Mapping Your Way - Class 5 Maths - Extra Questions

Use a ruler to measure the distance in cm between the places joined by dotted lines. If the map has been drawn using the scale 1 cm :10km, find the actual distances between
1) School and Library
2) College and Complex
3) House and School
1793262_5f7121114b544ac3adb479c26aed3257.png

As per question,
1) In the given figure, the distance between school and library $$= 6cm$$
So, the actual distance = $$6 X 10 = 60km$$
2) In the given figure, the distance between college and complex $$= 2cm$$
So, the actual distance $$ = 2 X 10 = 20km$$
3 ) In the given figure, the distance between school and house $$= 3.5cm$$ 


Study the given map of a zoo and answer the following questions.
Give the location of lions in the zoo.
1794248_4e261a293dc74426b5e3d029f2b7618c.png

From the given map,
The location of lions in the zoo $$= (\text A, \text f\ )$$


Ashish is travelling from Hyderabad to Vijayawada. He saw this board on the highway road while starting. How much distance he has to travel from Hyderabad to Vijayawada?
695641_9f778bb24cd8442195b6058306967054.png

To find how much distance he has to travel from Hyderabad to Vijayawada:
Since, Vijayawada  $$ \rightarrow 284 $$ Km
Therefore, distance from Hyderabad to Vijayawada 
$$ =  284$$ Km


How many points are marked in the following figures? Name them.
1302830_d6992aafe4354ba7b548a590794914a9.png

$$12$$ points are marked in the figure namely $$A, H, K, L, B, C, J, D, M, N, E, F$$


Study the given map of a zoo and answer the following questions.
Give the location of canteen.
1794256_64024885e23b4067b14674915534f544.png

From the given map,
Location of Canteen is : (C, c)


Ashish is travelling from Hyderabad to Vijayawada. He saw this board on the highway road while starting. Which distance is more - Suryapet to Kodad or Kodad to Vijayawada?

695641_9f778bb24cd8442195b6058306967054.png

To find which distance is more
Since, SURYAPET  $$ \rightarrow  120$$ Km
VIJAYAWADA  $$\rightarrow 284 $$ Km
KODAD  $$\rightarrow 162 $$ Km
Therefore, distance from Suryapet to Kodad can be calculated as
$$ =  162 -120   $$
$$ =  40$$ Km
Now, distance from Kodad to Vijayawada can be calculated as
$$  =  284  - 162 $$
$$  =   122  $$ Km 
 Hence, it is clear that distance from Kodad to Vijayawada ismore than Suryapet to Kodad.


The distance between school and house of a girl is given by 5 cm in a picture, using the scale 1cm: 5 km. Find the actual distance between the two places?

Given 
The scale $$1cm$$ $$:$$ $$5 km$$ 
So, 5cm in picture $$= 5 X 5$$ km of actual distance
                              $$ = 25km$$ of actual distance 
Therefore, the actual distance among two places $$= 25 km$$
Now, we can say that $$5cm$$ shows = $$25 km$$ of actual distance.


Study the given map of a zoo and answer the following questions.
Where are the toilets located?
1794251_2166476d6e904bb9b43213dc429e5169.png

From the given map,
Location of the toilets is: (0,e)


In the map of India, the distance between two cities is $$13.8\,cm$$.
Taking scale : $$1\,cm = 12\,km$$, find the actual distance between these two cities.

It is given that 
Scale for a map is $$1\,cm = 12 \,km $$ 
We know that 
Distance between two cities on the map $$ = 13.8\,cm$$
So the actual distance between these two cities $$ = 12 \times 13.8 = 165.6\,km$$


The streets of a city are arranged like the lines of a chessboard. There area $$m$$ streets running north and south and $$n$$ cast and west. Find the number of ways in which a man can travel from the N.W. to the S.E. corner going the shortest possible distance.


1582439_1747016_ans_ad474515fab3480f8a6c7492e8be192b.png


Find out the scale used to draw the map using the distance information given.
PlacesActual distanceDistance on map
From Begalore to Lucknow$$1855$$ km$$5.3$$ cm

Actual distance $$= 1855$$ km
Distance on map $$= 5.3$$ cm
$$1$$ cm $$=\dfrac{1855 }{5.3 }$$ km
$$= \dfrac{1855}{1} \dfrac{10}{53}$$ km
$$= \dfrac{1855}{1} \times \dfrac{10}{53}$$ km
$$= \dfrac{18550}{53}$$ km
$$\therefore 1 $$ cm $$= 350 $$ km


Height of a building is $$9$$ m and this building is represented by $$9$$ cm on a map. What is the scale used for the map?

Given: The height of the building is $$9 m.$$
$$9m$$ is represented by $$9cm$$ on the map.
We know that $$1m = 100cm$$
therefore,
$$9m:9cm  \Rightarrow  900cm:9cm$$
Scale used =>      $$ 100:1$$



If actual distance between two places $$A$$ and $$B$$ is $$110\ km$$ and it is represented on a map by $$25\ mm$$. Then the scale used is _____.

We know that
Scale of map $$=\cfrac{\text{Size drawn on map}}{\text{Actual size}}= \cfrac{25\ mm}{110\ km}$$

                       $$=\cfrac{25\ mm}{110000000\ mm}$$

                       $$=\cfrac{1}{4400000}$$
So, If actual distance between two places $$A$$ and $$B$$ is $$110$$ km and it is represented on a map by $$25$$ mm. Then the scale used is $$1:4400000$$


Look at the map given below. 
Houses
Now answer the following questions.
a) Name the roads that meet at round about.
b) What is the address of the stadium?
c) On which road is the Police Station situated?
d) If Ritika stays adjacent to bank and you have to send her a card, what address will you write?
e) Which sector has maximum number of houses?
f) In which sector is Fire Station located?
g) In the map, how many sectors have been shown?
1793224_9e8765f53b3a424daef2ac3c9ea43ca8.png

As per question 
a) Name of road are : Khel road , Flower road and Sneha road.
b) Address of the stadium : sector 27, B- Town, India.
c) Location of police station : Sneha road 
d) Sneha 's address : H.N. - 1Nr.,Bank 1 (A), Sector 19,B town India
e) Maximum number of house : Sector 27
f) Location of fire station : Sector 26 
g) Total sector in the given map : four 


If $$4\ km$$ on a map is represented by $$1\ cm$$, then $$16\ km$$ is represented by _______ $$cm$$ .

It is given that,
$$4\ km$$ on a map is represented by $$1\ cm$$ .
Let, $$16\ km$$ will be represented by $$y\ cm$$ .

We can say,
$$16\ km, 4\ km,y\ cm$$ and $$1\ cm$$ will be in proportion.

$$\therefore \cfrac{16\ km}{4\ km}=\cfrac{y\ cm}{1\ cm}$$

$$\Rightarrow \cfrac{16}{4}=\cfrac{y}{1}$$

$$\Rightarrow 4y=16$$

$$\Rightarrow y=\cfrac{16}{4}$$

$$\Rightarrow y=4$$

Hence, $$16\ km$$ will be represented by $$4\ cm$$ .


Refer to the given map to answer the following questions.
a) What is the built-up area of Govt.Model School I?
b) Name the school shown in the picture. 
c) Which park is nearest to the dispensary?
d) To which block does the main market belong?
e) How many parks have been represented in the map ?
1793194_1d7fd0178f85416eb02c8135315671bd.png

a) 2.1 acre
b) Govt. model school i and govt. model school are two school shown in picture 
c) Park A
d) Block A
e) Six parks 


Study the given map of a zoo and answer the following question.
(D, f) and (C,d) represent locations of which animals in the zoo?
1794249_73d5aa9dfe904246a4db10fe6276b812.png

From the graph, 
(D,f) represents the locations of Monkeys and 
(C,d) represents the locations of Elephants in the zoo


Draw a map of your school playground. Mark all necessary places like 2 libraries, Playground, Medical Room, Classroom, Assembly area, etc.


1653744_1793181_ans_6aabeccf88134727aa9127853572d55f.png


Rashmi has a road map with a scale of $$1$$km representing $$18$$ km. She drives on road for $$72$$ km. What would be her distance covered in the map?

$$ Road\, \, map\, \, with\, \, a\, \, scale\, \, of\, \, 1\, \, km\, \, representing\, \, 18\, \, km \\ \therefore 1\, \, km\, \, Road\, \, map\, \, with\, \, a\, \, scale\, \, of\, \, 1\, \, km\, \, representing\, \, \frac { 1 }{ { 18 } } cm \\ Therefor \\ she\, \, derives\, \, on\, \, road\, \, for\, \, 72\, \, km. \\ \therefore Scale\, \, of\, \, representing\, \, 72\times \frac { 1 }{ { 18 } } =4\, \, cm\, \, \, Ans. \\  $$


A map to scale is drawn for a state. If it takes $$4$$ hours to travel a distance shown as $$8 cm$$ on the map, find the time required to travel from city $$A$$ to city $$B$$ which are shown away by $$5cm$$ distance from each other on the map.

Time taken to travel $$8cm=4$$ hours.
$$\therefore$$ Time taken to travel $$1 cm=\dfrac {4}{8}$$ hours.
$$\therefore$$ Time taken to travel $$5cm =\dfrac {4}{8}\times 5=\dfrac {5}{2}$$ hours. 
                                                                $$=2\ 1/2$$ hours.
                                                                $$= 2$$hours $$30$$ minutes.


The side of a square is 10 cm. Find the area between inscribed and circumscribed circles of the square. 


1309217_1430253_ans_26cb0e18d0b3403fbda60be4f78a3c96.jpg


Class 5 Maths Extra Questions