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CBSE Questions for Class 6 Maths Knowing Our Numbers Quiz 4 - MCQExams.com
CBSE
Class 6 Maths
Knowing Our Numbers
Quiz 4
There are $$74$$ coconut cookies and $$48$$ chocolate cookies in a jar. Estimate the total number of cookies.
Round the numbers to the nearest ten and add.
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0%
$$120$$
0%
$$132$$
0%
$$130$$
0%
$$12$$
Explanation
Number of coconut cookies in jar $$=74$$
Rounding it off to nearest ten, we get $$70 (\because 4 < 5)$$
Number of chocolate cookies in jar $$=48$$
Rounding it off to nearest ten, we get $$50(\because 8>5)$$
Estimated total number of cookies $$= 70+50 = 120$$
If number read " Ten
thousand
eight hundred six." Find missing digit.
$$1\ \_,806$$
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0%
$$1$$
0%
$$10$$
0%
$$2$$
0%
$$0$$
Explanation
Number reads Ten thousand eight hundred six.
$$1$$ is at ten thousand's place, $$0$$ at thousand's place, $$8$$ at hundred's place, $$0$$ at ten's place and $$6$$ at one's place.
This written in numeral is $$10,806$$
Missing digit is $$0$$ in thousands place
Round off $$63$$ to nearest $$10$$
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0%
$$60$$
0%
$$70$$
0%
$$65$$
0%
$$63$$
Explanation
Rounding off $$63$$ to nearest $$10$$ we check if $$3$$ is less than $$5$$ or not,
As $$3 < 5$$, we round it off to $$0$$
$$\therefore 63$$ to nearest $$10$$ equals $$60$$
Convert the given Roman Numerals 'XC' and 'C' in English numeral and then find its difference.
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0%
$$100$$
0%
$$20$$
0%
$$10$$
0%
$$12$$
Explanation
In Roman numeral form,
$$C = 100$$
$$\Rightarrow XC = 100-10 = 90$$
$$\therefore$$ Difference between $$C$$ and $$XC = 100-90 = 10$$
Express $$19$$ in Roman numeral:
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$$XIX$$
0%
$$XXI$$
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$$XX$$
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$$XI$$
Explanation
In Roman numeral form,
$$10 = X$$
$$9 = IX$$
$$\Rightarrow 19 = XIX$$
Write $$14$$ in numeral form.
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$$IV$$
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$$XIV$$
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$$XVI$$
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$$XV$$
Explanation
In Roman numeral form,
$$10 = X$$
$$4 = IV$$
$$\Rightarrow 14 = XIV$$
In Roman Numeral $$C$$ has value of
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$$100$$
0%
$$50$$
0%
$$1000$$
0%
$$500$$
Explanation
In Roman numeral form,
$$100 = C$$
$$50 = L$$
$$1000 = M$$
$$500 = D$$
Find the greatest three-digit number using the digits $$7, 6, 3$$
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$$763$$
0%
$$367$$
0%
$$637$$
0%
$$376$$
Explanation
The descending order of the given numbers $$7,6,3$$ is:
$$7>6>3$$
We observe that the smallest digit is $$3$$ and the largest digit is $$7$$, so the number should start with $$7$$ and end with $$3$$.
Thus, the largest number formed is $$763$$.
Hence, the greatest three digit number formed is $$763$$.
Distance between two houses is $$40$$ m. If a new house with area $$4\times 4$$ is constructed in the middle of $$2$$ houses, then find the distance between middle house and one of the corner house.
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0%
$$20$$ m
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$$19$$ m
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$$18$$ m
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$$17$$ m
Explanation
The distance of middle point of middle house from the corner house is $$\dfrac { 40 }{ 2 } =20$$ and house to house distance will be $$\therefore 20-2=18$$
The distance between he Middle house and Corner house will be $$18$$ m.
Round off the following number to the nearest $$10$$ and $$100$$:
$$1634$$
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$$1630,1600$$
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$$1640,1730$$
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$$1740,1700$$
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$$1640,1734$$
Explanation
Rounding off $$1634$$ to nearest $$10$$ and $$100$$ we check if $$3$$ is less than $$5$$ or not,
As $$3 < 5$$, we round it off to $$0$$
$$\therefore 1634$$ to nearest $$10$$ equals $$1630$$ and
nearest $$100$$ equals $$1600$$
Form a three digits even number using the digits $$7, 6, 9.$$
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$$796$$
0%
$$769$$
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$$976$$
0%
$$967$$
Explanation
the number formed using given digits are
$$769,796,976,967,679,697$$
Even numbers are $$796,976$$
Milli starts from A and travels $$2$$ km and then come back for $$280$$ m. Then, the distance between point A and Milli is ?
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$$2$$ km
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$$1$$ km $$720$$ m
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$$1$$ km $$200$$ m
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$$1$$ km $$100$$ m
Explanation
Let us take the point of start A and point at a distant $$2$$km be B.
$$AB=2$$km=$$2000$$m
As she come back 280m , we assume that point be C.
We have to find out the distance AC
$$AC=AB-BC \therefore AC= 2000m - 280m = 1720m = 1 $$ km $$720$$ m
Find a smallest three digit number using the digits $$4,7,9$$
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0%
$$974$$
0%
$$497$$
0%
$$479$$
0%
$$794$$
Explanation
Smallest three digit number which can be formed is if we arrange them in ascending order, i.e. $$479$$
Hence $$479$$ is the smallest three digit number.
By referring the given figure, identify the distance between $$A$$ and $$B$$.
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$$4$$
0%
$$6$$
0%
$$8$$
0%
$$10$$
Explanation
For calculating the distance between $$A$$ and $$B$$, we need the sum of the distances between the points.
$$AB=1+2+1+3+1+2=10$$
Estimate $$5679-422$$ by rounding off each number to its greatest place.
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$$5257$$
0%
$$5300$$
0%
$$5400$$
0%
$$5200$$
Explanation
$$\Rightarrow$$ The given two numbers are $$5679$$ and $$422$$.
$$\Rightarrow$$
In number $$5679$$, its
tens digit is $$7$$, which is greater than $$5$$.
$$\Rightarrow$$ So, we increase the digits at hundreds place by $$1$$ and replace each one of the digits at tens and ones place by $$0$$ to round off the given number to its greatest place.
$$\therefore$$ Round off 5679 to its greatest place is $$5700$$
$$\Rightarrow$$ In number $$422$$, its
Itens digit is 2, which is less than 5.
$$\Rightarrow$$ So, we replace each of the tens and ones digits by 0 and keep the other digits as they are to round off the given number to its greatest.
$$\therefore$$
Round off 422 to its greatest place is $$400$$
$$\therefore$$ Required number = $$5700-400=5300$$
Estimate the value $$15+20+10$$
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$$45$$
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$$60$$
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$$40$$
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$$50$$
Explanation
On adding
$$15+20+10$$
$$=35+10$$
We get
$$=45$$
Hence, this is the answer.
Convert the following into grams :
$$24\ kg$$
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$$2,400\ gm$$
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$$24,000\ gm$$
0%
$$240\ gm$$
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$$24\ gm$$
Explanation
We know that
$$1$$ $$kg =1000$$ $$grams$$
$$1$$ $$gm =\dfrac1{1000}$$ $$kg$$
Given That, we have to convert $$24$$ $$kg$$ to $$gm$$
$$24$$ $$kg =24 \times 1000$$ $$gm$$
$$=24,000$$ $$gm$$
So, option $$B$$ is correct
Convert $$6045\ m$$ into kilometres and metres.
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$$6\ km\ 45\ m$$
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$$60\ km\ 45\ m$$
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$$6\ km\ 450\ m$$
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$$645\ km$$
Explanation
We know that
$$1$$ $$kilo meter =1000$$ $$m$$
$$1$$ $$m =\dfrac1{1000}$$ $$km$$
Given That, we have to convert $$6045$$ $$m$$ to $$kilometer$$
$$6045$$ $$m =\dfrac1{1000} \times 6045$$ $$km$$
$$=\dfrac{6045}{1000} $$ $$km$$
$$= 6.045$$ $$kilo meter$$
or
$$= 6$$ $$km$$ $$45 $$ $$m$$
So, Option $$A$$ is correct
Jessica walks $$2\ km$$ a day. How many meters does she walk in two days ?
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$$40$$ meters
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$$400$$ meters
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$$4000$$ meters
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$$4$$ meters
Explanation
given that
Jessica walks $$2 km$$ a day.
Total distance travelled by Jessica in TWO days is $$2 \times 2 =4km$$
We know that
$$1$$ $$kilometer =1000$$ $$m$$
$$1$$ $$m =\dfrac1{1000}$$ $$km$$
Given That, we have to convert $$4$$ $$km$$ into $$m$$
$$4$$ $$km =4 \times 1000$$ $$m$$
$$=4000$$ $$m$$
So, Option $$C $$ is correct
By referring the given figure, identify the distance between $$A$$ and $$C$$.
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0%
$$4.5$$
0%
$$5.5$$
0%
$$6.5$$
0%
$$10$$
Explanation
For calculating the distance between $$A$$ and $$C$$, we need the sum of the distances between the points.
$$AC=1+2+1+1.5=5.5$$
Rosy measured a line for his art project. It is $$400$$ millimeters long. How many centimeters is the line?
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$$40$$ cm
0%
$$4$$cm
0%
$$400$$ cm
0%
$$0.4$$ cm
Explanation
The total length of the line is $$400$$ mm.
We know that
$$1$$ $$\text{centimeter} =10$$ $$\text{millimeters}$$
$$1$$ mm $$=\dfrac1{10}$$ cm
We have to convert the $$400$$ mm to cm.
$$400$$ mm $$ =\dfrac1{10} \times 400$$ cm
$$=\dfrac{400}{10} $$ cm
$$= 40 $$ $$\text{centimeter}$$
The line is $$40$$ cm long.
So, option A is correct.
Round-off $$4353$$ to nearest $$100$$.
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0%
$$4353$$
0%
$$4350$$
0%
$$4360$$
0%
$$4400$$
Explanation
$$\Rightarrow$$ The given number is $$4353$$
$$\Rightarrow$$ In number 4353, its tens digit is 5, which is equal to 5.
$$\Rightarrow$$ So, we increase the digits at hundreds place by 1 and replace each one of the digits at tens and ones place by 0 to round off the given number to nearest to 100.
$$\therefore$$ The number becomes $$4400$$
Round-off $$76,890$$ to nearest $$10$$.
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0%
$$76,890$$
0%
$$76,880$$
0%
$$76,900$$
0%
$$77,000$$
Explanation
$$\Rightarrow$$ The given number is $$76,890$$.
$$\Rightarrow$$ In number 76890, its unit digit is $$0$$, which is already nearest to 10.
$$\Rightarrow$$ So, don't need to change anything.
$$\therefore$$ $$76,890$$ is nearest to 10.
Round-off $$3789$$ to nearest $$100$$
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0%
$$3789$$
0%
$$3790$$
0%
$$3800$$
0%
$$4000$$
Explanation
$$\Rightarrow$$ The given number is $$3789$$
$$\Rightarrow$$ In number 3789, its tens digit is 8, which is greater than 5.
$$\Rightarrow$$ So, we increase the digits at hundreds place by 1 and replace each one of the digits at tens and ones place by 0 to round off the given number to nearest to 100.
$$\therefore$$ The number becomes $$3800$$
Round-off $$52,398$$ to nearest $$1000$$.
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0%
$$52,390$$
0%
$$52,400$$
0%
$$52,000$$
0%
$$53,000$$
Explanation
$$\Rightarrow$$ The given number is $$52,398$$
$$\Rightarrow$$ In number $$52398$$, its hundred digit is $$3$$, which is less than $$5$$.
$$\Rightarrow$$ So, we replace each one of the digits at hundreds, tens and ones place by $$0$$ to round off the given number to nearest $$1000$$.
$$\therefore$$ The number obtained is $$52,000$$
Round-off $$47,897$$ to nearest $$1000$$.
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0%
$$47,897$$
0%
$$48,000$$
0%
$$47,900$$
0%
$$47,890$$
Explanation
$$\Rightarrow$$ The given number is $$47,897$$
$$\Rightarrow$$ In number 47897, its hundred digit is 8, which is greater than 5.
$$\Rightarrow$$ So, we increase the digits at thousand place by 1 and replace each one of the digits at hundreds, tens and ones place by $$0$$ to round off the given number to nearest to 1000.
$$\therefore$$ The number becomes $$48,000$$
If Tina weighs $$\dfrac{2}{3}$$times than Reema and Reema weighs $$45$$ kg, then Tina's weight is
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0%
$$45$$
0%
$$30$$
0%
$$15$$
0%
$$50$$
Explanation
Weight of Reema $$=w=45\ \ Kg$$
Weight of Tina $$=\dfrac{2}{3}w=\dfrac{2}{3}\times{45}=30\ \ Kg$$
Option $$B$$ is correct.
The number $$826315269$$ can be written in International system of numeration as
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Eight hundred twenty six million three hundred fifteen thousand two hundred sixty nine
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Eighty two crore sixty three lakh fifteen thousand two hundred and sixty nine
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Eight two six lakh three one thousand fifty two hundred sixty nine
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None of these
Explanation
$$826, 315, 269$$ in International system of numeration is written as eight hundred twenty-six million three hundred fifteen thousand two hundred sixty-nine.
The Roman numeral for $$1000$$ is
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0%
$$V$$
0%
$$L$$
0%
$$D$$
0%
$$M$$
Explanation
Roman numeral for $$1000$$ is $$M$$
$$(57)\times (-19)+5$$.
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0%
$$-1078$$
0%
$$1083$$
0%
$$1078$$
0%
$$-1083$$
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