CBSE Questions for Class 12 Medical Chemistry Organic Compounds Containing Nitrogen Quiz 9 - MCQExams.com

The correct IUPAC name for $$CH_{2}=CHCH_{2}NHCH_{3}$$ is
  • Allylmethylemine
  • $$2-$$ amino $$-4-$$ pentene
  • $$4-$$ aminopent $$-1-$$ ene
  • $$N-$$ methylprop $$-2-$$ en $$-1-$$ amine
The correct decreasing order of basic strength of the following species is:

$$H_{2}O, NH_{3}, OH^{-}, NH_{2}^{-}$$
  • $$NH_{2}^{-} > OH^{-} > NH_{3} > H_{2}O$$
  • $$OH^{-} > NH_{2}^{-} > H_{2}O > NH_{3}$$
  • $$NH_{3} > H_{2}O > NH_{2}^{-} > OH^{-}$$
  • $$H_{2}O > NH_{3} > OH^{-} > NH_{2}^{-}$$
Aniline dissolves in $$HCl$$ due to the formation of:
  • anilinium chloride
  • o-chloroaniline
  • azo dye
  • diazonium chloride
Gabriel phthalimide reaction is used for the preparation of: 
  • primary aromatic amines
  • secondary amines
  • primary aliphatic amines
  • tertiary amines
Diphenyl hydrazine is same as :
  • azoxybenzene
  • azobenzene
  • hydrazobenzene
  • aniline
Out of the following compounds, which is the most basic in aqueous solution?
  • $${ CH }_{ 3 }{ NH }_{ 2 }$$
  • $$\left( { CH }_{ 3 } \right) _{ 2 }NH$$
  • $$\left( { CH }_{ 3 } \right) _{ 3 }N$$
  • $${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$
$${ CaC }_{ 2 }\xrightarrow { Hydrolysis } A\xrightarrow [ Cu\:tube ]{ Red\:hot } B\xrightarrow [ { 50-60 }^{ 0 }C ]{ { HNO }_{ 3 }-{ H }_{ 2 }{ SO }_{ 4 } } C\xrightarrow { Fe+HCl }  D \xrightarrow { { NaNO }_{ 2 }+HCl,\:{ 0}^{ 0 }C } E$$

In the reaction sequence given above, $$E$$ is:
  • aniline
  • benzene diazonium chloride
  • phenyl osazone
  • benzoyl chloride
Which of the following has the maximum value of $${ pk_b }$$?
  • $$\left( { CH }_{ 3 } \right) _{ 2 }NH$$
  • $$\left( { CH }_{ 3 }{ CH }_{ 2 } \right) _{ 2 }NH$$
  • $$C_6H_5-NH-C_6H_5$$
  • $$C_6H_5-NH-CH_3$$
Arrange the following in the correct order of their basic character in the aqueous phase.

$$(i)$$ $${ NH }_{ 3 }$$

$$(ii)$$ $${ RNH }_{ 2 }$$

$$(iii)$$ $${ R }_{ 2 }NH$$

$$(iv)$$ $${ R }_{ 3 }N$$
  • $$IV > III > II > I$$
  • $$III > IV > II > I$$
  • $$III > II > IV > I$$
  • $$I > II > III > IV$$
Which of the following when treated with aniline will give benzene diazonium chloride as the major product?
  • $${ NaNO }_{ 2 }$$ and $$HCl$$ between $$0-{ 5 }^{ 0 }C$$
  • $${ HNO }_{ 3 }$$ and $$HCl$$ between $$0-{ 5 }^{ 0 }C$$
  • $${ C }_{ 6 }{ H }_{ 5 }{ NO }_{ 2 }$$ between $$0-{ 5 }^{ 0 }C$$
  • $${ NaNO }_{ 2 }$$ between $$0-{ 5 }^{ 0 }C$$
Reaction at $${ 0-5 }^{ 0 }C$$ between aniline, $${ NaNO }_{ 2 }$$ and HCl is known as____________
  • Suphonation of benzene
  • Acylation of aniline
  • Alkylation of aniline
  • Diazotisation
Which of the following statements is not correct?
  • Primary amines show intermolecular hydrogen bonding.
  • Secondary amines show intermolecular hydrogen bonding.
  • Tertiary amines show intermolecular hydrogen bonding.
  • Amines have lower boiling points as compared to those of alcohols and carboxylic acids of comparable molar masses.
Which of the following orders is correct regarding the basic strength of subsituted aniline ?
  • p - nitroaniline > p - aminobenzaldehyde > p- bromoaniline
  • p - nitroaniline < p - bromoaniline < p- aminobenzaldehyde
  • p - nitroaniline < p - aminobenzaldehyde < p- bromoaniline
  • p - nitroaniline > p - aminobenzaldehyde < p-bromoaniline
Which of the following undergoes diazotization?
  • $${ CH }_{ 3 }{ NH }_{ 2 }$$
  • $${ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }$$
  • $${ CH }_{ 3 }{ CONH }_{ 2 }$$
  • $${ CH }_{ 3 }N\left( { CH }_{ 3 } \right) _{ 2 }$$
The correct order of basicity of the given compounds is :
  • $$CH_{3} CH_{2} NH_{2} < HO(CH_{2})_{3}NH_{2}< HO(CH_{2})_{2}NH_{2}$$
  • $$CH_{3} CH_{2} NH_{2} < HO(CH_{2})_{3}NH_{2}> HO(CH_{2})_{2}NH_{2}$$
  • $$CH_{3} CH_{2} NH_{2} > HO(CH_{2})_{3}NH_{2}> HO(CH_{2})_{2}NH_{2}$$
  • $$CH_{3} CH_{2} NH_{2} > HO(CH_{2})_{3}NH_{2}< HO(CH_{2})_{2}NH_{2}$$
Which of the following orders with regards to the basic strength of substituted aniline is correct?
  • p - methylaniline > p - chloroaniline > p - aminoacetophenone
  • p - methylaniline > p - aminoacetophenone > p - chloroaniline
  • p - aminoacetophenone > p - methylaniline > p - chloroaniline
  • p - aminoacetophenone > p - chloroaniline > p - methylaniline
$${ CH }_{ 3 }{ CH }_{ 2 }Cl\xrightarrow { NaCN } X\xrightarrow { Pt/{ H }_{ 2 } } Y\xrightarrow [ anhydride ]{ Acetic  } Z$$ 
In the above sequence, $$Z$$ is:
  • $${ CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ NHCOCH }_{ 3 }$$
  • $${ CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ NH }_{ 2 }$$
  • $${ CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CONHCH }_{ 3 }$$
  • $${ CH }_{ 3 }{ CH }_{ 2 }{ CH }_{ 2 }{ CONHCOCH }_{ 3 }$$
Which of the following forms unstable diazonium ion when treated with $$NaNO_{2}$$ in aqueous $$HCl$$?
  • p-nitrotoluene
  • ethylamine
  • N,N-dimethyl aniline
  • All of the above
Amongst the following, the most basic compound is :
  • benzylamine
  • aniline
  • acetanilide
  • p-nitroaniline
The correct order of increasing basic nature for the bases  $$NH_{3} ,CH_{3} NH_{2}  and  (CH_{3})_{2}NH$$ in gas phase is :
  • $$(CH_{3})_{2}NH < NH_{3}< CH_{3}NH_{2}$$
  • $$NH_{3} < CH_{3}NH_{2} < (CH_{3})_{2}NH$$
  • $$CH_{3}NH_{2} < (CH_{3})_{2}NH_{2} < NH_{3}$$
  • $$CH_{3}NH_{2} < NH_{3} <(CH_{3})_{2}NH $$
Which of the following is correct formula for BDC?
  •   $${ C }_{ 6 }{ H }_{ 4 }{ N }_{ 2 }Cl$$
  •   $${ C }_{ 6 }{ H }_{ 5 }{ N }_{ 2 }$$
  •   $${ C }_{ 6 }{ H }_{ 5 }{ N }_{ 2 }Cl$$
  •    $${ C }_{ 6 }{ H }_{ 4 }{ N }_{ 2 }$$
Among the following which is more basic :
The major product expected, when Phthalmide is treated with NaOH, is :
The product $$U$$ is:

72533_45ed6e42e3af44fb953433b72f7f74b9.jpg
The starting reagents needed to make the azo compound shown below is:
26636_ef344524a146453fab9b41a5fb9f38e8.png
The correct order of basicity of the above compounds is given.
Identify the correct statement(s).
43841.PNG
  • In III, lone pair of electrons is involved in delocalisation but not in II.
  • In IV, lone pair of electrons is involved in delocalisation but not in III.
  • I is more basic than II because six membered ring is more stable than five membered ring.
  • In III, lone pair of electrons is present in sp orbital but in I, II and IV lone pair of electrons are present in $$sp^{2}$$ orbital.
Aniline when diazotized in cold and then treated with dimethylaniline gives a coloured product. Its structure would be:
The correct basicity order of various atoms is :
74355_dac12d4007d647b592c6d6d52b1afb0b.png
  • 1 < 2 < 3 < 4
  • 2 < 3 < 4 < 1
  • 3 < 2 < 1 < 4
  • 3 < 2 < 4 < 1
What is the principle product when aniline is treated with $$NaNO_2$$ and $$HCl$$ at $$0-5^{\circ}C$$, and this mixture is added to p-toludine (p-methyl aniline)?
Predict the product (T) for the following reaction sequence.
$$C_6H_5-CH=O \xrightarrow{KCN / OH^-} R \xrightarrow{CrO_2 / H^{\oplus}}S \xrightarrow[(ii)\, Acidification]{(i)\, conc\, KOH}T$$  :
  • Cinnamic acid
  • Mandelic acid
  • Benzilic acid
  • Benzoic acid & Benzyl alcohol
The increasing order of basic strength for the following compounds is:
(I) $$CH_{3}-CH_{2}-NH_{2}$$
(II) $$CH_{3}-NH-CH_{3}$$
(III) $$CH_{3}-NH-Ph$$
(IV) $$CH_{3}-NH-CHO$$
  • $$IV < III < I > II$$
  • $$III < IV < I > II$$
  • $$IV < III < II > I$$
  • $$II < I < III > IV$$
The following product(s) will be obtained from the above reaction:
121309_d6d1d31057454058810397464eb9aaac.png
N $$\displaystyle -$$ Ethyl pthalimide on hydrolysis gives:
  • methyl alcohol
  • ethyl amine
  • dimethyl amine
  • diethyl amine
Which of the following diazonium salt is relatively stable of $$0-5^\circ C$$- :
  • $$CH_{3}CH_2N\equiv N\left. \right \} ^\oplus Cl^{-} $$
  • $$CH_{3}-C(CH_{3})_{2}-N\equiv N\left. \right \} ^\oplus Cl^{-} $$
  • $$CH_{3}-N\equiv N\left. \right \} ^\oplus Cl^{-} $$
  • $$(CH_{3})_{3}C-N\equiv N\left. \right \} ^\oplus Cl^{-} $$
Which compound does not give positive test in Lassaigne's test for nitrogen?
  • Urea
  • Hydrazine
  • Azobenzene
  • Phenyl hydrazine
Which of the following is weakest base?
  • $$H_2N-CH_2-NO_2$$
  • $$CH_3NH-CH=O$$
Between any two of the following molecules, hydrogen bonding is not possible:
  • two primary amine molecules
  • two secondary amine molecules
  • two tertiary amine molecules
  • two ammonia molecules
Of the following statements :
$$(P)\:C_{6}H_{5}N=CH-C_{6}H_{5}$$ is a Schiff's base.
$$(Q)\:$$A dye is obtained by the reaction of aniline and $$C_{6}H_{5}N^+ \equiv NCl$$.
$$(R)\:C_{6}H_{5}CH_{2}NH_{2}$$ on treatment with $$[NaNO_{2}+HCl]$$ gives diazonium salt.
$$(S)\:p-$$Toluidine on treatment with $$[HNO_{2}+HCl]$$ gives diazonium salt.
  • only $$(P)\:and\:(Q)$$ are correct
  • only $$(P)\:and\:(R)$$ are correct
  • only $$(R)\:and\:(S)$$ are correct
  • $$(P),\:(Q)\:$$and$$\:(S)$$ are correct
Which compound is soluble in water :
  • $$\displaystyle \left [ \left ( CH_{3} \right )_{2}NH_{2}\right ]^{+}Cl^{-}$$
  • $$\displaystyle \left [ CH_{3}NH_{3} \right ]^{+}Cl^{-}$$
  • $$\displaystyle \left [ \left ( CH_{3} \right )_{3}NH\right ]^{+}Cl^{-}$$
  • $$\displaystyle PhNO_{2}$$
Arrange the following in the increasing order of their basicities.
I.  p - Toluidine
II.  N, N - Dimethyl - p - toluidine
III.  p - Nitroaniline
IV.  Aniline
  • III < IV < I < II
  • II < IV < I < III
  • III < II < I < IV
  • I < IV < III < II
Which one(s) is/are true?
244984_4a91c8421a5843ef99c951718adf0721.png
  • (I) and (III) are modest Bronsted bases whereas (II) is not
  • In (III) $${N}^{a}$$ is more basic than $${N}^{b}$$
  • When (II) is protonated in the presence of a strong acid, protonation occurs at $$C - 2$$
  • All the nitrogen present in (I), (II), and (III) is $$s{p}^{2}$$ hybridised
Which compound will liberate $$\displaystyle CO_{2}$$ from $$\displaystyle NaHCO_{3}$$ solution :
  • $$\displaystyle CH_{3}CO\:NH_{2}$$
  • $$\displaystyle CH_{3}NH_{2}$$
  • $$\displaystyle \left ( CH_{3} \right )_{4}N^{+}OH^{-}$$
  • $$\displaystyle CH_{3}N^{+}H_{3}Cl^{-}$$
Arrange the following in their decreasing order of acidity.

244989_b3f46e7b98d94e01bbdc8ed803a45d2c.png
  • $$III > IV > I > II$$
  • $$I > II > III > IV$$
  • $$IV > III > II > I$$
  • $$II > III > I > IV$$
Which of the following is the product of the reaction shown above?
206794.png
  • $$(CH_3)_2CHCH_2CH_2NHNH_2$$
  • $$[(CH_3)_2CHCH_2CH_2]_2NH$$
  • $$(CH_3)_2CHCH_2CH_2NH_2$$
  • $$(CH_3)_2CHCH_2CH_2CONH_2$$
The decreasing order of basic characters of the following is :
245041_86a21bdb1e854fd1a74329652e535599.png
  • III > IV > I > II
  • II > I > IV > III
  • IV > III > II > I
  • I > II > III > IV
Which of the following diazonium salt is relatively stable at $$\displaystyle 0-5^{\circ}$$C?
  • $$\displaystyle CH_{3}-N\equiv N^{\oplus }Cl^{-}$$
  • $$\displaystyle CH_{3}CH\left ( CH_{3} \right )-N\equiv N ^{\oplus }Cl^{-}$$
  • $$\displaystyle C_{6}H_{5}-N\equiv N ^{\oplus }Cl^{-}$$
  • $$\displaystyle \left ( CH_{3} \right )_{3}C-N\equiv N ^{\oplus }Cl^{-}$$
Which of the following statement(s) is/are correct?
244985_4a1a58265d4940aab28debbcc7a7befa.png
  • (I) and (II) are aromatic and have equal basic strength
  • (I) is aromatic and (II) is anti-aromatic, but (II) is stronger base than (I)
  • The order of basicity of the above compounds is (IV) > (III) > (II) > (I)
  • The conjugate acid of (IV) is more stabilised than the conjugate acid of (II)
Alkyl isocyanides ($$R N^{\bigoplus} \equiv C^{\ominus}$$) are reduced to 2$$^{\circ}$$ amines($$R-NH-CH_3$$) with:
  • $$LAH$$
  • $$NaBH_4$$
  • $$HI + P$$
  • $$H_2 / Pt$$
Compound $$(E)$$ is:
Compound $$(A)$$ is:
  • Ethylbenzene
  • $$p-Xylene$$
  • $$m-Xylene$$
  • $$o-Xylene$$
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