MCQ Questions for Class 6 Maths Algebra Quiz 4

$\dfrac{9}{4}$ is a solution of the equation

$5x - 1= 8$ .

0%
True
0%
False

Explanation

$\dfrac{9}{8}$ is a solution then it must satisfy the given equation

so,

From LHS

$5x-1=5\times \dfrac{9}{4}-1$

$=\dfrac{45}{4}-1$

$=\dfrac{45-4}{4}$

$=\dfrac{41}{4}$

$=10.25 \neq 8$

$\implies$ LHS

$\neq$ RHS

Hence

$\dfrac{9}{8}$ is not the solution of the given equation.

Let Arjun bought

$2$ apple on

$Day \ 1$ .
Then he bought

$4$ apple on

$Day \ 2$ .
He bought

$6$ apple on

$Day \ 3$ . And so on.

So we can say, Arjun bought

$2\times N$ apple on

$Day \ N$ .
Here

$"N"$ in

$2\times N$ represents

0%
The number of apples
0%
The number of days
0%
$N$ is a constant
0%
Can't say.

A non-variable/constant has a fixed value.

0%
True
0%
False

Select the equations where

$x = 1$ is solution.

0%
$x+3 = 4$
0%
$x-3 = 4$
0%
$3x+3 = 6$
0%
$3x-3 = 6$

In a playground, kids are playing in the groups of

$5$ .

If there is one group of kids, then, total number of kids =

$5$
If there is two group of kids, then, total number of kids =

$5+5 = 5\times 2$
and so on.

So the total number of kids playing in the playground are

$5 + 5+5+....= 5\times n$
Here, the variable

$n$ is

0%
The number of groups
0%
The number of kids
0%
The number of toys
0%
The number of games

Explanation

We observe that

$Total \quad no. \quad of\quad kids \quad= \quad5 \quad\times\quad no.\quad of\quad groups$

$\therefore$ ,

$n =$ No. of groups

What value of

$x$ that makes the following equation true ( using trail and error method) ?

$\dfrac{x+5}{2} = 3$

0%
$x = 0$
0%
$x = 1$
0%
$x = 2$
0%
$x = 3$

Find the suitable value of

$x$ for the following equation by trial and method:

$2x-21 = 21$

0%
$x = 20$
0%
$x = 21$
0%
$x = 22$
0%
$x = 23$

The non variable part in the expression

$2n$ is

0%
$2$
0%
$n$
0%
$2n$
0%
None of the above.

What is the method of finding a solution by trying out various values for the variable called?

0%
Trial method
0%
Trial and error method
0%
Substitution method
0%
Testing method

Solve the equation

$x-10 = 5$ using trial and error method.

0%
$x = 5$
0%
$x = 10$
0%
$x = 15$
0%
$x = 20$

In the expression

$-36y$ the variable part is

0%
$-x$
0%
$y$
0%
$36$
0%
$-36$

Evaluate using trial and error method:

$2(x+5) = 10$

0%
$x = 0$
0%
$x = 1$
0%
$x = 2$
0%
$x = 3$

What value of

$x$ makes

$4x-3 = 17$ a true statement.

0%
$x = 2$
0%
$x = 3$
0%
$x = 4$
0%
$x = 5$

$\dfrac{x+6}{3} = 7$ , what is the value of

$x$ ? ( using trail and error method)

0%
$x= 21$
0%
$x= 20$
0%
$x= 15$
0%
$x= 14$

Explanation

We need to find

$x$ such that

$\dfrac{x+6}{3}$ is

$7$ .

We know that

$\dfrac{21}{3}$ is

$7$ .

We thus get

$7$ if

$x+6=21$

$\Longrightarrow$

$x=15$

Choose the value of

$x$ that satisfies the equation

$6x = 12$ .

0%
$x = 2$
0%
$x = 3$
0%
$x = 4$
0%
None of these

Use trial amd error method, find the value of

$t$ if

$\dfrac{t}{4} = 4$ .

0%
$x = 4$
0%
$x = 8$
0%
$x = 12$
0%
$x = 16$

$\dfrac{x}{2} = \dfrac{3}{2}$ , what is the value of

$x$ ? ( using trail and error method)

0%
$x = 0$
0%
$x = 1$
0%
$x = 2$
0%
$x = 3$

Which of the following equation/s has/have

$x= 3$ solution?

0%
$x+3 = 6$
0%
$x+4 = 6$
0%
$2x = 6$
0%
$x+5 = 8$

Choose the equation for which

$x =2$ is a solution.

0%
$x+1 = 5$
0%
$x+3 = 5$
0%
$x+5 = 5$
0%
None of these

Determine the value of

$x$ using trail and error method if

$x+10 = 17$ .

0%
$x = 3$
0%
$x = 5$
0%
$x = 7$
0%
$x = 9$

CBSE Questions for Class 6 Maths Algebra Quiz 4 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Algebra Quiz 4 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

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