MCQ Questions for Class 6 Maths Algebra Quiz 3

The solution of the equation

$3(x - 4)= 30$ is

$x =6$

0%
True
0%
False

Explanation

$x=6$ is the solution then,

$3(x-4)=30$ is satisfied by

$x=6$

LHS

$=3(6-4)=6$

RHS

$=30$

LHS

$\neq$ RHS

$\implies x=6$ is not the solution

The solution of the equation

$3x - 5 =2 \, is\, x = \dfrac{7}{3}$

0%
True
0%
False

Explanation

True

$3x - 5 =2$

$\implies\, 3x = 2+ 5 =7$

$\implies\, x =\dfrac{7}{3}$

Convert this statement in mathematical form.
The number is

$8$ greater than

$80.$

0%
$x+8=80$
0%
$x-8=80$
0%
$8x=80$
0%
$x=80\times8$

Explanation

Let the number be

$x$ . Here, the given statement is the number is

$8$ greater than

$80$ .

The word 'greater than' suggests addition. So, the verbal expression the number is

$8$ greater than

$80$ can be represented by the algebraic expression:

$x=80+8\\ \Rightarrow x-8=80$

Hence, the statement the number is

$8$ greater than

$80$ can be rewritten as

$x-8=80$ .

$6$ more than twice the number is

$22$ . Express the statement in mathematical form.

0%
$2x+6=22$
0%
$2x-6=22$
0%
$2x+22=6$
0%
$2x-22=6$

Explanation

Let the number be

$x.$

Twice the number

$=2x$

Six more than

$2x$ will be

$6+2x.$

This is equal to

$22.$

Hence, the answer is

$6+2x=22.$

$\textbf{State whether the statement is True or False.}$

$5$ is the solution of the equation

$3x+2=17$ .

0%
True
0%
False

Explanation

Consider the given equation,

$3 x+2=17$
On transposing

$2$ to RHS.
We get,

$\Rightarrow 3 x=17-2$

$\Rightarrow 3 x=15$

$\Rightarrow x=\frac{15}{3}$

$\Rightarrow x=5$

$\therefore 5 \textbf{ is the solution of the equation } 3 x+2=17$ .

$\textbf{Hence, the given statement is true.}$

Meera bought packs of trading cards that contain

$10$ cards each. She gave away

$7$ cards.

$x=$ number of packs of trading cards, then which of the following expression shows the number of cards left with Meera?

0%
$10x-7$
0%
$7x-8$
0%
$5-10x$
0%
$8-5x$

Explanation

Given:Number of packs of trading cards

$=x$

Packs of trading cards that contain

$10$ cards each

$=10x$

She gave away

$7$ cards

$=-7$

Number of cards left with Meera

$=10x-7$

The weight of Rahul is

$5\ kg$ more than Sachin .The weight of Samir is

$12\ kg$ less than double the weight of Sachin .If the total weight of all the three is

$93$ form the equation

0%
$4x-7=93$
0%
x+5=0
0%

$x+ (x+5)+ (2x-12)=93$
0%
2x-12=21

Explanation

Let weight of sachin

$=x \ kg$

Acc. to question.

Weight of Rahul

$=(x+5)\ kg$

Weight of Samir

$=(2x-12)\ kg$

Total weight of all

$=93\ kg$

That is ,

$x+ (x+5)+ (2x-12)=93$

$4x-7=93$

Which of the following represents the given statement?
The sum of a and b is multiplied by taking away

$5$ from their sum.

0%
$(a+b)(a+b-5)$
0%
$(a+b)(5-a-b)$
0%
$(a+b)(5-a+b)$
0%
$(a+b)(5+a-b)$

Explanation

We know that the word 'sum' means 'addition' and 'taking away' means 'subtraction'.

So,

Sum of

$a$ and

$b= a+b$

$5$ taken away from sum of

$a$ and

$b = a+b-5$

Thus,

Sum of

$a$ and

$b$ is multiplied by taking away 5 from the sum of

$a$ and

$b = (a+b)(a+b-5)$

Which of the following represents the statement given below?
The product of

$a$ and

$b$ is added to their sum.

0%
$ab+a+b$
0%
$a+b-ab$
0%
$a+ab$
0%
$b+ab$

Explanation

We know that the word 'product' means 'multiplication' and 'sum' means 'addition'.

So,

Product of

$a$ and

$b$

$= a \times b$ .

Sum of

$a$ and

$b$

$=a+b$

Thus,

The product of

$a$ and

$b$ is added to their sum

$= a \times b+a+b$

$= ab+a+b$

____ represents the following statement.
The product of

$x$ and

$y$ is decreased by

$4$ .

0%
$4-xy$
0%
$x(y-4)$
0%
$xy-4$
0%
$xy+4$

Explanation

We know that the words 'product' and 'decreased' by 'multiplication' and 'subtracted' respectively.

So,

The product of

$x$ and

$y=$

$x \times y$ .

Thus,

The product of

$x$ and

$y$ is decreased by

$4= x \times y -4$ .

$= xy-4$ .

Which of the following represents the statement given below?

$9$ less than

$x$ ?

0%
$9-x$
0%
$x-9$
0%
$x+9$
0%
None of these

Explanation

We know that the word 'less than' represents 'subtraction'.

Thus,

$9$ less than

$x$

$=x-9$ .

_____ represents the following statement.

$5$ more than twice a number

$x$

0%
$5+x+2$
0%
$2x+5$
0%
$2x-5$
0%
$5x+2$

Explanation

We know that, the word 'twice' means double and 'more than a number' means 'adding a certain amount to a number'.

Let, the number

$=x$ .

Twice the number

$=2x$ .

Thus,

$5$ more than twice the number

$=2x+5$ .

If each matchbox contains

$48$ matchsticks, then the number of matchsticks required to fill

$n$ such boxes is

0%
$48+n$
0%
$48-n$
0%
$48\div n$
0%
$48n$

Explanation

Given,

Matchsticks required to fill

$1$ matchbox

$=48\times 1=48$

$\therefore$ Matchsticks required to fill

$n$ matchbox

$=48\times n=48n$

One third of a number added to itself give

$8,$ can be represented as

$\dfrac{x}{3}+8=x$

0%
True
0%
False

Explanation

Let the unknown number be x,
Then one third of the number would be

$\frac{1}{3} \times x$ or

$\frac{x}{3}$
Now, one third of

$x$ added to itself would be

$\frac{x}{3}+x$
Finally, One third of a number added to itself gives 8 would be

$\frac{x}{3}+x=8$
Clearly,

$_{3}^{x}+8=x$ and

$\frac{x}{3}+x=8$ are not the same,

$\textbf{Therefore, the above statement is False}$

The length of a side of square is given as

$2x+3$ . Which expression represents the perimeter of the square.

0%
$2x+16$
0%
$6x+9$
0%
$8x+3$
0%
$8x+12$

Explanation

Apply the formula of perimeter of square
Since, the perimeter of a square

$=side+side+side+side=4 \times side$
The perimeter of the given square

$=4 \times (2x+3)$

$=4 \times 2 x+4 \times 3$

$\Rightarrow 4 \times(2 x+3)=8 x+12$
Therefore, the perimeter of the given square

$=8x+12$

$\textbf{Hence, the correct option is (d)}$

State true/false:

The mathematical expression corresponding to statement: Sum of

$x$ and

$y$ is given as:

$x+y$

0%
True
0%
False

Explanation

Given statement is: Sum of

$x$ and

$y$ is

$x+y$

Here, the word "Sum" suggests addition.

So the verbal expression "Sum of

$x$ and

$y$ " can be represented by the algebraic expression

$x+y$

$x = -1$ is a solution of the equation

0%
$x - 5 =6$
0%
$2x + 5 = 7$
0%
$2(x - 2) + 6 =0$
0%
$3x + 5 =4$

Explanation

${\textbf{Step -1: Considering option A.}}$

${\text{We have given,}}$ $x - 5 = 1$

${\text{Putting }}x = - 1{\text{ we get,}}$

$- 1 - 5 = 6$

$\Rightarrow - 6 = 1$ ${\text{Which is not possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S}} \ne {\text{R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is not a solution of }}x - 5 = 6.$

${\textbf{Step -2: Considering option B.}}$

${\text{We have given,}}$ $2x + 5 = 7$

${\text{Putting }}x = - 1{\text{ we get,}}$

$2\left( { - 1} \right) + 5 = 7$

$\Rightarrow - 2 + 5 = 7$

$\Rightarrow 3 = 7$ ${\text{Which is not possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S }} \ne {\text{ R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is not a solution of 2}}x + 5 = 7.$

${\textbf{Step -3: Considering option C.}}$

${\text{We have given,}}$ $2\left( {x - 2} \right) + 6 = 0$

${\text{Putting }}x = - 1{\text{ we get,}}$

$2\left( { - 1 - 2} \right) + 6 = 0$

$\Rightarrow 2\left( { - 3} \right) + 6 = 0$

$\Rightarrow - 6 + 6 = 0$

$\Rightarrow 0 = 0$ ${\text{Which is possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S = R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is a solution of 2}}\left( {x - 2} \right) + 6 = 0.$

${\textbf{Step -4: Considering option D.}}$

${\text{We have given,}}$ $3x + 5 = 4$

${\text{Putting }}x = - 1{\text{ we get,}}$

$3\left( { - 1} \right) + 5 = 4$

$\Rightarrow - 3 + 5 = 4$

$\Rightarrow 2= 4$ ${\text{Which is not possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S}} \ne {\text{R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is not a solution of }}3x + 5 = 4.$

${\textbf{ Hence, option C}}{\textbf{. 2}}\left(\mathbf {x - 2} \right)\mathbf{ + 6 = 0}{\textbf{ is correct answer.}}$

The non variable part in the expression

$x-18$ is

0%
$1$
0%
$18$
0%
$x$
0%
$-x$

Explanation

The non-variable/constant part of the expression

$x-18$ is

$18$ .

Which equation among the following don't have

$(-1)$ as a solution?

0%
$x + 1=0$
0%
$3x + 4 =1$
0%
$5x + 7= 2$
0%
$x -1 =2$

Explanation

${\textbf{Step -1: Considering option A.}}$

${\text{We have given,}}$ $x +1 = 0$

${\text{Putting }}x = - 1{\text{ we get,}}$

$- 1 +1 = 0$

$\Rightarrow 0 = 0$ ${\text{Which is possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S}} = {\text{R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is a solution of }}x +1 = 0.$

${\textbf{Step -2: Considering option B.}}$

${\text{We have given,}}$ $3x + 4 = 1$

${\text{Putting }}x = - 1{\text{ we get,}}$

$3\left( { - 1} \right) + 4 = 1$

$\Rightarrow - 3 + 4 = 1$

$\Rightarrow 1 = 1$ ${\text{Which is possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S }} = {\text{ R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is a solution of 3}}x + 4 = 1.$

${\textbf{Step -3: Considering option C.}}$

${\text{We have given,}}$ $5x + 7 = 2$

${\text{Putting }}x = - 1{\text{ we get,}}$

$5\left( { - 1 } \right) + 7 = 2$

$\Rightarrow -5+ 7 = 2$

$\Rightarrow 2 = 2$ ${\text{Which is possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S = R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is a solution of }}5x+7 =2.$

${\textbf{Step -4: Considering option D.}}$

${\text{We have given,}}$ $x -1 = 2$

${\text{Putting }}x = - 1{\text{ we get,}}$

$-1-1= 2$

$\Rightarrow - 2 = 2$ ${\text{Which is not possible}}{\text{.}}$

${\text{Here, L}}{\text{.H}}{\text{.S}} \ne {\text{R}}{\text{.H}}{\text{.S }}$

${\text{So, - 1 is not a solution of }}x -1 = 2.$

${\textbf{ Hence, option D. }}\mathbf{ x-1 =2}{\textbf{ is correct answer.}}$

In the expression

$-24x$ , the variable is

0%
$24$
0%
$-24$
0%
$x$
0%
$-x$

Explanation

In the expression

$-24x$ , the variable is

$x$ and the constant / non-variable is

$-24$ .

CBSE Questions for Class 6 Maths Algebra Quiz 3 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Algebra Quiz 3 - MCQExams.com

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

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