MCQ Questions for Class 6 Maths Decimals Quiz 4

Golu's toothbrush is

$14.5\ cm$ long and Samaksh's toothbrush is

$12.8\ cm$ long. How much longer is Golu's toothbrush than Samaksh?

0%
$1.7\ cm$
0%
$1.6\ cm$
0%
$2.7\ cm$
0%
$1.9\ cm$

Explanation

Length of Golu's toothbrush

$= 14.5\ cm$
Length of Samaksh's toothbrush

$= 12.8\ cm$
Required difference in lengths

$= (14.5 - 12.8) cm$

$= 1.7\ cm$ .

$8m$

$57cm$ pole was put in a pond to measure its depth. If

$4m$

$66cm$ of pole remained outside water, then depth of pond is _____ .

0%
$3.91m$
0%
$3.00m$
0%
$3.45m$
0%
$3.23m$

A pole is painted yellow and black. The yellow part is

$1.8\ m$ long and the black is three times longer than yellow part. Find the length of pole.

0%
$5.4\ m$
0%
$7.2\ m$
0%
$3.6\ m$
0%
$none\ of\ these$

Explanation

Length of yellow Part

$=Y=1.8m$

Length of Black Part

$=3Y=5.4m=B$

So, Length of Pole

$=L=Y+B=1.8+5.4=7.2m$

The sum of two numbers is

$31.021$ . If one of them is

$11.56$ , then the other number is _______ .

0%
$19.461$
0%
$17.461$
0%
$18.641$
0%
$19.561$

The simplification of

$33.6 - 2 { .05 } + 0.133$ is equal to

0%
$31.63$
0%
$29.643$
0%
$25. { 61 }3$
0%
None of these

Evaluate:

$3.7-1.9$

0%
$0.6$
0%
$7.3$
0%
$3.4$
0%
$1.8$

Explanation

$3.7-1.9$

$=1.8$

$2+\dfrac {1}{2}$ In the decimal form

0%
$2.5$
0%
$1.5$
0%
$3.5$
0%
$2$

Explanation

$2+\dfrac{1}{2}$

$\dfrac{1}{2}=0.5$

$2+0.5=2.5$

The normal body temperature is

$98.6^{o} F$ . Ravi's temperature rose by

$2.5^{o} F$ . How much temperature did he have ?

0%
$101.1^{o}F$
0%
$102.^{o}F$
0%
$95.1^{o}F$
0%
$100.1^{o}F$

Mark against the correct answer in the following:

$6 cm =?$

0%
$0.006 km$
0%
$0.0006 km$
0%
$0.06 m$
0%
None of these

Explanation

We know that

$1m = 100 cm$
Then,

$= 6 cm$

$= \dfrac{6}{100} m$

$= 0.06 m$

Fill in the blank:

$70 g =$ _____

$kg$

0%
$0.7 g$
0%
$0.07 kg$
0%
$0.007 kg$
0%
None of these

Explanation

We know that

$1kg = 1000 g$

$70 g$

$= \dfrac{70}{1000}$

$kg$

$=0.07 kg$

Mark against the correct answer in the following:

5kg 6g=?5kg 6g=?

0%
$5.0006 kg$
0%
$5.06 kg$
0%
$5.006 kg$
0%
$5.6 kg$

Explanation

We know that

$1g = 0.001 kg$
So

$6$

$g$ =

$6 \times 0.001$

$kg =$

$0.006kg$

$5kg$

$6g$ =

$5.006kg$

The decimal form of

$5+\dfrac 7{100}$ is

0%
$5.7$
0%
$5.07$
0%
$5.70$
0%
$0.57$

Explanation

$5+\dfrac 7{100}=\dfrac {500+7}{100}=\dfrac{507}{100}= 5.07$

Mark against the correct answer in each of the following:

$( 1.007 - 0.7) = ?$

0%
$1$
0%
$0.37$
0%
$0.307$
0%
None of these

Explanation

$3.07$

First convert the given decimals into like decimals

$= (1.007 – 0.700)$

$= 0.307$

Fill the following blank:

$2 km\quad 5 m =$ ____

$km$

0%
$2.5$
0%
$2.05$
0%
$2.005$
0%
$2.0005$

Explanation

We know that

$1 m = 0.001 km$

So $5 m = 5 \times 0.001 km = 0.005 km$

$2km$ $5m$ = $2 km$ + $0.005km$ = $2.005km$

The value of

$\dfrac{3}{5}$ is

0%
$6$
0%
$0.06$
0%
$0.6$
0%
none of these

Explanation

We have,

$\dfrac{3}{5} = \dfrac{3}{5}\times \dfrac{2}{2}$ [multiply and divide by

$2$ ]

$=\dfrac{6}{10}\\=0.6$

Decimal form of

$\dfrac{63}{100}$ is

0%
$0.630$
0%
$0.603$
0%
$0.63$
0%
$0.630$

$5.2 - 3.6$ is equal to

0%
$0.16$
0%
$2.6$
0%
$0.26$
0%
$1.6$

Explanation

$5.2 - 3.6 = \dfrac{52}{10} - \dfrac{36}{10}$

$= \dfrac{16}{10}$

$=1.6$

$42.28-3.19=39.09 \quad$

0%
True
0%
False

Explanation

$42.28 - 3.19 = 39.09$

$42.28$

$-3.19$
__________

$39.09$

$0.7499$ lies between

0%
$0.7$ and $0.74$
0%
$0.75$ and $0.79$
0%
$0.749$ and $0.75$
0%
$0.74992$ and $0.75$

Explanation

Solution

$C$ is right

$\because 0.7499$ is successor of

$0.749$ and predecessor of

$0.75$
Thus

$0.749$ lies between

$0.749$ and

$0.75$

$15.8-6.73$ is equal to

0%
$8.07$
0%
$9.07$
0%
$9.13$
0%
$9.25$

Explanation

To subtract two decimals, convert 15.8 into like decimals with 2 decimal places,

$15.8 =15.80$

Now, subtracting decimals we get,

$15.80 - 6.73 = 9.07$

$\therefore \textbf{Option B is correct.}$

$3.03+ 0.016=3.019$

0%
True
0%
False

Explanation

$\Rightarrow 3.030 + 0.016 = 3.046$

$\Rightarrow 3.046 \neq 3.019$

$0.07 + 0.008$ is equal to

0%
$0.15$
0%
$0.015$
0%
$0.078$
0%
$0.78$

Explanation

To add two decimals, we need to convert 0.07 to 3 decimal places,

0.07 = 0.070

Now adding both the like decimals 0.070 and 0.008, we get

$\therefore \textbf{Option (C) is correct}$

$0.023$ lies between

0%
$0.2$ and $0.3$
0%
$0.02$ and $0.03$
0%
$0.03$ and $0.029$
0%
$0.026$ and $0.024$

Explanation

Converting the given decimals into like decimals we get the decimal number as,

0.020 and 0.030

Now comparing the place value of both the decimals with 0.023 we get,

$0.020 < 0.023, \ and \ 0.023 < 0.030$

Clearly, 0.023 lies between 0.02 and 0.03

$\therefore \textbf{Option B is correct}$

$24.58=2\times 10+4\times 1+5\times 10+8\times 100$

0%
True
0%
False

Explanation

False

$RHS=2\times 10+4\times 1+5\times 10+8\times 100=20+4+50+800=874\\ LHS\neq RHS$

$329.25=3\times 10^{2}+2\times 10^{1}+9\times 10^{0}+2\times 10^{-1}+5\times 10^{-2}$

0%
True
0%
False

Explanation

True

$RHS=3\times 10^{2}+2\times 10^{1}+9\times 10^{0}+2\times 10^{-1}+5\times 10^{-2}$

$=3\times 100+2\times 10+9\times 1+\dfrac{2}{10}+\dfrac{5}{10\times 10}$

$=3\times 100+2\times 10+9\times 1+0.2+0.05=329.25$
Therefore,

$LHS=RHS$

$0.31$ is greater than

0%
$0.32$
0%
$0.30$
0%
$0.34$
0%
$0.33$

$5.462$ is greater than

0%
$5.352$
0%
$5.468$
0%
$5.523$
0%
$5.469$

$1.461$ is less than

0%
$1.462$
0%
$1.469$
0%
$1.490$
0%
$1.450$

$0.046$ is less than

0%
$0.048$
0%
$0.045$
0%
$0.056$
0%
$0.050$

On a number line

$10.6$ lies between ____ and ____.

0%
10 and 11
0%
-10 and -11
0%
9 and 10
0%
-9 and -10

CBSE Questions for Class 6 Maths Decimals Quiz 4 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Decimals Quiz 4 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

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