Explanation
Gabriel synthesis is a reaction that converts primary alkyl halides into primary amines. This reaction uses potassium phthalimide. This reaction is named after the German chemist Siegmund Gabriel.
Hence option A is correct.
Amine is an organic compound derived from ammonia by replacement of one or more hydrogen atoms by organic groups. Ex: Aniline
($$C_6H_5NH_2$$). Because of the presence of lone pair amines acts as Lewis bases.
Hence, option $$B$$ is correct
Answer:
Primary amine has higher boiling point than secondary followed by tertiary amine, this is because higher boiling points of the primary amines is that they can form hydrogen bonds with each other as well as van der Waals dispersion forces and dipole-dipole interactions.
Tertiary amine has no hydrogen left for forming Hydrogen bonds among themselves so can not show intermolecular H-bonding. So intermolecular force will be weak and low boiling point of tertiary amines
$$I=Ethyldimethyl\ amine=3^0$$
$$II=n-butylamine=1^0$$
$$III=diethylamine=2^0$$
In primary amines only one hydrogen is substituted by an alkyl group, in secondary amines, two hydrogens are substituted by alkyl groups and in tertiary amines, all the three hydrogens are substituted by alkyl groups thereby resulting in the absence of intermolecular hydrogen bonding. Higher the hydrogen bonding difficult is to break the bonds thereby high boiling point.
Intermolecular hydrogen bonding is maximum in primary amines and absent in tertiary amines.
So order of boiling points will be $$II>III>I$$
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