MCQExams
0:0:1
CBSE
JEE
NTSE
NEET
Practice
Homework
×
CBSE Questions for Class 6 Maths Playing With Numbers Quiz 10 - MCQExams.com
CBSE
Class 6 Maths
Playing With Numbers
Quiz 10
Find the all the factors of
$$39$$
Report Question
0%
$$1, 3, 13, 39$$
0%
$$1, 3, 39$$
0%
$$1, 3, 13$$
0%
$$3, 13, 39$$
Using the divisibility test, determine which of the following numbers are divisible by $$2.$$
Report Question
0%
$$2144$$
0%
$$1258$$
0%
$$4336$$
0%
$$633$$
0%
$$1352$$
Explanation
For the number to be divisible by $$2$$, the last digit should be even.
$$A) 2144$$
The last digit of the given number is $$4$$, which is even. Therefore, the number is divisible by $$2.$$
$$B) 1258$$
The last digit of the given number is $$8$$, which is even. Therefore, the number is divisible by $$2.$$
$$C) 4336$$
The last digit of the given number is $$6,$$ which is even. Therefore, the number is divisible by $$2.$$
$$D) 633$$
The last digit of the given number is $$3,$$ which is odd. Therefore, the number is not divisible by $$2.$$
$$E) 1352$$
The last digit of the given number is $$2,$$ which is even. Therefore, the number is divisible by $$2.$$
Which one of the following is a common factor of $$15$$ and $$12$$.
Report Question
0%
$$2$$
0%
$$4$$
0%
$$5$$
0%
$$3$$
The least number of 4-digits which is exactly divisible by 9 is
Report Question
0%
1008
0%
1009
0%
1026
0%
1018
Explanation
We use a rule to check whether the number is divisible by 9 or not.
A number is divisible by 9 if the sum of the digits is evenly divisible by 9.
Sum of digits of $$1008$$ is $$1+0+0+8=9$$, which is divisible by 9 hence $$1008$$ is divisible by 9.
State true(T) or false(F).
The sum of primes cannot be a prime.
Report Question
0%
True
0%
False
Explanation
This statement is also false.
As consider, the numbers $$2$$ and $$3$$ then sum of $$2$$ and $$3$$ i.e. is $$5$$ is also a prime number.
State true or false:
The product of primes cannot be a prime.
Report Question
0%
True
0%
False
Explanation
The product of two primes can't be a prime because it violates the definition of the prime number as it will be divided by the prime numbers which are multiplied rather than $$1$$ and the number itself.
So the number is not prime it will become a composite number instead.
State true(T) or false(F).
Odd numbers cannot be composite.
Report Question
0%
True
0%
False
Explanation
The given statement is false.
As, consider the number $$9$$, which is an odd number and it is a composite number too.
Since $$3$$ divides the given number.
So $$3$$ is a divisor of $$9$$ other than $$1$$ and $$9$$.
Which of the following pairs are always co-primes?
Report Question
0%
Two prime numbers
0%
One prime and one composite number
0%
Two composite numbers
0%
None of the above
Explanation
Two prime numbers whose difference is two are called twin primes or we can say consecutive prime numbers are the twin primes and hence their HCF will be 1.
So answer will be A.
State true(T) or false(F).
An even number is composite.
Report Question
0%
True
0%
False
Explanation
This statement is also false.
Since $$2$$ is the number which is both even and prime.
Hence an even number may not be composite.
State true of false:
If two numbers are co-prime, at least one of them must be a prime number.
Report Question
0%
True
0%
False
Explanation
The given statement is not correct as consider the numbers $$8$$ and $$9$$ they are co-prime as HCF of them is $$1$$ but neither of them are prime.
Choose a perfect number:
Report Question
0%
$$16$$
0%
$$8$$
0%
$$24$$
0%
$$28$$
Explanation
The proper divisors of $$28$$ are $$, 2, 4, 7, 14 $$
Now their sum $$1+2+4+7+14 = 28 $$
Hence, $$28$$ is a perfect number.
The least prime is?
Report Question
0%
$$1$$
0%
$$2$$
0%
$$3$$
0%
$$5$$
Explanation
The number $$2$$ is the least prime. It is the only even prime also.
Which one of the following numbers is divisible by $$3$$?
Report Question
0%
$$27326$$
0%
$$42356$$
0%
$$73545$$
0%
$$45326$$
Explanation
We use a rule to check whether the number is divisible by 3 or not.
A number is divisible by 3 if the sum of the digits is evenly divisible by 3.
Sum of digits divisible by $$3$$
A) $$2 + 7 + 3 + 2 + 6 = 20$$
B) $$4 + 2 + 3 + 5 + 6 = 20$$
C) $$7 + 3 + 5 + 4 + 5 = 24$$
D) $$4 + 5 + 3 + 2 + 6 = 20$$
Only C) $$24$$ is divisible by $$3$$
So, option C is the correct option.
Which of the following are co-primes?
Report Question
0%
$$8, 10$$
0%
$$9, 10$$
0%
$$6, 8$$
0%
$$15, 18$$
Explanation
If the H.C.F of two numbers are $$1$$ they are said to be co-prime
Factors of $$9=1,3$$
Factors of $$10=1,2,5$$
$$\Rightarrow$$ Common factor $$=1$$
$$\therefore$$ $$(9, 10)$$ is pair of co-prime.
Which of the following number is divisible by $$4$$?
Report Question
0%
$$8675231$$
0%
$$9843212$$
0%
$$1234567$$
0%
$$543123$$
Explanation
Rule to check whether the number is divisible by 4 or not is as follows:
Suppose we have a number is $$abcde$$,
then if $$de$$ is divisible by $$4$$,
then the whole number is divisible by $$4$$.
We work on each option and use above rule to find which of the given options is divisible by 4.
A. $$8675231$$
31 is not divisible by 4. So, $$8675231$$ is also not divisible by $$4$$.
B. $$9843212$$
12 is divisible by 4. So, $$9843212$$ is also divisible by $$4$$.
$$\textbf{So, Option B is correct}$$
C. $$1234567$$
67 is not divisible by 4. So, $$1234567$$ is also not divisible by $$4$$.
D. $$543123$$
23 is not divisible by 4. So, $$543123$$ is also not divisible by $$4$$.
The total number of even prime numbers is?
Report Question
0%
$$0$$
0%
$$1$$
0%
$$2$$
0%
Unlimited
Explanation
The number $$2$$ is the only prime number, which is even.
So, the number of even primes is equal to $$1$$.
Choose the perfect number:
Report Question
0%
$$4$$
0%
$$12$$
0%
$$8$$
0%
None of these
Explanation
A perfect number is a positive integer that is equal to the sum of its positive divisors.
Mark the correct alternative of the following.
Which of the following is a prime number?
Report Question
0%
$$263$$
0%
$$361$$
0%
$$323$$
0%
$$324$$
Explanation
The option (a) is correct answer.
We know that 263 = 1 x 263 = 263 has two factors, 1 and 263
Therefore, it is a prime number
Which of the following number/s is/are divisible by $$6$$?
Report Question
0%
$$7908432$$
0%
$$68719402$$
0%
$$45982014$$
0%
None of the above
Explanation
We know that the divisibility test of $$6$$ states that a number is divisible by $$6$$ if the number is even and
the sum of the digits is divisible by
$$3$$.
As all the options are even they all are divisible by $$2.$$
Now we will check the sum of digits of numbers:
A) $$7 + 9 + 0 + 8 + 4 + 3 + 2 = 33$$
B) $$6 + 8 + 7 + 1 + 9 + 4 + 0 + 2 = 37$$
C) $$4 + 5 + 9 + 8 + 2 + 0 + 1 + 4 = 33$$
As $$33$$ is divisible by $$3$$ so A) and C) are divisible by $$3$$
So options A and C are divisible by $$6$$
option A, C are correct options
Mark the correct alternative of the following.
Which of the following numbers is prime?
Report Question
0%
$$23$$
0%
$$51$$
0%
$$38$$
0%
$$26$$
Which of the following numbers is divisible by $$8$$?
Report Question
0%
$$87653234$$
0%
$$78956042$$
0%
$$64298602$$
0%
$$98741032$$
Explanation
To check if a number is divisible by $$ 8 $$, we check if the last three digits of the number is divisible by $$ 8 $$ .
Last $$3$$ digits of the given numbers are:
A. $$234$$
B. $$042$$
C. $$602$$
D. $$032$$
We see that the only number divisible by $$8$$ is $$032$$.
$$\therefore \ 98741032$$ is the only number divisible by $$8$$.
Hence, option D is correct.
Mark the correct alternative of the following.
From the numbers $$2, 3, 4, 5, 6, 7, 8, 9$$ how many pairs of co-primes can be formed?
Report Question
0%
$$19$$
0%
$$18$$
0%
$$20$$
0%
$$21$$
Explanation
If the H.C.F of two numbers are $$1$$ they are said to be co-prime
The following are the pairs of co-prime numbers:
$$(2,3), (2,5), (2,7), (2,9), (3,4), (3,5), (3,7), (3,8), (4,5), (4,7), (4,9), (5,6), (5,7), (5,8), (5,9), (6,7), (7,8), (7,9), (8,9).$$
Number of pairs of co-prime numbers are $$19.$$
Mark the correct alternative of the following.
The smallest number which is neither prime nor composite is?
Report Question
0%
$$0$$
0%
$$1$$
0%
$$2$$
0%
$$3$$
Explanation
All primes have two positive divisors. There are only two integers that are neither composite or prime and they are 1 and 0.
The number 1 has only 1 positive divisor, itself. The number 0 has an infinite number of divisors.
1 is neither prime nor composite.
If a and b are two co-primes, then which of the following is/are true?
Report Question
0%
LCM(a, b)$$=a\times b$$
0%
HCF(a, b)$$=1$$
0%
Both (a) and (b)
0%
Neither (a) nor (b)
Explanation
Given $$a,b$$ are two co-primes then HCF $$(a,b)=1$$ [ Definition of co-primes].
We've,
LCM$$\times$$ HCF $$=a\times b$$
or, LCM $$=a\times b$$. [ Since HCF $$=1$$]
HCF of $$144$$ and $$198$$ is
Report Question
0%
$$9$$
0%
$$18$$
0%
$$6$$
0%
$$12$$
Explanation
$$\textbf{Step 1: Calculate Common Factors of 144 and 198}$$
$$\text{Prime Factors of 144 and 198 are:}$$
$$ 198 = 2 \times 3\times3 \times 11$$
$$ 144 = 2\times2\times2\times2 \times 3\times3$$
$$\Rightarrow \text{Common factor of 198 and 144 =}$$ $$(3\times 3)$$
$$\therefore\text{HCF=9}$$
$$\textbf{Thus, HCF of 198 and 144 is 9}$$
Which of the following numbers is divisible by $$3$$?
Report Question
0%
$$24357806$$
0%
$$35769812$$
0%
$$83479560$$
0%
$$3336433$$
Explanation
We use a rule to check whether the number is divisible by 3 or not.
A number is divisible by 3 if the sum of the digits is evenly divisible by 3.
Since sum of its digits $$= 8 + 3 + 4 + 7 + 9 + 5 + 6 + 0 = 42$$
$$42$$ is divisible by $$3$$
Option (c) is the correct answer
Which of the following numbers is divisible by $$4$$?
Report Question
0%
$$78653234$$
0%
$$ 98765042$$
0%
$$24689602 $$
0%
$$87941032$$
Explanation
A number is divisible by $$4$$ if the number formed
by the digits in $$\text{units and tens}$$
places
is divisible by $$4$$.
Since the number formed by tens and ones digits is divisible by $$4$$ i.e. $$32$$
$$32 \div 4 = 8$$
Option (d) is the correct answer
Which of the following number is divisible by $$8$$?
Report Question
0%
$$96354142$$
0%
$$ 37450176$$
0%
$$57064214 $$
0%
none of these
Explanation
To check if a number is divisible by $$ 8 $$, we check if the last three digits of the number is divisible by $$ 8 $$ .
Since the number formed by hundreds tens and one’s digits is divisible by $$8$$ i.e. $$176$$
$$176 \div 8 = 22$$
Option (b) is the correct answer
State whether the following statements are true (T) or false (F):
A natural number is called a composite number if it has at least one more factor other than $$ 1$$ and the number itself.
Report Question
0%
True
0%
False
Explanation
Given statement is true as a natural number is composite if it has at least one factor other than 1 and the number itself.
Which of the following are co-primes?
Report Question
0%
$$39,91$$
0%
$$161,192$$
0%
$$385,462$$
0%
none of these
Explanation
If the H.C.F of two numbers are $$1$$ they are said to be co-prime.
$$\therefore$$ $$(14,35)$$ is not pair of co-prime.
a) $$39, 91$$
Since $$39, 91$$ have common factor $$13$$
Hence $$39, 91$$ are not co-primes
b) $$161, 192$$
Since $$161, 192$$ have no common factor other than $$1$$ itself
Hence $$161, 192$$ are co-primes
c) $$385, 462$$
Since $$385, 462$$ have common factors $$7$$ and $$11$$
Hence $$385, 462$$ are not co-primes
Option (b) is the correct answer
0:0:1
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
0
Answered
0
Not Answered
0
Not Visited
Correct : 0
Incorrect : 0
Report Question
×
What's an issue?
Question is wrong
Answer is wrong
Other Reason
Want to elaborate a bit more? (optional)
Practice Class 6 Maths Quiz Questions and Answers
<
>
Support mcqexams.com by disabling your adblocker.
×
Please disable the adBlock and continue.
Thank you.
Reload page
