MCQ Questions for Class 6 Maths Fractions Quiz 4

Reduce fraction to lowest form:

$\dfrac{144}{36}$

0%
$\dfrac{4}{1}$
0%
$\dfrac{12}{2}$
0%
$\dfrac{1}{36}$
0%
$\dfrac{4}{9}$

Explanation

$\dfrac{144}{36}$

Dividing numerator and denominator by

$12$ , we get

$\dfrac{144}{36} = \dfrac{12}{3}$

Dividing both numerator and denominator again by

$3$ , we get

$\dfrac{12}{3} = \dfrac{4}{1}$

This is the lowest form

Reduce fraction to lowest form:

$\dfrac{25}{100}$

0%
$\dfrac{25}{10}$
0%
$\dfrac{1}{4}$
0%
$\dfrac{5}{10}$
0%
$\dfrac{5}{100}$

Explanation

$\dfrac{25}{100}$

Dividing numerator and denominator by

$25$ , we get

$\dfrac{25}{100} = \dfrac{1}{4}$

This is the lowest form

Reduce fraction to lowest form:

$\dfrac{125}{625}$

0%
$\dfrac{1}{5}$
0%
$\dfrac{12}{625}$
0%
$\dfrac{5}{625}$
0%
$\dfrac{15}{25}$

Explanation

$\dfrac{125}{625}$

Dividing numerator and denominator by

$25$ , we get

$\dfrac{125}{625} = \dfrac{5}{25}$

Dividing again both numerator and denominator by

$5$ , we get

$\dfrac{5}{25} = \dfrac{1}{5}$

This is the lowest form

Reduce fraction to lowest form:

$\dfrac{81}{36}$

0%
$\dfrac{18}{2}$
0%
$\dfrac{1}{36}$
0%
$\dfrac{8}{36}$
0%
$\dfrac{9}{4}$

Explanation

$\dfrac{81}{36}$

Dividing numerator and denominator by

$9$ , we get

$\dfrac{81}{36} = \dfrac{9}{4}$

This is the lowest form

Out of these which are proper fractional numbers?

0%
$\displaystyle\frac{3}{2}$
0%
$\displaystyle\frac{2}{5}$
0%
$\displaystyle\frac1{7}$
0%
$\displaystyle\frac{8}{3}$

Explanation

Proper fractions are the one whose numerator is less than the denominator

$\dfrac{3}{2}$ and

$\dfrac{8}{3}$ , the numerator is greater than the denominator

So, they are not proper fractions

Whereas in

$\dfrac{2}{5}$ and

$\dfrac{1}{7}$ , the numerator is less than the denominator

Thus, they are proper fractions.

Hence,

$\dfrac{2}{5}$ and

$\dfrac{1}{7}$ are proper fractional numbers.

Which of these are improper fractional numbers?

0%
$\displaystyle\frac{2}{7}$
0%
$\displaystyle\frac{7}{11}$
0%
$\displaystyle\frac{13}{2}$
0%
$\displaystyle\frac{7}8$

Explanation

Improper fractions are the one who numerator is more than the denominator

$\dfrac{13}{2}$ and

$\dfrac{7}{3}$ , the numerator is greater than the denominator

So, they are not proper fractions

Whereas in

$\dfrac{2}{7}$ and

$\dfrac{7}{11}$ , the numerator is less than the denominator

Thus, they are proper fractions.

Hence,

$\dfrac{13}{2}$ and

$\dfrac{7}{3}$ are improper fractional numbers.

Simplify:

$\dfrac{5}{9}+\dfrac{7}{12}-\dfrac{5}{6}$

0%
$\dfrac{11}{36}$
0%
$\dfrac{36}{11}$
0%
$\dfrac{7}{15}$
0%
$\dfrac{41}{36}$

Explanation

$\dfrac{5}{9}+\dfrac{7}{12}-\dfrac{5}{6}=\dfrac{20+21-30}{36}=\dfrac{11}{36}$

where, 36 is the LCM of 9,6 and 12

State whether the following statement is True or False.
Simplify:

$\dfrac{5}{12}+\dfrac{7}{4}-\dfrac{1}{6}$ =

$2$ .

0%
True
0%
False

Explanation

$\dfrac{5}{12}+\dfrac{7}{4}-\dfrac{1}{6}=\dfrac{5+21-2}{12}\\=\dfrac{24}{12}=2$

Solve :-

$\dfrac{3}{8} + \dfrac{8}{3}$

0%
$\dfrac{9}{24}$
0%
$\dfrac{64}{24}$
0%
$\dfrac{73}{24}$
0%
$\dfrac{55}{24}$

Explanation

$\dfrac{3}{8}+\dfrac{8}{3}=\dfrac{9+64}{24}$ (24 is the LCM of 8 and 3)

$=\dfrac{73}{24}$

$\dfrac {3}{4} + \dfrac {5}{8}$ .

0%
$\dfrac {11}{8}$ .
0%
$\dfrac {12}{8}$ .
0%
$\dfrac {13}{8}$ .
0%
$\dfrac {23}{8}$ .

Explanation

We have,

$\,\,\,\dfrac{3}{4} + \dfrac{5}{8}$

$= \dfrac{{6 + 5}}{8}\,\,\,\left[ {L.C.M\,of\,4\& 8 = 8} \right]$

$= \dfrac{{11}}{8}$

Hence, option (A) is true.

What fraction of the figure is shaded?

0%
$\displaystyle\frac{7}{25}$
0%
$\displaystyle\frac{8}{25}$
0%
$\displaystyle\frac{9}{25}$
0%
$\displaystyle\frac{2}{5}$

Explanation

Total number of parts squares

$=25$

Number of squares which are shaded

$=9$

Fraction of the figure which is shaded

$=\dfrac{9}{25}$

Simplify:

$\displaystyle\frac{3}{8}+\frac{7}{2}+\frac{-3}{5}+\frac{9}{8}+\frac{-3}{2}+\frac{6}{5}$ .

0%
$\displaystyle\frac{-2}{3}$
0%
$\displaystyle\frac{-41}{10}$
0%
$\displaystyle\frac{39}{5}$
0%
$\displaystyle\frac{41}{10}$

Explanation

$\dfrac{3}{8} + \dfrac{7}{2}+\dfrac{-3}{5} + \dfrac{9}{8} + \dfrac{-3}{2} + \dfrac{6}{5}$

$=\dfrac{3\times 5 +7\times 5\times 4 -3\times 8+9\times 5-3\times 4\times 5+6\times 8}{8\times 5}$

$=\dfrac{164}{40}$

$=\dfrac{41}{10}$

Which fraction of one metre is

$10cm$ ?

0%
$\cfrac { 1 }{ 10 }$
0%
$\cfrac { 1 }{ 100 }$
0%
$\cfrac { 100 }{ 100 }$
0%
$\cfrac { 9 }{ 100 }$

Explanation

We Know

$1m = 100cm$

Hence,

$10\ cm$ is

$\dfrac{1}{10}$ of

$1m$

Any mixed fraction can be divided into two parts and they are:

0%
Whole number and proper fraction
0%
Whole number and improper fraction
0%
Proper fraction and improper fraction
0%
None of the above

Explanation

A Mixed Fraction is a whole number and a proper fraction combined.

for example

$4 \dfrac{2}{3}$ , where

$4$ is the whole number part and

$\dfrac{2}{3}$ is the proper fraction.

The standard form of

$\displaystyle\frac{192}{-168}$ is _________.

0%
$\displaystyle\frac{-2}{3}$
0%
$\displaystyle\frac{-8}{7}$
0%
$\displaystyle\frac{-1}{7}$
0%
$\displaystyle\frac{-6}{7}$

Explanation

the standard form of

$- \dfrac{192}{168}$

$=-\dfrac{2 \times 3\times 4\times 8}{2\times 3\times 4\times 7}$

$-\dfrac{8}{7}$

Add the fractions:

0%
$\dfrac{29}{24}$
0%
$\dfrac{12}{20}$
0%
$\dfrac{20}{24}$
0%
$\dfrac{16}{24}$

Explanation

Out of

$12$ squares,

$7$ are filled, the fraction of squares filled will be =

$\dfrac{7}{12}$

Out of

$8$ squares,

$5$ are filled ,the fraction of squares filled will be =

$\dfrac{5}{8}$

Adding them, we get

$=\dfrac{7}{12}+\dfrac{5}{8}=\dfrac{14+15}{24}=\dfrac{29}{24}$

Which number should come in place of

$\square$

$\dfrac{4}{9}$ +

$\dfrac{7}{9}$ +

$\dfrac\square{9}$ = 2

$\dfrac{1}{9}$

0%
$7$
0%
$1$
0%
$8$
0%
$9$

Explanation

We have,

$\dfrac{4}{9}$ +

$\dfrac{7}{9}$ +

$\dfrac\square{9}$ = 2

$\dfrac{1}{9}$

$\dfrac{4}{9}$ +

$\dfrac{7}{9}$ +

$\dfrac\square{9}$ =

$\dfrac{19}{9}$

$\dfrac\square{9}$ =

$\dfrac{19}{9}$ -

$\dfrac{4}{9}$ -

$\dfrac{7}{9}$

$\dfrac{\square}{9}$ =

$\dfrac{8}{9}$
Thus

$\square$ = 8

What should be placed in the empty space '?' so that the sum of fractions on each side of the triangle is same?

0%
$\dfrac{7}{15}$
0%
$\dfrac{9}{15}$
0%
$\dfrac{6}{15}$
0%
$\dfrac{8}{15}$

Explanation

We have,

$\dfrac{2}{15}$ +

$\dfrac{4}{15}$ +

$\dfrac{5}{15}$ =

$\dfrac{11}{15}$ ,

$\dfrac{1}{15}$ +

$\dfrac{5}{15}$ +

$\dfrac{5}{15}$ =

$\dfrac{11}{15}$
And

$\dfrac{1}{15}$ + ? +

$\dfrac{2}{15}$ =

$\dfrac{11}{15}$ or,

$\dfrac{1}{15}$ +

$\dfrac{8}{15}$ +

$\dfrac{2}{15}$ =

$\dfrac{11}{15}$

$\therefore$ ? =

$\dfrac{8}{15}$

In the given number line, point M represents which of the following fractional numbers?

0%
$\displaystyle\frac{2}{28}$
0%
$\displaystyle\frac{6}{5}$
0%
$\displaystyle\frac{2}{3}$
0%
$\displaystyle\frac{7}{10}$

Explanation

Point m is at

$1.2$ on the number line.

And

$\dfrac{6}{5}$ corresponds to

$1.2$

Hence the correct answer is option B

Using appropriate properties of addition, find the following:
(i)

$\cfrac{4}{5}+\cfrac{11}{7}+\cfrac{-7}{5}+\cfrac{-2}{7}$

0%
$\dfrac{24}{35}$
0%
$\dfrac{14}{35}$
0%
$\dfrac{34}{35}$
0%
$\dfrac{44}{35}$

Explanation

(i)

$\cfrac{4}{5}+\cfrac{11}{7}+\cfrac{-7}{5}+\cfrac{-2}{7}$

$\Rightarrow \cfrac{4}{5}+\cfrac{11}{7}-\cfrac{7}{5}-\cfrac{2}{7}$

$\Rightarrow$ L.C.M.

$(5,7)=35$

$\Rightarrow \cfrac{4\times 7+11\times 5-7\times 7-2\times 5}{35}$

$\Rightarrow \cfrac{28+55-49-10}{35}$

$= \cfrac {24}{35}$

Subtract the fractions:

0%
$\dfrac{2}{3}$
0%
$\dfrac{1}{3}$
0%
$\dfrac{5}{12}$
0%
$\dfrac{7}{12}$

Explanation

Out of three rectangles, two of them are filled ,the fraction filled will be

$\dfrac{2}{3}$

Out of four rectangles, one of them is filled ,the fraction filled will be

$\dfrac{1}{4}$

Subtracting them we get

$\dfrac{2}{3}-\dfrac{1}{4}=\dfrac{8-3}{12}=\dfrac{5}{12}$

Evaluate:

$\dfrac{1}{\frac{7}{9}} + \dfrac{1}{\frac{5}{3}}$

0%
$\dfrac{66}{27}$
0%
$\dfrac{66}{35}$
0%
$\dfrac{27}{66}$
0%
$\dfrac{35}{66}$

Explanation

Given

$\dfrac{1}{\frac{7}{9}}+\dfrac{1}{\frac{5}{3}}$

$=\dfrac{9}{7}+\dfrac{3}{5}$ --------[since

$\dfrac{1}{\frac{1}{x}}=x$ ]

$=\dfrac{45+21}{35}=\dfrac{66}{35}$

Option B.

Draw number line and locate the points on them. Which of the following are equidistant from the preceding points

0%
$\dfrac{1}{4} ,\dfrac{1}{2}, \dfrac{3}{4}, \dfrac{4}{4}$
0%
$\dfrac{1}{8} ,\dfrac{2}{8}, \dfrac{3}{8}, \dfrac{7}{8}$
0%
$\dfrac{2}{5} ,\dfrac{3}{5}, \dfrac{8}{5}, \dfrac{4}{5}$
0%
none of these

Explanation

R.E.F image

Difference between 2 adjacent point

$= 1/4$

1159412_1036507_ans_32230cb9747e4d408a21b59a7cdf01f7.jpg

Evaluate:

$\dfrac{3}{7} + \dfrac{3}{5} + \left( {\dfrac{{ - 2}}{3}} \right)$

0%
$\dfrac {38}{105}$
0%
$\dfrac {19}{105}$
0%
$\dfrac {38}{108}$
0%
$\dfrac {19}{108}$

Explanation

$\dfrac{3}{7} +\dfrac{3}{5} +\dfrac{-2}{3} = \dfrac{15+21}{35} +\dfrac{-2}{3} = \dfrac{36}{35} - \dfrac{2}{3} = \dfrac{108 - 70}{105} = \dfrac{38}{105}$

Find

$\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{2}{5}$

0%
$1$
0%
$2$
0%
$\dfrac{61}{60}$
0%
$\dfrac{109}{60}$

Explanation

Here, $\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{2}{5}$

$=\dfrac{40+45-24}{60}=\dfrac{61}{60}$

A proper fraction with denominator

$10$ is

0%
$\dfrac{8}{7}$
0%
$\dfrac{4}{7}$
0%
$\dfrac{6}{10}$
0%
$\dfrac{11}{7}$

Explanation

In a proper fraction numerator of the fraction is less than the denominator of the fraction. Also, the denominator must be

$10$ according to the question.

Hence, option

$C$ is correct.

The sum of the fraction

$\dfrac{1}{18}$ and

$\dfrac{1}{18}$ is given by

0%
$\dfrac{1}{18}$
0%
$\dfrac{1}{9}$
0%
$\dfrac{2}{36}$
0%
$\dfrac{36}{18}$

Which one of the following is an improper fraction

0%
$\dfrac{11}{4}$
0%
$\dfrac{3}{8}$
0%
$\dfrac{3}{4}$
0%
$\dfrac{9}{11}$

Explanation

We have,

let,

$2\dfrac{3}{4}$

$=\dfrac{(4\times 2)+3}{4}$

$=\dfrac{8+3}{4}$

$=\dfrac{11}{4}$

Hence, this is answer.

The standard from of a rational number -225 / 465 is

0%
$\frac { -4 }{ 7 }$
0%
$\frac { -6 }{ 7 }$
0%
$\frac { -6 }{ 17 }$
0%
none of these

Explanation

$\dfrac{-225}{465}=\dfrac{-45}{93}=-\dfrac{15}{31}$

Thus, option D is correct.

Subtract :

$\dfrac {51}{8}$ to

$\dfrac {23}{6}=$

0%
$\dfrac {17}{8}$
0%
$\dfrac {24}{7}$
0%
$\dfrac {34}{9}$
0%
$\dfrac {35}{8}$

Explanation

$\dfrac{51}{8} - \dfrac{23}{6}$

LCM of 6 and 8 is 24

So,

$\dfrac{153 - 92}{24}$

$\dfrac{61}{24}$

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CBSE Questions for Class 6 Maths Fractions Quiz 4 - MCQExams.com

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