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CBSE Questions for Class 6 Maths Fractions Quiz 7 - MCQExams.com
CBSE
Class 6 Maths
Fractions
Quiz 7
Mark the correct answer in the following:
The ratio $$92:115$$ in its simplest form is
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$$23:25$$
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$$18:23$$
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$$3:5$$
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$$4:5$$
Explanation
Since $$HCF$$ of $$92$$ and $$115$$ is $$23$$
$$\therefore 92:115$$
$$=\dfrac{92}{115}$$
$$=\dfrac{(92\div 23)}{ (115\div 23)}$$
$$=\dfrac45$$
$$=4:5$$
Hence option (D) is correct answer.
Write $$-\dfrac{33}{55}$$ in standard form
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$$\dfrac{3}{5}$$
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$$-\dfrac{3}{5}$$
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$$-\dfrac{33}{55}$$
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$$None\ of\ these$$
Explanation
$$(B) (-3/5)$$
Because,
We write $$-\dfrac{33}{55}$$ in standard form as
$$=-\dfrac{3\times 11}{5\times 11}$$
$$=-\dfrac{3}{5}$$
Shabana has to stitch 35 dresses. So, ar she has stitched 21 dresses. What fraction of dresses has she stitched ?
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$$\dfrac{7}{9}$$
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$$\dfrac{3}{5}$$
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$$\dfrac{6}{5}$$
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$$\dfrac{3}{7}$$
Explanation
Number of dresses she had to stiches $$ = 35$$
Number of dresses she has finished $$= 21$$
$$\therefore$$ Fraction of dresses she has finished $$= \dfrac{21}{35} =\dfrac{3}{5}$$
Write $$-\dfrac{102}{119}$$ in standard form
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$$\dfrac{6}{7}$$
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$$-\dfrac{6}{7}$$
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$$\dfrac{6}{17}$$
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None of these
Explanation
To write the given fraction in standard form first write numerator and denominator as product of its prime factors and then by cancelling the common factors from we will get standard form,
$$\begin{aligned}{} - \frac{{102}}{{119}} &= - \frac{{17 \times 2\times3}}{{17 \times 7}}\\\\& = - \dfrac{6}{7}\end{aligned}$$
Hence, option $$B$$ is correct.
$$\cfrac{3}{10}+\cfrac{8}{15}$$=?
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$$\cfrac{3}{4}$$
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$$\cfrac{11}{15}$$
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$$\cfrac{5}{6}$$
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none of these
Explanation
$$\cfrac{3}{10}+\cfrac{8}{15}$$
$$LCM$$ of $$10$$ and $$15$$ is $$30$$
So, we will write these fractions with $LCM$$ as their denominator.
$$\therefore \cfrac3{10}=\cfrac{3\times 3}{10\times 3}=\cfrac{9}{30}$$
And, $$\cfrac{8}{15}=\cfrac{8\times 2}{15\times 2}=\cfrac{16}{30}$$
$$\therefore \cfrac{3}{10}+\cfrac{8}{15}=\cfrac{9}{30}+\cfrac{16}{30}$$
$$=\cfrac{9+16}{30}$$
$$=\cfrac{25}{30}$$
$$=\cfrac{5\times 5}{5\times 6}$$
$$=\cfrac{5}{6}$$
Henc. option $$C$$ is correct
On subtracting $$ \dfrac{5}{9} $$ from $$ \dfrac{19}{9} $$, the result is
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$$ \dfrac{24}{9} $$
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$$ \dfrac{14}{9} $$
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$$ \dfrac{14}{18} $$
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$$ \dfrac{14}{0} $$
Explanation
As denominators of the given fractions are the same, the difference is just subtracting their numerators and keeping the denominator same.
$$\therefore \ Difference \ of \ \dfrac{5}{9} \ and \ \dfrac{19}{9} = \dfrac{19}{9}-\dfrac{5}{9}$$
$$ = \dfrac{19-5}{9}$$
$$= \dfrac{14}{9}$$
$$\therefore \textbf{Option B is correct.}$$
Which of the following is not in the lowest form?
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$$ \dfrac{7}{5} $$
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$$ \dfrac{15}{20} $$
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$$ \dfrac{13}{33} $$
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$$ \dfrac{27}{28} $$
Explanation
Simplifying the fraction into its lowest form by dividing numerator and denominator by the HCF of numerator and denominator equal 5, we get
$$\dfrac{15}{20} = \dfrac{15÷5}{20÷5}$$
$$ = \dfrac{3}{4}$$
$$\therefore \dfrac{15}{20}$$ can be reduced into the lowest form $$\dfrac{3}{4}$$
$$\therefore \textbf{ Option B is correct.}$$
$$ \dfrac{11}{7} $$ can be expressed in the form
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$$ 7 \dfrac{1}{4} $$
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$$ 4 \dfrac{1}{7} $$
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$$ 1 \dfrac{4}{7} $$
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$$ 11 \dfrac{1}{7} $$
Explanation
Numbers of the type $$ 7 \dfrac{1}{4} , 4\dfrac{1}{7}, 1\dfrac{4}{7} , 11\dfrac{1}{7}$$…….. are called mixed fractions. A mixed fraction is a combination of whole and fractional parts.
To find a mixed fraction, divide: 11 by 7
$$ \dfrac{11}{7} = \dfrac{1 × 7 + 4}{7}$$
Where, 1 is the quotient and 4 is the remainder
A mixed fraction is written as $$Quotient \dfrac{remainder}{divisor}$$
$$\dfrac{11}{7}=1 \dfrac{4}{7}$$
$$\therefore \textbf{Option C is correct.}$$
Which of the following fraction is the greatest?
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$$ \dfrac{5}{7} $$
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$$ \dfrac{5}{6} $$
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$$ \dfrac{5}{9} $$
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$$ \dfrac{5}{8} $$
Explanation
In the above option given that , among the entire fraction with same numerator , the one with smaller denominator will be greatest.
Thus required fraction is $$ \dfrac {5}{6} $$
Sum of $$ \dfrac{4}{17} $$ and $$ \dfrac{15}{17} $$is.
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$$ \dfrac{19}{17} $$
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$$ \dfrac{11}{17} $$
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$$ \dfrac{19}{34} $$
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$$ \dfrac{2}{17} $$
Explanation
As denominators of the given fractions are same, so sum is just adding their numerators and keeping the denominator same.
$$\therefore $$ Sum of $$\dfrac{4}{17}$$ and $$\dfrac{15}{17} = \dfrac{4}{17} + \dfrac{15}{17}$$
$$ = \dfrac{4+15}{17}$$
$$ = \dfrac{19}{17}$$
$$\therefore \textbf{Option A is correct.}$$
$$ \dfrac{7}{12} + \dfrac{11}{12} = \dfrac{3}{2} $$
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True
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False
Explanation
$$ \Rightarrow \dfrac {7}{12} + \dfrac {11}{12} = \dfrac { 7 +11 }{ 12} = \dfrac { 18 \div 6}{ 12 \div 6} = \dfrac {3}{2} $$
The sum of fraction is always a fraction.
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True
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False
Explanation
Let , two fraction $$ \dfrac {17}{9} $$ and $$ \dfrac {41}{9} $$
$$ \dfrac {17}{9} + \dfrac {41}{9} = \dfrac {58}{9} $$
Also, consider the following example
$$\dfrac{3}{7}+\dfrac{11}{7}=\dfrac{14}{7}\\=\dfrac{2}{1}$$
Thus sum of two fractions is a fraction
$$ \dfrac{8}{18} - \dfrac{8}{15} = \dfrac{8}{3} $$
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True
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False
Explanation
Cross multiple the both fraction with each other
$$ \Rightarrow \dfrac {8}{18} - \dfrac {8}{15} = \dfrac { 8 \times 15 - 8 \times 18}{18 \times 15}= \dfrac {120 - 144}{270} = \dfrac { -24}{270} = -\dfrac {4}{45} $$
$$ \Rightarrow - \dfrac {4}{45} \neq \dfrac {8}{3} $$
Fraction $$ \dfrac{18}{39} $$ is in its lowest form.
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True
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False
Explanation
$$ \because \dfrac {18}{39} \Rightarrow \dfrac { 18 \div 3}{39 \div 3} = \dfrac {6}{13} $$
$$ \frac{25}{19} + \frac{6}{19} = \frac{31}{38} $$
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True
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False
Explanation
$$ \Rightarrow \dfrac {25}{19} + \dfrac {6}{19 }= \dfrac { 25 +6}{19} = \dfrac {31}{19} $$
$$ \Rightarrow \dfrac {31}{19} \neq \dfrac {31}{38} $$
State whether the following statements are true $$\left(T\right)$$ or false $$\left(F\right)$$ :
The fraction $$\dfrac{2}{3}$$ lies between $$2 \, and \, 3$$.
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True
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False
Explanation
As $$\dfrac{2}{3} =0.666$$ lies between $$ 0 \, and \, 1$$
To reduce a rational number to its standard form, we divide its numerator and denominator by their
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LCM
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HCM
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product
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multiple
Explanation
For standard form, we have to divide numerator and denominator by their highest common factor(HCF).
The standard form of $$-\dfrac{48}{60}$$ is
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$$\dfrac{48}{60}$$
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$$\dfrac{-60}{48}$$
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$$\dfrac{-4}{5}$$
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$$\dfrac{-4}{-5}$$
Explanation
For standard form, we have to divide numerator and denominator by their highest common factor(HCF).
$$\dfrac{-45÷12}{60÷12}=\dfrac{-4}{5}$$
Therefore, the standard form of $$-\dfrac{48}{60}$$ is $$\dfrac{-4}{5}.$$
State whether the following statements are true $$\left(T\right)$$ or false $$\left(F\right)$$:
A fraction in which the numerator is greater than is denominator is called an improper fraction
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True
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False
Explanation
True
A fraction in which the numerator is greater than the denominator is called an improper fraction .
Multiple Questions.
Which of the following fractions is the greatest ?
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$$\dfrac{5}{6}$$
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$$\dfrac{5}{7}$$
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$$\dfrac{5}{8}$$
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$$\dfrac{5}{9}$$
Explanation
$$\dfrac{5}{6}$$ $$\left(a\right)$$, as it's denominator is the least
Pick out the mixed fractions from these.
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$$\displaystyle \frac{3}{5}$$
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$$\displaystyle 1\frac{2}{7}$$
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$$\displaystyle\frac{7}{2}$$
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$$\displaystyle 2\frac{3}{5}$$
Which number is equal to $$\left( \cfrac { 0.1 }{ 0.01 } +\cfrac { 0.01 }{ 0.1 } \right) $$?
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$$10.1$$
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$$1.10$$
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$$1.01$$
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$$10.01$$
$$\cfrac { 8 }{ 10 } +0+\cfrac { 7 }{ 1000 } =\_ \_ \_ \_ \_ \_ \quad $$
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$$0.087$$
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$$807$$
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$$0.807$$
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$$0.870$$
Write where each of the improper fractional numbers would lie on the number lie?
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$$\displaystyle\frac{2}{7}$$
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$$\displaystyle\frac{7}{11}$$
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$$\displaystyle\frac{9}{11}$$
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$$\displaystyle\frac{13}{2}$$
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$$\displaystyle\frac{7}{3}$$
What is the value of the fraction ?
$$\dfrac { 5 }{ 8 } m+\dfrac { 3 }{ 16 } m-\dfrac { 3 }{ 4 } m$$
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$$\dfrac { 25 }{ 16 } m$$
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$$\dfrac { 11 }{ 16 } m$$
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$$\dfrac { 5 }{ 16 } m$$
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$$\dfrac { 1 }{ 16 } m$$
How many times should $$\frac{3}{{15}}$$ be added to $$\frac{3}{{15}}$$ to get the sum?
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10 times
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9 times
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15 times
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12 times
Simplify the expression$$2\frac { 1 }{ 4 } \times \frac { 5 }{ 12 } \times \frac { 1 }{ 2 } $$
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$$1\frac { 7 }{ 8 } $$
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$$5\frac { 5 }{ 2} $$
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$$4\frac { 3 }{ 3 } $$
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$$3\frac { 1 }{ 5} $$
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