Write the fraction in which (i) numerator $$= 5 $$ and denominator $$= 13$$ (ii) denominator $$= 23$$ and numerator $$ = 17 $$

$$(i)\dfrac{5}{13},(ii)\dfrac{17}{23}$$

$$(i)\dfrac{23}{17},(ii)\dfrac{5}{13}$$

$$(i)\dfrac{17}{23},(ii)\dfrac{5}{13}$$

$$(i)\dfrac{13}{5},(ii)\dfrac{23}{17}$$

MCQ Questions for Class 6 Maths Fractions Quiz 5

The improper fraction is :

0%
$\dfrac { 12 }{ 15 }$
0%
$\dfrac { 13 }{ 17 }$
0%
$\dfrac { 16 }{ 21 }$
0%
$\dfrac { 25 }{ 11 }$

Explanation

A fraction in which the numerator is greater than the denominator is an improper fraction.

(a) \frac{12}{15} :

$(a)\dfrac{12}{15}:$ Here

12 < 15 \Rightarrow

$12<15\Rightarrow$ Numerator

<

$<$ Denominator.Hence it is not an improper fraction.

(b) \frac{13}{17} :

$(b)\dfrac{13}{17}:$ Here

13 < 17 \Rightarrow

$13<17\Rightarrow$ Numerator

<

$<$ Denominator.Hence it is not an improper fraction.

(c) \frac{16}{21} :

$(c)\dfrac{16}{21}:$ Here

16 < 21 \Rightarrow

$16<21\Rightarrow$ Numerator

<

$<$ Denominator.Hence it is not an improper fraction.

(d) \frac{25}{11} :

$(d)\dfrac{25}{11}:$ Here

25 > 11 \Rightarrow

$25>11\Rightarrow$ Numerator

>

$>$ Denominator.Hence it is an improper fraction.

Simplify:

\frac{1}{- 12} + \frac{2}{15}

$\dfrac 1{-12}+\dfrac{2}{15}$

0%
$\dfrac1{20}$
0%
$\dfrac{-1}{20}$
0%
$\dfrac1{2}$
0%
none of these

Explanation

\frac{1}{- 12} + \frac{2}{15} = \frac{- 1}{12} + \frac{2}{15} = \frac{- 5 + 2 \times 4}{60} = \frac{- 5 + 8}{60} = \frac{3}{60} = \frac{1}{20}

$\dfrac{1}{-12} + \dfrac{2}{15}=\dfrac{-1}{12} + \dfrac{2}{15} = \dfrac{-5+2\times 4}{60} = \dfrac{-5+8}{60} = \dfrac{3}{60} = \dfrac{1}{20}$

Which of the following statements is correct?

0%
$3/4 < 3/5$
0%
$3/4 > 3/5$
0%
$3/4 \,and \,3/5$
0%
cannot be compared

Explanation

Between the two fractions having the same numerator, the one with the smaller denominator is the greater factor.
Hence,

3 / 4 > 3 / 5

$3 / 4 > 3 / 5$
Option (b) is correct answer

Write the fraction in which
(i) numerator

= 5

$= 5$ and denominator

= 13

$= 13$
(ii) denominator

= 23

$= 23$ and numerator

= 17

$= 17$

0%
$(i)\dfrac{23}{17},(ii)\dfrac{5}{13}$
0%
$(i)\dfrac{5}{13},(ii)\dfrac{17}{23}$
0%
$(i)\dfrac{17}{23},(ii)\dfrac{5}{13}$
0%
$(i)\dfrac{13}{5},(ii)\dfrac{23}{17}$

Explanation

We know that a fraction represents a part of a whole. Its general form is

\frac{a}{b}

$\dfrac{a}{b}$ , where

a

$a$ is called the numerator and

b

$b$ is called the denominator of the fraction.

(i)

$(i)$ Given that the numerator is

5

$5$ and denominator is

13

$13$ .

Hence, the fraction will be

\frac{5}{13}

$\dfrac{5}{13}$ .

(i i)

$(ii)$ Given that the numerator is

17

$17$ and denominator is

23

$23$ .

Hence, the fraction will be

\frac{17}{23}

$\dfrac{17}{23}$ .

State whether the following statements are true

(T)

$\left(T\right)$ or false

(F)

$\left(F\right)$ :
Every fraction can be represented by a point on a number line.

0%
True
0%
False

Multiple Questions :
Which of the following fractions is the smallest?

0%
$\dfrac{11}{7}$
0%
$\dfrac{11}{9}$
0%
$\dfrac{11}{10}$
0%
$\dfrac{11}{6}$

Explanation

\frac{11}{10}

$\dfrac{11}{10}$

(c)

$\left(c\right)$ , as it's denominator is the largest

Multiple choice.

\frac{1}{7} + \frac{4}{14}

$\dfrac{1}{7} + \dfrac{4}{14}$ is equal to

0%
$\dfrac{5}{14}$
0%
$\dfrac{5}{7}$
0%
$\dfrac{3}{14}$
0%
$\dfrac{3}{7}$

Explanation

\frac{1}{7} + \frac{4}{14}

$\dfrac{1}{7} + \dfrac{4}{14}$

(L . C . M . o f 7 a n d 14 i s 14)

$\left(L.C.M. of \,7 \, and\, 14\, is\, 14\right)$

\Rightarrow \frac{(1 \times 2) + (4 \times 1)}{14} = \frac{2 + 4}{14} = \frac{6}{14} = \frac{3}{7}

$\Rightarrow \dfrac{\left(1 \times 2\right) + \left(4 \times 1\right)}{14} = \dfrac{2 + 4}{14} = \dfrac{6}{14} = \dfrac{3}{7}$

(d)

$\left(d\right)$

Multiple Choice.
Which of the following fractions is not in the lowest form ?

0%
$\dfrac{27}{28}$
0%
$\dfrac{13}{33}$
0%
$\dfrac{39}{87}$
0%
$\dfrac{14}{9}$

Explanation

The lowest form of this can be written as

\frac{39}{87} = \frac{13}{29}

$\dfrac{39}{87} = \dfrac{13}{29}$

Multiple choice.

\frac{7}{9} - \frac{5}{18}

$\dfrac{7}{9} - \dfrac{5}{18}$ is equal to

0%
$\dfrac{2}{18}$
0%
$\dfrac{2}{9}$
0%
$\dfrac{1}{2}$
0%
$\dfrac{11}{18}$

Explanation

\frac{7}{9} - \frac{5}{18}

$\dfrac{7}{9} - \dfrac{5}{18}$

(L . C . M . o f o f 9 a n d 18 i s 18)

$\left(L.C.M. \, of \, of \,9\, and \, 18\, is 18\right)$

\Rightarrow \frac{(7 \times 2) - (5 \times 1)}{18} = \frac{14 - 5}{18} = \frac{9}{18} = \frac{1}{2}

$\Rightarrow \dfrac{\left(7 \times 2\right) - \left(5 \times 1\right)}{18} = \dfrac{14 - 5}{18} = \dfrac{9}{18} = \dfrac{1}{2}$

(c)

$\left(c\right)$

\frac{1}{5} + \frac{4}{5}

$\frac{1}{5} + \frac{4}{5}$ equal to :

0%
$\frac{4}{5}$
0%
$\frac{1}{5}$
0%
$\frac{5}{4}$
0%
$1$

In the given number line, what fraction does the dot represent?

0%
$\dfrac{1}{2}$
0%
$\dfrac{3}{2}$
0%
$\dfrac{5}{2}$
0%
$\dfrac{7}{2}$

Explanation

The dot lies exactly midway between

0

$0$ and

1,

$1,$ and divides the number line region into two equal parts. Hence, the fraction is

\frac{1}{2}

$\dfrac 12$

In given number line, what number is at

A

$A$ ?

0%
$\dfrac{1}{4}$
0%
$\dfrac{3}{4}$
0%
$\dfrac{5}{4}$
0%
$\dfrac{7}{4}$

Explanation

The number is

\frac{1}{4}

$\dfrac{1}{4}$

Which of the following number line has maximum number of marked fractions?

0%
0%
0%
0%
None of these

On the given number line letter P represents which of the following fraction ?

0%
$\dfrac{1}{4}$
0%
$\dfrac{2}{4}$
0%
$\dfrac{3}{4}$
0%
$\dfrac{4}{4}$

Explanation

It represents

\frac{3}{4}

$\dfrac{3}{4}$
1986085_1947347_ans_9084f6295d824ad1973971c4b1f066e5.png

Observe the given number line and hence answer the following.

0%
$T$ represents the fractions $\dfrac{1}{3}$
0%
$T$ represents the fractions $\dfrac{2}{3}$
0%
$Q$ represents the fractions $\dfrac{1}{3}$
0%
$Q$ represents the fractions $\dfrac{2}{3}$

Explanation

T is

\frac{1}{3}

$\cfrac{1}{3}$

Q is

\frac{2}{3}

$\cfrac{2}{3}$

On the basis of given number line, the reasonable value for

B

$B$ is ____.

0%
$\dfrac{1}{6}$
0%
$\dfrac{3}{6}$
0%
$\dfrac{5}{6}$
0%
None of these

Explanation

B =

$B=$

\frac{1}{6}

$\dfrac{1}{6}$

Which of the following number line is corresponds to the fraction represented by the shaded portion?

0%
0%
0%
0%
None of these

Explanation

2

$2$ out of

4

$4$ is shaded

∴ \frac{2}{4}

$\therefore\dfrac{2}{4}$

Identify the number represented by the given number line.

0%
$\dfrac{5}{7}$
0%
$\dfrac{5}{6}$
0%
$-\dfrac{1}{6}$
0%
$\dfrac{1}{6}$

Explanation

the fraction is

\frac{1}{6}

$\dfrac{1}{6}$

Dot on the given number line represents the fraction

\frac{17}{38}

$\dfrac{17}{38}$ .

0%
True
0%
False

Explanation

the number is

\frac{3}{2}

$\dfrac{3}{2}$

Which of the following number line is corresponds to the fraction represented by the shaded portion?

0%
0%
0%
0%
None of these

Explanation

4

$4$ out of

8

$8$ is shaded

∴ \frac{4}{8}

$\therefore \dfrac{4}{8}$

The given number line represents the fraction

\frac{7}{6}

$\dfrac{7}{6}$ .

0%
True
0%
False

Explanation

the number is

\frac{7}{6}

$\dfrac{7}{6}$

Which of the following is a proper fraction ?

0%
0%
0%
0%
All the above

Explanation

Fraction is proper if the denominator is greater than the numerator.

Fraction is improper if the numerator is greater than or equal to the denominator.

fig A =

\frac{4}{8}

$\cfrac{4}{8}$ = proper fraction

fig B =

\frac{6}{9}

$\cfrac{6}{9}$ = proper fraction

fig C =

\frac{1}{4}

$\cfrac{1}{4}$ = proper fraction

Example for a proper fraction is

0%
$\displaystyle \frac {28}{13}$
0%
$\displaystyle \frac {11}{23}$
0%
$\displaystyle \frac {16}{9}$
0%
$\displaystyle \frac {14}{3}$

Explanation

Proper fraction is a fraction in which the numerator is less than the denominator, for example

\frac{11}{23}

$\dfrac {11}{23}$ .

Hence,

\frac{11}{23}

$\dfrac {11}{23}$ is a proper fraction.

\frac{5}{8} - \frac{2}{8} =

$\displaystyle \frac {5}{8}\, -\, \displaystyle \frac {2}{8}\, =$ ...........

Explanation

Let us first consider the given subtraction of the fractions as follows:

\frac{5}{8} - \frac{2}{8} = \frac{3}{8}

$\dfrac { 5}{ 8 } -\dfrac { 2 }{ 8 }=\dfrac { 3 }{ 8 }$

The fraction

\frac{3}{8}

$\dfrac { 3 }{ 8 }$ means that we need to determine that circular object which is divided in

8

$8$ equal triangles and

3

$3$ triangles should be shaded amongst them.

Hence, the circular object with the fraction

\frac{3}{8}

$\dfrac { 3 }{ 8 }$ is shown in the figure

Which of the following is not an improper fraction?

0%
$\cfrac {4}{3}$
0%
$\cfrac {3}{2}$
0%
$\cfrac {5}{3}$
0%
$\cfrac {7}{11}$

Explanation

Fractions that are greater than

0

$0$ but less than

1

$1$ are called proper fractions.

In proper fractions, the numerator is less than the denominator.

When a fraction has a numerator that is greater than or equal to the denominator, then the fraction is an improper fraction.

An improper fraction is always

1

$1$ or greater than

1

$1$ .

Now looking at options

\frac{4}{3} = 1.33 > 1

$\dfrac{4}{3}=1.33 > 1$

\frac{3}{2} = 1.5 > 1

$\dfrac{3}{2}= 1.5 > 1$

\frac{5}{3} = 1.66 > 1

$\dfrac{5}{3}= 1.66 >1$

\frac{7}{11} = 0.63 < 1

$\dfrac{7}{11}= 0.63 < 1$

\frac{7}{11}

$\dfrac{7}{11}$ is Not a Improper fraction.

So option

D

$D$ is correct.

4 \frac{7}{11}

$\displaystyle 4\frac{7}{11}$ =

\frac{?}{11}

$\displaystyle \frac{?}{11}$

0%
$44$
0%
$7$
0%
$51$
0%
$28$

Explanation

4 \frac{7}{11} = \frac{4 \times 11 + 7}{11} = \frac{51}{11}

$\displaystyle 4 \frac{7}{11} = \frac{4 \times 11 + 7}{11} = \frac{51}{11}$

A fraction of the group of marbles below is shaded.
Which figure below is shaded to represent a fraction with the same value?

Explanation

In the given set of marbles, there are a total of

8

$8$ marbles and

6

$6$ marbles are shaded amongst them. Therefore, the ratio of shaded marbles to the total number of marbles is:

\frac{S h a d e d}{T o t a l} = \frac{6}{8} = \frac{3}{4}

$\dfrac {Shaded}{Total}=\dfrac { 6 }{ 8 } =\dfrac { 3 }{ 4 }$

(a) In the given set of squares, there are a total of

6

$6$ squares and

1

$1$ squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

\frac{S h a d e d}{T o t a l} = \frac{1}{6}

$\dfrac {Shaded}{Total}=\dfrac { 1 }{ 6 }$

Hence, the fraction

\frac{1}{6}

$\dfrac {1}{6}$ is not same as the given fraction

\frac{3}{4}

$\dfrac {3}{4}$

(b) In the given set of squares, there are a total of

6

$6$ squares and

2

$2$ squares are shaded amongst them. Therefore, the ratio of shaded squares to the total number of squares is:

\frac{S h a d e d}{T o t a l} = \frac{2}{6} = \frac{1}{3}

$\dfrac {Shaded}{Total}=\dfrac { 2 }{ 6 }=\dfrac {1}{3}$

Hence, the fraction

\frac{1}{3}

$\dfrac {1}{3}$ is not same as the given fraction

\frac{3}{4}

$\dfrac {3}{4}$

4

$4$ rectangles and

2

$2$ rectangles are shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

\frac{S h a d e d}{T o t a l} = \frac{2}{4} = \frac{1}{2}

$\dfrac {Shaded}{Total}=\dfrac { 2 }{ 4 }=\dfrac {1}{2}$

Hence, the fraction

\frac{1}{2}

$\dfrac {1}{2}$ is not same as the given fraction

\frac{3}{4}

$\dfrac {3}{4}$

(d) In the given set of rectangles, there are a total of

4

$4$ rectangles and

3

$3$ rectangles are shaded amongst them. Therefore, the ratio of shaded rectangles to the total number of rectangles is:

\frac{S h a d e d}{T o t a l} = \frac{3}{4}

$\dfrac {Shaded}{Total}=\dfrac { 3 }{ 4 }$

Hence, the fraction

\frac{3}{4}

$\dfrac {3}{4}$ is same as the given fraction

\frac{3}{4}

$\dfrac {3}{4}$ .

The difference between the greatest and least numbers of

\frac{5}{9}, \frac{1}{9}, \frac{11}{9}

$\displaystyle {\frac{5}{9},\, \frac{1}{9},\, \frac{11}{9}}$ is

0%
$\displaystyle \frac{2}{9}$
0%
$\displaystyle \frac{4}{9}$
0%
$\displaystyle \frac{10}{9}$
0%
$\displaystyle \frac{2}{3}$

Explanation

Amongst the given fractions

\frac{5}{9}, \frac{1}{9}

$\dfrac {5}{9},\dfrac {1}{9}$ and

\frac{11}{9}

$\dfrac {11}{9}$ , the smallest is

\frac{1}{9}

$\dfrac {1}{9}$ and the largest is

\frac{11}{9}

$\dfrac {11}{9}$ .

Now, consider the subtraction of the greatest and least fraction as follows:

\frac{11}{9} - \frac{1}{9} = \frac{10}{9}

$\dfrac { 11 }{ 9 } -\dfrac { 1 }{ 9 } =\dfrac { 10 }{ 9 }$

Hence, the difference between the greatest and least numbers is

\frac{10}{9}

$\dfrac {10}{9}$ .

2 - \frac{11}{39} + \frac{5}{26}

$2 - \displaystyle \frac{11}{39} + \frac{5}{26}$ = ..........

0%
$\displaystyle \frac{149}{39}$
0%
$1 + \displaystyle \frac{71}{78}$
0%
$\displaystyle \frac{149}{76}$
0%
$\displaystyle \frac{149}{98}$

Explanation

\frac{2}{1} - \frac{11}{39} + \frac{5}{26}

$\displaystyle \frac{2}{1} - \frac{11}{39} + \frac{5}{26}$

= \frac{156 - 22 + 15}{78} = \frac{149}{78} == 1 + \frac{71}{78}

$= \displaystyle \frac{156 - 22 + 15}{78} = \frac{149}{78} == 1 + \frac{71}{78}$

Example of improper fraction is ________

0%
$\displaystyle \frac{2}{3}$
0%
$\displaystyle \frac{1}{2}$
0%
$\displaystyle \frac{23}{22}$
0%
$\displaystyle \frac{11}{15}$

Explanation

When the numerator is greater than the denominator, it is called an improper fraction.

So only

\frac{23}{22}

$\dfrac{23}{22}$ is an improper fraction.

Hence, the answer is

\frac{23}{22}

$\dfrac{23}{22}$ .

CBSE Questions for Class 6 Maths Fractions Quiz 5 - MCQExams.com

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CBSE Questions for Class 6 Maths Fractions Quiz 5 - MCQExams.com

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