MCQ Questions for Class 6 Maths Fractions Quiz 2

.............

$\displaystyle -\frac { 3 }{ 8 } = \frac { 3 }{ 8 }$

0%
1
0%
0
0%
$\displaystyle \frac { 4 }{ 3 }$
0%
$\displaystyle \frac { 3 }{4 }$

Improper fraction of

$12\displaystyle \frac {1}{6}$ is

0%
$\displaystyle \frac {72}{6}$
0%
$\displaystyle \frac {73}{6}$
0%
$\displaystyle \frac {108}{6}$
0%
$\displaystyle \frac {85}{6}$

Explanation

A mixed fraction is usually in the form

$Whole\,number \dfrac{Numerator}{Denominator}$ .

It can be written as improper fraction using

$\displaystyle \frac {(Whole\,number\, \times\, Denominator)\, +\, Numerator}{Denominator}$

$\Rightarrow 12\dfrac{1}{6} = \displaystyle \frac {12\,\times\, 6\, +\, 1}{6}$

$\Rightarrow\, \displaystyle \frac {72\, +\, 1}{6}\, =\, \displaystyle \frac {73}{6}$

Fraction is a part of _________ .

0%
whole
0%
half
0%
quarter
0%
none of these

Explanation

Fraction is a part of whole. it is in the form of

$\displaystyle \frac ab,$ where

$a$ is called numerator and

$b$ is called denominator. So,

$a$ is a part of

$b$ .
Option

$A$ is correct.

$\displaystyle \frac {4}{11}\, +\, \displaystyle \frac {7}{11}$ = ..........

0%
$\displaystyle \frac {11}{22}$
0%
$\displaystyle \frac {11}{11}$
0%
$\displaystyle \frac {3}{11}$
0%
$11$

Explanation

$\displaystyle \frac {4}{11}\, +\, \displaystyle \frac {7}{11}\, =\, \displaystyle \frac {4+7}{11}\, =\, \displaystyle \frac {11}{11}$

Which of the following fraction is the largest?

0%
$\displaystyle \frac {29}{30}$
0%
$\displaystyle \frac {29}{23}$
0%
$\displaystyle \frac {29}{27}$
0%
$\displaystyle \frac {29}{25}$

Explanation

$\because$ all fractions are having same numerator.
So the fraction having smallest denominator is the largest.
Hence

$\displaystyle \frac {29}{23}$ is the largest.

The difference between

$\displaystyle \frac {12}{19}$ and

$\displaystyle \frac {4}{19}$ is ...........

0%
$\displaystyle \frac {16}{19}$
0%
$\displaystyle \frac {16}{38}$
0%
$\displaystyle \frac {8}{19}$
0%
$8$

Explanation

$\displaystyle \frac {12}{19}\, -\, \displaystyle \frac {4}{19}\, =\, \displaystyle \frac {12-4}{19}\, =\, \displaystyle \frac {8}{19}$

By how much is

$\displaystyle \frac {19}{20}$ greater than

$\displaystyle \frac {2}{20}$ ?

0%
$\displaystyle \frac {21}{10}$
0%
$\displaystyle \frac {21}{40}$
0%
$\displaystyle \frac {17}{20}$
0%
$\displaystyle \frac {17}{40}$

Explanation

$\displaystyle \frac {19}{20}\, -\, \displaystyle \frac {2}{20}\, =\, \displaystyle \frac {19-2}{20}\, =\, \displaystyle \frac {17}{20}$

What should be added to

$\displaystyle \frac {11}{17}$ to make it

$\displaystyle \frac {15}{17}$ ?

0%
$\displaystyle \frac {26}{17}$
0%
$4$
0%
$\displaystyle \frac {4}{17}$
0%
$\displaystyle \frac {4}{34}$

Explanation

$\displaystyle \frac {15}{17}\, -\, \displaystyle \frac {11}{17}\, =\, \displaystyle \frac {15-11}{17}\, =\, \displaystyle \frac {4}{17}$

The sum of

$\displaystyle \frac {4}{13},\, \displaystyle \frac {3}{13}$ and

$\displaystyle \frac {5}{13}$ is

0%
$\displaystyle \frac {12}{39}$
0%
$\displaystyle \frac {13}{13}$
0%
$\displaystyle \frac {12}{13}$
0%
$\displaystyle \frac {11}{13}$

Explanation

$\displaystyle \frac {4}{13}\, +\, \displaystyle \frac {3}{13}\, +\, \displaystyle \frac {5}{13}\, =\, \displaystyle \frac {4+3+5}{13}\, =\, \displaystyle \frac {12}{13}$

$\displaystyle \frac {3}{4}\, +\, \displaystyle \frac {2}{4}\, =$ .......... fraction.

0%
proper
0%
improper
0%
mixed
0%
none of these

Explanation

$\displaystyle \frac {3}{4}\, +\, \displaystyle \frac {2}{4}\, =\, \displaystyle \frac {3+2}{4}\, =\, \displaystyle \frac {5}{4}$ IS an Impr-oper fraction

Sum of

$\displaystyle \frac {7}{12},\,\displaystyle \frac {12}{12},\,\displaystyle \frac {8}{12}$ is

0%
$\displaystyle \frac {26}{12}$
0%
$\displaystyle \frac {19}{12}$
0%
$\displaystyle \frac {27}{12}$
0%
$\displaystyle \frac {23}{12}$

Explanation

We need to find sum of

$\displaystyle \frac {7}{12}, \frac {12}{12}, \frac {8}{12}$

Since, the denominators of all fractions are same, the LCM is

$12$ .

$\therefore \displaystyle \frac{7}{12} +\frac{12}{12}+\frac{8}{12} = \frac{7+12+8}{12}$

$= \displaystyle \frac{27}{12}$

In an improper fraction, the numerator is always .......... the denominator.

0%
less than
0%
greater than
0%
equal to
0%
none

Explanation

A improper fraction is a fraction in which the numerator is greater than or equal to the denominator,

E.g

$\dfrac74$ ;

$\dfrac44$

Option

$D$ is correct.

$1\displaystyle \frac {3}{4}$ is a ____ fraction.

0%
proper
0%
improper
0%
mixed
0%
none

Explanation

A mixed fraction is defined as a fraction formed by combining a whole number and a fraction

$1\dfrac{3}{4}$ is a mixed fraction as :

$1+\dfrac{3}{4}=1\dfrac{3}{4}$

$\displaystyle \frac {6}{11}\, +\, \displaystyle \frac {5}{11}\, -\, \displaystyle \frac {7}{11}$ = ..........

0%
$\displaystyle \frac {7}{11}$
0%
$\displaystyle \frac {6}{11}$
0%
$\displaystyle \frac {4}{11}$
0%
$\displaystyle \frac {10}{11}$

Explanation

$\displaystyle \frac {6}{11}\, +\, \displaystyle \frac {5}{11}\, -\, \displaystyle \frac {7}{11}=\, \displaystyle \frac {6+5-7}{11}\, =\, \displaystyle \frac {4}{11}$

Numerator in the fraction

$\displaystyle \frac {4}{7}$ is ..........

0%
$4$
0%
$7$
0%
$\displaystyle \frac {4}{7}$
0%
$\displaystyle \frac {1}{7}$

The difference between the greatest and least numbers of

$\displaystyle \frac{5}{9}, \frac{1}{9}, \frac{11}{9}$ is

0%
$\displaystyle \frac{2}{9}$
0%
$\displaystyle \frac{4}{9}$
0%
$\displaystyle \frac{10}{9}$
0%
$\displaystyle \frac{2}{3}$

Explanation

$\dfrac{11}{9}-\dfrac{1}{9}=\dfrac{10}{9}$

The sum of

$\displaystyle \frac {8}{15}$ and

$\displaystyle \frac {7}{15}$ is ..........

0%
$1$
0%
$\displaystyle \frac {1}{15}$
0%
$\displaystyle \frac {1}{30}$
0%
None

Explanation

$\displaystyle \frac {8}{15}\, +\, \displaystyle \frac {7}{15}\, =\, \displaystyle \frac {8+7}{15}\, =\, \displaystyle \frac {15}{15}\, =\, 1$

........... +

$\displaystyle \frac {4}{7}\, =\, 1$

0%
$\displaystyle \frac {4}{7}$
0%
$1$
0%
$\displaystyle \frac {3}{7}$
0%
$\displaystyle \frac {7}{4}$

Explanation

$1\, -\, \displaystyle \frac {4}{7}\, =\, \displaystyle \frac {7-1}{7}\, =\, \displaystyle \frac {3}{7}$

Which of the following is/are proper fraction?

Explanation

Proper fraction is a fraction that is less than one, with the numerator less than the denominator.

In figure A,

Shaded parts

$= 3$

Total parts

$= 8$

Fraction

$=\dfrac{3}{8}$

In figure B,

Shaded parts

$= 1$

Total parts

$= 1$

Fraction

$=\dfrac{1}{1}$

In figure C,

Shaded parts

$= 1$

Total parts

$= 4$

Fraction

$=\dfrac{1}{4}$

In figure D,

Shaded parts

$= 3$

Total parts

$= 7$

Fraction

$=\dfrac{3}{7}$

$\therefore$ Figures A, C and D are examples of proper fraction.

Out of the rational numbers

$\displaystyle {\frac{-5}{11},\, \frac{-5}{12},\, \frac{-5}{17}}$ , which is greater ?

0%
$\displaystyle \frac{-5}{11}$
0%
$\displaystyle \frac{5}{-12}$
0%
$\displaystyle \frac{-5}{17}$
0%
None of these

Explanation

$\displaystyle {\frac{-5}{11},\, \frac{-5}{12},\, \frac{-5}{17}}$

$\because$ All have same numerator. Sothe rational number having theleast denominator is the greatest.But here all have negative sign.So, the number having greatestdenominator is greater. Hence,

$\displaystyle \frac{-5}{17}$ is greater

Which number should come in place of

$\square$ ?

$\displaystyle \frac {1}{7}\, +\, \displaystyle \frac {2}{7}\, +\, \displaystyle \frac {\square }{7}\, =\, 1\displaystyle \frac {3}{7}$

0%
1
0%
2
0%
3
0%
7

Explanation

$\displaystyle \frac {10}{7}\, -\, \displaystyle \frac {1}{7}\, -\, \displaystyle \frac {2}{7}\, =\, \displaystyle \frac {10-1-2}{7}\, =\, \displaystyle \frac {7}{7}$

$2\, -\, \displaystyle {\frac{11}{39}\, +\, \frac{5}{26}}$ = ............

0%
$\displaystyle \frac{149}{39}$
0%
$1\, +\, \displaystyle \frac{71}{78}$
0%
$\displaystyle \frac{149}{76}$
0%
$\displaystyle \frac{149}{98}$

Explanation

Given:

$\displaystyle {\frac{2}{1}\, -\, \frac{11}{39}\, +\, \frac{5}{26}}$

Factors of

$39=3\times 13$

Factors of

$26=2\times 13$

$LCM(39,26)=2\times 3\times 13=78$

$\displaystyle {\frac{2}{1}\, -\, \frac{11}{39}\, +\, \frac{5}{26}}$

$=\, \displaystyle {\frac{2\times 78\, -\, 11\times 2\, +\, 5\times 3}{78}\, }$

$=\, \displaystyle {\frac{156\, -\, 22\, +\, 15}{78}\, =\, \frac{149}{78}}$

$=\, 1\displaystyle {\frac{71}{78}\, =\, 1\, +\, \frac{71}{78}}$

In Krishna's flower garden,

$\dfrac{1}{7}$ are white roses,

$\dfrac{4}{7}$ are red roses and the rest are yellow roses. What fraction of the roses are yellow?

0%
$\displaystyle \frac {1}{7}$
0%
$\displaystyle \frac {2}{7}$
0%
$\displaystyle \frac {3}{7}$
0%
$\displaystyle \frac {4}{7}$

Explanation

Let the total number of yellow roses be $x$

Hence, $\dfrac{1}{7} + \dfrac{4}{7} + x = 1$

$\Rightarrow \dfrac{(1 + 4 + 7x) }{7} = 1$

$\Rightarrow \dfrac{(5 + 7x) }{ 7} = 1$

$\Rightarrow 5 + 7x = 7$ [ by cross multiplication]

$\Rightarrow 7x = 7 - 5$

$\Rightarrow 7x = 2$

$\Rightarrow x = \dfrac{2}{7}$

$\therefore$ The fraction of yellow roses are $\dfrac{2}{7}$

Which of the following is not a proper fraction ?

0%
$\displaystyle \frac{2}{3}$
0%
$\displaystyle \frac{3}{4}$
0%
$\displaystyle \frac{5}{7}$
0%
$\displaystyle \frac{6}{5}$

Explanation

Proper fraction is a fraction that is less than one, with the numerator less than the denominator.

So, option

$D$ is correct.

Which of the following is not a proper fraction?

0%
$\cfrac {2}{3}$
0%
$\cfrac {3}{4}$
0%
$\cfrac {5}{7}$
0%
$\cfrac {6}{5}$

Explanation

Fractions that are greater than

$0$ but less than

$1$ are called proper fractions.

In proper fractions, the numerator is less than the denominator.

When a fraction has a numerator that is greater than or equal to the denominator, then the fraction is an improper fraction.

An improper fraction is always

$1$ or greater than

$1$ .

Now looking at options

$\dfrac{2}{3}=.666 < 1$

$\dfrac{3}{4}= .75 < 1$

$\dfrac{5}{7}= .71 <1$

$\dfrac{6}{5}=1.2 > 1$

$\dfrac{6}{5}$ is Not a Proper fraction.

So option

$D$ is correct.

A quantity which expresses a part of the whole is called a/an:

0%
fraction
0%
prime number
0%
integer
0%
none of these

The lowest form of

$\displaystyle \frac { 30 }{ 60 }$ is -

0%
$\displaystyle \frac { 1 }{ 2 }$
0%
$\displaystyle \frac { 6 }{ 12 }$
0%
$\displaystyle \frac { 15 }{ 30 }$
0%
$\displaystyle \frac { 10 }{ 20 }$

Explanation

lowest form of

$\dfrac{30}{60}$ is

$\dfrac{30}{60}=\dfrac{3}{6}=\dfrac{1}{2}$

The sum of

$\displaystyle \frac { 8 }{ 14 } and \frac { 6 }{ 14 }$

0%
$\displaystyle \frac { 1 }{ 7 }$
0%
$\displaystyle \frac { 2 }{ 14 }$
0%
One
0%
None of these

Explanation

$\displaystyle \frac { 8 }{ 14 } + \frac {6} {14} = \frac {14} {14} = 1$

Re-arrange suitably and find the sum of the following

$\displaystyle\frac{-4}{7}+\displaystyle\frac{7}{6}+\displaystyle\frac{2}{7}+3+\displaystyle\frac{-11}{6}$ .

0%
$\displaystyle\frac{43}{21}$
0%
$\dfrac{43}{42}$
0%
$\dfrac{23}{42}$
0%
$\dfrac{23}{21}$

Explanation

Re-arranging and grouping the numbers in pairs in such a way that each group contains a pair of rational numbers with equal denominators, we have

$\cfrac{-4}{7}+\cfrac{7}{6}+\cfrac{2}{7}+3+\cfrac{-11}{6}$

$=\begin{pmatrix}\cfrac{-4}{7}+\cfrac{2}{7}\end{pmatrix}+\begin{pmatrix}\cfrac{7}{6}+\cfrac{-11}{6}\end{pmatrix}+3$

$=\cfrac{(-4)+2}{7}+\cfrac{7+(-11)}{6}+3=\cfrac{-2}{7}+\cfrac{(-4)}{6}+3$

$=\cfrac{(-2)}{7}+\cfrac{(-2)}{3}+3\begin{bmatrix}\therefore\cfrac{-4}{6}=\cfrac{-2}{3}\end{bmatrix}$

$=\begin{pmatrix}\cfrac{(-2)}{7}+\cfrac{(-2)}{3}\end{pmatrix}+3$

$=\cfrac{(-2)\times3+(-2)\times7}{21}+3=\cfrac{(-6)+(-14)}{21}+3$

$=\cfrac{(-20)}{21}+\cfrac{3}{1}=\cfrac{(-20)+3\times21}{21}$

$=\cfrac{(-20)+63}{21}=\cfrac{43}{21}$

Simplify

$\displaystyle\frac{-3}{10}+\displaystyle\frac{7}{15}+\displaystyle\frac{3}{-20}+\displaystyle\frac{-9}{10}+\displaystyle\frac{13}{15}+\displaystyle\frac{13}{-20}$

0%
$\displaystyle\frac{-2}{3}$
0%
$\dfrac{3}{5}$
0%
$\dfrac45$
0%
$\dfrac13$

Explanation

Re-arranging and grouping the numbers in pairs such that each group

contains a pair of rational numbers with equal denominators, we have

$\displaystyle\frac{-3}{10}+\displaystyle\frac{7}{15}+\displaystyle\frac{3}{-20}+\displaystyle\frac{-9}{10}+\displaystyle\frac{13}{15}+\displaystyle\frac{13}{-20}$

$=\begin{pmatrix}\displaystyle\frac{-3}{10}+\displaystyle\frac{-9}{10}\end{pmatrix}+\begin{pmatrix}\displaystyle\frac{7}{15}+\displaystyle\frac{13}{15}\end{pmatrix}+\begin{pmatrix}\displaystyle\frac{3}{-20}+\displaystyle\frac{13}{-20}\end{pmatrix}$

$=\displaystyle\frac{(-3)+(-9)}{10}+\displaystyle\frac{7+13}{15}+\displaystyle\frac{(-3)+(-13)}{20}$

$=\displaystyle\frac{-12}{10}+\displaystyle\frac{20}{15}+\displaystyle\frac{-16}{20}$

$=\displaystyle\frac{-6}{5}+\displaystyle\frac{4}{3}+\displaystyle\frac{-4}{5}$ [Expressing each rational in lowest terms]

$=\begin{pmatrix}\displaystyle\frac{-6}{5}+\displaystyle\frac{-4}{5}\end{pmatrix}+\displaystyle\frac{4}{3}$

$=\displaystyle\frac{(-6)+(-4)}{5}+\displaystyle\frac{4}{3}=\displaystyle\frac{-10}{5}+\displaystyle\frac{4}{3}$

$=-2+\displaystyle\frac{4}{3}=\displaystyle\frac{-6+4}{3}=\displaystyle\frac{-2}{3}$

CBSE Questions for Class 6 Maths Fractions Quiz 2 - MCQExams.com

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Fractions Quiz 2 - MCQExams.com

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.