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CBSE Questions for Class 6 Maths Mensuration Quiz 1 - MCQExams.com
CBSE
Class 6 Maths
Mensuration
Quiz 1
Perimeter of a square whose side measures $$4$$ m is:
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$$16$$ m
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$$16$$ cm
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$$4$$ m
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$$12$$m
Explanation
Perimeter of a square = $$4 \times side$$
= $$4 \times 4 = 16 m$$
Perimeter of square of sides is
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$$4*side$$
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$$\displaystyle side^{4}$$
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$$4 + side$$
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$$\displaystyle side\times side$$
Explanation
since perimeter is defined as sum of all sides
a square has 4 sides
perimeter of square = s+s+s+s
= 4s
If the length and breadth of a rectangle are doubled then its perimeter is
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tripled
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doubled
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made half
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none of these
Explanation
Perimeter of rectangle $$= 2(l+b)$$
Here length $$= l$$ and breadth $$= b$$
If the length and breadth of a rectangle are doubled.
then length $$= 2l$$ and breadth $$= 2b$$
$$\therefore$$ perimeter of new rectangle would be $$ 2(2l+2b) = 4(l+b) = 2.2(l+b)$$
$$\therefore $$ if the length and breadth of a rectangle are doubled then its perimeter is also doubled.
Option B is correct.
Perimeter of a square whose side measures $$4\ m$$ is
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$$16\ m$$
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$$16\ cm$$
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$$4\ m$$
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$$12\ m$$
Explanation
Perimeter of the square side $$ = 4 *side of square $$
Hence, perimeter of this square of side $$4\ m$$ $$ = 4 \times 4 = 16\ m $$
Perimeter of a square $$728$$ cm. Then the measure of its side is :
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$$187$$ cm
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$$182$$ cm
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$$128$$ cm
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$$185$$ cm
Explanation
Perimeter of square $$= 4 \times side$$
$$\therefore 4\, \times\, side\, =\, 728$$
$$side\, =\, \displaystyle \frac{728}{4}\, =\, 182\ m$$
Thus the measure of the side of the square is $$182$$ cm.
The perimeter of a square field whose side is $$ 4 \ m$$ is ........... m.
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$$8$$
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$$16$$
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$$12$$
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$$10$$
Explanation
Perimeter of a square is = $$4 \times side$$
Hence Perimeter of square = $$4 \times 4 = 16 m$$
The perimeter of a rectangle whose length$$(l)$$ and breadth$$(b)$$ are given, is
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$$2(l+b)$$
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$$2l+b$$
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$$2l+3b$$
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None of these
Explanation
Perimeter of a rectangle is the sum of all its four sides.
Since, two sides measure $$l$$ and the other two sides measure $$b$$ , Perimeter of a rectangle whose length$$(l)$$ and breadth$$(b)$$ are given, is $$ l + b + l + b = 2(l + b) $$
Perimeter of a square is?
Where $$s$$ is the side of the square.
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$$4s$$
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$$s^4$$
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$$4 + s$$
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$$s \times s$$
Explanation
Perimeter of square = 4s
The perimeter of the rectangle whose length = $$25$$ cm, breadth = $$15$$cm is ............ cm.
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$$40$$
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$$80$$
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$$50$$
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$$81$$
Explanation
Perimeter of a rectangle $$=$$ $$2 \times (length+breadth)$$
Hence perimeter $$=$$ $$2 \times(25+15)$$
$$=$$ $$80\ cm$$
Perimeter of a square garden is $$444$$ m. Then its side measures
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$$101$$ m
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$$111$$ cm
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$$111$$ m
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$$101$$ cm
Explanation
Given, perimeter of a square garden is $$444$$ m.
So, perimeter $$= 444 = 4$$ $$\times$$ $$side$$
$$side\, =\, \displaystyle \frac{444}{4}\, =\, 111$$ m
Then sides of a garden measures $$111$$ m.
What is formula of perimeter of square ?
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4 $$\times \,\, side^2$$
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2 $$\times$$ side
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2 $$\times \,\, side^2$$
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4 $$\times$$ side
Explanation
if side of a square is $$a$$
then perimeter of square is$$= a+a+a+a=4a$$
Hence option $$' D'$$ is the answer.
The distance covered by a farmer around a field of$$ 120 $$m length and $$80$$ m width is ........... m.
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$$200$$
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$$300$$
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$$400$$
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$$500$$
Explanation
Distance covered by the farmer = perimeter of the filed = $$2\times(length+breadth)$$
= $$2\times(120+80)$$
= $$ 2 \times 200$$
= $$ 400 m$$
The perimeter of a square is $$144 \text{ m}$$, then the side of the square is …..
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$$34 \text{ m}$$
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$$36 \text{ m}$$
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$$44 \text{ m}$$
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$$38 \text{ m}$$
Explanation
Perimeter of square $$=4\times side$$ $$=144$$
Hence, $$side $$ $$=144 \div 4$$ $$=36 \text{ m}$$
The formula for the perimeter of a rectangle is:
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$$(l + b)$$
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$$2(l + b)$$
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$$2 (l \times b)$$
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$$(l \times b)$$
Explanation
Here, $$ABCD$$ is a rectangle.
Let the length and breadth of the rectangle be $$l$$ and $$b$$ respectively.
$$\therefore \ $$ Perimeter of rectangle $$ABCD=AB+BC+CD+DA$$
$$=l+b+l+b$$
$$=2l+2b$$
$$=2(l+b)$$
$$\therefore\ $$ The formula for the perimeter of a rectangle is $$2(l+b).$$
Perimeter of square 728 cm Then the measure of its side is
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$$81$$ cm
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$$182$$ m
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$$128$$ cm
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$$182$$ cm
Explanation
We know that,
$$Peri$$$$=4*side$$
$$ 4\displaystyle \times side \displaystyle = 728$$
$$\displaystyle side= \frac{728}{4}= 182m $$
If the length of a rectangle is $$5$$ cm and the breadth of the rectangle is $$12$$ cm then find the area of the rectangle.
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$$25 cm^{2}$$
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$$60 cm^{2}$$
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$$31 cm^{2}$$
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$$12 cm^{2}$$
Explanation
Given: The length of the rectangle is $$5 cm$$ and breadth is $$12 cm$$.
Then area of rectangle $$=length \times breadth=5\times 12$$
$$=60 cm^{2}$$
If the side of a square park is $$5 $$m, then its perimeter is ............
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$$10$$ m
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$$25$$ m
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$$20$$ m
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$$15$$ m
Explanation
Perimeter of the square park = $$4\times side$$
= $$ 4*5 = 20 $$
Perimeter of the square = $$20 m$$
Perimeter of a rectangle of length $$l$$ and breadth $$b$$ is__
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$$2l+ b$$
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$$\displaystyle l\times b$$
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$$2 (l + b)$$
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$$2 (l - b)$$
Explanation
Given the length of the rectangle $$=\ l$$
the breadth
of the rectangle $$=\ b$$
perimeter of the rectangle $$=$$ sum of length of all sides of the rectangle
$$=\ l+\ b+\ l+ \ b $$
$$=2\ l+2\ b $$
$$=2(\ l+\ b) $$
$$\therefore$$
perimeter of the rectangle
$$=2(\ l+\ b) $$
Perimeter of a square whose side measures 4 m is
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16 m
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16 cm
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4 m
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12 m
Explanation
We know,
Side of square$$=a=4\ \text{m}$$
Perimeter of a square$$ = 4 \times a$$
$$= 4 \displaystyle \times 4\ \text{m} $$
$$= 16 \ \text{m}$$
The distance covered by a farmer around a rectangular field of 120 m length and 80 m width is _____ m.
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200
0%
300
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400
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500
Explanation
We know that the distance covered would be equal to the perimeter of the rectangle.
$$\therefore Distance = 2\times (l+b) = 2\times (120+80) =400m$$
If the side of a square park is 5 m then its perimeter is______
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10 m
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25 m
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20 m
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15 m
Explanation
We know,
Perimeter $$=4 \ast side $$ = $$ 4\ast 5$$ = $$20m$$
Perimeter of square garden is 444 sq m. Then its side measures:
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101 m
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111 cm
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111 m
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101 cm
Explanation
Perimeter of square garden $$\displaystyle = 444 \displaystyle = 4 \displaystyle \times side$$
$$\displaystyle side= \frac{444}{4}= 111m $$
Area of square whose side measures 13 m is
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9 m
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9 sq m
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169 sq m
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169 m
Explanation
We know,
Area of a square = $$ Side^2$$
= 13 $$\displaystyle \times $$ 13 $$\displaystyle = $$ 169 sq m
Area of a rectangle whose length is $$13$$ m and breadth is $$12$$ m is
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$$156$$ m
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$$156$$ cm
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$$156$$ sq m
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none
Explanation
Here, $$ABCD$$ is a rectangle.
$$AB,CD$$ are length of a rectangle and $$AD,BC$$ breadth of a rectangle.
$$\therefore$$ $$AB=CD=13m$$ and $$AD=BC=12m$$
$$\Rightarrow$$ Length of a rectangle $$(l)=13m$$
$$\Rightarrow$$ Breadth of a rectangle $$(b)=12m$$
$$\Rightarrow$$ Area of rectangle $$ABCD=l\times b$$
$$=13m\times 12m$$
$$=156\,m^2$$
A rectangular playground which is $$250\ m$$ long and $$20\ m$$ broad is to be fenced with wire.How much wire needed?
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$$270\ m$$
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$$230\ m$$
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$$540\ m$$
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none
Explanation
Wire needed would be perimeter of the playground:
We know,
Perimeter of rectangle: $$ 2(l+b) $$
$$=250 + 20 + 250 + 20 = 540\ m$$
A postage stamp is $$12\ mm$$ in breadth and $$20\ mm$$ in length. Find the area of stamp in $$cm^{2}$$
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$$0.24$$
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$$240$$
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$$24$$
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$$2.4$$
Explanation
As we know that,
$$1\ cm=10\ mm$$
So, $$1\ mm=0.1\ cm$$
Given:-
Length $$= 20\ mm$$
$$=20\times 0.1\ cm$$
$$=2\ cm$$
Breadth $$= 12\ mm$$
$$=12\times 0.1\ cm$$
$$=1.2\ cm$$
Area of stamp $$=$$ Length $$\times$$ Breadth
$$=2\times 1.2$$
$$=2.4\ cm^2$$
Hence, option $$D$$ is correct.
Fill in the blanks:
Perimeter of the square of side $$4$$ cm = _____ cm
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$$16$$
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$$12$$
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$$18$$
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$$8$$
Explanation
Given, Side of a square = $$4$$ cm
Perimeter of a square $$= 4 \times side$$
So, perimeter of the square $$= 4 \times 4 \ cm= 16 cm$$
Hence, the perimeter of the square is $$16\ cm$$
An athelete takes $$5$$ rounds of a rectangular park, $$50$$ m long and $$250$$ m wide. Then the total distance covered by him is ______ .
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$$150$$ m
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$$75$$ m
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$$1000$$ m
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$$3000$$ m
Explanation
Given, Breadth of the rectangular park $$b=250$$ m
and Length
$$l=50$$ m
Perimeter of the park $$=2(b+l)$$
$$=2\times (250+50)$$
$$=2\times 300$$
$$=600$$ m
Given: Athlete take $$5$$ rounds around the rectangular park
So, the total distance covered by the athlete $$=$$ $$5\times 600$$ m $$=3000$$ m
How many paving stones each measuring $$2.5\text{ m}$$ $$\times 2\text{ m}$$ are required to pave a rectangular courtyard $$30\text{ m}$$ long and $$16.5\text{ m}$$ wide?
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$$105$$
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$$89$$
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$$99$$
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$$84$$
Explanation
Area of paving stones
$$=2.5 \times 2=5 \text{ m}^2$$
Area of courtyard
$$=30 \times 16.5=495 \text{ m}^2$$
Now,
Number of paving stones required $$=$$ area of courtyard $$÷$$ area of paving stone
$$= 495 ÷ 5$$
$$= 99 $$ paving stones
So option C is the correct answer.
The figure is made up of $$2$$ rectangles
What is the perimeter of the big rectangle?
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$$11r+12$$
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$$22r+24$$
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$$11r$$
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$$11r+6$$
Explanation
$$\Rightarrow$$ Length of a big rectangle $$(l)=(7r+3+3)cm=(7r+6)cm$$
.
$$\Rightarrow$$ Breadth of a big rectangle $$(b)=(4r+3+3)cm=(4r+6)cm$$
$$\Rightarrow$$ Perimeter of big rectangle $$=2(l+b)cm$$
$$=2[(7r+6)+(4r+6)]cm$$
$$=2[11r+12]cm$$
$$=22r+24\,cm$$
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