MCQ Questions for Class 6 Maths Ratio And Proportion Quiz 4

What is ratio in between

$7$ months and

$7$ years?

0%
$1 : 12$
0%
$1 : 13$
0%
$1 : 14$
0%
None of these

Explanation

$7 \ Years = 84 \ Months$

$Ratio = \ \dfrac{7 \ Months}{7 \ Years}$

$\rightarrow \dfrac {7 Months}{84 Months }$

$\rightarrow \dfrac {1}{12 }$

$1 :12$

$Correct \ Answer \ is \ A$

Write True (T) or False (F) against each of the following statement

$16:24= 20:30$

0%
True
0%
False

Explanation

$\dfrac{16}{24}=\dfrac{2}{3}\\ \dfrac{20}{30}=\dfrac{2}{3}\\\ \Rightarrow\cfrac{16}{24}=\cfrac{20}{30}$

The ratio of the present ages of two brothers is

$1:2$ and

$5$ years back the ratio was

$1:3$ . What will be the ratio of their ages after

$5$ years?

0%
$1:4$
0%
$2:3$
0%
$3:5$
0%
$5:6$

Explanation

Let the age of the two brothers be

$x$ and

$y$ respectively

Given

At present

$\dfrac { x }{ y } =\dfrac { 1 }{ 2 } \Rightarrow y=2x$

Five years ago

$\dfrac { x-5 }{ y-5 } =\dfrac { 1 }{ 3 }$

substitute

$y=2x$

$\dfrac { x-5 }{ 2x-5 } =\dfrac { 1 }{ 3 }$

$\Rightarrow 3x-15=2x-5\Rightarrow x=10$

$\Rightarrow y=2x=2(10)=20$

$\therefore\ x=10$ and

$y=20$

Required ratio:

$\displaystyle \frac { x+5 }{ y+5 } =\frac { 10+5 }{ 20+5 } =\frac { 15 }{ 25 } =\frac { 3 }{ 5 }$

Hence option (C) is the correct option.

$a\neq b$ , then the ratio

$a:b$ is different from the ratio

$b:a$ .

0%
True
0%
False

Explanation

$a\neq b$ , then the ratio

$a:b$ is different from the ratio

$b:a$ . True

The ratio of

$150\ g$ to

$2\ kg$ is

0%
$75:1$
0%
$40:3$
0%
$3:40$
0%
$3:200$

Explanation

We have,

$150\ g$ to

$2\ kg$

$=150\ g:2\times 1000\ g$

$=150\ g:2000\ g$
Divide both term by

$50$

$=\dfrac{150}{50}:\dfrac{2000}{50}$

$=3:40$

State whether the given statement is true (T) or false (F):

$5\ kg:7.5\ kg=₹7.50:₹5$

0%
True
0%
False

Explanation

Given,

$5\ kg:7.5\ kg=₹7.50:₹5$

Here we have,

$5\ kg:7.5\ kg=\dfrac5{7.5}=\dfrac{50}{75}=\dfrac23$ and

$₹7.50:₹5=\dfrac{7.5}5=\dfrac{75}{50}=\dfrac32$

Clearly,

$\dfrac23\neq\dfrac32$

$\therefore$

$5\ kg:7.5\ kg\neq ₹7.50:₹5$

Hence, the given statement is false.

State whether the given statement is true (T) or false (F):

$27cm:57cm=18cm:38cm$

0%
True
0%
False

Explanation

Given,

$27\ cm:57\ cm=18\ cm:38\ cm$

Here,

$LHS=27\ cm:57\ cm=\dfrac{27}{57}=\dfrac{27\div3}{57\div3}=\dfrac9{19}$

And,

$RHS =18\ cm:38\ cm=\dfrac{18}{38}=\dfrac{18\div2}{38\div2}=\dfrac9{19}$

$\therefore LHS=RHS$

Hence, the given statement is true.

State whether the given statement is true (T) or false (F):
The ratio

$5:4$ is different from the ratio

$4:5$

0%
True
0%
False

Explanation

Ratio

$5: 4$ can be written as

$\frac{5}{4}$
Ratio

$4: 5$ can be written as

$\frac{4}{5}$
Fractions

$\frac{5}{4}$ and

$\frac{4}{5}$ are different.
So the ratio

$5: 4$ is different from the ratio

$4: 5$ .

$\therefore \textbf{The given statement is True.}$

State whether the given statement is true (T) or false (F):
The two terms of a ratio can be in two different units.

0%
True
0%
False

State whether the given statement is true (T) or false (F):

$25\ kg:20\ g=50 \ kg:40\ g$

0%
True
0%
False

Explanation

Converting the rations into same units:
(i)

$25 \mathrm{~kg}: 20 \mathrm{~g}=\frac{25 \mathrm{~kg}}{20 \mathrm{~g}}=\frac{25 \times 1000 \mathrm{~g}}{20 \mathrm{~g}} \quad[\because 1 \mathrm{Kg}=1000 \mathrm{gm}]$

$=\frac{1250}{1}=1250: 1$
(ii)

$\begin{aligned} 50 \mathrm{~kg}: 40 \mathrm{~g}=\frac{50 \mathrm{~kg}}{40 \mathrm{~g}} &=\frac{50 \times 1000 \mathrm{~g}}{40 \mathrm{~g}} \\ &=\frac{1250}{1}=1250: 1 \end{aligned}$

After simplifying, the ratios resulted in the same ratio.

$\therefore 25 \mathrm{~kg}: 20 \mathrm{~g}=50 \mathrm{~kg}: 40 \mathrm{~g}$

$\textbf{The given statement is true.}$

Select the appropriate alternative answer for the following question.
What is the ratio of

$1 mm$ to

$1 cm$ ?

0%
$1:100$
0%
$10:1$
0%
$1:10$
0%
$100:1$

Explanation

We know that:

$1cm=10mm$

Therefore,

Ratio of

$1mm$ to

$1cm = 1mm:1cm$

$=1mm:10mm$

$=1:10$

Raju is twice as good as Vijay. Together they can finish the work in

$14$ days. In how many days Vijay alone can do the same work?

0%
$16$ days
0%
$21$ days
0%
$32$ days
0%
$42$ days

State if the below inequality is true or false

$\displaystyle\,2\,\frac{1}{2}\,:\,3\,\frac{1}{3}\,\, > \,\,3.5\,:\,4.5$

0%
True
0%
False

Explanation

Converting the given ratios into fractions we get,

$2 \cfrac {1}{2} : 3 \cfrac { 1 } {3} = \cfrac { 2 \cfrac {1}{2} } { 3 \cfrac { 1 } {3}} = \cfrac {\cfrac {5}{2}}{\cfrac {10}{3}} = \cfrac {3}{4}$

$3.5: 4.5 = \cfrac { \cfrac {7}{2} } { \cfrac { 9 } {2}} = \cfrac {7}{9}$

LCM of $4, 9 = 36$
Converting the fractions in like fractions with denominator $36$ , we get
$\cfrac {3}{4} = \cfrac {3 \times 9}{4 \times 9} = \cfrac {27}{36}$

$\cfrac {7}{9} = \cfrac {7 \times 4}{9 \times 4 } = \cfrac {28}{36}$
Comparing these fractions, $\cfrac {28}{36} > \cfrac {27}{36}$
Hence, $3.5 : 4.5$ is greater.

The ratio of

$96$ m and

$72$ m is:

0%
$3 : 4$
0%
$4 : 3$
0%
$2 : 1$
0%
$4 : 1$

Explanation

$96 m : 72 m = 96 : 72 = 4 : 3$

$\displaystyle M=a\left ( m+n \right )$ and

$\displaystyle N=b(m-n)$ then the value of

$\displaystyle \left ( \frac{M}{a}+\frac{N}{b} \right )\div \left ( \frac{M}{a}-\frac{N}{b} \right )$ is :

0%
$\displaystyle \frac{m}{n}$
0%
$\frac{n}{m}$
0%
1
0%
$\frac{1}{2}$

Explanation

$\displaystyle \frac{M}{a}=m+n;\frac{N}{b}=m-n$

$\displaystyle \therefore \left ( \frac{M}{a}+\frac{N}{b} \right )\div \left ( \frac{M}{a}-\frac{N}{b} \right )=2m\div 2n=\frac{m}{n}$

In an office the working hours are 9:30 AM to 4:30 PM and in between 20 minutes are spent on lunch Find the ratio of office hours to the time spent for lunch-

0%
$21:1$
0%
$1:14$
0%
$7:30$
0%
$30:7$

Explanation

Total time in office

$= 9:30\ to\ 4:30 = 7 hours$

Ratio of two quantities can be found when they are of same units.

So,

$7 \ hours = 7 \times 60 = 420 \ minutes$
Hence, ratio

$= \dfrac {420 \ min }{20\ min } = 21:1$

The ratio

$15:75$ in its simplest form is

0%
$1:8$
0%
$1:5$
0%
$7:1$
0%
$1:7$

Explanation

Given ratio is

$15:75$

$\Rightarrow \cfrac{15}{75} =\cfrac{1 \times15}{5 \times15}=\cfrac{1}{5}$

so, the simplest form is

$1:5$

Find the ratio of the following :
The speed of cycle is

$15$ km per hour to the speed of scooter

$30$ km per hour.

0%
$1:2$
0%
$1:4$
0%
$2:1$
0%
$4:1$

Explanation

Speed of cycle which is

$15km/hr$ to the speed of scooter which is

$30km/hr = \cfrac {15 km}{30 km} =\cfrac 12 = 1:2$

State true or false.

$8 : 15 > 11 : 20$

0%
True
0%
False

Explanation

Converting the given ratios into fractions we get,

$\cfrac {8}{15} ; \cfrac {11}{20}$

LCM of

$15, 20 = 60$

Converting the fractions in like fractions with denominator

$60$ , we get

$\cfrac {8}{15} = \cfrac {8 \times 4}{15 \times 4 } = \cfrac {32}{60}$

$\cfrac {11}{20} = \cfrac {11 \times 3}{20 \times 3 } = \cfrac {33}{60}$

Comparing these fractions,

$\cfrac {33}{60} > \cfrac {32}{60}$
Hence,

$11: 20 > 8:15$

The ratio of 4kgs and 16kgs is

0%
$1:\sqrt{2}$
0%
$1: 2$
0%
$1: 4$
0%
$1:8$

Explanation

The ratio gets divided as,

$\dfrac{4}{16}$ =

$\dfrac{1}{4}$

A basket has 30 items, find the number of items that two persons A and B gets if the the items are divided in the ratio of 2:3.

0%
14 and 16
0%
12 and 18
0%
9 and 21
0%
none of these

Explanation

Since the ratio is

$2:3$ ,

$\displaystyle 30\times \frac{2}{5}=12$

$\displaystyle 30\times \frac{3}{5}=18$

So person A will get

$12$ and person B will get

$18$ items

In an office, the working hours are

$10:30\text{ AM}$ to

$5:30\text{ PM}$ and in between

$30\text{ min.}$ are spent on lunch. Find the ratio of office hours to the time spent for lunch.

0%
$7:30$
0%
$1:14$
0%
$14:1$
0%
$30:7$

Explanation

Office hours are from

$10:30\text{ AM}$ to

$5:30\text{ PM}$ i.e.

$7\text{ hrs}$ that is equal to

$420 \text{ min.}$

And, the lunch time is equal to

$30\text{ min.}$

So, the required ratio will be,

$\Rightarrow 420:30$

$\Rightarrow 14:1$

The antecedent and consequent of a ratio .............. interchanged unless there is a change in the given statements.

0%
Can be
0%
Cannot be
0%
Sometime
0%
None of these

Arrange the following ratios in decreasing order.

$2:3,\,3:4,\,5:6\ and$

$1:5$

0%
$2:3>3:4>5:6>1:5$
0%
$3:4>5:6>2:3>1:5$
0%
$1:5>2:3>3:4>5:6$
0%
$5:6>3:4>2:3>1:5$

Explanation

Given ratios are

$\dfrac{2}{3},\,\dfrac{3}{4},\,\dfrac{5}{6},\,\dfrac{1}{5}$

The L.C.M of

$3,\,4,\,6,\,5$ is

$2\times2\times3\times5=60$

Now,

$\dfrac{2}{3}=\dfrac{2\times20}{3\times20}=\dfrac{40}{60}$

$\dfrac{3}{4}=\dfrac{3\times15}{4\times15}=\dfrac{45}{60}$

$\dfrac{5}{6}=\dfrac{5\times10}{6\times10}=\dfrac{50}{60}$

$\dfrac{1}{5}=\dfrac{1\times12}{5\times12}=\dfrac{12}{60}$

Clearly,

$50/60 > 45/60 > 40/60 > 12/60$

Therefore,

$\dfrac{5}{6} > \dfrac{3}{4} > \dfrac{2}{3} > \dfrac{1}{5}$
So,

$5:6 > 3:4 > 2:3 > 1:5$

If,

$13$ is the antecedent and

$12$ is the consequent, then the ratio is ........

0%
$13 : 12$
0%
$12 : 13$
0%
$1 : 3$
0%
$3 : 2$

Explanation

In a ratio, the first term is called the antecedent and the second term is called the consequent. Therefore, the required ratio having

$13$ as the antecedent and

$12$ as the consequent is

$13 : 12$ .

In a ratio

$b : a$ ,

$a$ is called ______

0%
Antecedent
0%
Consequent
0%
Constant
0%
None of the above

Explanation

In a ratio, the second term is called consequent. Thus, in $b:a$ , $a$ is called the consequent.

$b:a\longrightarrow \\ \downarrow$ Consequent

Antecedent

The ratio of heights of two people A and B whose height are

$6 ft$ and

$4 ft$ is

$6 : 4$ . Here,

$6$ is called ______

0%
Constant
0%
Consequent
0%
Antecedent
0%
None of these

Explanation

In a ratio, the first term is called the antecedent. Therefore, in

$6 : 4$ ,

$6$ is called the antecedent.

In a ratio

$3:4$ , if the antecedent is

$12$ , then the consequent is

0%
$9$
0%
$16$
0%
$20$
0%
$24$

Explanation

$\dfrac{3}{4}=\dfrac{12}{x}\;$

$\Rightarrow\;3x=48$

$x=16$

$7$ is the consequent and

$15$ is the antecedent of a ratio, then the ratio is ____

0%
$7 : 15$
0%
$15 : 7$
0%
$7 : 5$
0%
$5 : 7$

Explanation

In a ratio, the first term is called the antecedent and the second term is called the consequent. Therefore, the given ratio is

$15 : 7$ .

$4 : 9$ , _________ is the antecedent

0%
$1$
0%
$4$
0%
$9$
0%
$4$ and $9$

Explanation

$\dfrac { a }{ b } =a:b\\ a\rightarrow Antecedent\\ b\rightarrow Consequent\\ 4:9\\$

$4$ is the Antecedent

CBSE Questions for Class 6 Maths Ratio And Proportion Quiz 4 - MCQExams.com

In a ratio, the second term is called consequent. Thus, in $b:a$ , $a$ is called the consequent.

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Ratio And Proportion Quiz 4 - MCQExams.com

In a ratio, the second term is called consequent. Thus, in b:ab:a, aa is called the consequent.

0:0:1

Practice Class 6 Maths Quiz Questions and Answers

Support mcqexams.com by disabling your adblocker.

In a ratio, the second term is called consequent. Thus, in $b:a$ , $a$ is called the consequent.