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CBSE Questions for Class 6 Maths Decimals Quiz 3 - MCQExams.com
CBSE
Class 6 Maths
Decimals
Quiz 3
Solve the given
$$3.005+4.7$$
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0%
$$3.052$$
0%
$$3.475$$
0%
$$7.705$$
0%
$$3.007$$
Explanation
Addition of $$3.005$$ and $$4.7$$ gives $$3.005+4.7=7.705$$
Abhishek had Rs. $$7.45$$. He bought toffees for Rs. $$5.30$$. The balance amount left with Abhishek is ______ .
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0%
Rs. $$2.30$$
0%
Rs. $$2.00$$
0%
Rs. $$2.15$$
0%
Rs. $$3.00$$
Explanation
Since he bought toffees some amount has been reduced:
Thus final amount= Initial Amount- Money Spent
$$F.A=Rs. 7.45-5.30=Rs. 2.15$$
The value of 30.5 - 30.4 + 30.3 - 30.2 + 30.1 - 30 + 29.9 - 29.8
+ 29.7 - 29.6 + 29.5 - 29.4 + 29.3 - 29.2 + 29.1 - 29.0 = _________.
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0%
$$0.8$$
0%
$$0.7$$
0%
$$0.6$$
0%
$$1.8$$
Explanation
We have, $$(30.5 - 30.4) + (30.3 - 30.2) + (30.1 - 30) + (29.9 - 29.8) + (29.7 - 29.6) + (29.5 - 29.4)
+ (29.3 - 29.2) + (29.1 - 29.0)$$
$$= 0.1+ 0.1 + 0.1 + 0.1 + 0.1+ 0.1 + 0.1 + 0.1$$
$$= 0.8$$.
Shalini's car has $$15\ L\ 315\ ml$$ of petrol in its tank, while her scooter has $$2\ L\ 945\ ml$$ of petrol in its tank. How much petrol is there in both the vehicles altogether?
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0%
$$18\ L\ 370\ ml$$
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$$18\ L\ 260\ ml$$
0%
$$13\ L\ 945\ ml$$
0%
$$13\ L\ 370\ ml$$
Explanation
Quantity of petrol in car $$= 15\ L\ 315\ ml$$
Quantity of petrol in scooter $$= 2\ L\ 945\ ml$$
$$\therefore$$ Total quantity of petrol
$$= (15\ L+315\ ml) +( 2\ L+ 945\ ml)$$
$$=17\ L+1260\ ml$$
$$=17\ L+ (1\ L +260\ ml)$$
$$= 18\ L\ 260\ ml$$.
What is the missing number in the box?
$$600.0651 = 600 +$$ _____ $$+ 0.005+ 0.0001$$
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0%
$$0.005$$
0%
$$0.06$$
0%
$$0.5$$
0%
$$5$$
Explanation
$$600.0651 = 600+ \dfrac{6}{100} +\dfrac{5}{1000} +\dfrac{1}{10000} = 600 + 0.06 + 0.005 + 0.0001$$.
Subtract the given decimals:
$$4.17$$ from
$$5.5$$
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0%
$$1.33$$
0%
$$3.62$$
0%
$$1.12$$
0%
$$3.15$$
Explanation
$$5.5-4.17=1.33$$
The decimal number $$1.9$$ lies between ________ on the number line.
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0%
$$0$$ and $$1$$
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$$1$$ and $$2$$
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$$2$$ and $$3$$
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$$-1$$ and $$0$$
Explanation
A positive decimal always lies between the number on left side of the decimal and its successor .
In $$1.9$$ the number on the left side of decimal is $$1$$ .So the decimal number lies between $$1$$ and $$2$$.
Find the value of $$617+6.017+0.617+6.0017$$.
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0%
$$6.2963$$
0%
$$62.965$$
0%
$$629.6357$$
0%
$$62.8975$$
Explanation
given that, $$617.0000+6.0170+0.6170+6.0017=629.6357$$
hence option $$C$$ is correct
Find the sum of $$1.2$$ and $$2.3$$.
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$$35$$
0%
$$3.5$$
0%
$$0.35$$
0%
$$1.23$$
Explanation
The sum of $$1.2$$ and $$2.3$$ will be $$1.2+2.3=3.5$$
Write down $$9275\ meters$$ in $$km$$, as a decimal fraction.
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0%
$$927.5Km$$
0%
$$92.75Km$$
0%
$$10.275Km$$
0%
$$9.275Km$$
Explanation
$$9275$$ meters in km, as decimal fraction
$$=\dfrac{9275}{1000} km$$
$$=9.275 km$$
In which figure does the shaded part represents 0.3?
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0%
0%
0%
0%
Explanation
In figure A,
Total Divisions $$= 10$$
Shaded Divisions $$= 3$$
$$\therefore\ $$ Shaded part $$= \dfrac{3}{10} = 0.3$$
In figure B,
Total Divisions $$= 4$$
Shaded Divisions $$= 1$$
$$\therefore\ $$ Shaded part $$= \dfrac{1}{4} = 0.25$$
In figure C,
Total Divisions $$= 4$$
Shaded Divisions $$= 1$$
$$\therefore\ $$ Shaded part $$= \dfrac{1}{4} = 0.25$$
In figure D,
Total Divisions $$= 30$$
Shaded Divisions $$= 9$$
$$\therefore\ $$ Shaded part $$= \dfrac{9}{30} = 0.33$$
Hence, the figure in option A represents $$0.3$$.
$$3.\overline{25}$$ is equal to
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0%
$$ 2+\dfrac{25}{99} $$
0%
$$ 3+\dfrac{24}{99} $$
0%
$$ 3+\dfrac{25}{99} $$
0%
$$ 3+\dfrac{25}{98} $$
Explanation
$$3.\bar { 25 } =3+25*0.\bar { 01 } =3+25*\dfrac { 1 }{ 99 } =3+\dfrac { 25 }{ 99 } $$
Solve : $$25 +\displaystyle{\frac{3}{100}}+\displaystyle{\frac{4}{1000}}=$$ ?
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0%
$$25.34$$
0%
$$25.304$$
0%
$$25.034$$
0%
$$25.0034$$
Explanation
The value of $$25 $$ $$+$$ $$\displaystyle{\frac{3}{100}}$$ $$+$$ $$\displaystyle{\frac{4}{1000}}$$ is
$$=25+0.03+0.004$$
$$= 25.034$$
Amanda creates the base of a picture frame, using 4.55 inches of red fabric and 6.25 inches of blue fabric. How many inches of fabric are used to create the base of the frame?
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10.80 inches
0%
10.85 inches
0%
10.75 inches
0%
10.90 inches
Rahul bought $$4 \,kg\, 90\, g$$ of apples, $$2 \,kg \,60\, g$$ of grapes and $$5\, kg \,300 \,g$$ of mangoes. The
total weight of all the fruits he bought is _______
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0%
$$11.000 \,kg$$
0%
$$11.450 \,kg$$
0%
$$11.350\, kg$$
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$$11.250 \,kg$$
Explanation
$$\Rightarrow$$ Apples weight $$=4kg\,90g$$
$$\Rightarrow$$ Grapes weight $$=2kg\,60g$$
$$\Rightarrow$$ Mangoes weight $$=5kg\,300g$$
$$\Rightarrow$$ Total weight of all fruits $$=4kg\,90g+2kg\,60g+5kg\,300g=(4+2+5)kg\,(90+60+300)g= 11kg 450g= 11.450\,kg$$
$$\therefore$$ The total weight of all the fruits Rahul bought is $$11.450\,kg$$
Expanded form of $$78.059$$ is
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$$78$$ + $$\displaystyle{\frac{5}{10}}$$ + $$\displaystyle{\frac{9}{100}}$$
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$$70 + 8 + 0 +$$ $$\displaystyle{\frac{5}{100}}$$ + $$\displaystyle{\frac{9}{1000}}$$
0%
$$70 + 8 +$$ $$\displaystyle{\frac{5}{10}}$$ + $$\displaystyle{\frac{9}{100}}$$
0%
none
Explanation
Expanded form of $$78.059$$ is $$70+ 8+\displaystyle \frac { 0 }{ 10 } +\frac { 5 }{ 100 } +\frac { 9 }{ 1000 } $$
What is the difference between 3.8 and 0.571?
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0%
0.73
0%
2.567
0%
3.229
0%
4.262
Explanation
Numbers are $$3.8$$ and $$0.571$$.
Subtracting both of them,
Ref. image
Answer - C
Your supervisor instructs you to purchase 240 pens and 6 staplers for the nurse's station. Pens are purchased in sets of 6 for $2.35 per pack. Staplers are purchased in sets of 2 for 12.How much will purchasing these products cost?
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0%
$132.85
0%
$145.75
0%
$162.90
0%
$225.25
0%
$226.75
$$3$$ tenths $$ 5$$ thousandths is written as
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0%
$$35.00$$
0%
$$0.35$$
0%
$$3.5$$
0%
$$0.305$$
Explanation
3 tenths 5 thousandth =$$3\times \dfrac{1}{10}+5\times \dfrac{1}{1000}$$$$=0.3+0.005=0.305 $$
Co-ordinate of $$P$$ is.
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0%
$$-0.6$$
0%
$$0.3$$
0%
$$0.4$$
0%
$$-0.4$$
Explanation
$$\textbf{Step 1: Using number line}$$
$$\text{It can be seen that between two whole numbers there are 10 divisions.}$$
$$\Rightarrow \text{1 division}=\dfrac1{10}$$
$$\text{It can be seen that P is after 6 divisions.}$$
$$\Rightarrow \text{Coordinate of P}=6\times\dfrac1{10}=-0.6$$
$$\text{The negative sign is because the point is to the left of 0.}$$
$$\textbf{Hence , the coordinate of the point P is}\mathbf{-0.6.}$$ $$\textbf{Option A is correct.}$$
Represent $$4.5$$ and $$-2.3$$ on a number line and find the distance between them.
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0%
$$6.8$$
0%
$$2.2$$
0%
$$-6.8$$
0%
$$-2.2$$
State true or false:
$$9$$ paise is equal to
Rs.$$0.09$$.
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0%
True
0%
False
Explanation
As we know,
1 Rs = 100 paisa
Given, 9 paisa
So, 9 paisa = $$\frac{9}{100}$$ Rs
= 0.09 Rs
State true or false:
$$10cm$$ in meters is
$$0.1$$ $$m$$
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0%
True
0%
False
Explanation
As we know,
$$1$$ m $$= 100$$ m
$$1$$ km $$= 1000$$ m
Given, $$10$$ cm
So, $$10$$ cm $$= \dfrac{10}{100}$$ m$$= 0.1$$ m
On expressing the following in kilograms:
$$247$$ $$g$$=
$$ 2.47 $$ $$kg$$
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0%
True
0%
False
Explanation
To convert grams into kilograms we divide the given value by
1,000. A kilogram is one thousand grams.
$$247$$ grams $$=$$ $$\dfrac{247}{1000} $$ kilograms
$$247$$ grams $$=$$ $$0.247$$ kilograms
$$0.247≠2.47$$
So the given statement is false.
Option B is the correct answer
$$1\ km\ 250\ m =....................km$$
Fill in the blank by chosing correct option from the following options
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0%
$$10.360$$
0%
$$10250$$
0%
$$1.250$$
0%
$$10.625$$
Explanation
We know that $$1\ m$$=$$1000\ km$$.
Now, let us convert $$250\ m$$ in kms by dividing it by $$1000$$ as follows:
$$\dfrac {250}{1000}=0.25$$
Therefore, $$250\ m$$=$$0.25\ km$$
Thus we have:
$$1\ km$$ $$250\ m$$=$$(1+0.25)\ km$$=$$1.25\ km$$
Hence,
$$1\ km$$ $$250\ m$$=$$1.25\ km$$
Which decimal number does arrow represent?
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0%
$$3.05$$
0%
$$3.025$$
0%
$$3.005$$
0%
$$3.004$$
Explanation
Let the marking $$3.00$$ is at $$A$$ and $$3.01$$ is at $$B$$
$$AB=3.01-3.00=.01$$
Number of units betwwen $$A$$ and $$B$$ $$=10$$
Length of each unit $$=\dfrac{.01}{10}=.001$$
Given point is $$5$$ units from $$3.00$$
So location of given point is $$=3.00+.001\times5=3.005$$
Option $$C$$ is correct.
State true or false:
$$77$$ rupees $$7$$ paise is equal to
Rs.$$77.07$$.
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0%
True
0%
False
Explanation
As we know,
1 Rs $$=$$ 100 paisa
Given, 77 Rs 7 paisa
So,
77 Rs 7 paisa
$$=$$ 77 + $$\frac{7}{100}$$ Rs
$$=$$ 77 + 0.07 Rs
$$=$$77.07 Rs
so answer is true
Fill in the banks:
$$1765$$ grams $$= $$ _______ $$kg$$
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0%
$$1.765$$
0%
$$1.65$$
0%
$$1.55$$
0%
$$1.25$$
Explanation
$$1$$ kg $$= 1000$$ gm
So, $$1765$$ grams $$= \dfrac{1765}{1000}$$ kg
$$= 1.765$$ kg
State true/false:
$$1234.56$$ is equal to
$$1000+200+30+4+\cfrac { 5 }{ 10 } +\cfrac { 6 }{ 100 } $$
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0%
True
0%
False
Explanation
Given 1234.56 can be written as
$$1234.56 = 1000 + 200 + 30 + 4 + 0.5 + 0.6$$
$$= 1000 + 200 + 30 + 4 +$$ $$\dfrac{5}{10}$$ + $$\dfrac{6}{100}$$
So, given statement is true
Rahul bought $$4kg$$ $$90g$$ of apples, $$2kg$$ $$60g$$ of grapes and $$5kg$$ $$300g$$ of mangoes. The total weight of all the fruits he bought is _______ .
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0%
$$11.000kg$$
0%
$$11.450kg$$
0%
$$11.350kg$$
0%
$$11.250kg$$
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