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CBSE Questions for Class 6 Maths Algebra Quiz 4 - MCQExams.com
CBSE
Class 6 Maths
Algebra
Quiz 4
$$\dfrac{9}{4}$$ is a solution of the equation $$5x - 1= 8$$.
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True
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False
Explanation
If $$\dfrac{9}{8}$$ is a solution then it must satisfy the given equation
so,
From LHS
$$5x-1=5\times \dfrac{9}{4}-1$$
$$=\dfrac{45}{4}-1$$
$$=\dfrac{45-4}{4}$$
$$=\dfrac{41}{4}$$
$$=10.25 \neq 8$$
$$\implies $$ LHS $$\neq$$ RHS
Hence $$\dfrac{9}{8}$$ is not the solution of the given equation.
Let Arjun bought $$2$$ apple on $$Day \ 1$$.
Then he bought $$4$$ apple on $$Day \ 2$$.
He bought $$6$$ apple on $$Day \ 3$$. And so on.
So we can say, Arjun bought $$2\times N$$ apple on $$Day \ N$$.
Here $$"N"$$ in $$2\times N$$ represents
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The number of apples
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The number of days
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$$N$$ is a constant
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Can't say.
A non-variable/constant has a fixed value.
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True
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False
Select the equations where $$x = 1$$ is solution.
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$$x+3 = 4$$
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$$x-3 = 4$$
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$$3x+3 = 6$$
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$$3x-3 = 6$$
In a playground, kids are playing in the groups of $$5$$.
If there is one group of kids, then, total number of kids = $$5$$
If there is two group of kids, then, total number of kids = $$5+5 = 5\times 2$$
and so on.
So the total number of kids playing in the playground are
$$5 + 5+5+....= 5\times n$$
Here, the variable $$n$$ is
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The number of groups
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The number of kids
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The number of toys
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The number of games
Explanation
We observe that $$Total \quad no. \quad of\quad kids \quad= \quad5 \quad\times\quad no.\quad of\quad groups$$
$$\therefore$$, $$n =$$ No. of groups
What value of $$x$$ that makes the following equation true ( using trail and error method) ?
$$\dfrac{x+5}{2} = 3$$
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$$x = 0$$
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$$x = 1$$
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$$x = 2$$
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$$x = 3$$
Find the suitable value of $$x$$ for the following equation by trial and method:
$$2x-21 = 21$$
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$$x = 20$$
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$$x = 21$$
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$$x = 22$$
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$$x = 23$$
The non variable part in the expression $$2n$$ is
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$$2$$
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$$n$$
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$$2n$$
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None of the above.
What is the method of finding a solution by trying out various values for the variable called?
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Trial method
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Trial and error method
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Substitution method
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Testing method
Solve the equation $$x-10 = 5 $$ using trial and error method.
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$$x = 5$$
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$$x = 10$$
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$$x = 15$$
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$$x = 20$$
In the expression $$-36y$$ the variable part is
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$$-x$$
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$$y$$
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$$36$$
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$$-36$$
Evaluate using trial and error method:
$$2(x+5) = 10 $$
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$$x = 0$$
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$$x = 1$$
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$$x = 2$$
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$$x = 3$$
What value of $$x$$ makes $$4x-3 = 17$$ a true statement.
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$$x = 2$$
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$$x = 3$$
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$$x = 4$$
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$$x = 5$$
If $$\dfrac{x+6}{3} = 7$$, what is the value of $$x$$?
( using trail and error method)
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$$x= 21$$
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$$x= 20$$
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$$x= 15$$
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$$x= 14$$
Explanation
We need to find $$x$$ such that $$\dfrac{x+6}{3}$$ is $$7$$.
We know that $$\dfrac{21}{3}$$ is $$7$$.
We thus get $$7$$ if $$x+6=21$$ $$\Longrightarrow$$ $$x=15$$
Choose the value of $$x$$ that satisfies the equation $$ 6x = 12$$.
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$$x = 2$$
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$$x = 3$$
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$$x = 4$$
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None of these
Use trial amd error method, find the value of $$t$$ if $$\dfrac{t}{4} = 4$$.
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$$x = 4$$
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$$x = 8$$
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$$x = 12$$
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$$x = 16$$
If $$\dfrac{x}{2} = \dfrac{3}{2}$$, what is the value of $$x$$?
( using trail and error method)
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$$x = 0$$
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$$x = 1$$
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$$x = 2$$
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$$x = 3$$
Which of the following equation/s has/have $$x= 3 $$ solution?
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$$x+3 = 6$$
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$$x+4 = 6 $$
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$$ 2x = 6$$
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$$x+5 = 8$$
Choose the equation for which $$x =2$$ is a solution.
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$$x+1 = 5 $$
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$$x+3 = 5 $$
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$$x+5 = 5 $$
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None of these
Determine the value of $$x$$ using trail and error method if $$x+10 = 17$$.
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$$x = 3$$
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$$x = 5$$
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$$x = 7$$
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$$x = 9$$
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