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CBSE Questions for Class 6 Maths Practical Geometry Quiz 4 - MCQExams.com
CBSE
Class 6 Maths
Practical Geometry
Quiz 4
In square $$\square ABCD$$, join $$AC$$. Let $$O$$ be midpoint of $$AC$$ and $$AO \perp BD$$.
Which one of following is true?
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$$AO$$ passes through $$D$$.
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$$AO$$ cuts $$CD$$ between $$C,D$$
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$$AO$$ cuts $$BC $$ in point other than $$B,C$$.
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$$AO$$ passes through $$C$$.
Explanation
According to property of square, diagonals bisect each other at right angle.
Since, AO is perpendicular to BD and O is midpoint of AC. So, AO must pass through point C.
Hence, Option D is correct.
Construct square $$ ABCD$$. Construct $$ MN$$ $$\perp\ AB$$. $$M$$ is point on $$AB$$. $$M$$ is point between $$A$$ and $$B$$.
Which one of following is true?
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Line $$MN\parallel$$ line $$DC$$
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Line $$MN\perp$$ line $$DC$$
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Line $$MN\parallel$$ line $$AC$$
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None of the above
Explanation
Consider the square $$ABCD$$ of $$4cm$$
In a square, all angles are $$90^o$$ or they are perpendicular.
By constructing $$MN$$ perpendicular to $$AB$$
$$MN$$ is also perpendicular to $$CD$$ as all sides and angles are same.
A perpendicular is drawn to a line segment $$\overline{MN}$$ at N using protractor and point P is marked on perpendicular , then_______ .
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$$\overline{MP}\perp \overline{NP}$$
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$$\overline{MN}\parallel \overline{NP}$$
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$$\overline{MN}\parallel \overline{MP}$$
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$$\overline{MN}\perp \overline{NP}$$
Explanation
$$\Rightarrow$$ In the given figure, $$\overline{MN}$$ is a line segment and at point N using protractor and point P we have drawn perpendicular.
$$\therefore$$ We can say, $$\overline{MN}\perp\overline{NP}$$
The steps of construction of an $$\angle AOB=45^{o}$$ is given in jumbled order below:
1. Place compass on intersection point.
Place ruler on start point and where arc intersects perpendicular line.
Adjust compass width to reach start point.
Construct a perpendicular line.
Draw $$45$$ degree line.
Draw an arc that intersects perpendicular line.
Which step comes last ?
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$$2$$
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$$3$$
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$$4$$
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$$5$$
Explanation
Correct sequence is :
1. Construct a perpendicular line .
2. Draw an arc that intersect the perpendicular line.
3. Adjust the compass width to reach the start point .
4.Place compass on intersection point.
5. Place ruler on start point and where the arc intersects the perpendicular line.
6. Draw $$45$$ degree line.
So the last step is $$5$$
Option $$D$$ is correct.
Using compass and ruler, draw the following angles:
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$$37.5^{\circ}$$
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$$150^{\circ}$$
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$$67\frac{1}{2}^{\circ}$$
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$$45^{\circ}$$
State whether the statement are true (T) or false (F).
Infinitely many perpendiculars can be drawn to a given ray.
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True
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False
Explanation
True.
You can draw as many perpendiculars to a ray as you want.
State whether the following statement true (T) or false (F);
It is possible to draw two bisectors of a given angle.
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True
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False
Explanation
False
Only one possible bisectors can draw of a given angle.
State whether the statement is true (T) or false (F).
Using only the two set-squares of the geometry box, an angle of $$ 15^{\circ} $$ can be drawn.
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True
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False
Explanation
Using $$ 45^{\circ}+45^{\circ}=90^{\circ} $$ set square we can draw an angle of $$ 45^{\circ} $$ and using $$ 30^{\circ}+60^{\circ}= 90^{\circ} $$ we can draw $$30^{\circ}$$. So, $$ 15^{\circ} $$ is the angle between $$ 45^{\circ}$$ and $$ 30^{\circ} $$.
State whether the statement is true (T) or false (F).
Using only the two set-squares of the geometry box, an angle of $$ 40^{\circ} $$ can be drawn.
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True
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False
Explanation
False
it is not possible to draw $$40^{\circ}$$ using only two set-squares.
(Not a multiple if $$15^{\circ}$$)
In Roman numeration, a symbol is not repeated more than three times.
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True
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False
Explanation
It is true statement.
A symbol is not repeated more than three times in representation of a number in Roman Numeration.
Write True or False. Give reason for your answer:
An angle of $$ 52.5^{\circ} $$ can be constructed.
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True
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False
Explanation
Since , $$ 52.5^{\circ} = \dfrac{1}{4} \times 210^{\circ} $$ and $$ 210^{\circ} = 180^{\circ} + 30^{\circ} $$ which can be constructed and $$ 52.5 ^{\circ} $$ is the multiple of $$ 3 $$.
Hence , the given statement is correct .
Construct the following angles using a compass.
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$${30^0}$$
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$${45^0}$$
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$${60^0}$$
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$${75^0}$$
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$${18^0}$$
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$${120^0}$$
Construction the following angles at the initial point of given ray and justify the construction
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$$90^{ \circ }$$
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$$45^{ \circ } $$
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$$50^{ \circ }$$
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None
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