$\mathrm{CH_{3}COCH_{3} + X \rightarrow (CH_{3}) _3C - (OMgCl) \overset{H_{2}O}{\rightarrow} (CH_3)_3C-OH}$

0%
$CH_{3}Mg Cl$
0%
$CH_{3}COCl + Mg$
0%
$Mg Cl_{2}$
0%
$CH_{3} CH_{2} MGCl$

Explanation

Complete Reaction:

$\mathrm{ CH_{3}COCH_{3} + CH_3MgCl \rightarrow (CH_{3}) _3C - (OMgCl) \overset{H_{2}O}{\rightarrow} (CH_3)_3C-OH}$

So, X is

$\mathrm{CH_3MgX}$

Hence, Option "A" is the correct answer.

Study the following sequence of reaction and identify the product (Y).

$CH_{3} CHO + HCHO \xrightarrow[heat]{dil . NaOH} X \xrightarrow[H_{3}O^{+}]{HCN} Y$

The end product (Z) in the given sequence of reaction is

$CH_{3}CH = CHCHO \overset{NaBH_{4}}{\rightarrow} X \xrightarrow[ZnCl_{2}]{HCl} Y \xrightarrow[(ii)H^{+}]{KCN} Z$

0%
$CH_{3}CH = CHCH_{2}COOH$
0%
$CH_{3}CH_{2}CH_{2}COOH$
0%
$CH_{3}CH = CHCOOH$
0%
$CH_{3}CH (Cl)CH_{2}COOH$

Explanation

Complete Reaction:

$CH_{3}CH = CHCHO \overset{NaBH_{4}}{\rightarrow} CH_3CH-CH_2CH_2OH \xrightarrow[ZnCl_{2}]{HCl} CH_3CH=CHCH_2Cl \xrightarrow[(ii)H^{+}]{KCN} CH_3CH=CHCH_2COOH$

So, the end product Z is

$CH_{3}CH = CHCH_{2}COOH$

Hence, Option "A" is the correct answer.

A compound (X) having molecular formula

$C_{4}H_{8}O_{2}$ is hydrolysed by water in presence of an acid to give a carboxylic acid (Y) and an alcohol (Z) . (Z) on oxidation with chrome acid gives (Y), (X), (Y) and (Z) are

0%
X $CH_{3}COOCH_{3}$
Y $CH_{3}COOH$
Z $CH_{3}OH$
0%
X $CH_{3}COOC_{2}H_{5}$
Y $CH_{3}COOH$
Z $C_{2}H_{5}OH$
0%
X $C_{2}C_{5}COOCH_{3}$
Y $C_{2}C_{5}COOH$
Z $C_{2}H_{5}OH$
0%
X $CH_{3}COOC_{2}H_{5}$
Y $C_{2}H_{5}COOH$
Z $CH_{3}OH$

Explanation

As the compound on hydrolysis gives carboxylic acid, so, the given compound X is a ketone.

Ketones possible with molecular mass

$\mathrm{(C_4H_8O_2)}$ are

$\mathrm{CH_3-COO-C_2H_5}$ and

$\mathrm{C_2H_5-COO-CH_3}$

X is

$\mathrm{CH_3-COO_C_2H_5 \ or \ C_2H_5-COO-CH_3 }$

Y is

$\mathrm{CH_3COOH \ or \ C_2H_5COOH}$

Z is

$\mathrm{CH_3-CH_2OH \ or \ C_2H_5-CH_2OH}$

Hence, Option "B" is the correct answer.

Which functional group does

$CH_{3}COCH_{3}$ contains ?

0%
$-CHO$
0%
$-\overset {\overset {\displaystyle {\text O}}{||}} C-$
0%
$-COOH$
0%
$-OH$

Product

$A$ and

$B$ for the following reactions are as follows:

0%
0%
0%
0%
None of the above

The IUPAC name of

$CH_{3}CH = CHCOOC_{2}H_{5}$ is

0%
Ethyl but-1-enoate
0%
Ethyl but-2-enoate
0%
Ethyl prop-2-enoate
0%
None of these

CBSE Questions for Class 12 Medical Chemistry Aldehydes, Ketones And Carboxylic Acids Quiz 14 - MCQExams.com

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Practice Class 12 Medical Chemistry Quiz Questions and Answers

CBSE Questions for Class 12 Medical Chemistry Aldehydes, Ketones And Carboxylic Acids Quiz 14 - MCQExams.com

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Practice Class 12 Medical Chemistry Quiz Questions and Answers

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