MCQ Questions for Class 6 Maths Playing With Numbers Quiz 3

Which of the following is not a composite number ?

0%
$4$
0%
$6$
0%
$7$
0%
$10$

Which list shows the first five multiples of

$2$ ?

0%
$2, 3, 4, 5, 6$
0%
$2, 4, 6, 8, 10$
0%
$2, 20, 200, 2,000, 20,000$
0%
$2, 22, 222, 2,222, 22,222$

Explanation

The first

$5$ multiples of

$2$ are as follows,

$2×1=2$

$2×2=4$

$2×3=6$

$2×4=8$

$2×5=10$

Option B has the desired list.

So option B is the correct answer.

Which of the following is not a composite number?

0%
5
0%
6
0%
7
0%
8

Smallest

$6$ digit number divisible by

$6$ is __________.

0%
$100000$
0%
$100002$
0%
$100003$
0%
$100004$

Explanation

We know that the divisibility test of

$6$ states that a number is divisible by

$6$ if the number is even and the sum of the digits is divisible by

$3.$ Hence,

$100002$ is the smallest number divisible by

$6$ as it is even and the sum of digits

$1+0+0+0+0+2=3.$

So, option

$B$ is correct.

The number which have more than two factors is called _____.

0%
Even
0%
Prime
0%
Odd
0%
None of these

The number of prime numbers between

$0$ and

$20$ is

0%
$7$
0%
$8$
0%
$6$
0%
$9$

Explanation

We know that, a prime number is a number having exactly two factors,

$1$ and the number itself.

Hence, the prime numbers between

$0$ and

$20$ are

$2, 3, 5, 7, 11, 13, 17$ and

$19$

$\therefore \$ The number of prime numbers between

$0$ and

$20$ is

$8.$

Numbers ending with

$0$ or

$5$ are divisible by ___________.

0%
$10$
0%
$2$
0%
$5$
0%
$6$

Sum of first three prime numbers which end at 3 is:

0%
20
0%
16
0%
39
0%
40

Explanation

First three prime numbers which end with

$3$ are

$3,13,23$ .

$Sum=3+13+23=39$

Which of the following pairs are co-prime?

0%
348 & 296
0%
59 & 97
0%
3025 & 4920
0%
None

$1$ is a ............ of every prime number.

0%
factor
0%
multiple
0%
both factor and multiple
0%
none of these

Explanation

$1$ is a factor of prime number.

Highest common factor of

$10$ and

$100$ is

0%
$10$
0%
$100$
0%
$5$
0%
All of the above

Explanation

First we will write

$10$ and

$100$ as product of its prime factors,

$10=5\times 2$

$100=5\times 2\times 5\times 2$

So, from above we can observe that

$5$ and

$2$ is common factors,

$HCF (10,100)= 5\times 2$

$=10$

So, option

$A$ is correct.

$21$ is not co-prime with

0%
$3$
0%
$7$
0%
$22$
0%
$24$

Explanation

If the H.C.F of two numbers are

$1$ they are said to be co-prime.

$21 = 3\times 7$

$24 = 8\times 3$

$22 = 1\times 11$

$21$ and

$24$ have common factors

$1$ and

$3$ .

So, options

$A, B$ and

$D$ are correct.

Which of the following numbers are divisible by

$2$ ?

0%
$64$
0%
$16$
0%
$32$
0%
All of the above

Explanation

Divisibility by 2:

If the number contains an even number (0, 2, 4, 6, 8) in the units place,

then the number is completely divisible by

$2$ .

All the options given here are even numbers i.e

$64$ ends with

$4$ ,

$16$ with

$6$ and

$32$ ends with

$2$

So, option D is correct.

Which of the following numbers are divisible by

$2$ ?

0%
$63$
0%
$62$
0%
$65$
0%
$61$

Explanation

For a number to be divisible by

$2$ , it must contain an even digit in its unit place.

Since,

$62$ ends with

$2$ .

Therefore, it is divisible by

$2$ .

So, option B is correct.

The factor(s) of

$59$ is/are

0%
$1$
0%
$59$
0%
$2$
0%
None of these

Explanation

$59 = 1\times 59$

$1$ and

$59$ are the factors.

So, options A and B are correct.

Identify co-prime numbers.

0%
$(2, 3)$
0%
$(3, 5)$
0%
$(5, 7)$
0%
All of the above

Explanation

$(2, 3)$ has

$1$ factor in common

$(3, 5)$ has

$1$ factor in common

$(5, 7)$ has

$1$ factor in common

So, option D is correct.

Co-prime numbers

0%
have two factors in common
0%
have one factor in common
0%
have three factor in common
0%
none of these

If a number

$N$ is divisible by

$2$ , then which of the following numbers can be at it's units' position.

0%
$0$
0%
$1$
0%
$2$
0%
$4$

Explanation

If N is a number divisible by

$2$ ,

then the digit in the units place of N should be either

$0, 2, 4, 6$ or

$8.$

So, options A, C and D are correct.

The composite numbers _________ .

0%
has atleast one factors other than itself and 1
0%
has no factor other than 1
0%
only A
0%
none

$21$ is co-prime with

0%
$3$
0%
$7$
0%
$22$
0%
all of the above

Explanation

$21 = 3\times 7\times 1$

$22 = 1\times 2\times 11$
Only

$1$ is common, so option

$C$ is correct.

Which of the following numbers are divisible by

$5$ ?

0%
$10$
0%
$100$
0%
$1000$
0%
All of the above

Explanation

A number is divisible by

$5$ , if it contains

$0$ or

$5$ in the units place.

Since all the numbers have

$0$ in the units place,

therefore all are divisible by

$5$ .

So, option D is correct.

The product of

$2 \times 7 \times 3 \times 5$ is a .........

0%
composite number
0%
prime number
0%
negative number
0%
none of the above

Explanation

Composite numbers are numbers which have more then

$2$ factors. They have at least

$1$ factor more than

$1$ and the number itself.

The given expression has more than

$2$ factors. So, it is a Composite number.

Therefore,

$A$ is the correct answer.

Fundamental theorem of arithmetic is when any .......... greater than

$1$ is either a prime number or can be written as a unique product of prime numbers.

0%
decimal number
0%
fraction
0%
irrational number
0%
integer

Explanation

Let us take an example,

$15$ is not a prime number.

$15 = 3 \times 5$ , where

$3$ and

$5$ are prime numbers.
We cannot get the number

$15$ by multiplying any other prime numbers.

$15 \neq 2 \times 5 \times 7.$

It is only with one particular set of prime numbers.
Hence, it is said integers greater than

$1$ are prime numbers or unique product of prime numbers.
Therefore,

$D$ is the correct answer.

Every ........ number can be expressed as a product of prime numbers.

0%
composite
0%
prime
0%
natural
0%
irrational

Explanation

For example,

$6 = 2\times 3$ , where

$2$ and

$3$ are prime numbers.
When we multiply two or more prime numbers we get the product as a composite number.
Therefore,

$A$ is the correct answer.

Which of the following numbers are divisible by

$3$ ?

0%
$12$
0%
$14$
0%
$20$
0%
None of the above

Explanation

The sum of the digits of

$12$ is

$1+2 =3$ .

$3$ is divisible by

$3$

Therefore,

$12$ is divisible by

$3$ .

So, option A is correct.

Which of the following numbers are divisible by

$9$ ?

0%
$81$
0%
$99$
0%
$108$
0%
All of the above

Explanation

A number is divisible by

$9$ , if the sum of the digits is also divisible by

$9$ .

Sum of digits of

$81$ is

$8+1=9$

Sum of digits of

$99$ is

$9+9=18$

Sum of digits of

$108$ is

$1+0+8=9$

Thus, all given numbers are divisible by

$9$

So, option D is correct.

Which of the following number is divisible by

$5 ?$

0%
$63$
0%
$65$
0%
$64$
0%
None of the ablove

Explanation

A number is divisible by

$5$ if it contains

$0$ or

$5$ in the units place.

Since only

$65$ has

$5$ in the units place, therefore it is divisible by

$5$ .

So, option B is correct.

Which of the following numbers are divisible by

$4$ ?

0%
$23$
0%
$1,216$
0%
$1,200$
0%
$235$

Explanation

We know the divisibility rule for

$4$ :
Check the last two digits are a multiple of

$4$ or if the last two digits are

$00$ .
Here,

$1,216$ and

$1,200$ are divisible by

$4$ because the last two digits are a multiple of

$4$ and

$00$ respectively.

So, options B and C are correct.

Choose the number divisible by

$2$ .

0%
$12907$
0%
$23484$
0%
$12971$
0%
$34987$

Explanation

We know the divisibility rule for

22:
The number which is divisible by

$2$ always end with either

$0, 2, 4, 6$ or

$8$

$12,907$ ends with

$7$ . So, not divisible by

$2$

$12,971$ ends with

$1$ . So, not divisible by

$2$

$34,987$ ends with

$7$ . So, not divisible by

$2$
But,

$23,484$ is divisible by

$2$ because the last digit is

$4$ .

Which of these numbers are divisible by

$2$ ?

0%
$1299$
0%
$2387$
0%
$2091$
0%
$3052$

Explanation

We know the divisibility rule for

$2$ :
Always check the last digit end with

$0, 2, 4, 6$ or

$8$ .
Here,

$3,052$ is divisible by

$2$ because the last digit ends with

$2$ .

So, option D is correct.

CBSE Questions for Class 6 Maths Playing With Numbers Quiz 3 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

CBSE Questions for Class 6 Maths Playing With Numbers Quiz 3 - MCQExams.com

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Practice Class 6 Maths Quiz Questions and Answers

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