MCQ Questions for Class 6 Maths Playing With Numbers Quiz 8

The co-prime numbers from the following pairs, is ...........

0%
7 and 63
0%
36 and 25
0%
35 and 21
0%
63 and 81

Factor

$\displaystyle \times$ factor is equal to _______.

0%
difference
0%
multiple
0%
sum
0%
none

A number which is not a factor of every number is:

0%
$1$
0%
$2$
0%
$3$
0%
$5$

Explanation

${\textbf{Step -1: Define factor and solve}}$

${\text{A factor is a number that divides another number exactly and without leaving any remainder.}}$

${\text{Any number multiplied by 1 is that number itself, so 1 is the common factor of every number.}}$

${\Rightarrow\text{1 is the greater factor of itself and smaller factor of any other number.}}$

${\text{As we observe except 1 other numbers are not a factor of every number}}$

${\textbf{Hence, 2,3,5 are not a factor of every number}}$

Every number is a ____ and a _____ of itself

0%
factor, multiple
0%
prime, composite
0%
even, odd
0%
none

The HCF of

$136, 170$ and

$255$ is

0%
$13$
0%
$15$
0%
$17$
0%
$1$

HCF of 24, 36 and 92 is:

0%
$24$
0%
$36$
0%
$12$
0%
$4$

Explanation

The given numbers are

$24,\ 36\ and\ 92$ .

The HCF of

$24,36,92$ can be found by factorising all three numbers, as shown below:

$24= 2 \times 2 \times 2 \times 3$

$36= 2 \times 2 \times 3 \times 3$

$92 =2 \times 2 \times 23$

Now, common factors are

$2$ and

$2$

So, HCF is

$2 \times 2=4$

Hence, option D is correct.

What is the

$H.C.F.$ of

$1134,\;1344$ and

$1512$ ?

0%
$42$
0%
$64$
0%
$1344$
0%
$1512$

Explanation

$1134 = 2\times3\times3\times3\times3\times7$

$=2^1\times3^4\times7^1$

$1344 = 2\times2\times2\times2\times2\times2\times3\times7$

$=2^6\times3^1\times7^1$

$1512 = 2\times2\times2\times3\times3\times3\times7$

$=2^3\times3^3\times7^1$

$\therefore \;\;H.C.F = 2\times 3\times 7$

$= 42$

The HCF of

$12$ and

$24$ is equal to

0%
$6$
0%
$12$
0%
$24$
0%
None of the above

Explanation

$12 = 2 \times 2 \times 3$

$24 = 2 \times 2 \times 2 \times 3$

So, HCF of

$12$ and

$24$ is

$12$ .

So, option B is correct.

The

$H.C.F$ of

$18$ and

$30$ is equal to

0%
$6$
0%
$5$
0%
$4$
0%
$3$

Explanation

$18 = 2 \times 3 \times 3$

$30 = 2 \times 3 \times 5$
It can be seen that

$2\times 3$ is common for both

$18$ and

$30$ .

So,

$H.C.F$ of

$18$ and

$30$ is

$6$ .

So, option A is correct.

The HCF of

$75$ and

$15$ is equal to

0%
$12$
0%
$13$
0%
$14$
0%
$15$

Explanation

$75=5\times5\times 3$

$15=5\times3$

HCF

$=15$

The factor(s) of

$42$ is/are

0%
$1$
0%
$6$
0%
$7$
0%
All of the above

Explanation

$42 = 1\times 2\times 3 \times 7$ .

The factors are

$1, 2, 3, 6, 7, 14, 21, 42$ .

So, option D is correct.

Which of the following is divisible by

$3$ ?

0%
$18$
0%
$60$
0%
$24$
0%
All of the above

Explanation

A number is divisible by

$3$ if the sum of its digits is divisible by

$3$ .

$18 = 1 + 8 = 9$

$60 = 6 + 0 = 6$

$24 = 4 + 2 = 6$
Therefore, all are divisible by

$3$ .

So, option D is correct.

The the H.C.F of

$420$ and

$396$ is equal to

0%
$12$
0%
$13$
0%
$14$
0%
$15$

Explanation

$420 =7 \times 5\times 3\times 2\times2$

$396=2\times2 \times 3\times3\times 11$
So,

$H.C.F=2\times2 \times 3=12$
Ans- Option

$A$

The factor(s) of

$16$ is/are

0%
$2$
0%
$4$
0%
$16$
0%
all of the above

Explanation

$16 = 2\times 2\times 2\times 2$

The factors are

$1, 2, 4, 8, 16$ .

So, option D is correct.

$286$ can be expressed as

0%
$2\times 11\times 13$
0%
$3\times 11\times 13$
0%
$3\times 5\times 11$
0%
$11\times 2\times 5$

Explanation

$2\times 11\times 13 = 286$
Therefore,

$A$ is the correct answer.

Among the following numbers, how many numbers are divisible by

$4$ ?

$12, 476, 308, 201, 23, 368$

0%
$4$
0%
$3$
0%
$5$
0%
$2$

Explanation

We know the divisibility rule for

$4$ :
Check the last two digits are a multiple of

$4$ or if the last two digits are

$00$ .
Here,

$12, 476, 308$ and

$368$ are divisible by

$4$ because the last two digits are a multiple of

$4$ .

So, option A is correct.

The number of even prime factor(s) in

$1955$ is/are

0%
$5$
0%
$0$
0%
$3$
0%
$2$

Explanation

Factor of

$1955 = 5\times 17\times 23$

$1, 5, 17, 23$ are not even, so there are no even factors.
Therefore, B is the correct answer.

The number of prime factors in

$1955$ are

0%
$5$
0%
$8$
0%
$3$
0%
$2$

Explanation

Factors of

$1955 = 5\times 17\times 23$
Number of factors are

$3.$
Therefore,

$C$ is the correct answer.

How many of the following numbers are divisible by

$6$ ?

$12, 36, 45, 51, 78, 96, 57$

0%
$4$
0%
$3$
0%
$2$
0%
$1$

Explanation

We know the divisibility rule for

$6$ :
If the number is exactly divisible by both

$2$ and

$3$ , then the given number is also divisible by

$6$ .
Here,

$12, 36, 78$ and

$96$ are divisible by

$6$ , because the last digit ends with even number and sum of numbers are multiples of

$3$ .
Therefore, there are

$4$ numbers which are divisible by

$6$ .

So, option A is correct.

What is the largest

$3$ digit number exactly divisible by

$4$ ?

0%
$124$
0%
$846$
0%
$984$
0%
$996$

Explanation

We know the divisibility rule for

$4$ :
Check the last two digits are a multiple of

$4$ or if the last two digits are

$00$
Here,

$996$ is divisible by

$4$ because the last two digits are multiple of

$4$ .
So,

$996$ is the largest

$3$ digit number exactly divisible by

$4$ .

So, option D is correct.

Which of these numbers are divisible by 6?

0%
$12,453$
0%
$23,498$
0%
$56,821$
0%
$78,324$

Explanation

The divisibility rule for

$6$ states that:
If the number is exactly divisible by both

$2$ and

$3$ , then the given number is also divisible by

$6$ .
Since,

$78,324$ has the last digit ending with an even number and the sum of its digits is a multiple of

$3$ , it is divisible by both

$2$ and

$3$ , and hence, by

$6$ .

Hence, option D is correct.

How many numbers are divisible by

$8$ ?

$1264, 288, 163, 268, 2364, 1328$

0%
$3$
0%
$4$
0%
$5$
0%
$6$

Explanation

We know the divisibility rule for

$8$ :
If the last three digits are divisible by

$8$ or last three digits of the given number are zeros, then the number is divisible by

$8$ .
Here,

$1264, 288$ and

$1328$ are divisible by

$8$ , because the last three digits are divisible by

$8$ .

So, option A is correct.

Check the numbers which are divisible by

$6$ ?

0%
$23,456$
0%
$12,345$
0%
$98,765$
0%
$33,516$

Explanation

We know the divisibility rule for

$6$ :
If the number is exactly divisible by both

$2$ and

$3$ , then the given number is also divisible by

$6$ .
Here,

$3 + 3 + 5 + 1 + 6 = 18$
So,

$33516$ is divisible by

$6$ , because the last digit ends with even and the sum of digits of number is multiple of

$3$ .

So, option D is correct.

How many numbers are divisible by

$6$ ?

$234, 346, 248, 348, 684, 580, 329, 125, 376$

0%
$0$
0%
$1$
0%
$2$
0%
$3$

Explanation

We know the divisibility rule for

$6$ :
If the number is exactly divisible by both

$2$ and

$3$ then the given number is also divisible by

$6$ .
Hence,

$2 + 3 + 4 = 9$ which is divisible by

$6$ .

And

$3 + 4 + 8 = 15$ which is divisible by

$6$

And

$6 + 8 + 4 = 18$ which is divisible by

$6$ .

Because the last digits are ending with even number

and the sum of digits of all numbers are multiple of

$3$ .
So, there are

$3$ numbers

$234, 348$ and

$684$ divisible by

$6$ .

So, option D is correct.

Which of the following number is divisible by

$8$ ?

0%
$12764$
0%
$28643$
0%
$2976$
0%
$1286$

Explanation

We know the divisibility rule for

$8$ :
If the last three digits are divisible by

$8$ or last three digits of the given number are zeros, then the number is divisible by

$8$ .
Here,

$2976$ is divisible by

$8$ , because the last three digits

$296$ are divisible by

$8$ .

So, option C is correct.

Which number is divisible by

$3$ ?

0%
$68$
0%
$45$
0%
$20$
0%
$65$

Explanation

${\textbf{Step - 1 : Describe the rules of divisibility test of 3}}{\text{.}}$

${\text{As per the rule , any number can divisible by 3 if and only if}}$

${\text{ the last sum of the digits of this number is a multiple of 3,itself}}{\text{.}}$

${\textbf{Step - 2 : Check with divisibility test for the options}}{\text{. }}$

${\text{For option A, The sum of digits of 68 is}}=6+8=14{\text{.}}$

${\text{So obviously 14 is not a multiple of 3.So 68 is not divisible by 3.}}$

${\text{For option B, The sum of digits of 45 is}}=4+5=9{\text{.}}$

${\text{So 9 ist a multiple of 3.So 45 is divisible by 3.}}$

${\text{For option C, The sum of digits of 20 is}}=2+0=2{\text{.}}$

${\text{So obviously 2 is not a multiple of 3.So 20 is not divisible by 3.}}$

${\text{For option D, The sum of digits of 65 is}}=6+5=11{\text{.}}$

${\text{So obviously 11 is not a multiple of 3.So 65 is not divisible by 3.}}$

${\textbf{Hence, The number which is divisible by 3 is 45(B)}}{\text{.}}$

Which one is the largest

$5$ digit number among the given numbers which is exactly divisible by

$8$ ?

0%
$98642$
0%
$99878$
0%
$99864$
0%
$99872$

Explanation

We know the divisibility rule for

$8$ is given by:
If the last three digits of a number is divisible by

$8$ or last three digits of the given number are zeros, then the number is divisible by

$8$ .

Checking the options, we can say

$99864$ and

$99872$ both are divisible by

$8$ because the last three digits are divisible by

$8$ .

And the largest between them is

$99872$
So, option

$D$ is correct.

How many numbers are divisible by

$8$ ?

$1246, 2486, 34986, 3965, 2864, 1298, 3240$

0%
$1$
0%
$2$
0%
$3$
0%
$4$

Explanation

We know the divisibility rule for

$8$ :
If the last three digits are divisible by

$8$ or last three digits of the given number are zeros, then the number is divisible by

$8$ .
Here,

$2864$ and

$3240$ are divisible by

$8$ because the last three digits is divisible by

$8$ .
Therefore, there are

$2$ numbers divisible by

$8$ .

So, option B is correct.

Find the number that should be added to

$452671$ to make it exactly divisible by

$8$ ?

0%
$5$
0%
$6$
0%
$1$
0%
$8$

Explanation

To check if a number is divisible by

$8$ , we check if the last three digits of the number is divisible by

$8$ .

When we divide the number formed by the last three digits from the given number,

$671$ , by

$8$ , we get a remainder

$7$ .

Hence, if we add

$1$ to the number, it will be exactly divisible by

$8$ .

So, option C is correct.

Which number among the following is divisible by

$8$ ?

0%
$1,638$
0%
$2,648$
0%
$2,564$
0%
$3,126$

Explanation

We know the divisibility rule for

$8$ :
The last three digits is divisible by

$8$ or last three digits of the given number are zeroes then the number is divisible by

$8$ .
Here,

$2648$ is divisible by

$8$ , because the last three digits are multiple of

$8$ .

So, option B is correct.

CBSE Questions for Class 6 Maths Playing With Numbers Quiz 8 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Playing With Numbers Quiz 8 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

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