MCQ Questions for Class 6 Maths Fractions Quiz 7

Mark the correct answer in the following:
The ratio

$92:115$ in its simplest form is

0%
$23:25$
0%
$18:23$
0%
$3:5$
0%
$4:5$

Explanation

Since

$HCF$ of

$92$ and

$115$ is

$23$

$\therefore 92:115$

$=\dfrac{92}{115}$

$=\dfrac{(92\div 23)}{ (115\div 23)}$

$=\dfrac45$

$=4:5$

Hence option (D) is correct answer.

Write

$-\dfrac{33}{55}$ in standard form

0%
$\dfrac{3}{5}$
0%
$-\dfrac{3}{5}$
0%
$-\dfrac{33}{55}$
0%
$None\ of\ these$

Explanation

$(B) (-3/5)$
Because,
We write

$-\dfrac{33}{55}$ in standard form as

$=-\dfrac{3\times 11}{5\times 11}$

$=-\dfrac{3}{5}$

Shabana has to stitch 35 dresses. So, ar she has stitched 21 dresses. What fraction of dresses has she stitched ?

0%
$\dfrac{7}{9}$
0%
$\dfrac{3}{5}$
0%
$\dfrac{6}{5}$
0%
$\dfrac{3}{7}$

Explanation

Number of dresses she had to stiches

$= 35$
Number of dresses she has finished

$= 21$

$\therefore$ Fraction of dresses she has finished

$= \dfrac{21}{35} =\dfrac{3}{5}$

Write

$-\dfrac{102}{119}$ in standard form

0%
$\dfrac{6}{7}$
0%
$-\dfrac{6}{7}$
0%
$\dfrac{6}{17}$
0%
None of these

Explanation

To write the given fraction in standard form first write numerator and denominator as product of its prime factors and then by cancelling the common factors from we will get standard form,

$\begin{aligned}{} - \frac{{102}}{{119}} &= - \frac{{17 \times 2\times3}}{{17 \times 7}}\\\\& = - \dfrac{6}{7}\end{aligned}$

Hence, option

$B$ is correct.

$\cfrac{3}{10}+\cfrac{8}{15}$ =?

0%
$\cfrac{3}{4}$
0%
$\cfrac{11}{15}$
0%
$\cfrac{5}{6}$
0%
none of these

Explanation

$\cfrac{3}{10}+\cfrac{8}{15}$

$LCM$ of

$10$ and

$15$ is

$30$

So, we will write these fractions with

$LCM$ $ as their denominator.

$\therefore \cfrac3{10}=\cfrac{3\times 3}{10\times 3}=\cfrac{9}{30}$

And,

$\cfrac{8}{15}=\cfrac{8\times 2}{15\times 2}=\cfrac{16}{30}$

$\therefore \cfrac{3}{10}+\cfrac{8}{15}=\cfrac{9}{30}+\cfrac{16}{30}$

$=\cfrac{9+16}{30}$

$=\cfrac{25}{30}$

$=\cfrac{5\times 5}{5\times 6}$

$=\cfrac{5}{6}$

Henc. option

$C$ is correct

On subtracting

$\dfrac{5}{9}$ from

$\dfrac{19}{9}$ , the result is

0%
$\dfrac{24}{9}$
0%
$\dfrac{14}{9}$
0%
$\dfrac{14}{18}$
0%
$\dfrac{14}{0}$

Explanation

As denominators of the given fractions are the same, the difference is just subtracting their numerators and keeping the denominator same.

$\therefore \ Difference \ of \ \dfrac{5}{9} \ and \ \dfrac{19}{9} = \dfrac{19}{9}-\dfrac{5}{9}$

$= \dfrac{19-5}{9}$

$= \dfrac{14}{9}$

$\therefore \textbf{Option B is correct.}$

Which of the following is not in the lowest form?

0%
$\dfrac{7}{5}$
0%
$\dfrac{15}{20}$
0%
$\dfrac{13}{33}$
0%
$\dfrac{27}{28}$

Explanation

Simplifying the fraction into its lowest form by dividing numerator and denominator by the HCF of numerator and denominator equal 5, we get

$\dfrac{15}{20} = \dfrac{15÷5}{20÷5}$

$= \dfrac{3}{4}$

$\therefore \dfrac{15}{20}$ can be reduced into the lowest form

$\dfrac{3}{4}$

$\therefore \textbf{ Option B is correct.}$

$\dfrac{11}{7}$ can be expressed in the form

0%
$7 \dfrac{1}{4}$
0%
$4 \dfrac{1}{7}$
0%
$1 \dfrac{4}{7}$
0%
$11 \dfrac{1}{7}$

Explanation

Numbers of the type

$7 \dfrac{1}{4} , 4\dfrac{1}{7}, 1\dfrac{4}{7} , 11\dfrac{1}{7}$ …….. are called mixed fractions. A mixed fraction is a combination of whole and fractional parts.

To find a mixed fraction, divide: 11 by 7

$\dfrac{11}{7} = \dfrac{1 × 7 + 4}{7}$

Where, 1 is the quotient and 4 is the remainder

A mixed fraction is written as

$Quotient \dfrac{remainder}{divisor}$

$\dfrac{11}{7}=1 \dfrac{4}{7}$

$\therefore \textbf{Option C is correct.}$

Which of the following fraction is the greatest?

0%
$\dfrac{5}{7}$
0%
$\dfrac{5}{6}$
0%
$\dfrac{5}{9}$
0%
$\dfrac{5}{8}$

Explanation

In the above option given that , among the entire fraction with same numerator , the one with smaller denominator will be greatest.
Thus required fraction is

$\dfrac {5}{6}$

Sum of

$\dfrac{4}{17}$ and

$\dfrac{15}{17}$ is.

0%
$\dfrac{19}{17}$
0%
$\dfrac{11}{17}$
0%
$\dfrac{19}{34}$
0%
$\dfrac{2}{17}$

Explanation

As denominators of the given fractions are same, so sum is just adding their numerators and keeping the denominator same.

$\therefore$ Sum of

$\dfrac{4}{17}$ and

$\dfrac{15}{17} = \dfrac{4}{17} + \dfrac{15}{17}$

$= \dfrac{4+15}{17}$

$= \dfrac{19}{17}$

$\therefore \textbf{Option A is correct.}$

$\dfrac{7}{12} + \dfrac{11}{12} = \dfrac{3}{2}$

0%
True
0%
False

Explanation

$\Rightarrow \dfrac {7}{12} + \dfrac {11}{12} = \dfrac { 7 +11 }{ 12} = \dfrac { 18 \div 6}{ 12 \div 6} = \dfrac {3}{2}$

The sum of fraction is always a fraction.

0%
True
0%
False

Explanation

Let , two fraction

$\dfrac {17}{9}$ and

$\dfrac {41}{9}$

$\dfrac {17}{9} + \dfrac {41}{9} = \dfrac {58}{9}$

Also, consider the following example

$\dfrac{3}{7}+\dfrac{11}{7}=\dfrac{14}{7}\\=\dfrac{2}{1}$

Thus sum of two fractions is a fraction

$\dfrac{8}{18} - \dfrac{8}{15} = \dfrac{8}{3}$

0%
True
0%
False

Explanation

Cross multiple the both fraction with each other

$\Rightarrow \dfrac {8}{18} - \dfrac {8}{15} = \dfrac { 8 \times 15 - 8 \times 18}{18 \times 15}= \dfrac {120 - 144}{270} = \dfrac { -24}{270} = -\dfrac {4}{45}$

$\Rightarrow - \dfrac {4}{45} \neq \dfrac {8}{3}$

Fraction

$\dfrac{18}{39}$ is in its lowest form.

0%
True
0%
False

Explanation

$\because \dfrac {18}{39} \Rightarrow \dfrac { 18 \div 3}{39 \div 3} = \dfrac {6}{13}$

$\frac{25}{19} + \frac{6}{19} = \frac{31}{38}$

0%
True
0%
False

Explanation

$\Rightarrow \dfrac {25}{19} + \dfrac {6}{19 }= \dfrac { 25 +6}{19} = \dfrac {31}{19}$

$\Rightarrow \dfrac {31}{19} \neq \dfrac {31}{38}$

State whether the following statements are true

$\left(T\right)$ or false

$\left(F\right)$ :
The fraction

$\dfrac{2}{3}$ lies between

$2 \, and \, 3$ .

0%
True
0%
False

Explanation

$\dfrac{2}{3} =0.666$ lies between

$0 \, and \, 1$

To reduce a rational number to its standard form, we divide its numerator and denominator by their

0%
LCM
0%
HCM
0%
product
0%
multiple

The standard form of

$-\dfrac{48}{60}$ is

0%
$\dfrac{48}{60}$
0%
$\dfrac{-60}{48}$
0%
$\dfrac{-4}{5}$
0%
$\dfrac{-4}{-5}$

Explanation

For standard form, we have to divide numerator and denominator by their highest common factor(HCF).

$\dfrac{-45÷12}{60÷12}=\dfrac{-4}{5}$
Therefore, the standard form of

$-\dfrac{48}{60}$ is

$\dfrac{-4}{5}.$

State whether the following statements are true

$\left(T\right)$ or false

$\left(F\right)$ :
A fraction in which the numerator is greater than is denominator is called an improper fraction

0%
True
0%
False

Multiple Questions.
Which of the following fractions is the greatest ?

0%
$\dfrac{5}{6}$
0%
$\dfrac{5}{7}$
0%
$\dfrac{5}{8}$
0%
$\dfrac{5}{9}$

Explanation

$\dfrac{5}{6}$

$\left(a\right)$ , as it's denominator is the least

Pick out the mixed fractions from these.

0%
$\displaystyle \frac{3}{5}$
0%
$\displaystyle 1\frac{2}{7}$
0%
$\displaystyle\frac{7}{2}$
0%
$\displaystyle 2\frac{3}{5}$

Which number is equal to

$\left( \cfrac { 0.1 }{ 0.01 } +\cfrac { 0.01 }{ 0.1 } \right)$ ?

0%
$10.1$
0%
$1.10$
0%
$1.01$
0%
$10.01$

$\cfrac { 8 }{ 10 } +0+\cfrac { 7 }{ 1000 } =\_ \_ \_ \_ \_ \_ \quad$

0%
$0.087$
0%
$807$
0%
$0.807$
0%
$0.870$

Write where each of the improper fractional numbers would lie on the number lie?

0%
$\displaystyle\frac{2}{7}$
0%
$\displaystyle\frac{7}{11}$
0%
$\displaystyle\frac{9}{11}$
0%
$\displaystyle\frac{13}{2}$
0%
$\displaystyle\frac{7}{3}$

What is the value of the fraction ?

$\dfrac { 5 }{ 8 } m+\dfrac { 3 }{ 16 } m-\dfrac { 3 }{ 4 } m$

0%
$\dfrac { 25 }{ 16 } m$
0%
$\dfrac { 11 }{ 16 } m$
0%
$\dfrac { 5 }{ 16 } m$
0%
$\dfrac { 1 }{ 16 } m$

How many times should

$\frac{3}{{15}}$ be added to

$\frac{3}{{15}}$ to get the sum?

0%
10 times
0%
9 times
0%
15 times
0%
12 times

Simplify the expression

$2\frac { 1 }{ 4 } \times \frac { 5 }{ 12 } \times \frac { 1 }{ 2 }$

0%
$1\frac { 7 }{ 8 }$
0%
$5\frac { 5 }{ 2}$
0%
$4\frac { 3 }{ 3 }$
0%
$3\frac { 1 }{ 5}$

CBSE Questions for Class 6 Maths Fractions Quiz 7 - MCQExams.com

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Fractions Quiz 7 - MCQExams.com

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.