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CBSE Questions for Class 6 Maths Playing With Numbers Quiz 3 - MCQExams.com
CBSE
Class 6 Maths
Playing With Numbers
Quiz 3
Which of the following is not a composite number ?
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0%
4
0%
6
0%
7
0%
10
Explanation
A composite number is a positive integer that has at least one positive divisor other than one and
number itself.
Here 7 is not composite number as it is cannot be divided evenly orwe can say
7 has divisor 1 and 7 itself that means it is a prime number.
Which list shows the first five multiples of
2
?
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0%
2
,
3
,
4
,
5
,
6
0%
2
,
4
,
6
,
8
,
10
0%
2
,
20
,
200
,
2
,
000
,
20
,
000
0%
2
,
22
,
222
,
2
,
222
,
22
,
222
Explanation
The first
5
multiples of
2
are as follows,
2
×
1
=
2
2
×
2
=
4
2
×
3
=
6
2
×
4
=
8
2
×
5
=
10
Option B has the desired list.
So option B is the correct answer.
Which of the following is not a composite number?
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0%
5
0%
6
0%
7
0%
8
Explanation
A composite number is a positive integer that has at least one positive divisor other than one and number itself.
Here 5 & 7 are not composite number as both cannot be divided evenly.
Smallest
6
digit number divisible by
6
is __________.
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0%
100000
0%
100002
0%
100003
0%
100004
Explanation
We know that the divisibility test of
6
states that a number is divisible by
6
if the number is even and
the sum of the digits is divisible by
3.
Hence,
100002
is the smallest number divisible by
6
as it is even and the sum of digits
1
+
0
+
0
+
0
+
0
+
2
=
3.
So, option
B
is correct.
The number which have more than two factors is called _____.
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0%
Even
0%
Prime
0%
Odd
0%
None of these
Explanation
The number with more than two factors is called a composite number.
So option C is the correct answer.
The number of prime numbers between
0
and
20
is
Report Question
0%
7
0%
8
0%
6
0%
9
Explanation
We know that, a prime number is a number having exactly two factors,
1
and the number itself.
Hence, the prime numbers between
0
and
20
are
2
,
3
,
5
,
7
,
11
,
13
,
17
and
19
∴
The number of prime numbers between
0
and
20
is
8.
Numbers ending with
0
or
5
are divisible by ___________.
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0%
10
0%
2
0%
5
0%
6
Explanation
Divisibility of 5 : Numbers ending with 0 and 5 are always divisible by 5
Sum of first three prime numbers which end at 3 is:
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0%
20
0%
16
0%
39
0%
40
Explanation
First three prime numbers which end with
3
are
3
,
13
,
23
.
S
u
m
=
3
+
13
+
23
=
39
Which of the following pairs are co-prime?
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0%
348 & 296
0%
59 & 97
0%
3025 & 4920
0%
None
Explanation
In number theory, two integers a and b are said to be relatively prime, mutually prime, or coprime if the only positive integer that divides both of them is 1.
Hence answer will be B as there is only one positive integer that divides 59 and 97 is 1.
1
is a ............ of every prime number.
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0%
factor
0%
multiple
0%
both factor and multiple
0%
none of these
Explanation
1
is a factor of prime number.
Highest common factor of
10
and
100
is
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0%
10
0%
100
0%
5
0%
All of the above
Explanation
First we will write
10
and
100
as product of its prime factors,
10
=
5
×
2
100
=
5
×
2
×
5
×
2
So, from above we can observe that
5
and
2
is common factors,
H
C
F
(
10
,
100
)
=
5
×
2
=
10
So, option
A
is correct.
21
is not co-prime with
Report Question
0%
3
0%
7
0%
22
0%
24
Explanation
If the H.C.F of two numbers are
1
they are said to be co-prime.
21
=
3
×
7
24
=
8
×
3
22
=
1
×
11
21
and
24
have common factors
1
and
3
.
So, options
A
,
B
and
D
are correct.
Which of the following numbers are divisible by
2
?
Report Question
0%
64
0%
16
0%
32
0%
All of the above
Explanation
Divisibility by 2:
If the number contains an even number (0, 2, 4, 6, 8) in the units place,
then the number is completely divisible by
2
.
All the options given here are even numbers i.e
64
ends with
4
,
16
with
6
and
32
ends with
2
So, option D is correct.
Which of the following numbers are divisible by
2
?
Report Question
0%
63
0%
62
0%
65
0%
61
Explanation
For a number to be divisible by
2
, it must contain an even digit in its unit place.
Since,
62
ends with
2
.
Therefore, it is divisible by
2
.
So, option B is correct.
The factor(s) of
59
is/are
Report Question
0%
1
0%
59
0%
2
0%
None of these
Explanation
59
=
1
×
59
1
and
59
are the factors.
So, options A and B are correct.
Identify co-prime numbers.
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0%
(
2
,
3
)
0%
(
3
,
5
)
0%
(
5
,
7
)
0%
All of the above
Explanation
(
2
,
3
)
has
1
factor in common
(
3
,
5
)
has
1
factor in common
(
5
,
7
)
has
1
factor in common
So, option D is correct.
Co-prime numbers
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0%
have two factors in common
0%
have one factor in common
0%
have three factor in common
0%
none of these
Explanation
Co-prime numbers have one factor in common.
So, option B is correct.
If a number
N
is divisible by
2
, then which of the following numbers can be at it's units' position.
Report Question
0%
0
0%
1
0%
2
0%
4
Explanation
If N is a number divisible by
2
,
then the digit in the units place of N should be either
0
,
2
,
4
,
6
or
8.
So, options A, C and D are correct.
The composite numbers _________ .
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0%
has atleast one factors other than itself and 1
0%
has no factor other than 1
0%
only A
0%
none
Explanation
Composite numbers has at least one factor other than itself & 1.
21
is co-prime with
Report Question
0%
3
0%
7
0%
22
0%
all of the above
Explanation
21
=
3
×
7
×
1
22
=
1
×
2
×
11
Only
1
is common, so option
C
is correct.
Which of the following numbers are divisible by
5
?
Report Question
0%
10
0%
100
0%
1000
0%
All of the above
Explanation
A number is divisible by
5
, if it contains
0
or
5
in the units place.
Since all the numbers have
0
in the units place,
t
herefore all are divisible by
5
.
So, option D is correct.
The product of
2
×
7
×
3
×
5
is a .........
Report Question
0%
composite number
0%
prime number
0%
negative number
0%
none of the above
Explanation
Composite numbers are numbers which have more then
2
factors. They have at least
1
factor more than
1
and the number itself.
The given expression has more than
2
factors. So, it is a Composite number.
Therefore,
A
is the correct answer.
Fundamental theorem of arithmetic is when any .......... greater than
1
is either a prime number or can be written as a unique product of prime numbers.
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0%
decimal number
0%
fraction
0%
irrational number
0%
integer
Explanation
Let us take an example,
15
is not a prime number.
15
=
3
×
5
, where
3
and
5
are prime numbers.
We cannot get the number
15
by multiplying any other prime numbers.
15
≠
2
×
5
×
7.
It is only with one particular set of prime numbers.
Hence, it is said integers greater than
1
are prime numbers or unique product of prime numbers.
Therefore,
D
is the correct answer.
Every ........ number can be expressed as a product of prime numbers.
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0%
composite
0%
prime
0%
natural
0%
irrational
Explanation
For example,
6
=
2
×
3
, where
2
and
3
are prime numbers.
When we multiply two or more prime numbers we get the product as a composite number.
Therefore,
A
is the correct answer.
Which of the following numbers are divisible by
3
?
Report Question
0%
12
0%
14
0%
20
0%
None of the above
Explanation
The sum of the digits of
12
is
1
+
2
=
3
.
3
is divisible by
3
Therefore,
12
is divisible by
3
.
So, option A is correct.
Which of the following numbers are divisible by
9
?
Report Question
0%
81
0%
99
0%
108
0%
All of the above
Explanation
A number is divisible by
9
, if the sum of the digits is also divisible by
9
.
Sum of digits of
81
is
8
+
1
=
9
Sum of digits of
99
is
9
+
9
=
18
Sum of digits of
108
is
1
+
0
+
8
=
9
Thus, all given numbers are divisible by
9
So, option D is correct.
Which of the following number is divisible by
5
?
Report Question
0%
63
0%
65
0%
64
0%
None of the ablove
Explanation
A number is divisible by
5
if it contains
0
or
5
in the units place.
Since only
65
has
5
in the units place,
t
herefore it is divisible by
5
.
So, option B is correct.
Which of the following numbers are divisible by
4
?
Report Question
0%
23
0%
1
,
216
0%
1
,
200
0%
235
Explanation
We know the divisibility rule for
4
:
Check the last two digits are a multiple of
4
or if the last two digits are
00
.
Here,
1
,
216
and
1
,
200
are divisible by
4
because the last two digits are a multiple of
4
and
00
respectively.
So, options B and C are correct.
Choose the number divisible by
2
.
Report Question
0%
12907
0%
23484
0%
12971
0%
34987
Explanation
We know the divisibility rule for
2
2
:
The number which is divisible by
2
always end with either
0
,
2
,
4
,
6
or
8
12
,
907
ends with
7
. So, not divisible by
2
12
,
971
ends with
1
. So, not divisible by
2
34
,
987
ends with
7
. So, not divisible by
2
But,
23
,
484
is divisible by
2
because the last digit is
4
.
Which of these numbers are divisible by
2
?
Report Question
0%
1299
0%
2387
0%
2091
0%
3052
Explanation
We know the divisibility rule for
2
:
Always check the last digit end with
0
,
2
,
4
,
6
or
8
.
Here,
3
,
052
is divisible by
2
because the last digit ends with
2
.
So, option D is correct.
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