Tenths And Hundreths - Class 5 Maths - Extra Questions

$$ \dfrac {1}{4}$$ km = _______ m 

To find how  many $$m$$ are there in a $$ \dfrac{1}{4}$$ Km kilometer
 As  we  know   that  ,
 $$  1$$ Km $$=  1000$$ m 
Therefore, $$ \dfrac{1}{4}\text{Km} =   \dfrac{1000}{4}\text{m}$$
$$\dfrac{1}{4}\text{Km} = 250\text{m}$$
 Hence, $$250$$ m are there in $$\dfrac{1}{4}$$ Km.


$$ \dfrac {1}{2}$$ km = _______ m 

To find how many $$m$$ are there in a $$ \dfrac{1}{2}$$ Km kilometer
As we know that,
$$  1$$ Km $$=  1000$$ m 
Therefore, $$ \dfrac{1}{2}\text{Km} =   \dfrac{1000}{2}\text{m}$$
$$\dfrac{1}{2} = 500$$
 Hence, $$\dfrac{1}{2}$$ Km $$= 500$$ m


Fill in the blanks 
7750 m = _____ km _____ m ________cm

Since $$ 7750\ m =  7000\ m + 700\ m + 50\ m$$
As we know that
$$ 1\ Km =  1000\ m$$ 
$$\therefore 7000\ m = 7\ km$$ 
Also $$  1$$ m $$=  100$$ cm 
$$\therefore $$ $$ 50$$ m $$= 5000$$ cm
Therefore, $$ 7750$$ m $$ =  7$$ Km $$ +$$ $$700$$ m $$+$$ $$5000$$ cm


Record your height and your four friends in feet and inches.
S. No.NameHeight in feet & inchesHeight in inches
ExampleSonu4'11"59"
1.
2.
3.
4.

Who is the tallest amongst all of you? ____________

  
  Height of four friends in feet and inches

 S.NO Name  Height  in  feets  & inches Height  in  inches
 ExampleSonu   4' 11" 59"
 1 .My  Height  5' 6 "  66"
 2.Ashish  6' 1" 73" 
 3. Sagar   5' 5" 65"
 4. Akshay  5' 7" 67"

To find who is the tallest amongst all of you: 
Amongst all students  Ashish is the tallest. 


Fill in the blanks :
12 km = _____ m

$$ 12$$ Km $$= .......$$ m 
Since $$1$$ Km $$= 1000$$ m
$$\therefore $$ $$12$$ Km $$= 12,000$$ m
Hence, $$12$$ Km $$= 12,000$$ m


$$\dfrac{1}{2}$$ of a rupee=_________ paise

The required conversion of rupee $$ \frac {1}{2}$$
$$ = \dfrac{1}{2} \times 100$$
$$ = 50 \,paise$$


$$1028\ cm $$ (We divide as we are moving $$2$$ units toward left)

We have,
$$1028 \ cm$$

Since, $$1 \ m=100\ cm$$

Therefore,
$$=\dfrac{1028}{100}$$
$$=10.28\ m$$

Hence, this is the answer.


Convert $$1\ m\ 4\ dm$$ in $$m.$$ 

Relation between $$m$$ and $$dm$$ is,
$$1\ m=10\ dm$$
$$\Rightarrow 1\ dm = 0.1\ m$$

$$1\ m\ 4\ dm=1\ m+4\times0.1\ m$$
                  $$=(1+0.4)\ m$$
                  $$=1.4\ m$$


$$\dfrac{1}{5}$$ of $$Rs\ 100$$ =Rs_______

$$\dfrac{1}{5} $$ of Rs $$100$$

$$\dfrac{1}{5}$$  $$\times100$$
$$ = 20$$ Rs


$$\dfrac{1}{20}$$ of $$Rs\ 2000\ =Rs$$______

$$\dfrac{1}{{20}}$$ of RS $$2000$$

$$ = \dfrac{1}{{20}} \times 2000$$

$$ = 100$$


Convert $$800$$ km $$250$$ m $$45$$ cm into cm.

$$800 km$$  $$ 250 m$$ $$  45 cm$$
$$1 km=1000 m$$
$$ 1 m = 100 cm$$
$$800(1000)(100)+250(100)+45$$
$$80000000+25000+45$$
$$80025045 cm$$


$$\dfrac{1}{10}$$ of $$Rs\ 1000$$ =Rs_______

$$\dfrac{1}{{10}}$$ of Rs $$1000$$

$$ = \dfrac{1}{{10}} \times 1000$$

$$ = 100$$ Rs


Fill in the blanks : 
(i) 2 $$m^{2}$$=_______ $$cm^{2}$$
(ii) 1 $$m^{2}$$ =_______ $$km^{2}$$
(iii) 1 $$m^{2}$$= _______$$mm^{2}$$

(i) 2 $$m^{2}$$= $$20000\ cm^{2}$$
(ii) 1 $$m^{2}$$ = $$0.000001\ km^{2}$$
(iii) 1 $$m^{2}$$= $$1000000\ mm^{2}$$


Divide the following.
$$3\ km\ 500\ m\ by\ 5$$

Now,
$$3$$ km $$500$$ m$$=3,500$$ m.

As , $$1 \ km= 1000 \ m$$

Now if we divide $$3$$ km $$500$$ m by $$5$$ 

then we get, $$\dfrac{3,500}{5}=700$$ m.


Aparna got $$Rs\ 27840$$ as her monthly salary and over-time. Her salary exceeds the over-time by $$Rs\ 16560$$. What is her monthly salary?

Let the salary and overtime of Aparna be $$Rs. x$$ and $$Rs. y$$ respectively.
Now according to the question-
Condition I:-
$$x + y = 27840 ..... \left( 1 \right)$$
Condition II:-
$$x = y + 16560 ..... \left( 2 \right)$$
Substiotuting the value of $$x$$ in $${eq}^{n} \left( 1 \right)$$, we have
$$\left( y + 16560 \right) + y = 27840$$
$$2y = 27840 - 16560$$
$$\Rightarrow y = \cfrac{11280}{2} = 5640$$
Substituting the value of $$y$$ in $${eq}^{n} \left( 2 \right)$$, we have
$$x = 5640 + 16560 = 22200$$
Hence the salary of Aparna is $$Rs. 22200$$.


How many decametres make one Metre?

100100 decametres = 11 kilometre

$$0.1$$ decametres = $$1$$ metre


How many decametres make an kilometre?

$$100$$ decametres = $$1$$ kilometre


How many centimetres make a kilometre?

$$1$$ kilometre$$-100000$$ centimetre.


Convert these measurements.
$$39\ cm$$ into $$m$$

$$1cm=\dfrac { 1 }{ 100 } m$$
so, $$39cm=\dfrac { 39 }{ 100 } =0.39m$$


$$1{\ m^2} =....... cm^2?$$

We know $$1m= 100cm$$
$$1 \ m^2=100\ cm \times100\ cm$$
$$1 \ m^2=10000 \ cm^2$$


The value of 50 coins of 50 paisa = Rs_____

The value of $$ 50 $$ coins of $$ 50 $$ paisa = Rs $$ 25 $$
$$ 50 \times 50 = 2500 paisa $$
$$ \Rightarrow Rs \dfrac {2500}{100} =  Rs  \dfrac  { 2500 \div  100}{ 100 \div  100} = Rs 25 $$


Express in rupees:
$$327 P$$

3279P3279P
We know that,
1P=1/100Rs1P=1/100Rs
=3279/100=3279/100
We get,
=Rs32.79=Rs32.79
Hence, the expression for 3279P3279P in the form of rupees is Rs32.79


Express in paise:
$$Rs 62.35$$

$$Rs 62.35$$
$$= 62.35 × 100 paise$$ $$[WKT 1 Rs = 100 Paise]$$
$$= (6235 / 100) × 100 paise$$
We get
$$= 6235 paise$$
Therefore, $$Rs 62.35 = 6235 paise$$


Express in rupees:
$$8 P$$

8P8P
We know that,
1P=1/100Rs1P=1/100Rs
=8/100=8/100
We get,
=Rs0.08=Rs0.08
Hence, the expression for 8P8P in the form of rupees is Rs0.08


Express in paise:
$$Rs 0.97$$

Rs0.97Rs0.97
=0.97100paise=0.97100paise [WKT1Rs=100Paise][WKT1Rs=100Paise]
On calculating, we get
=97paise=97paise
Therefore, Rs0.97=97paise


Express in paise:
$$Rs 0.09$$

Rs0.09
=0.09100 [WKT1Rs=100Paise]
We get,
=9.00paise
Therefore,  Rs0.09=9.00paise


Express in rupees:
$$55 P$$

$$55 P$$
We know that,
$$1 P = 1 / 100 Rs$$
$$= 55 / 100$$
We get,
$$= Rs 0.55$$
Hence, the expression for $$55 P$$ in the form of rupees is $$Rs 0.55$$


Express in centimetre (cm):
$$6 m$$

6m6m
We know that 1m=100cm1m=100cm
=6100=6100
We get,
=600cm=600cm
Hence, 6m=600cm


Add (giving answer in rupees):
$$Rs 24.03$$ and $$532$$ paise

$$Rs 24.03$$ and $$532$$ paise
$$= Rs 24.03 + 532 / 100$$
(Since, $$1 Rs = 100 paise$$)
$$= Rs (24.03 + 5.32)$$
$$= Rs 29.35$$
$$\therefore$$ $$Rs 24.03 + 532 paise = Rs 29.35$$


Express in rupees:
$$695 P$$

695P695P
We know that,
1P=1/100Rs1P=1/100Rs
=695/100=695/100
We get,
=Rs6.95=Rs6.95
Hence, the expression for 695P695P in the form of rupees is Rs6.95


Add (giving answer in rupees):
$$73$$ paise and $$Rs 2.08$$

$$73$$ paise and $$Rs 2.08$$
$$= 73 + 2.08 × 100$$
Since, $$100 paise = Rs 1$$
$$= 73 + 208$$
$$= 209 paise$$
Now, $$209 / 100 = Rs 2.09$$
$$\therefore$$ $$73 paise + Rs 2.08 = Rs 2.09$$


Subtract:
$$Rs 0.55$$ from $$121$$ paise

$$Rs 0.55$$ from $$121 paise$$
$$= Rs 121 / 100 – 0.55$$
$$= Rs 1.21 – 0.55$$
$$= Rs 0.66$$
Or $$.66 × 100 = 66 paise$$
$$\therefore$$ The subtraction of $$Rs 0.55$$ from $$121 paise = 66 paise$$


Add (giving answer in rupees):
$$8 paise$$ and $$Rs 15.36$$

8paise8paise and Rs15.36Rs15.36
=8+15.36100=8+15.36100
Since, 100paise=Rs1100paise=Rs1
=8+1536=8+1536
=1544paise=1544paise
Now, 1544/100=Rs15.441544/100=Rs15.44
∴∴ 8paise8paise and Rs15.36=Rs15.44


Subtract:
$$286 paise$$ from $$Rs 7.02$$

$$286 paise$$ from $$Rs 7.02$$
$$= Rs 7.02 – 286 paise$$
$$= Rs 7.02 – 286 / 100$$
$$[1 Rupee = 100 paise]$$
$$= Rs 7.02 – 2.86$$
$$= Rs 4.16$$
$$\therefore$$ The subtraction of $$286 paise$$ from $$Rs 7.02$$ is $$Rs 4.16$$


Express in meters using decimals.
$$9\ m$$ and $$7\ cm$$

$$9m$$  &  $$7cm$$

$$9m+7\left(\dfrac{1}{100}\right)m$$   ...........  As$$100\ cm=1\ m$$

$$9m+0.07m$$

$$=9.07m$$


There are $$.914$$ meters in a yard. A line drawn on a blue print measures $$1.5$$ yards. What is its length in meters?

  • The length in meters is $$1.5 \times 0.914 = 1.371$$ meters


Kanika was given her pocket money on $$1^{st}$$ Jan,$$2008$$. She puts $$Rs\ 1$$ on Day $$1$$, $$Rs\ 2$$ on Day $$2$$, $$Rs\ 3$$ on Day $$3$$, and continued on doing so till the end of the month, from this money into her piggy bank. She also spent $$Rs\ 204$$ of her pocket money, and was found that at the end of the month she still has $$Rs\ 100$$ with her. How much money was her pocket money for the month?

Total pocket Money $$=$$ Money in piggy bank $$+$$ expenses $$+$$ left
                                 $$= (1 + 2 + 3+ ... + 31) + 204 + 100$$
                                 $$= \dfrac{31 \times 32}{2} + 204 + 100$$
                                 $$= 31\times 16 + 304$$
                                 $$=496 \times 116 + 304$$
                                 $$ = 800Rs.$$

1048845_1177820_ans_8b9eea1d9975498aafb7e361a043388d.png


Express in meters using decimals.
$$419\ cm$$

$$419cm$$
As $$100cm=1m$$
$$1cm=\dfrac{1}{100}m$$
So $$419cm$$
$$=\dfrac{419}{100}m$$
$$=4.19m$$




Express as $$km$$ using decimals.
$$70\ km$$ and $$5\ m$$

$$70\ km\ 5\ m$$
$$=70\ km+5\ m$$
$$=70\ km+5\times 1\ m$$
$$=70\ km+5\left(\dfrac{1}{1000}\right)\ km$$  ........ As $$1000m=1\ km$$
$$=70\ km+0.005\ km$$
$$=70.005\ km$$


Express as $$km$$ using decimals.
$$88\ m$$

$$88m$$

As $$1000m=1km$$

$$1m=\dfrac{1}{1000}km$$

$$=88\times 1m$$

$$=88\times\dfrac{1}{1000}km$$

$$=0.088km$$


Express as $$kg$$ using decimals.
$$26\ kg$$ and $$50\ g$$

As $$1000g=1\ kg$$ $$\implies 1g=\dfrac{1}{1000}\ kg$$.

$$26\ kg\ 50\ g$$.

$$=26\ kg+50\ g$$

$$=26\ kg+50\left(\dfrac{1}{1000}\right) kg$$.

$$=26+0.05\ kg$$.

$$=26.05\ kg$$.


Express as $$km$$ using decimals.
$$8888\ m$$

$$8888\ m$$

As $$1000m=1\ km$$

$$8888\times 1\ m$$

$$=8888\times\dfrac{1}{1000}km$$

$$=\dfrac{8888}{1000}\ km$$

$$=8.888\ km$$


Express as $$km$$ using decimals.
$$8\ m$$

$$8m$$

As $$1000m=1km$$

$$1m=\dfrac{1}{1000}km$$

$$8m=8\times 1m$$

$$=8\times\dfrac{1}{1000}km$$

$$=0.008km$$


Express the following measurement in $$kg$$ using decimals.
$$5\ kg$$ and $$8\ g$$

As $$1000g=1\ kg$$ $$\implies 1g=\dfrac{1}{1000}\ kg$$.

$$5\ kg\ 8\ g$$.

$$=5\ kg+8\ g$$

$$=5\ kg+8\left(\dfrac{1}{1000}\right) kg$$.

$$=5\ kg+0.008\ kg$$.

$$=5.008\ kg$$.


On the internet, Pranay sees a grey jacket for $$165$$ euros($$euro$$) and a blue jacket for $$\$ 180$$. There are exchange rates.
$$1 euro =76.05$$ rupees
$$1$$ rupee$$=\$ 0.0152$$
Work out which jacket is the cheapest and by how many rupees.
The _________ jacket is cheapest by _________ rupees.

Given cost of blue jacket is $$180 \$ $$ 
as we know that $$1$$ rupee $$=0.0152\$ \implies 1\$ =\dfrac{1}{0.0152}=65.79\ $$rupees
$$1\ $$ euro $$=76.05\ $$rupee
Cost of grey jacket is $$165\ $$euro $$=165\times 76.05\ =12,548.25\ $$ rupees
Cost of blue jacket in rupees is $$180\times 65.79=11,842.2$$ rupees
Difference in the cost is $$12,548.25-11,842.2=706.05$$ rupees
So we can say that
Blue jacket is cheapest by $$706.05$$ rupees


Express the following as rupees using decimals 
Ten paise

We know that $$1$$ rupee$$=100$$ paise
$$1$$ paise$$=\cfrac { 1 } { 100 }$$ Rs.
$$=0.01$$ Rs.
Ten paise$$=10\times 0.01$$
$$=0.1$$ Rs./-


Find the ratio of the following.
$$55$$ paise to Rs. $$1$$.

First of all to find ratio let's convert them in the same units
$$\text{Rs }1=100\text{ paise}$$
so ratio is $$55:100$$
$$=11:20$$   (dividing by $$5$$)


How to convert Centimeter to meter?

We know,
$$\begin{matrix} 1\, \, \, cm\, \, =\dfrac { 1 }{ { 100 } } \, \, meter \\ \therefore x\, \, cm\, \, =\dfrac { x }{ { 100 } } \, \, meter \\  \end{matrix}$$


The maximum temperature on a day in Delhi was $$p^\circ \ C$$. The minimum temperature was $$(p-10)^\circ \ C$$.


1902984_1789871_ans_e22633833e304b18b1cb69ab6d5f9a7f.jpg


Express as rupees using decimals.
$$50$$ rupees $$90$$ paise

We know that, $$1$$ Rupee = $$100$$ paise
$$50 \,rupees \,90 \,paise = \left ( 50 + \dfrac{90}{100} \right ) rupees=50.90  \ rupees$$


The ratio of $$5$$ paisa to $$25$$ paisa is the same as the ratio of $$20$$ paisa to                 .

Let the missing paisa be $$x$$

According to the question,
$$5$$ paisa $$:25$$ paisa $$=20$$ paisa $$:x$$ paisa
$$\Rightarrow \dfrac5{25}=\dfrac{20}x\\\Rightarrow 5\times x=20 \times 25\qquad\text{ [ On cross multiplication ]}\\ \Rightarrow x=\dfrac{20\times 25}{5}=4\times 25\\ \therefore x=100$$ paisa

Hence, The ratio of $$5$$ paisa to $$25$$ paisa is the same as the ratio of $$20$$ paisa to $$100$$ paisa.


Convert $$400$$ euros into rupees using these exchange rates. _____ rupees.
$$1$$ euro$$=\$ 1.09$$
$$\$ 1=62$$ rupees


1695351_1647177_ans_a2c21659d9b84163af086c9fd99ccf4f.jpg


Class 5 Maths Extra Questions