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CBSE Questions for Class 6 Maths Fractions Quiz 3 - MCQExams.com
CBSE
Class 6 Maths
Fractions
Quiz 3
$$\displaystyle 3 \dfrac { 6 }{ 10 } = \dfrac { ? }{ 10 } $$
Find $$?$$
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$$63$$
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$$26$$
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$$36$$
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$$62$$
Explanation
since we are given a mixed fraction so the resulting fraction will be:
$$=\dfrac { (3\times10)+6 }{ 10 } $$
$$=\dfrac{36}{10}$$
$$ \displaystyle \frac{4}{5} $$+ $$ \displaystyle \frac{2}{5} $$
- $$ \displaystyle \frac{1}{5} $$ is equal to
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1
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$$ \displaystyle \frac{1}{5} $$
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-5
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None of these
Explanation
$$ \displaystyle \frac{4}{5} $$+ $$ \displaystyle \frac{2}{5} $$
- $$ \displaystyle \frac{1}{5}=\dfrac{4+2-1}{5}=\dfrac{5}{5}=1 $$
$$\displaystyle \frac { 20 }{ 25 } = \frac {?} {5} $$
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$$2$$
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$$5$$
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$$4$$
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$$6$$
Explanation
$$\displaystyle \frac { 20 }{ 25 } =\frac { 20\div 5 }{ 25\div 5 } =\frac { 4 }{ 5 } $$
The sum of $$\displaystyle \frac { 5 }{ 17 } , \frac {4} {17} and \frac {6} {17} is $$
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$$\displaystyle \frac { 15 }{ 51} $$
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$$\displaystyle \frac { 17 }{ 17 }$$
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$$\displaystyle \frac { 15 }{ 17 } $$
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$$\displaystyle \frac { 14 }{ 17 }$$
Explanation
Sum $$=\displaystyle \dfrac { 5 }{ 17 } + \dfrac {4} {17} + \dfrac {6} {17}$$
$$=\dfrac{5+4+6}{17}$$
$$= \dfrac {15} {17} $$
Compare $$\displaystyle \frac { 8 }{ 16 } \Box \frac { 8 }{ 4 } $$
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=
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<
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>
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None of these
Explanation
$$ \dfrac{8}{16}=\dfrac{1}{2}\ and\ \dfrac{8}{4}=2$$
obviously $$\dfrac{1}{2} < 2$$
Example for an improper fraction is -
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$$\displaystyle \frac { 35 }{ 36 } $$
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$$\displaystyle \frac { 11 }{ 4 } $$
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$$\displaystyle \frac { 12 }{ 14 } $$
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$$\displaystyle \frac { 17 }{ 20 } $$
Explanation
In a fraction, if the denominator is less than the numerator, then it is called as an improper fraction.
Among these, in $$\dfrac {11}{4}$$, the denominator is greater than the numerator.
Hence it is an improper fraction.
Subtract $$\displaystyle \frac { 3 }{ 17 } from \frac {8} {17} $$
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$$\displaystyle \frac { 5 }{ 34 } $$
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$$\displaystyle \frac { 5 }{ 17 } $$
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$$\displaystyle \frac { 5 }{ 0 } $$
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$$\displaystyle \frac { 11 }{ 17 } $$
Explanation
$$\displaystyle \frac { 8 }{ 17 } - \frac {3} {17} = \frac {5} {17}$$
What fraction on the number line below is in the wrong place?
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$$\dfrac {1}{4}$$
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$$\dfrac {1}{8}$$
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$$\dfrac {1}{2}$$
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$$\dfrac {3}{4}$$
Explanation
$$\dfrac 1 8$$ is a smaller value than $$\dfrac1 4$$.
So $$\dfrac 18$$ should be mentioned on the left of $$\dfrac 14.$$
So, we can conclude that $$\dfrac 1 8$$ is in the wrong place.
S
o option B is the correct answer.
Difference of $$\dfrac {19}{25}$$ and $$\dfrac {27}{25}$$ is
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$$\dfrac {9}{25}$$
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$$\dfrac {3}{25}$$
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$$\dfrac {8}{25}$$
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$$\dfrac {6}{25}$$
Explanation
Due to the common denominator, we'll easily find the difference,
$$\dfrac{(27-19)}{25}$$
$$=\dfrac 8{25}$$
So option C is the correct answer.
Improper fraction of $$12\dfrac {1}{6}$$ is
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$$\dfrac {72}{6}$$
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$$\dfrac {73}{6}$$
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$$\dfrac {108}{6}$$
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$$\dfrac {85}{6}$$
Explanation
$$\dfrac {WN\times D+N}{D}$$
$$\dfrac {12\times 6+1}{6}=\dfrac {72+1}{6}=\dfrac {73}{6}$$
Sum of $$\dfrac {7}{12}, \dfrac {12}{12}, \dfrac {8}{12}$$ is
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$$\dfrac {26}{12}$$
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$$\dfrac {19}{12}$$
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$$\dfrac {27}{12}$$
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$$\dfrac {23}{12}$$
Explanation
Therefore, $$\dfrac{7}{12}+\dfrac{12}{12}+\dfrac{8}{12}=\dfrac{27}{12}$$
As $$7+12+8=27$$
So option C is the correct answer.
Mixed fraction for $$\dfrac {39}{12}$$ is
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$$3\dfrac {1}{12}$$
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$$3\dfrac {2}{12}$$
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$$3\dfrac {3}{12}$$
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$$2\dfrac {14}{12}$$
Explanation
To convert an improper fraction to a mixed fraction, we divide the numerator by the denominator, then write down the whole number answer. Finally, we write down any remainder above the denominator.
So, in this case when $$39$$ is divided by $$12$$ then it leaves the remainder equal to $$3$$ and the quotient is $$3$$ as well.
$$\dfrac{{39}}{{12}} = 3\dfrac{3}{{12}}$$
So, option $$C$$ is correct.
The sum of $$\displaystyle \frac{4}{13},\frac{3}{13}$$ and $$\displaystyle \frac{5}{13}$$ is __________
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$$\displaystyle \frac{12}{39}$$
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$$\displaystyle \frac{13}{13}$$
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$$\displaystyle \frac{12}{13}$$
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$$\displaystyle \frac{11}{13}$$
Explanation
The sum of $$\displaystyle \frac{4}{13},\frac{3}{13}$$ and $$\displaystyle \frac{5}{13}$$ is
$$\displaystyle \frac{14}{13}+\frac{3}{13}+\frac{5}{13}=\frac{4+3+5}{13}=\frac{12}{13}$$
Solve:$$\displaystyle \frac{4}{11}+\frac{7}{11}=$$_________
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$$\displaystyle \frac{11}{22}$$
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$$\displaystyle \frac{11}{11}$$
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$$\displaystyle \frac{3}{11}$$
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11
Explanation
$$\displaystyle \frac{4}{11}+\frac{7}{11}= \frac{4+7}{11}= \frac{11}{11}$$
Example for a proper fraction is ____
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$$\dfrac {28}{13}$$
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$$\dfrac {11}{23}$$
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$$\dfrac {16}{9}$$
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$$\dfrac {14}{3}$$
Explanation
A proper fraction is a fraction that is less than one, with the numerator less than the denominator.
The only fraction with the numerator less than the denominator in the given options is $$\dfrac{11}{23}.$$
So option B is the correct answer.
Example for an improper fraction is
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$$\dfrac {25}{26}$$
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$$\dfrac {12}{13}$$
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$$\dfrac {15}{14}$$
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$$\dfrac {19}{20}$$
Explanation
An improper fraction is a fraction that has a larger number on the top than on the bottom.
The number on the top of the fraction is a numerator and the number on the bottom is a denominator.
Therefore, an improper fraction has a greater numerator than the denominator.
The only option with the numerator greater than the denominator is option C
$$\dfrac{15}{14}$$
So, option C is the correct answer.
Improper fraction of $$\displaystyle 12\tfrac{1}{6}$$ is
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$$\displaystyle \frac{72}{6}$$
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$$\displaystyle \frac{73}{6}$$
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$$\displaystyle \frac{108}{6}$$
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$$\displaystyle \frac{85}{6}$$
Explanation
$$\displaystyle \frac{WN \times D + N}{D}$$
$$\displaystyle \frac{12\times 6+1}{6}= \frac{72+1}{6}= \frac{73}{6}$$
Which of the following is an improper fraction?
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$$\dfrac{15}{1}$$
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$$\dfrac{1}{3}$$
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$$\dfrac{2}{3}$$
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none of the above
Explanation
Since numerator > denominator only in option $$A.$$
Therefore, it is correct.
What is the sum?
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$$\displaystyle \frac{1}{3}$$
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$$\displaystyle \frac{3}{8}$$
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$$\displaystyle \frac{2}{3}$$
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$$\displaystyle \frac{5}{8}$$
Explanation
The question depicts a whole circle divided in 8 equal parts.
The first figure has 3 parts shaded out of 8 parts. The second figure to be added in the first figure has 2 parts shaded out of 8 parts. This can be depicted as,
(3/8)+(2/8)=(5/8)
Option D is the correct answer.
Solve:$$ \displaystyle \frac{6}{11}+\frac{5}{11}-\frac{7}{11} $$=__________
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$$ \displaystyle \frac{7}{11}$$
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$$ \displaystyle\frac{6}{11}$$
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$$ \displaystyle\frac{4}{11}$$
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$$ \displaystyle\frac{10}{11}$$
Explanation
$$ \displaystyle \frac{6}{11}+\frac{5}{11}-\frac{7}{11}=\frac{6+5-7}{11}=\frac{4}{11} $$
What should be added to $$\displaystyle \dfrac{11}{17}$$ to make it $$\displaystyle \dfrac{15}{17}$$
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$$\displaystyle \dfrac{26}{17}$$
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$$4$$
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$$\displaystyle \dfrac{4}{17}$$
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$$\displaystyle \dfrac{4}{34}$$
Explanation
Let $$x$$ to be added to get $$\dfrac{15}{17}$$
$$\dfrac{11}{17} +x=\dfrac{15}{17}$$
$$x=\dfrac{15}{17}-\dfrac{11}{17}$$
$$= \dfrac{15-11}{17}= \dfrac{4}{17}$$
Hence, $$\dfrac{4}{17}$$ should be added to make $$\dfrac{15}{17}$$
Which of the following is a proper fraction?
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$$1\dfrac {1}{3}$$
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$$\dfrac {5}{4}$$
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$$\dfrac {2}{3}$$
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None of these
Explanation
We know that, a proper fraction is a fraction where the numerator is less than the denominator.
Since numerator $$<$$ denominator in $$\dfrac 23$$, it is a proper fraction.
Hence, option C is correct.
$$\displaystyle \frac { 1 }{ 3 } +\frac { 1 }{ 2 } -\frac { 5 }{ 6 } +\frac { 1 }{ 5 } +\frac { 1 }{ 4 } -\frac { 9 }{ 20 } =$$
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0
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$$\displaystyle \frac { 2 }{ 15 } $$
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$$\displaystyle \frac { 2 }{ 5 } $$
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$$\displaystyle \frac { 9 }{ 20 } $$
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$$\displaystyle \frac { 5 }{ 6 } $$
Explanation
$$\displaystyle \frac { 1 }{ 3 } +\frac { 1 }{ 2 } -\frac { 5 }{ 6 } +\frac { 1 }{ 5 } +\frac { 1 }{ 4 } -\frac { 9 }{ 20 } $$
$$=\displaystyle \frac { 2 }{ 6 } +\frac { 3 }{ 6 } -\frac { 5 }{ 6 } +\frac { 4 }{ 20 } +\frac { 5 }{ 20 } -\frac { 9 }{ 20 } $$
$$=\displaystyle \frac { 5 }{ 6 } -\frac { 5 }{ 6 } +\frac { 9 }{ 20 } -\frac { 9 }{ 20 } $$
$$=0$$
Convert $$\dfrac{13}{7}$$ into a mixed fraction.
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$$\displaystyle 1\frac{6}{7}$$
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$$\displaystyle 2\frac{3}{7}$$
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$$\displaystyle 3\frac{0}{7}$$
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$$\displaystyle 3\frac{5}{7}$$
Explanation
Divide $$13$$ by $$7$$. The quotient is $$1$$ and remainder is $$6$$.
$$\therefore \dfrac{13}{7}=1\dfrac{6}{7}$$
So, option A is correct.
Which of the following is/are improper fraction(s)?
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$$\dfrac{21}{20}$$
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$$\dfrac{23}{24}$$
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$$\dfrac{14}{15}$$
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None of the above
Explanation
Here, Numerator $$>$$ denominator only in option $$A.$$
Hence, option $$A$$ is correct.
Which of the following is improper fraction?
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$$\dfrac{1}{3}$$
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$$\dfrac{4}{3}$$
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$$\dfrac{3}{5}$$
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none of the above
Explanation
A fraction in which the numerator is greater than
the denominator is called an improper fraction.
$$\therefore \dfrac{4}{3}$$ is correct.
The value of expression $$1 + \left \{\dfrac {1}{2} + \dfrac {1}{3} + \dfrac {1}{6} + \left (\dfrac {3}{4} - \dfrac {1}{3} \right )\right \}$$ is
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$$\dfrac {29}{12}$$
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$$1$$
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$$\dfrac {5}{12}$$
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$$\dfrac {1}{12}$$
Explanation
$$ 1+\left [ \dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}+\left ( \dfrac{3}{4}-\dfrac{1}{3} \right ) \right ] = 1+\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{3}{4} = \dfrac{9}{4}+\dfrac{1}{6} = \boxed{\dfrac{29}{12}} $$
Simplify: $$\displaystyle \dfrac{\dfrac{3}{5}+\dfrac{1}{3}}{\dfrac{2}{3}+\dfrac{2}{5}}$$
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$$\cfrac{3}{4}$$
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$$\cfrac{4}{5}$$
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$$\cfrac{6}{7}$$
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$$\cfrac{7}{8}$$
Explanation
First, add the fractions in the numerator and denominator:
$$\displaystyle \dfrac{\dfrac{14}{15}}{\dfrac{16}{15}} = \frac{14}{15}\times \frac{15}{16}=\dfrac{14}{16}=\frac{7}{8}$$
Alternatively, to save time, multiply each of the small fractions by 15,which is
the common denominator of all the fractions in the problem. Because you are
multiplying the numerator and the denominator of the whole complex fraction by 15,you are not changing its value:
$$\displaystyle \frac{9+5}{10+6}=\frac{14}{16}=\frac{7}{8}$$
Reduce fraction to lowest form:
$$\dfrac{100}{200}$$
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$$\dfrac{1}{2}$$
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$$\dfrac{2}{3}$$
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$$\dfrac{2}{5}$$
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$$\dfrac{2}{6}$$
Explanation
$$\dfrac{100}{200}$$
Dividing numerator and denominator by $$100$$, we get
$$\dfrac{100}{200} = \dfrac{1}{2}$$
This is the lowest form
Reduce fraction to lowest form:
$$\dfrac{12}{16}$$
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$$\dfrac{3}{4}$$
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$$\dfrac{1}{4}$$
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$$\dfrac{1}{16}$$
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$$\dfrac{2}{8}$$
Explanation
$$\dfrac{12}{16}$$
Dividing numerator and denominator by $$4$$, we get
$$\dfrac{12}{16} = \dfrac{3}{4}$$
This is the lowest form
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