Class 5 Maths - Can You See The Pattern

Solve the magic square.

The Concept of Solving a Magic Square is that the sum of all numbers in each

$row, column$ and

$diagonal$ are

$equal$ to

$15$

Now,

$4$	let $x$	$2$
let $y$	$5$	$7$
$8$	$1$	let $z$

Now, in first row

$Sum=4+x+2=15\Rightarrow x=9$

Now in second Row

$Sum=y+5+7=15\Rightarrow y=3$

Now in third Row

$Sum=8+1+z=15\Rightarrow z=6$

Therfore Required magic Square is

$4$	$9$	$2$
$3$	$5$	$7$
$8$	$1$	$6$

Draw a magic triangle whose magic number's sum is $11$ .

Consider the given question,

We take numbers are

$1$ ,

$2$ ,

$3$ ,

$4$ ,

$5$ and

$6$

We put the numbers as that sum of every side is equal to be

$11$ .

$6+1+4=11$

$4+5+2=11$

$6+3+2=11$

1000206_1070243_ans_c5bb2f1edf434590943248c4ccb3ab52.jpg

Observe the toothpick pattern given below:
Would make sense to join the points on this graph Explain.

Yes, it makes sense to join the points on the graph as the points join together form a straight line y = 3x + 1 .
1882955_1795231_ans_9da6ed84ad074bb2ae09ac5a2c3173e0.jpg

1882955_1795231_ans_9da6ed84ad074bb2ae09ac5a2c3173e0.jpg

Fill in the blank spaces by integers of the given magic square so that the sum of the integers in each row, each column and each diagonal is $-6$ .
$-1$
$3$ $-2$

Sum of integers of the magic square is

$-6$ in each row, column and each diagonal as shown here:

$-1$

$-9$

$\ \ 4$

$\ \ 3$

$-2$

$-7$

$-8$

$\ \ 5$

$-3$

Using the numbers from $9$ to $17$ , construct a $3\times 3$ magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

Using the numbers from

$9$ to

$17$ , a

$3\times 3$ magic square is constructed as shown above:

Considering the above drawn magic square, the magic sum is

$13\times 3=39$ .

Hence, the relation between the magic sum and the number in the central cell is that if we multiply the middle number to

$3$ (middle number

$\times 3$ ), then we get the magic sum.

Find the value of magic square.

The Concept of Solving a Magic Square is that the sum of all numbers in each

$row, column$ and

$diagonal$ are

$equal$ to

$15$

Now,

$7$	let $x$	$17$
let $y$	$5$	let $z$
let $a$	let $b$	let $c$

Now, in first row

$Sum=7+x+17=15\Rightarrow x=-9$

Now in second column

$Sum=-9+5+b=15\Rightarrow b=19$

Now in first Diagonal

$Sum=7+5+c=15\Rightarrow c=3$

Now in Second Diagonal

$Sum=17+5+a=15\Rightarrow a=-7$

Now in first column

$Sum=7+y-7=15\Rightarrow y=15$

Now in third column

$Sum=17+z+3=15\Rightarrow z=-5$

Therfore Required magic Square is

$7$	$-9$	$17$
$15$	$5$	$-5$
$-7$	$19$	$3$

Solve the magic square.

Let the sum of each row, column and diagonal be x.

So, we have

19 + 16 + g = x

35 + g = x

g = x - 35 --(1)

Hence, i = x - (x-35) - 14 = 21

So, the sum of the left diagonal is 60.

Hence, g = 25

b = 26

f = 24

Solve the magic square.

The rows, columns and diagonals must add up to

$36$ .

$1\times 2 = 19$ [first row, second column]

$2\times 3 = 9$ [second row, third column]

$2\times 2 = 12$

Complete the magic square.

The Concept of Solving a Magic Square is that the sum of all numbers in each

$row, column$ and

$diagonal$ are

$equal$ to

$15$

Now,

let $x$	$-8$	$18$
let $y$	$4$	let $z$
$-10$	let $a$	let $b$

Now, in first row

$Sum=18-8+x=15\Rightarrow x=5$

Now in first column

$Sum=x+y-10=15\Rightarrow y=20$

Now in second Row

$Sum=20+4+z=15\Rightarrow z=-9$

Now in second column

$Sum=-8+4+a=15\Rightarrow a=19$

Now in third column

$Sum=18-9+b=15\Rightarrow b=6$

Therfore Required magic Square is

$5$	$-8$	$18$
$20$	$4$	$-9$
$-10$	$19$	$6$

Solve the magic square.

Sum of any row, column, or diagonal is 9.

In a row of boys, Srinath is ${7}^{th}$ from the left and Venkat is ${12}^{th}$ from the right. If they interchange their positions, Srinath becomes ${22}^{nd}$ from the left. How many boys are there in the row?

Srinath is

${7}^{th}$ from the left and Venkat is

${12}^{th}$ from the right.

Now ,If they interchange their positions, Srinath becomes

${22}^{nd}$ from the left.

So, Srinath is

$22$ from left and

$12$ from right.

So, he has

$21$ boys before him and

$11$ boys after him.

So, total number of boys

$=$ number of boys before him

$+$ Number of boys after him

$+$ Srinath

$= 21+11+1=33$

Hence there are

$33$ boys

In a row of plants, a plant is $16^{th}$ from either end of the row. How many trees are there in the row ?

A plant is

$16^{th}$ from either end of the row.

So, it have

$15$ plants in front and

$15$ plants behind.

Thus, number of plants

$=15+15+1$ [Including the mentioned plant]

$=31$

Hence, number of plant is

$31$ .

$\square +\square +\square =30$
Fill the boxes using $(1, 3, 5, 7, 9, 11, 13, 15)$ You can also repeat the numbers.

1328558_1080921_ans_a27bf4bf500748a18307277ecb01b27b.jpg

In a "magic square", the sum of the numbers in each row, in each column and along the diagonals is the same. Is this a magic square?
$\dfrac {4}{11}$ $\dfrac {9}{11}$ $\dfrac {2}{11}$
$\dfrac {3}{11}$ $\dfrac {5}{11}$ $\dfrac {7}{11}$
$\dfrac {8}{11}$ $\dfrac {1}{11}$ $\dfrac {6}{11}$
(Along the first row $\dfrac {4}{11} + \dfrac {9}{11} + \dfrac {2}{11} = \dfrac {15}{11})$ .

Sum of first row

$= \dfrac {4}{11} + \dfrac {9}{11} + \dfrac {2}{11} = \dfrac {15}{11}$ [Given]

Sum of second row

$= \dfrac {3}{11} + \dfrac {5}{11} + \dfrac {7}{11} + \dfrac {3 + 5 + 7}{11} = \dfrac {15}{11}$

Sum of third row

$= \dfrac {8}{11} + \dfrac {1}{11} + \dfrac {6}{11} = \dfrac {8 + 1 + 6}{11} = \dfrac {15}{11}$

Sum of first column

$= \dfrac {4}{11} + \dfrac {3}{11} + \dfrac {8}{11} = \dfrac {4 + 3 + 8}{11} = \dfrac {15}{11}$

Sum of second column

$= \dfrac {9}{11} + \dfrac {5}{11} + \dfrac {1}{11} = \dfrac {9 + 5 + 1}{11} = \dfrac {15}{11}$

Sum of third colum

$= \dfrac {2}{11} + \dfrac {7}{11} + \dfrac {6}{11} = \dfrac {2 + 7 + 6}{11} = \dfrac {15}{11}$

Sum of first diagonal (left to right)

$= \dfrac {4}{11} + \dfrac {5}{11} + \dfrac {6}{11} = \dfrac {4 + 5 + 6}{11} = \dfrac {15}{11}$

Sum of second diagonal (left to right)

$= \dfrac {2}{11} + \dfrac {5}{11} + \dfrac {8}{11} + \dfrac {2 + 5 + 8}{11} = \dfrac {15}{11}$

Since the sum of fractions in each row, in each column and along the diagonals are the same, therefore it's a magic square.

In a "magic square", the sum of the numbers in each row, in each column and along the diagonal is the same. Is this a magic square ?
$\dfrac{4}{11}$ $\dfrac{9}{11}$ $\dfrac{2}{11}$
$\dfrac{3}{11}$ $\dfrac{5}{11}$ $\dfrac{7}{11}$
$\dfrac{8}{11}$ $\dfrac{1}{11}$ $\dfrac{6}{11}$

1675595_1675900_ans_d168332aa1064cbc9e6952eccddbe72e.PNG

Complete the following magic square by supplying the missing numbers:
2 15 16
9 12
7 10
14 17

1872741_1658674_ans_9c3e4800a6034b18b2a5c6b606de8a7c.jpg

Fill in the blanks to complete the following number triangle:

here is the complete triangle :
1715214_1808036_ans_b7fc7debd1f04a9e8bf1030e4fe9afde.png

In two-digit numbers, how many times does the digit $5$ occur in the unit's place?

$15,25,35,45,55,65,75,85,95$ are the two digit numbers which have 5 at units place. Total numbers are

$9.$

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares:
22 6 13 20
10 12 19
9 11 18 25
15 17 24 26
16 7 14

1872309_1658484_ans_3891780569784f76884737707a27b1ed.jpg

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares:
8 13
12
11

1872307_1658483_ans_18ccdd5fb9be4ec39745fd62ab6af61c.jpg

The given figure represents a weighing balance. The weights of some objects in the balance are given.
Find the weight of each square and the circle.

Since weight is balanced

$\implies$ Weight on L.H.S

$=$ Weight of R.H.S

$\implies 20+20=14+4+x$ (suppose

$x$ is the weight of circle)

$\implies 40=18+x$

$\implies x=40-18=22\text{ kg}$

$\therefore$ the weight of the circle is

$22\text{ kg}$

Observe the toothpick pattern given below:
Imagine that this pattern continues. Complete the table to show the number of toothpicks in the first six terms.

By observing the given pattern, we can say that

1 → 4

2 → 4 + 3 = 7

3 → 7 + 3 = 10

4 → 10 + 3 = 13

5 → 13 + 3 = 16

6 → 16 + 3 = 19

In tabular form it can be represented as :

Pattern	1	2	3	4	5	6
Toothpicks	4	7	10	13	16	19

Complete the magic square given alongside using number $0,1,2,3,........,15$ (only once),so that sum along each row, column and diagonal is $30.$

Given :
In the magic square , the use of number

$0 , 1 , 2 , 3 ............, 15$
So only once the sum along each row, column and diagonal is

$30$ .
Some numbers are already filled .

$3+ 8 +4 = 15 + 15 = 30$

$3 +12 = 5 + 10 = 30$

$3 + 14 + 0 = 17 + 13 = 30$

$0+ 6 = 9 + 15 = 30$

$0+ 7 + 12 = 19 +11 = 30$

$15 + 1 + 12 = 28 + 2 = 30$

$8 + 6 + 11 = 25 + 5 = 30$

$13 + 6 +1 = 20 +10 = 30$

$14 + 5 + 2 = 21 + 9 = 30$

In two-digit numbers, how many times does the digit $5$ occur in the ten's place.

$50,51,52,53,54,55,56,57,58,59$ are the numbers which have 5 at ten's place. Total numbers are 10.

Solve the following riddles, you may yourself construct such riddles.
Who am I?
Go round a square counting every corner Thrice and no more! Add the count to me To get exactly thirty-four!

There are

$4$ comers in a square
Thrice the number of comers in the square will be

$3 \times 4 = 12$
When this result i,e

$12$ , is added to the number if Comes to be

$34$ . therefore the number will be the difference of

$34$ and

$12$ i.e

$34 - 12 = 22$ .

Complete the following magic squares:

Sum for row-wise is as follows:

$6 + 7 + 2 = 15$ ,

$1 + 5 + 9 = 15$ ,

$8 + 3 + 4 = 15$ .

Sum for column wise is as follows:

$6 + 1 + 8 = 15$ ,

$7 + 5 + 3 = 15$ ,

$2 + 9 + 4 = 15$ .

Sum for diagonal wise is as follows:

$6 + 5 + 4 = 15$ ,

$2 + 5 + 8 = 15$

Hence, the magic square is as shown above

1790167_1819450_ans_5578d34105ef43ab9060ccd823055bb2.png

Using the numbers from 9 to 17 construct a $3 \times 3$ magic square. What is the Magic sum here? What relation is there between the magic sum and the number in the central cell?

Magic sum is

$39$
Central Number is

$13$

we have

$\Rightarrow 39=3 \times 13$
Thus, the magic sum is 3 times the number in central cell

1961057_1871173_ans_09d0a7413c044bb9bae77c6c3c3eaf00.png

Construct a $3 \times 3$ magic square using all odd numbers from 1 to 17.

As shown in figure, magic sum is

$27$

Number in the central cell is

$9$

$9\times 3=27$

Thus, magic sum is three times number in the central cell

1961136_1871178_ans_b7633c633bf44a918876f33d2aebe0ac.png

Starting with the middle cell in the bottom row of the square and "using numbers from 1 to 9 construct a $3 \times 3$ magic square.

Figure shows

$3\times 3$ magic square in which magic sum is

$15$ and central cell contains

$5$

We know that

$5\times 3=15$

Thus, magic sum is 3 times the number in central cell.

1961082_1871175_ans_a0f72c65fdb24366a3ce1cb8915a3beb.png

Complete the following magic square:

Row wise sum is as follows:

$16 + 2 + 12 = 30$ ,

$6 + 10 + 14 = 30$ ,

$8 + 18 + 4 = 30$ .

Column wise sum is as follows:

$16 + 6 + 8 = 30$ ,

$2 + 10 + 18 = 30$ ,

$12 + 14 + 4 = 30$ .

Diagonal wise sum is as follows:

$16 + 10 + 4 = 30$ ,

$12 + 10 + 8 = 30$ .

Hence, the magic square is as shown above

1790158_1819454_ans_8c7022578cc04552801aca899948c8bd.png

Complete the following magic square:

Row wise sum is as follows:

$4 + 9 + 8 = 21$ ,

$11 + 7 + 3 = 21$ ,

$6 + 5 + 10 = 21$ .

Column wise sum is as follows:

$4 + 11 + 6 = 21$ ,

$9 + 7 + 5 = 21$ ,

$8 + 3 + 10 = 21$ .

Diagonal wise sum is as follows:

$4 + 7 + 10 = 21$ ,

$8 + 7 + 6 = 21$ .

Hence, the magic square is

1790162_1819452_ans_be2c168b396b44189f7ace6d9f3f3816.png

Complete the adjoining magic square (Hint. In a $3 \times 3$ magic square the magic sum is times the central number)

Central number is

$7$ .

The magic sum is

$3\times 7=21$

1961191_1871222_ans_40f8d02a987a48d5830ab58bbfd843e4.png

Construct a $5 \times 5$ magic square using all even numbers from 1 to 50.

As shown in the figure,

magic sum is

$130$

Number in the central cell is

$26$

$26\times 5=120$

Thus, magic sum is five times the number in central cell

1961137_1871182_ans_550da74eec134e8995585d6638e7ca82.png

What relation is there between the magic sum and the number in the central cell?

1) If we take sum of numbers in any row, in any column and in any diagonal, it comes up to be

$27$

2) Number in the central cell is

$9$

$9\times 3=27$

Thus, we can say that magic sum is three times the number in the central cell

1961051_1871166_ans_14aeb55f1ff64284a60c6328a4807236.png

Write an algorithm to check if a number is even or odd, using both pseudocode and flowchart.

pseudocode:

take Number

remainder=Number%2

if remainder==0;

print even

else

print odd

1945804_1940775_ans_e139d4ff322c4dc6972f70bda370505c.png

Now use number $1 - 6$ to make your own magic triangle.
Rule : Numbers on each side must add up to $10$ .

Starting with the middle cell in the bottom row of the square and using numbers from $1$ to $9$ , construct a $3\times 3$ magic square

Using the numbers from

$1$ to

$9$ , a

$3\times 3$ magic square is constructed as shown above:

Considering the above drawn magic square, the magic sum is

$5\times 3=15$ .

Construct a $3\times 3$ magic square using all odd number from $1$ to $17$

Using all the odd numbers from

$1$ to

$17$ , a

$3\times 3$ magic square is constructed as shown above:

Considering the above drawn magic square, the magic sum is

$9\times 3=27$ .

Using the numbers from $5$ to $13$ , construct a $3\times 3$ magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

Using the numbers from

$5$ to

$13$ , a

$3\times 3$ magic square is constructed as shown above:

Considering the above drawn magic square, the magic sum is

$9\times 3=27$ .

Hence, the relation between the magic sum and the number in the central cell is that if we multiply the middle number to

$3$ (middle number

$\times 3$ ), then we get the magic sum.

Construct a $5\times 5$ magic square using all even number from $1$ to $50$

Using all the even numbers from

$1$ to

$50$ , a

$3\times 3$ magic square is constructed as shown above:

Considering the above drawn magic square, the magic sum is

$26\times 5=130$ .

Replace each $\ast$ by the correct digit of the above:

1678839_1778081_ans_2b0205d8564240fd9b1081621cb9dd33.jpg

Replace each $\ast$ by the correct digit of the above:

1678828_1778079_ans_d2f2b61472684d8bb233432047847a74.jpg

$\dfrac {4}{11}$	$\dfrac {9}{11}$	$\dfrac {2}{11}$
$\dfrac {3}{11}$	$\dfrac {5}{11}$	$\dfrac {7}{11}$
$\dfrac {8}{11}$	$\dfrac {1}{11}$	$\dfrac {6}{11}$

$\dfrac{4}{11}$	$\dfrac{9}{11}$	$\dfrac{2}{11}$
$\dfrac{3}{11}$	$\dfrac{5}{11}$	$\dfrac{7}{11}$
$\dfrac{8}{11}$	$\dfrac{1}{11}$	$\dfrac{6}{11}$

Can You See The Pattern - Class 5 Maths - Extra Questions

Solve the magic square.

Draw a magic triangle whose magic number's sum is 1111.

Observe the toothpick pattern given below:Would make sense to join the points on this graph Explain.

Fill in the blank spaces by integers of the given magic square so that the sum of the integers in each row, each column and each diagonal is −6-6.−1-133−2-2

Using the numbers from 99 to 1717, construct a 3×33\times 3 magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

Find the value of magic square.

Solve the magic square.

Solve the magic square.

Complete the magic square.

Solve the magic square.

In a row of boys, Srinath is 7th{7}^{th} from the left and Venkat is 12th{12}^{th} from the right. If they interchange their positions, Srinath becomes 22nd{22}^{nd} from the left. How many boys are there in the row?

In a row of plants, a plant is 16th16^{th} from either end of the row. How many trees are there in the row ?

◻+◻+◻=30\square +\square +\square =30Fill the boxes using (1,3,5,7,9,11,13,15)(1, 3, 5, 7, 9, 11, 13, 15) You can also repeat the numbers.

In a "magic square", the sum of the numbers in each row, in each column and along the diagonal is the same. Is this a magic square ?411\dfrac{4}{11}911\dfrac{9}{11}211\dfrac{2}{11}311\dfrac{3}{11}511\dfrac{5}{11}711\dfrac{7}{11}811\dfrac{8}{11}111\dfrac{1}{11}611\dfrac{6}{11}

Complete the following magic square by supplying the missing numbers: 215169127101417

Fill in the blanks to complete the following number triangle:

In two-digit numbers, how many times does the digit 55 occur in the unit's place?

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares: 226132010121991118251517242616714

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares: 8131211

The given figure represents a weighing balance. The weights of some objects in the balance are given.Find the weight of each square and the circle.

Observe the toothpick pattern given below:Imagine that this pattern continues. Complete the table to show the number of toothpicks in the first six terms.

Complete the magic square given alongside using number 0,1,2,3,........,15 0,1,2,3,........,15 (only once),so that sum along each row, column and diagonal is 30. 30.

In two-digit numbers, how many times does the digit 55 occur in the ten's place.

Solve the following riddles, you may yourself construct such riddles.Who am I?Go round a square counting every corner Thrice and no more! Add the count to me To get exactly thirty-four!

Complete the following magic squares:

Using the numbers from 9 to 17 construct a 3 \times 3 3 \times 3 magic square. What is the Magic sum here? What relation is there between the magic sum and the number in the central cell?

Construct a 3 \times 3 3 \times 3 magic square using all odd numbers from 1 to 17.

Starting with the middle cell in the bottom row of the square and "using numbers from 1 to 9 construct a 3 \times 3 3 \times 3 magic square.

Complete the following magic square:

Complete the following magic square:

Complete the adjoining magic square (Hint. In a 3 \times 3 3 \times 3 magic square the magic sum is times the central number)

Construct a 5 \times 5 5 \times 5 magic square using all even numbers from 1 to 50.

What relation is there between the magic sum and the number in the central cell?

Write an algorithm to check if a number is even or odd, using both pseudocode and flowchart.

Now use number 1 - 61 - 6 to make your own magic triangle.Rule : Numbers on each side must add up to 1010.

Starting with the middle cell in the bottom row of the square and using numbers from 11 to 99, construct a 3\times 33\times 3 magic square

Construct a 3\times 33\times 3 magic square using all odd number from 11 to 1717

Using the numbers from 55 to 1313, construct a 3\times 33\times 3 magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

Construct a 5\times 55\times 5 magic square using all even number from 11 to 5050

Replace each \ast\ast by the correct digit of the above:

Replace each \ast\ast by the correct digit of the above:

Class 5 Maths Extra Questions

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Draw a magic triangle whose magic number's sum is $11$ .

Observe the toothpick pattern given below:
Would make sense to join the points on this graph Explain.

Fill in the blank spaces by integers of the given magic square so that the sum of the integers in each row, each column and each diagonal is $-6$ .
$-1$
$3$ $-2$

Using the numbers from $9$ to $17$ , construct a $3\times 3$ magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

In a row of boys, Srinath is ${7}^{th}$ from the left and Venkat is ${12}^{th}$ from the right. If they interchange their positions, Srinath becomes ${22}^{nd}$ from the left. How many boys are there in the row?

In a row of plants, a plant is $16^{th}$ from either end of the row. How many trees are there in the row ?

$\square +\square +\square =30$
Fill the boxes using $(1, 3, 5, 7, 9, 11, 13, 15)$ You can also repeat the numbers.

In a "magic square", the sum of the numbers in each row, in each column and along the diagonal is the same. Is this a magic square ?
$\dfrac{4}{11}$ $\dfrac{9}{11}$ $\dfrac{2}{11}$
$\dfrac{3}{11}$ $\dfrac{5}{11}$ $\dfrac{7}{11}$
$\dfrac{8}{11}$ $\dfrac{1}{11}$ $\dfrac{6}{11}$

Complete the following magic square by supplying the missing numbers:
2 15 16
9 12
7 10
14 17

In two-digit numbers, how many times does the digit $5$ occur in the unit's place?

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares:
22 6 13 20
10 12 19
9 11 18 25
15 17 24 26
16 7 14

A magic square is an array of numbers having the same number of rows and columns and the sum of numbers in each row, column or diagonal being the same. Fill in the blank cells of the following magic squares:
8 13
12
11

The given figure represents a weighing balance. The weights of some objects in the balance are given.
Find the weight of each square and the circle.

Observe the toothpick pattern given below:
Imagine that this pattern continues. Complete the table to show the number of toothpicks in the first six terms.

Complete the magic square given alongside using number $0,1,2,3,........,15$ (only once),so that sum along each row, column and diagonal is $30.$

In two-digit numbers, how many times does the digit $5$ occur in the ten's place.

Solve the following riddles, you may yourself construct such riddles.
Who am I?
Go round a square counting every corner Thrice and no more! Add the count to me To get exactly thirty-four!

Using the numbers from 9 to 17 construct a $3 \times 3$ magic square. What is the Magic sum here? What relation is there between the magic sum and the number in the central cell?

Construct a $3 \times 3$ magic square using all odd numbers from 1 to 17.

Starting with the middle cell in the bottom row of the square and "using numbers from 1 to 9 construct a $3 \times 3$ magic square.

Complete the adjoining magic square (Hint. In a $3 \times 3$ magic square the magic sum is times the central number)

Construct a $5 \times 5$ magic square using all even numbers from 1 to 50.

Now use number $1 - 6$ to make your own magic triangle.
Rule : Numbers on each side must add up to $10$ .

Starting with the middle cell in the bottom row of the square and using numbers from $1$ to $9$ , construct a $3\times 3$ magic square

Construct a $3\times 3$ magic square using all odd number from $1$ to $17$

Using the numbers from $5$ to $13$ , construct a $3\times 3$ magic square. What is the magic sum here? What relation is there between the magic sum and the number in the central cell?

Construct a $5\times 5$ magic square using all even number from $1$ to $50$

Replace each $\ast$ by the correct digit of the above:

Replace each $\ast$ by the correct digit of the above: