Decimals - Class 6 Maths - Extra Questions

Sonu went to a shop. He wanted to buy a chiki and a toffee. One chiki costs Rs. $$0.75$$ and a toffee costs Rs.$$0.50$$. If he buys one each of them how much he has to pay to the shop keeper. Sonu's mother gave him Rs.$$2$$. He gave it to shopkeeper and bought items of Rs.$$1.25$$. How much he will get in return? Suppose if his mother gave her Rs.$$5$$ then how much will the shopkeeper return?

Price of one Chiki $$=$$ Rs. $$0.75$$
Price of one Toffee $$=$$ Rs. $$0.50$$

Sonu buys one each of them, so he has to pay $$=1\times 0.75+1\times 0.50=Rs\; 1.25$$

Sonu's mother gave him Rs. $$2$$
Sonu paid Rs. $$1.25$$ to the shopkeeper.

The money, Sonu will get in return $$=2.00-1.25=$$Rs. $$0.75$$

If his mother gave him Rs. $$5$$  and Sonu paid Rs. $$1.25$$ to the shopkeeper.

The money, Sonu will get in return $$=5.00-1.25=$$Rs. $$3.75$$


Hitesh and Hiral goes to market to buy some items for their home. Rate of items are in kg. Answer the following question on its base. What is the cost(in rupees) of Wheat, Sugar, and Rice?
710815_cd8f79b05cdd4cef947158344512e136.jpg

Total Cost of Wheat, sugar and Rice $$=60.50+30.50+20.50$$
$$Rs.66.00$$
$$=Rs.66$$
Hence,
Total cost of wheat, sugar and Rice is $$Rs.66$$ 


Hitesh and Hiral goes to the market to buy some items for their home. The rate of items are in kg. Answer the following question on its base. What is the total cost(in rupees) of Mung, Wheat, and Sugar, if they bought it as $$1kg$$?
710815_cd8f79b05cdd4cef947158344512e136.jpg

Total Cost of Mung, Wheat and sugar , if they bought $$1kg$$ each= Cost of $$1kg$$ Mung $$+$$Cost of $$1kg$$ wheat $$+$$ Cost of $$1kg$$ sugar
$$=60.50+15+30.50$$
$$Rs.106.00$$
$$=Rs.106$$
Hence,
Total cost of Mung , wheat and Sugar, if they bought $$1kg$$ each is $$Rs.106$$ 


A shopkeeper had $$12.500\ kg$$ potatoes. He bought another $$15\ kg$$ potatoes. Out of these, he sold out $$17.500\ kg$$ potatoes. Now, how much potatoes remains with shopkeeper is $$x\ kg$$. Find $$x$$.

At, First
Total Quantity of potatoes a shopkeeper had $$=12.500kg$$.
Quantity of potatoes asold by shopkeeper $$17.500kg$$.
Now,
Potatoes remains with shopkeeper $$(12.500+15.000-17.500)kg$$.
$$ \Rightarrow x = \left( {27.500 - 17.500} \right)$$
$$=17kg$$
Hence,
$$X=10kg$$


Find the value: $$3-10.2$$

We have,
$$42.3-10.2$$
$$=32.1$$

Hence, this is the answer.


The value of $$(3-32.7)$$ is

We have,
$$=64. 3-32.7$$

$$=31.6$$

Hence, this is the answer.


Express the following as $$cm$$ using decimals.
$$116\ mm$$

We know that,

$$1\ cm=10\ mm$$

So, $$1\ mm=0.1\ cm$$

$$\therefore 116\ mm= 116\times 0.1 = 11.6\ cm$$


Find the difference between $$ 3.47777 $$ and $$2.85888.$$



1143860_1006359_ans_5025ab5cfdaf423087ab4b5013944b30.png


Find the sum of $$5.14,3.12$$ and $$7.26$$

$$5.14 + 3.12 + 7.26$$
$$=5.14+10.38$$
$$ = 15.52$$


Write $$Rs.\ 9$$ and paise $$5$$ in decimal form.

$$Rs. 9$$ and paise $$5$$ in decimal  fraction = $$Rs.9+ Rs \dfrac{5}{100}$$
                                                               =  $$Rs. 9.05$$


Express some numbers as cm using decimals.
5mm, 60mm , 8mm  and 93mm

$$(A)\ 5\ mm\Rightarrow \dfrac{5}{10}=0.5\ cm$$
$$(B)\ 60\ mm\Rightarrow \dfrac{60}{10}=6\ cm$$
$$(C)\ 8\ mm\Rightarrow \dfrac{8}{10}=0.8\ cm$$
$$(D)\ 93\ mm\Rightarrow \dfrac{93}{10}=9.3\ cm$$
                                         or $$9\ cm\ 3\ cm$$
as $$1\ mm=\dfrac{1}{10}\ cm$$
or $$1\ cm=10\ mm$$


 $$584.29$$ - $$213.95$$?


$$=584.29$$ $$- 213.95$$
$$=370.34$$.


Express the following as $$cm$$ using decimals.
$$30\ mm$$

We know that,

$$1\ cm=10\ mm$$

So, $$1\ mm=0.1\ cm$$

$$\implies 30\ mm=3.0\ cm$$


Find the difference between $$3.25$$ and $$9.86$$

Let the difference,
=bigger value - smaller value
Therefore,
$$9.86-3.25$$
$$=6.61$$


Subtract each of the following from $$12$$ :
$$5.044$$

On subtraction, we get

$$12-5.044=6.956$$


Subtract the following from $$12$$:
$$7.013$$

By Subtracting, we get,
$$12-7.013=4.987$$


Subtract each of the following from $$12$$ :
$$3.002$$

Subtracting, we get

$$12-3.002=8.998$$


Subtract each of the following from $$12$$ :
$$6.303$$

Subtracting, we get

$$12-6.303=5.697$$


Subtract:
$$64.444$$ from $$99.449$$

On subtraction , we get

$$99.449-64.444=35.005$$


Subtract:
$$6.005$$ from $$6.105$$

On subtraction, we get

$$6.105-6.005=0.1$$


What should be added to $$78.9$$ to get $$93.06$$?

Let the added no. be $$x$$,

According to question,

$$78.9+x=93.06$$

$$ x=93.06-78.9$$

So $$ x=14.16$$


Express the following as $$cm$$ using decimals.
$$83\ mm$$

We know that,

$$1\ cm=10\ mm$$

So, $$1\ mm=0.1\ cm$$

$$\implies 83\ mm=8.3\ cm$$


Subtract:
$$65.005$$ from $$99.449$$

On subtraction, we get

$$99.449-65.005=34.444$$


Subtract:
$$8.105$$ from $$16.104$$

On subtraction , we get

$$16.104-8.105=7.999$$


Express the decimal in expanded notation: $$785.685$$

$$785.685=700+80+5+$$ $$\dfrac{6}{10}$$ $$+\dfrac{8}{100}$$ $$+\dfrac{5}{1000}$$



Express the decimal in expanded notation: $$43.901$$

$$43.901=40+3+$$ $$\dfrac{9}{10}$$ $$+\dfrac{0}{100}$$ $$+\dfrac{1}{1000}$$



What is the answer when we add $$266+2.76=$$


1114391_1204232_ans_f34ed5d82b094785a3466cafa6a2e025.jpeg


Convert these measurements.
$$1493\ m$$ into $$km$$

As we know, $$1000 m = 1 km$$

So, $$1493$$ m = $$\dfrac{1493}{1000}$$ km

$$= 1.493$$ km


Subtract:
$$6.912$$ from $$11.012$$

On subtraction, we get

$$11.012-6.912=4.1$$


Express the decimal in expanded notation: $$1207.85$$

$$1207.85=1000+200+7+$$ $$\dfrac{8}{10}$$ $$+\dfrac{5}{100}$$ 



Subtract:
$$2.009$$ from $$3.018$$

On subtraction, we get

$$3.018-2.009=1.009$$


Express the decimal in expanded notation: $$0.847$$

$$0.847=0+$$ $$\dfrac{8}{10}$$ $$+\dfrac{4}{100}$$ $$+\dfrac{7}{1000}$$



Express the decimal in expanded notation: $$375.4015$$

$$375.4015=300+70+5+$$ $$\dfrac{4}{10}$$ $$+\dfrac{0}{100}$$ $$+\dfrac{1}{1000}$$ $$+\dfrac{5}{10000}$$



Convert into decimal :

$$37 \dfrac{2}{100}$$

$$37\dfrac{2}{100} = 37 +\dfrac{2}{100} = 37 + 0.02 = 37.02$$


Radhika's mother gave her Rs.10.50 and her father gave her Rs.10.85, find the total amount given to Radhika by the parents,

Amount given by Radhika's mother $$=10.50$$
Amount given by Radhika's father $$=10.85$$
Total amount given to Radhika $$=10.50+10.85=21.35$$


Subtract:
27.86 from 53.7

This is a simple decimal subtraction
$$53.7-27.86=25.84$$


subtract Rs $$5.36$$ from Rs $$8.40$$

$$=8.40-5.36$$
$$=Rs.\ 3.04$$



Complete the following 
$$56\ cm=$$____________ m

$$1$$ $$cm$$ $$=\dfrac{1}{100} m $$
$$56$$ $$cm$$ $$=\dfrac{56}{100}m=0.56m$$


The value of 
$$3+3.33+0.03+33.03+3.003+3.03+3.333$$ is


1335903_1267203_ans_fbe5baea76be452f9f5e64ec7c3c678d.PNG


Add the given decimals: $$9.6, 14.8, 37$$ and $$5.9$$.


1225267_1227247_ans_062b478750ff41478d50d2890f3c5e84.jpg


Rashid spent $$Rs.35.75$$ for maths book and$$ Rs.32.60$$ for science book. find the  total amount spent by Rashid.

Amount spent for maths book $$=35.75$$
Amount spent for science book $$=32.60$$
 Total amount spent by Rashid  =
                        $$35.75\\ \underline{32.60}\\68.35$$


Rahim has to travel $$1.25\ km$$ to reach school . How much distance to go to school and come back home ?

We have,

Rahim travel to $$=1.25\,km.$$

Total distance

$$ =go+Come $$

$$ =1.25+1.25 $$

$$ =2.50 $$

Hence, this is the answer.



Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all ?

Distance travelled in morning $$= 2 km 35 m = 2.035 km$$

Distance travelled in evening $$= 1 km 7 m = 1.007 km$$

Total distance travelled $$= 2.035 + 1.007 = 3.042 km$$

Therefore, total distance travelled by Naresh is $$3.042 km.$$




Add $$9.610\ kg$$  and  $$6.750\ kg $$

$$9.610$$ kg $$+6.750$$ kg

$$=16.360$$ kg


Subtract $$12\ L\ 435\ mL$$ from $$18\ L\ 295\ mL$$

$$18$$ litres $$295$$ ml $$=18.295$$ litres
$$12$$ litres $$435$$ml $$=12.435$$ litres
$$18.295-12.435=5.86$$ litres


Saira cuts off $$1$$ m $$75$$ cm from $$12$$ m of rope. How much rope was left ?

Rope left = $$(12 - 1.75) $$m = $$10.25$$ m =$$10$$ $$m$$ $$25$$ $$cm$$.


Add the following: 3.5,16.08,125.073

Add $$3.5, 16.08, 125.073$$
$$\Rightarrow 3.5+16.08+125.073$$
$$\Rightarrow 144.653$$


Convert $$59342$$ g to kilograms.

$$1000gms$$  $$=1kg$$

$$59342gms$$ $$=\dfrac{59342\times 1}{1000}=59.342kgs‬$$


Show the following numbers on the number line.
$$1.9$$

  • $$1.9$$ represents a point between $$1$$ and $$2$$ on number line
  • Divide the space between $$1$$ and $$2$$ into $$10$$ equal parts and mark each point of division
  • $$10$$ points of divison are $$1.1,~1.2,~1.3,~1.4,~1.5,~1.6,~1.7,~1.8,~1.9,~2.0$$
  • Now, $$1.9$$ is the ninth point between $$1$$ and $$2$$.

1325030_1644391_ans_fc4e0bb2174c4f348b3f553a503dc7c0.png


If the length of $$2$$ roads are $$25$$ km $$500$$ m and $$30$$ km $$400$$ m. What is the total length of both the roads?

$$ L_1 = 25 \,km + 0.5\,km = 25.5 \, km. $$

$$ L_2 = 30 \, km + \dfrac{400}{1000}\,km = 30.4 \,km$$

$$ \therefore L_1 + L_2 = 25.5 + 30.4 = 55.9 \,km.$$

The total length of both the roads is $$55.9 \,km.$$


 Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?


1353286_3e228d5214f54d3f8e74b6c9f2b72d6b.png

Distance travelled by Dinesh = AB + BC = 7.5+12=19.5
Distance travelled by Ayub = AD + DC = 9.3+11.8=21.1
Ayub travelled more than Dinesh .
difference=21.1-19.5=1.6
He travelled 1.6 km more than Dinesh


Convert the fraction to decimal: $$\dfrac{3}{4}$$.

We've,
$$\dfrac{3}{4}$$
$$=\dfrac{3\times 25}{4\times 25}$$
$$=\dfrac{75}{100}$$
$$=0.75$$
This is the required decimal representation.


Find the sum :$$280.69 + 25.2 + 38$$

$$280.95 + 25.2 + 38$$
  $$280.69$$
    $$25.20$$
$$\underline {+\ 38.00}$$
 $$ {343.89}$$


Find the sum in each of the following:
$$15 + 0.632 + 13.8$$

$$15 + 0.632 + 13.8$$
   $$15.000$$
     $$0.632$$
$$+\underline {13.800}$$
  $$ {29.432}$$


Find the sum : $$0.75 + 10.425 + 2$$

    $$0.750$$
   $$10.425$$
$$\underline {+\ 2.000}$$
 $$ {13.175}$$


Add the following decimals
$$8.236,16.064,63.8$$ and $$27.53$$

Converting the given decimals in to like decimals, we get 
$$8.236, 16.064, 63,800$$ and $$27.530$$
Now writing these decimals in column from and adding , we get
$$ \therefore $$ The sum of the given decimals is $$115.63$$

1635190_1777035_ans_e21ca7cb06ad4d35a4aa9b30c9ccdf73.PNG


Add the following decimals
$$9.6$$,$$14.8$$,$$37$$ and $$ 5.9$$

Converting the given decimals into like decimals, we get
$$9.6$$,$$14.8$$,$$37.0$$ and $$ 5.9$$
Writing these decimals in the column form and adding, we get 
$$ \therefore $$ The sum of the given decimals is $$67.3$$

1635171_1777027_ans_0688e7c608744e189f05c20326159b7a.PNG


Add the following decimals
$$72.8, 7.68 , 16,23 $$ and $$0.7$$

Converting the given decimals into like decimals, we get
$$72.80, 7.68 , 16,23$$ and$$ 0.70$$
Now writing these decimals in  column form and adding, we get 
$$ \therefore $$ The sum of the given decimals is $$97.41$$

1635183_1777030_ans_67eef47dc1e84f2f8a05a29bbbfafd10.PNG


Which is greater:
$$1.37$$ or $$1.49$$.

$$1.37= \dfrac{137}{100}$$
and
$$1.49=\dfrac{149}{100}$$

The numerator of $$\dfrac{149}{100}$$ is greater than the numerator of $$\dfrac{137}{100}$$ and both have same denominator.

So, it is obvious that 1.49 is greater than 1.37


Show the following numbers on the number line.
(1) $$2.5$$

$$2.5$$ represents a point between $$2$$ and $$3$$ on number line, such that the space between $$2$$ and $$3$$ is divided into $$10$$ equal parts. Hence, each equal part will be equal to one-tenth. Now, $$2.5$$ is the fifth point between $$2$$ and $$3$$.
1325035_1644393_ans_0481a6248972433ebc5a459cc3303feb.png


Add the following decimals
$$23.7, 106.94, 68.9$$ and $$29.5$$

converting the given decimals into like decimals, we get
$$23.70, 106.94,68.90$$ and $$29.50$$
Now writing these decimals in column form and adding , we get
$$ \therefore $$ The sum of the given decimals is $$229.04$$

1635180_1777029_ans_cf0ae84a7e124a04b62589ef0dfd84b2.PNG


Add the following decimals
$$18.6,84.75,8.345$$ and $$9.7$$

Converting the given decimals into like decimals, we get 
$$18.600, 84,750,8.345$$ and $$9.700$$
Now writing these decimals in column form and adding, we get
$$ \therefore $$ The sum of the given decimals is $$121.395$$

1635185_1777034_ans_840a9c3d0d2949caa6cf710272d0c656.PNG


Subtract:
$$56.8$$ from $$204$$

Converting the given decimals into like decimals, we get
$$56.80$$ and $$204.00$$
Now writing these decimals in column from with the larger one at the top and substracting. we get
Hence, $$204.00 - 56.80 = 147.2$$
1635222_1777050_ans_3be70b8022b1429580ca937b39e61c62.PNG


Add the following decimals
$$4.37,9.638,17.007$$ and $$6.8$$

Converting these decimals into like decimals, we get 
$$4.370,9.638,17.07$$ and $$6,800$$
Now writing these decimals in column form, we get
$$ \therefore $$ The sum of the given decimals is $$ 37.815$$
1635213_1777042_ans_83afdef249864677a65d4301a3f1584e.PNG


Subtract:
$$348.237$$ form $$523.12$$

Converting the given decimals into like decimals, we get
$$348.237$$ and $$523.120$$
Now writing these decimals in column form with the larger one at the top and substracting , we get
Hence, $$523.120 - 348.237 = 174.883$$
1635236_1777068_ans_8493b38d323042059847be183ed9d57b.PNG


Subtract:
$$64.98$$ from $$103.87$$

Now writing these decimals in column from with the larger one at the top and substracting. We get
Hence, $$103.87 - 64.98 = 38.89$$
1635218_1777047_ans_e91cbd92eed54b138e30fccfd883d3f6.PNG


Subtract:
$$27.86$$ from $$53.74$$

Now writing these decimals in column from with the larger one at the top and subtracting, we get
Hence, $$53.74-27.84=25.88$$
1635216_1777045_ans_1f72af3165874a0598d19de068951b67.PNG


Add the following decimals
$$28.9,19.64,123,697$$ and $$0.354$$

Converting the given decimals into like decimals, we get
$$28.900, 19640,123.697$$ and $$ 0.354$$
Now writing these decimals in column form, we get
$$ \therefore $$ The sum of the given decimals is $$172.591$$

1635201_1777038_ans_e7679f9b65cf4c6dbb1e450f8898c368.PNG


Subtract:
$$127.38$$ from $$216.2$$

Converting the given decimals into like decimals , we get 
$$127.38$$ and $$216.20$$
Now writing these decimals in column from with the larger one at the top and substracting, we get 
Hence, $$216.20 - 127.38 = 88.82$$
1635226_1777056_ans_085b291560a7469caf178a8b9690b591.PNG


Subtract:
$$59.63$$ from $$92.4$$

Converting the given decimals into like decimals, we get
$$59.63$$ and $$92.40$$
Now writing these decimals in column from with the larger one at the top substracting. We get 
Hence, $$92.40 - 59.63 = 32.77$$
1635221_1777049_ans_80d59a844e2c40719d4c0a6db17afae5.PNG


Subtract:
$$39.875$$ from $$ 70.68$$

Converting the given decimals into like decimals, we get
$$39.875$$ and $$70.680$$
Now writing these decimals in column from with the larger one at the top and substracting, we get 
Hence, $$70.680 - 39.875 = 30.805$$
1635231_1777063_ans_0a58885f0d0e4bea81ce7517c25513ca.PNG


Add the following decimals
$$4.37,9.638,17.007$$ and $$ 6.8$$

Converting these decimals into like decimals, we get 
$$4.370,9.638,17.007$$ and $$ 6,800$$
Now writing these decimals in column form, we get
$$ \therefore $$ The sum of the given decimals is $$ 37.815$$
1635208_1777041_ans_59c3ed3a8ee54413a44ce2fe1f692085.PNG


Subtract:
$$149.456$$ from $$206.321$$

Writing these decimals in column form with the larger one at the top and substracting, we get
Hence, $$206.321-149.456 = 56.865$$
1635241_1777091_ans_edb866a855d6444b89be6530ecc6e61f.PNG


Write the following decimal in expanded form:
$$ 24.675 $$

$$ 24.675=20+4$$ $$+\dfrac{6}{10}$$$$+\dfrac{7}{100}$$ $$+\dfrac{5}{1000}$$


Add:
$$17.5+ 8.8$$

$$17.5+ 8.8$$

$$\dfrac {\quad 17.5\\ \  +8.8}{\ \ 26.3}$$


Write the following decimal in expanded form:
$$ 0.294 $$

The given decimal number is $$0.294$$

Now, the expanded form is,

$$ 0.294=0$$ $$+\dfrac{2}{10}$$$$+\dfrac{9}{100}$$ $$+\dfrac{4}{1000}$$


Subtract:
$$0.612$$ from $$3.4$$

Move decimal point three places to the right of given numbers.
Thus we get
$$\Rightarrow 612$$ and $$3400$$
Now perform the required subtraction,
$$3400-612=2788$$
Now move decimal point three places to the left.
$$\Rightarrow 2.788$$


Subtract:
$$458.573$$ from $$600$$

Converting the given decimals, we get
$$458.573$$ and $$600.00$$
Now writing these decimals in column form with the larger one at the top and substracting, we get 
Hence, $$ 600.00-458.573= 141.427$$
1635237_1777086_ans_e01960dd5a1b4b5caf2e4a0ce781e123.PNG


Write the following decimal in expanded form:
$$ 8.006 $$

The given decimal number can be written as,
$$ 8.006=8$$ $$+\dfrac{0}{10}$$$$+\dfrac{0}{100}$$ $$+\dfrac{6}{1000}$$


Write the following decimal in expanded form:
$$ 67.83 $$

$$ 67.83=60+7$$ $$+\dfrac{8}{10}$$$$+\dfrac{3}{100}$$ 


Add:
$$9.999+ 0.03$$

$$9.999+ 0.03$$

$$\dfrac {\quad 9.999\\ +0.030}{10.029}$$


Write the following decimal in expanded form:
 $$ 283.61$$

$$ 283.61=200+80+3$$ $$+\dfrac{6}{10}$$$$+\dfrac{1}{100}$$ 


Write the following decimal number in the expanded form:
$$123.7$$

The expanded form of $$123.7$$ is as follows:

$$123.7 = 100+20+3+\dfrac {7}{10}$$


Work out:
$$19.01-12.234$$

$$19.01-12.234$$

$$\dfrac {\quad 19.010\\ -12.234}{\underline{\quad 6.776}}$$


Write the following decimals numbers in the expanded form:
$$43.06$$

$$43.06 = 40+3+\dfrac {6}{100}$$


Write the following decimals numbers in the expanded form:
$$509.306$$

$$509.306 = 500+9+\dfrac {3}{10}+\dfrac {6}{1000}$$


Add:
$$8.79+ 23.001+ 5.41+ 0.875$$

$$8.79, 23.001, 5.41, 0.875$$

$$\dfrac {\quad 08.790\\ \quad 23.001\\ \quad 05.410\\ +00.875}{\underline{\quad 38.076}}$$




Work out:
$$5.82-2.65$$

$$5.82-2.65$$

$$\dfrac {\quad 5.82\\ -2.65}{\underline{\quad 3.17}}$$




Add:
$$4.5+ 16.024+ 7.99$$

$$4.5+ 16.024+ 7.99$$

$$\dfrac {\quad 04.500\\ \quad 16.024\\ +07.990}{\underline{\ \ 28.514}}$$


If the school bags of Garima and Nakul weight $$5.2\ kg$$ and $$4.832\ kg$$ respectively, find 
the total weight

Weight of Garima's bag $$=5.2\ kg$$
Weight of Nakul's bag $$=4.832\ kg$$

Hence total weight of bags $$=\dfrac {\quad 5.200\\ +4.832}{\ \ 10.032\ kg}$$


Add:
$$23.71+ 9.9+ 4.023$$

$$23.71+ 9.9+ 4.023$$

$$\dfrac {\quad 23.710\\ \quad \ \ 9.900\\ +\ \ 4.023}{\underline{\ \ 37.633}}$$


Anita bought $$2\ m\ 70\ cm$$ cloth for her shirt and $$2\ m\ 85\ cm$$ cloth for her trouser. Find the total length of the cloth bought by her.

Cloth bought for her shirt
$$=2\ m\ 70\ cm = 2\ m + 70\ cm$$
$$2\ m + \dfrac {70}{100}m = 2\ m + 0.70\ m\ (\because 1\ cm = \dfrac {1}{100}m) $$
$$(2\ m + 0.70)\ m = 2.70\ m$$
Cloth bought for her trouser
$$=2\ m\ 85\ cm = 2\ m + 85\ cm$$
$$2\ m + \dfrac {85}{100}m = 2\ m + 0.85\ m (\because 1\ cm = \dfrac {1}{100}m)$$
$$(2 + 0.85)\ m = 2.85$$
$$\therefore $$ Total lengths of cloth bought is $$2.70\ m + 2.85\ m = 5.55\ m$$


Tina had $$20\ m\ 5\ cm$$ long cloth. She cuts $$4\ m\ 50\ cm$$ length of cloth from this for making a curtain. How much cloth is left with her?

Length of cloth Tina had
$$=20\ m\ 5\ cm= 20\ m\ +\ 0.05\ m$$ $$\left[\because \dfrac {1}{100}cm = 0.01\ m\right]$$
$$=(20 + 0.05)\ m = 20.05\ m$$

Length of cloth cut of $$4\ m\ 50\ cm$$
$$=4\ m + 50\ cm$$
$$=4\ m + \dfrac {50}{100}m =4\ m + 0.50\ m$$ $$\left[\because \dfrac {1}{100}cm = 0.01\ m\right]$$
$$=(4 + 0.50)\ m= 4.50\ m$$

$$\therefore$$ Length of cloth left $$= 20.05\ m - 4.50\ m$$
$$=15.55$$

$$\begin{matrix}  & 1 & 9 &  & 10 &  &  \\  & 2 & 0 & \cdot  & 0 & 5 & m \\ - &  & 4 & \cdot  & 5 & 0 & m \\ = & 1 & 5 & \cdot  & 5 & 5 & m \end{matrix}$$


Fill in the blanks to make the statement true:
To convert a decimal into a per cent, we shift the decimal point two places to the ..............

To convert a decimal into a per cent, we shift the decimal point two places to the right.


Fill in the blanks:
$$5+ \dfrac{6}{100} = $$ _____

$$5 + \dfrac{6}{100} = 5 + 0.06 = 5.06$$


Subtract (giving answer in metre):
$$428 cm$$ from $$1033 m$$


2004054_1820172_ans_65cab6a24bcd4eaf86ff5856dfae17cd.png


Subtract (giving answer in metre):
$$0.84 m$$ from $$122 cm$$


2004056_1820174_ans_89ab651f9d1a4a73b14190bc818e07ec.png


Add (giving answer in metre):
$$0.93 m$$ and $$64 cm$$

$$0.93 m$$ and $$64 cm$$
$$= 0.93 m + 64 / 100 cm$$
$$= 0.93 m + 0.64 m$$
$$0.93$$
$$0.64 +$$
___________
$$1.57$$
____________
$$\therefore$$ The addition of $$0.93 m + 64 cm = 1.57 m$$


Subtract (giving answer in metre):
$$5.03 m$$ from $$19.6 m$$

$$5.03 m$$ from $$19.6 m$$
$$= 19.60 m – 5.03 m$$
We get,
$$= 14.57 m$$
$$\therefore$$ The subtraction of $$5.03 m$$ from $$19.6 m$$ is $$14.57 m$$


Rani had $$Rs\ 18.50$$. She bought one ice-cream for $$Rs\ 11.75$$. How much money does she have now?

Money Rani had $$= Rs.\ 18.75.$$
Ice-cream bought for $$= Rs.\ 11.75.$$
$$\therefore$$ Money she has now $$=Rs.\ 18.50 - Rs.\ 11.75 = Rs.\ 6.75$$

$$\begin{matrix}  &  &  & 7 &  & 14 & 1 \\  & Rs. & 1 & 8 & \cdot  & 5 & 0 \\ - & Rs. & 1 & 1 & \cdot  & 7 & 5 \\ = & Rs. &  & 6 & \cdot  & 7 & 5 \end{matrix}$$


Subtract:
$$0.43$$ from $$0.97$$

To subtract the decimal numbers, first convert the decimals into like decimals numbers and then subtract
The given decimals are like decimals
   $$0.97$$
$$–$$ $$0.43$$ 
  ________
    $$0.54$$
  _________

Hence, the subtraction of the decimal numbers is $$0.54$$



Subtract :
$$1.002$$ from $$17$$

To subtract $$1.002$$ from $$17$$
Convert the decimals into like decimals by adding zeros
Like decimals are $$17.000$$ and $$1.002$$
$$17.000$$
$$–$$$$1.002$$ 
_________
$$15.998$$
__________
Hence, the subtraction of the decimal numbers is $$15.998$$


Add:
$$9.25,3.4$$ and $$6.666$$

$$9.25,3.4$$ and $$6.666$$
        $$9.25$$ 
        $$3.4$$ 
    $$+ 6.666$$ 
$$ \begin{array}{l l}\hline & 19.316\\\end{array} $$
So we get $$ 9.25+3.4+6.666=19.316 $$


Subtract :
$$0.18$$ from $$0.6$$

To subtract $$0.18$$ from $$0.6$$
Convert the decimals into like decimals by adding zeros
Like decimals are $$0.60$$ and $$0.18$$
    $$0.60$$
$$–$$ $$0.18$$ 
_________
$$0.42$$
__________

Hence, the subtraction of the decimal numbers is $$0.42$$



Subtract :
$$83$$ from $$92.05$$

To subtract $$83$$ from $$92.05$$
Convert the decimals into like decimals by adding zeros
Like decimals are $$92.05$$ and $$83.00$$
 $$92.05$$
$$–$$$$83.00$$
__________
$$9.05$$
___________
Hence, the subtraction of the decimal numbers is $$9.05$$


Add:
0.5 and 0.37

$$0.5$$ and $$0.37$$
        $$0.5 $$
    $$+0.37 $$
      $$\begin{array}{r}\hline 0.87 \\\hline\end{array}$$
So we get $$ 0.5+0.37=0.87 $$


Add:
3.8 and 8.7

$$3.8$$ and $$8.7$$
        $$3.8$$
    $$+8.7$$
$$ \begin{array}{l l}  \hline &12.5 \end{array} $$
so, we get
$$3.8+8.7 = 12.5$$


Add:
$$0.02,0.008$$ and $$0.309$$

 $$0.02,0.008$$ and $$0.309$$
$$ \begin{array}{l l}& 0.02 \\& 0.008 \\+& 0.309 \\\hline & 0.337\\\end{array} $$
So we get
 $$ 0.02+0.008+0.309=0.337 $$


Add (giving answer in kg):
$$0.065 kg$$ and $$4023 gm$$

$$0.065 kg$$ and $$4023 gm$$
$$= 0.065 × 1000 gm + 4023 gm$$
We get,
$$= 65 gm + 4023 gm$$
$$= 4088 gm$$
Now, converting into kilogram, we get
$$= 4088 / 1000$$
$$= 4.088kg$$
$$\therefore$$ The addition of $$0.065 kg$$ and $$4023 gm$$ is $$4.088 kg$$


Add the following:
$$0.243, 2.47$$ and $$3.009$$

To add the decimal number, first convert the decimals into like decimal numbers and then add
To add $$0.243, 2.47$$ and $$3.009,$$
Convert the decimals into like decimals by adding zeros
Like decimal are $$0.243, 2.470$$ and $$3.009$$
$$0.243$$
$$2.470$$ $$+$$
$$3.009$$ $$+$$
__________
$$5.722$$
_________
Hence, the addition of the given decimal numbers is $$5.722$$


Subtract the first number from the second:
$$4.73,8.5$$

It can be written as
$$8.5-4.73=3.77$$
$$ \begin{array}{l l}& 8.50 \\-& 4.73 \\\hline & 3.77\end{array} $$


Subtract the first number from the second:
2.237,9.425

It can be written as
$$9.425-2.237=7.188$$
$$ \begin{array}{l l}& 9.425 \\-& 2.237 \\\hline & 7.188\end{array} $$


What should be subtracted from $$100$$ to give $$19.29?$$

It is given that Sum of two numbers $$ =100 $$ 
One number $$ =19.29 $$ 
So the other number $$ =100-19.29=80.71 $$
   $$ 100.00 $$
  $$-19.29 $$
$$ \begin{array}{l l}\hline & 80.71 \end{array}$$


Subtract the first number from the second:
$$0.16,4.3$$

$$0.16,4.3$$
It can be written as
$$4.3-0.16=4.14$$
$$ \begin{array}{l l}& 4.30 \\-&0.16 \\\hline & 4.14\end{array} $$


Subtract the first number from the second:
$$36.2,12.63$$

$$36.2,12.63$$
It can be written as
$$36.2-12.63=23.57$$
$$ \begin{array}{l l}& 36.20 \\-& 12.63 \\\hline & 23.57\end{array} $$


Subtract the first number from the second:
$$5.4,9.8$$

$$5.4,9.8$$
It can be written as
$$9.8-5.4=4.4$$
$$ \begin{array}{l l}& 9.8 \\-&5.4 \\\hline & 4.4\end{array} $$


Subtract the first number from the second:
$$3.92,26.86$$

It can be written as
$$26.86-3.92=22.94$$
     $$26.86 $$
    $$- 3.92 $$
$$ \begin{array}{l l}\hline & 22.94\end{array} $$


Find the difference between 6.85 and 0.685

The difference between $$6.85$$ and $$ 0.685=6.850-0.685 $$
$$=6.165$$
$$ \begin{array}{l l}& 6.850 \\-&0.685 \\\hline & 6.165 \end{array}$$


Subtract the first number from the second:
$$0.82,8.6$$

It can be written as
$$8.6-0.82=7.78$$
$$ \begin{array}{l l}& 8.60 \\-& 0.82 \\\hline & 7.78\end{array} $$


Add:
$$3.007,0.587$$ and $$18.341$$

$$3.007,0.587$$ and $$18.341$$
       $$ 3.007$$ 
       $$0.587$$ 
  $$+ 18.341$$
$$ \begin{array}{l l}\hline & 21.935\\\end{array} $$ 
So we get $$ 3.007+0.587+18.341=21.935 $$


What is the excess of 75 over 48.29?

We know that the excess of $$75$$ over $$48.29$$ can be written as
$$ \begin{array}{l l}& 75.00 \\-&48.29 \\\hline & 26.71 \end{array}$$
Hence, the excess of $$75$$ over $$48.29$$ is $$26.71.$$


What is the excess of 584.29 over 213.95?

It is given that
Sum of two numbers$$=584.29$$
One number$$=213.95$$
So the other number $$=584.29-213.95=370.34$$
$$ \begin{array}{l l}& 584.29 \\-&213.95 \\\hline & 370.34 \end{array}$$


The diagram shows part of a number line with evenly spaced intervals between marks. What is the value of 1000P?
535915_d5d9c6b8505b47309e3bfa3159ea94c7.png


1305715_535915_ans_e3736e49ee004972851c9ff3c0f830b9.jpg


Express some numbers as meters using decimals.
$$15\ cm$$
$$6\ cm$$
$$419\ cm$$

$$(A) \ 15\ cm=\dfrac{15}{100}=0.15\ m$$
$$(B) \ 6\ cm=\dfrac{6}{100}=0.06\ m$$
$$(C) \ 7\ cm=\dfrac{7}{100}=0.07\ m$$
$$(D) \ 419\ cm=\dfrac{419}{100}=4.19\ m$$
                                          or $$4\ m\ 19\ cm$$
as $$1\ cm=\dfrac{1}{100}\ m$$
or $$1\ m=100\ cm$$ 


Find the sum each of the following. 
$$0.007+8.5+30.08$$

$$0.007+8.5+30.08$$

$$=\dfrac{0007}{1000}+\dfrac{85}{10}+\dfrac{3008}{100}$$

$$=\dfrac{7}{1000}+\dfrac{85}{10}+\dfrac{3008}{100}$$

$$=\dfrac{7}{1000}+\dfrac{85}{10}\times\dfrac{100}{100}+\dfrac{3008}{100}\times\dfrac{10}{10}$$

$$=\dfrac{7}{1000}+\dfrac{8500}{1000}+\dfrac{30080}{1000}$$

$$=\dfrac{7+8500+30080}{1000}$$

$$=\dfrac{30080+8500+7}{1000}$$

$$=\dfrac{38587}{1000}$$

$$=38.587$$



Express some numbers  as kg using decimals.
2g , 100g , 5kg8g and 50g

$$(A)\ 2g=\dfrac{2}{1000}=0.002\ kg$$
$$(B)\ 100g=\dfrac{100}{1000}=0.1\ kg$$
$$(C)\ 5\ kg\ 8g=5+\dfrac{8}{1000}=5.008\ kg$$
$$(D)\ 50g=\dfrac{50}{1000}=0.05\ kg$$
as $$1\ g=\dfrac{1}{1000}\ kg$$ as $$1\ kg=1000\ g$$


Express decimal in expanded notation: $$6.083$$

$$6.083=6+$$ $$\dfrac{0}{10}$$ $$+\dfrac{8}{100}$$ $$+\dfrac{3}{1000}$$



An adults toothbrush is $$15.5cm$$ long and a childs toothbrush is $$13.7cm$$long .How much longer is an adults toothbrush?

Adult tooth brush=$$15.5cm$$
Child tooth brush=$$13.7cm$$
Therefore,$$15.5-13.7=1.8cm.$$
Adult tooth brush is 1.8cm longer than Child tooth brush.


Fill in the blanks:
$$27.63+54.17+40.45$$=___________.

$$27.63+54.17+40.45$$
$$=81.8+40.45$$
$$=122.25$$


Express 100 g in kg, using decimals.

Given weight is $$100\ g$$.

We know that, $$1000\ g=1\ kg$$

$$\therefore \ 1\ g=\dfrac{1}{1000}\ kg$$.

Now, $$100\ g=100\times 1\ g$$

          $$=100\times \dfrac{1}{1000}\ kg$$

          $$=\dfrac{1}{10}=0.1\ kg$$.

Hence, $$100\ g=0.1\ kg$$.


find the sum of 0.007+8.5+30.08

$$\textbf{Step -1: Convert all the given decimals into like decimals.}$$

                 $$\text{Among }).007,8.5\text{ and }30.08,$$

                 $$0.007\text{ has maximum decimal places, i.e. }3.$$

                 $$\text{Write }8.5\text{ and }30.08\text{ also to three decimal places.}$$

                 $$\therefore 8.5=8.500$$

                 $$\text{and }30.08=30.080$$

$$\textbf{Step -2: Add them.}$$

                 $$\text{Now, simply add the three decimal numbers from right to left }$$

                 $$\text{and place a decimal point after three places from right.}$$

                 $$0.007+8.500+30.080=38.587$$

$$\textbf{Hence, 0.007+8.5+30.08=38.587}$$



Sumit bought 2 notebooks (each costing Rs.16.5), 5 pencils (each costing Rs. 2.5) and a pencil box for Rs.36.He gave a 100 rupee note to the shopkeeper. What amount would the shopkeeper return him?

Price of 2 Notebooks $$= 2 \times 16.5$$
$$= 33 \quad R s$$
Price of 5 Pencils $$= 5 \times 2.5$$
$$= 12.5 \mathrm { Rs }$$
price of Pencil box = 36.75 Rs
$$\begin{array} { r l } { \text { total cost } = } & { 33 + 12.5 + 36.75 } \\ { = } & { 82 \cdot 25 } \end{array}$$
shopkeeper return him $$= 100 - 82.25$$
$$= 17.75 \mathrm { Rs }$$




Express as $$kg$$ using decimals.
$$2\ g$$

$$2g$$.

As $$1000 g=1\ kg$$

$$1g=\dfrac{1}{1000}\ kg$$

$$2g=2\times 1 g$$

     $$=2\times \dfrac{1}{1000}\ kg$$

     $$=0.002\ kg$$


Express as $$kg$$ using decimals.
$$3750\ g$$

As $$1000g=1\ kg$$ $$\implies 1g=\dfrac{1}{1000}\ kg$$.

$$3750\ g$$

$$=3750\times 1g$$

$$=3750\times \dfrac{1}{1000}\ kg$$

$$=\dfrac{3750}{1000}\ kg$$

$$=3.750\ kg$$


Write the decimals as fractions. Reduce the fractions to lowest from
$$2.5$$

=$$2.5$$
reducing fraction to lowest from
=$$\dfrac{25/5}{10/5}$$
=$$\dfrac{5}{2}$$


The weight of Harish when he holds a flower pot is $$47.5$$kgs and his weight increases when he holds a cat of weight $$5$$kgs.What is the present weight of Harish.

Let the weight of Harish be $$x$$

Given: Weight of Harish while holding the flowerpot is $$47.5$$

$$\therefore 47.5+5$$$$ = 52.5\,kg$$  ................... weight when he holds a cat

Weight of Harish is $$52.5\, Kgs$$


Three friends wanted to buy a cricket bat and ball. Bina had $$\text{Rs. }48.50$$, Raman had $$\text{Rs. }55.50$$ and Venu had $$\text{Rs. }38.00,$$ how much money did they have in all?

$$\begin{array}{l}\;\;\;48.50\\ + 55.50\\\underline { + 38.00} \\\underline{142.00}\end{array}$$

Hence, the total money two friends has is equal to $$\text{Rs. }142.00$$.


(a) The length of Ramesh's notebook is $$9$$ cm $$5$$ mm. What will be its length in cm? 
(b) The length of a young gram plant is $$65$$ mm. Express its length in cm. 

We know,
$$10\ mm=1\ cm\implies 1\ mm=0.1\ cm$$

a) Length of ramesh notebook $$= 9\ cm \,  5\ mm$$
Length of ramesh notebook $$=9 + 0.5 = 9.5\ cm$$

b) Length of a young gram $$= 65\ mm$$
Length of a young gram $$= 6.5\ cm$$


Write as decimal numbers.
A.$$70+3+\dfrac {2}{100}+\dfrac {7}{1000}$$
B.$$5000+400+30+2+\dfrac {1}{10}+\dfrac {2}{100}$$
C.$$256+\dfrac {7}{1000}$$
D.$$\dfrac {7}{10}+\dfrac {3}{100}+\dfrac {5}{1000}$$

$$(a)70+3+\dfrac{2}{100}+\dfrac{7}{1000}$$
$$=70+3+0.02+0.007=73.027$$
$$(b)5000+400+30+2+\dfrac{1}{10}+\dfrac{2}{100}$$
$$=5000+400+30+2+0.1+0.02=5432.12$$
$$(c)256+\dfrac{7}{1000}$$
$$=256+0.007=256.007$$
$$(d)\dfrac{7}{10}+\dfrac{3}{100}+\dfrac{5}{1000}$$
$$=0.7+0.03+0.005=0.735$$


Write the following as decimals.
$$23 + \dfrac {2}{10} + \dfrac {6}{100}$$

$$23 + \dfrac {2}{10} + \dfrac {6}{100} $$

$$= 23 + 0.2 + 0.06 $$

$$=23+0.26$$

$$= 23.26$$.


A mixture is obtained by mixing two products A and B respectively. Product A weighs 234.56 grams and the mixture weighs 988.76 grams. How much does Product B weigh?

Product A$$=234.56$$ gms
Mixture of products A and B$$=988.76$$gms
Product B$$=988.76 - 234.56$$
$$=754.2$$gms.

1240654_1502251_ans_52d6360fcd7a44c6921c28f0e0a04cd4.PNG


Express the following in the form p/q where p and q are integers and $$q \neq 0$$.
$$0.6$$.


1311047_1585604_ans_77d4067732a44669bd84dda62fc13e6c.jpg


Find the value of:
$$9.756-6.28$$

$${\textbf{Step  -  1: Convert this numbers into fraction  }}$$

                     $$\text{Given numbers are 9.756 and 6.28}$$

                     $${\text{9}}{\text{.756 = }}\dfrac{{9756}}{{1000}}$$

                     $${\text{6}}{\text{.28 = }}\dfrac{{628}}{{100}}$$

$${\textbf{Step  -  2: Perform the subtraction between two numbers}}$$

                     $$9.756 - 6.28$$

                     $$=\dfrac{{9756}}{{1000}} - \dfrac{{628}}{{100}}$$

                     $$= \dfrac{{9756}}{{1000}} - \dfrac{{628 \times 10}}{{100 \times 10}}$$

                     $$= \dfrac{{9756}}{{1000}} - \dfrac{{6280}}{{1000}}$$

                     $$= \dfrac{{9756 - 6280}}{{1000}}$$

                     $$= \dfrac{{3476}}{{1000}}$$

                     $$= 3.476$$

$${\textbf{ So the value of }}\mathbf{9.756 - 6.28 = 3.476}$$



Write the decimal number represented by the points $$A, B, C, D$$ on the given number line.
1644394_f723fcdc2e0442f0803eb23181ac415b.png

point $$A$$ represents $$0.8$$

point $$B$$ represent $$1.3$$

point $$C$$ represent $$2.2$$

point $$D$$ represent $$2.9$$


Represent the following decimal numbers on the number line:
$$1.9$$

Represents a print between 1 and 2 on number line. Such that the space between 1 and 2 is divided into 10 equal parts.
  Hence, each part will be equal to one – tenth
 Now, 1.9 is the ninth point between 1 and 2. 

1670957_1658104_ans_01dc76f8590346e082dafdc05b0b1b91.PNG


Represent the following decimal number on the number line:
$$0.2$$

The above diagram represents a print between $$0$$ and $$1$$ on numbers line. Such that the space between $$0$$ and $$1$$ is divided into $$10$$ equal parts. 
 Hence, each equal part will be equal to $$one – tenth$$.
 So, $$0.2$$ will be the second point from $$0$$ between $$0$$ and $$1$$.

1670953_1658103_ans_e541cbd80dfe41b0be6f2e55e33886ac.PNG


Write as decimal number : $$\dfrac {2}{5}$$


1502442_1658098_ans_8e754d0e460a499db7ad56dac66c1142.jpg


Represent the following decimal numbers on the number line:
$$2.5$$

Represents a point between 2 and 3 on number line, such that the space between 2 and 3 is divided into 10 equal parts.
  Hence each equal part will be equal to one – tenth 
 Now, 2.5 is the fifth point between 2 and 3.

1670967_1658106_ans_8a50b692bbde4de4ae55c575bb02e434.PNG


Express the following decimal as fraction in the lowest form:
$$0.5$$


1501946_1658154_ans_e78639dc7145457b9788bfefc2ffae7f.jpg


Express the following fractions as decimals:
$$\dfrac {139}{100}$$


1501926_1658144_ans_a9e873b9d92146b8b049aea16f0be24d.PNG


Find the sum in each of the following:
$$27.076 + 0.55 + 0.004$$

$$27.076 + 0.55 + 0.004$$
   $$27.076$$
    $$0.550$$
$$\underline {+ 0.004}$$
$${27.630}$$


Find the sum in each of the following:
$$25.65 +9.005 + 3.7$$

    $$25.650$$
     $$9.005$$
$$\underline {+\ 3.700}$$
  $${38.355}$$


Represent the following decimal numbers on the number line:
$$1.1$$

Represents a point between 1 and 2 on number line, Such that the space between 1 and 2 is divided into 10 equal parts.
 Hence each equal part will be equal to one – tenth 
Now, 1.1 is the first point between 1 and 2. 

1670962_1658105_ans_77ca5cc41ec04a07aaed2ba0582bead9.PNG


Write as decimal number: $$\dfrac {3}{2}$$

$$\dfrac{3}{2}=$$ $$\dfrac{3\times5}{2\times5}$$
$$=\dfrac{15}{10}=1.5$$



Find the sum in each of the following:
    $$113.285$$
$$+\quad \quad 6.7$$
$$+\quad \,\,\,9.34$$
$$\underline {+\quad 30.08}$$


1501944_1658218_ans_2fae728aef864dc9a9e723f194ddb435.jpg


Find the sum in each of the following:
    $$0.06$$
$$+\, 4.108$$
$$\underline {+\,\, 91.5}$$


1501940_1658216_ans_507f2833b4f44ce5b774793e363cbfb3.jpg


Express the following decimal as fraction in the lowest form:
$$0.60$$


1501962_1658156_ans_3b64d776d0824ade98206cff953b4a3e.PNG


Express the following decimal as fraction in the lowest form:
$$600.75$$

$$600.75$$ has two decimals, so we can remove its decimal by dividing decimal free number with $$100$$
$$\Rightarrow 600.75$$
$$=\cfrac{60075}{100}$$
$$=\cfrac{25\times 2403}{25\times4}$$
$$=\cfrac{2403}{4}$$
So, $$\cfrac{2403}4$$ is the lowest fraction form of $$600.75$$ 


Find the sum in the following:
    $$18.003$$
$$+\quad 41.7$$
$$+\, \,\,10.95$$
$$\underline {+\, \,\,5.057}$$

    $$18.003$$
$$+\,\,41.7$$
$$+\, \,10.95$$
$$+\, \,\,\,5.057$$
$$\overline{\,\,\,\,\,\,\,75.710\,}$$
$$\Rightarrow {75.71}$$


Find the sum in each of the following:
     $$312.8$$
$$+\,\,\,290.02$$
$$\underline  {+ \, \, \, 128.457}$$


1501943_1658217_ans_3172edb3fa4142e69ed848a0b1f33933.jpg


Find the sum in each of the following:
   $$102.36$$
$$+\,\,7.054$$
$$\underline {+\quad 0.8}$$


1501872_1658215_ans_3fd139c5b8d1414a89fcede472bfad18.jpg


Express the following decimal as fraction in the lowest form:
$$2.5$$


1501960_1658155_ans_2f4c6e86b8bf453fb70585cb70c9d0ab.jpg


Express the decimal $$5.25$$ as fraction in the lowest form

$$5.25$$ $$=\dfrac{5.25}{1} \times \dfrac{100}{100}$$

        $$=\dfrac{525}{100}$$

        $$=\dfrac{25\times 21}{25\times 4}$$

        $$=\dfrac{21}{4}$$


Find the sum in each of the following:
        $$3.42$$
$$+\,264.08$$
$$+\quad \,\,\,7.6$$
$$\underline {+\, 95.321}$$

         $$3.42$$
     $$264.08$$
          $$7.6$$
$$+\,\,\,95.321$$
$$\overline{\,\,\,\,\,\,370.421}$$


Subtract :
   $$45.03$$
$$\underline {-27.80}$$


1501828_1658235_ans_50a2d224c5384da3bd61c1a768164af5.jpg


Find the value of :
$$32.7 - 25.86$$

$$\Rightarrow \,\,32.7$$
    $$-25.86$$
      $$\overline{\,\,\,6.84\,\,\,\,}$$


Urmila's school is at a distance of $$5\ km \ and\ 350\ m$$ from her house. She travels $$1\ km\  and \ 70\ m$$ on foot and the rest she travels by bus. How much distance does she travel by bus?

Total distance = Foot + bus
$$5km + 350m = 1km + 70m$$ +bus
$$5.350 - 1.070 = bus$$
$$Bus = 4.28km$$


Find the value of :
$$91.001 - 72.9$$

$$91.001 - 72.9$$

$$\Rightarrow 91.001$$
  $$\underline{-72.9\,\,\,\,\,}$$
    $$18.101$$


Subtract :
$$23.93$$
$$\underline {5.946}$$

  $$23.93$$
$$\underline{-5.946}$$
 $$17.984$$


Subtract:
$$128.4$$
$$\underline {53.05}$$

  $$128.4$$
$$\underline{-53.05}$$
   $$75.35$$


Subtract:
  $$46.23$$
$$\underline {-\,37.5}$$


1501972_1658231_ans_e7f0ad45dd824ee68b068f5b44b5a503.jpg


Add the following:
$$4.702, 4.2, 6.02$$ and $$1.27$$

         $$4.702$$
         $$4.2$$
         $$6.02$$
   $$+\,\,\,1.27$$
  $$\overline{\,\,\,\,\,\,16.192\,\,}$$


Ruby bought a watermelon weighing $$5\ kg\ 200\ g$$. Out of this she gave $$2\ kg\ 750\ g$$ to her neighbour. What is the weight of the watermelon left with Ruby?

Watermelon = given + remaning
$$5kg 200g = 2kg 750g +left$$
$$5.2kg= 2.75kg+left$$
$$left = 5.2 - 2.75$$
$$= 2.45$$


Find the value of:
$$9.756 - 6.28$$

To find the value of: $$9.756 - 6.28$$

$$9.756 - 6.28=3.476$$

Hence, the answer is $$3.476$$


Vineeta bought a book for $$Rs. 18.90$$, a pen for $$Rs. 8.50$$ and some papers for $$Rs. 5.05$$. She gave fifty rupee to the shopkeeper. How much balance did she get back?

Balance she get back = 50 -total cost
                                      = 50 -( bok+pen+paper)
                                      = 50 - (32.45)
                                      = 17.55


What is to be subtracted from $$17.1$$ to get  $$2.051$$?

Let $$x$$ is to be subtracted from $$17.1$$ to get $$2.051$$.
Then,
$$17.1-x=2.051$$
or, $$x=17.1-2.051$$
or, $$x=15.049$$


Take out $$3.547$$ from $$7.2$$

If we take out $$3,547$$ from $$7.2$$ then we get,
$$=7.200-3.547$$
$$=3.653$$


Tanuj walked $$8.62\ km$$ on Monday, $$7.05\ km$$ on Tuesday and some distance on Wednesday. If he walked $$21.01\ km$$ in three days, how much distance did he walk on Wednesday?

Total = Monday + Tuesday + Wednesday
 21.01 = 8.62 + 7.05  + Wednesday
Wednesday = 21.01 - 15.67
                     = 5.34


Gopal travelled $$125.5\ km$$ by bus, $$14.25\ km$$ by pony and the rest of distance to Kedarnath on foot. If he covered a total distance of $$150\ km$$, how much did he travel on foot?

Total distance = Foot + bus+pony
150 = 125.5 + 14.25 + foot
$$ 150 = 139.75 + foot$$
$$foot = 150 - 139.75$$
$$ = 10.25$$


Victor drove $$89.050\ km$$ on Saturday and $$73.9\ km$$ on Sunday. How many kilometres more did he drive on Saturday?

Victor drove on saturday = 89.050
Victor drove on sunday = 73.9
More he drive on saturday
$$ 89.050 -73.9 = 15.15$$


By how much should $$34.79$$ be increased to get $$70.15$$?

Let the number $$34.79$$ be increased by $$x$$ to get $$70.15$$.
Then,
$$x+34.79=70.15$$
or, $$x=70.15-34.79$$
or, $$x=35.36$$


Add  :
$$ 63.5, 9.7, 0.8, 26.66 $$  and $$ 12.17 $$

First convert the given decimals into like decimals.
we get,
$$ 63.50, 9.70, 0.80, 26.66 $$ and $$ 12.17 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in column from and adding, we get,
$$ 63.50 $$
$$ 9.70 $$
$$ 0.80 $$
$$ 26.66 $$
$$ 12.17 $$
__________
$$ 112.83 $$
Hence, the sum of the given decimals is $$ 112.83 $$


Add : 
$$ 18.6, 206.37, 8.008, 26.4 $$ and $$ 6.9 $$

First convert the given decimals into like decimals.
we get,
$$ 18.600, 206.370, 8.008, 26.400, 6.900 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column .
Writing these decimals in column from and adding, we get 
$$ 18.600 $$
$$ 206.370 $$
$$ 8.008 $$ 
$$ 26.400 $$
$$ 6.900 $$
_________
$$ 266.278 $$
Hence, the sum of the given decimals is $$ 266.278 $$


Add : 
$$ 16, 8.7, 0.94, 6.8 $$ and $$ 7.77 $$

First convert the given decimals into like decimals.
we get,
$$ 16.00, 8.70, 0.94, 6.80, 7.77 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in column from and adding, we get,
$$ 16.00 $$
$$ 8.70 $$
$$ 6.80 $$
$$ 7.77 $$
__________
$$ 40.21 $$
Hence, the sum of the given decimals is $$ 40.21 $$


Add :
$$ 26.9, 19.74, 231.769 $$ and $$ 0.48 $$

First convert the given decimals into like decimals.
we get,
$$26.900, 19.740, 231.769 $$ and $$ 0.048 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in column from and adding, we get,
  $$ 26.900 $$
  $$ 19.740 $$
$$ 234.769 $$
    $$ 0.048 $$
__________
$$ 278.457 $$
Hence, the sum of the given decimals is $$  278.457 $$


Add:
 
$$ 174 , 86.39,  9.435 , 8.8  $$ and $$ 0.06 $$

First convert the given decimals into like decimals.
we get,
$$17.400, 86,390, 9.435, 8.800 $$ and $$ 0.060 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in a column form and adding, we get,
$$ 17.400 $$
$$ 86.390 $$
  $$ 9.435 $$
  $$ 8.800 $$
   $$ 0.060 $$
__________
$$ 122.085 $$
Hence, the sum of the given decimals is $$  122.085 $$


Add:
$$ 9.09 , 0.909, 99.9, 9.99, 0.099 $$

First convert the given decimals into like decimals.
we get,
$$ 9.090, 0.909, 99.900, 9.990 , 0.99 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in column from and adding, we get,
  $$ 9.090 $$
  $$ 0.909 $$
$$ 99.900 $$
  $$ 9.990 $$
  $$ 0.099 $$
_________
$$ 119.988 $$


Subtract :
$$ 36.74 $$ from $$ 52.60 $$

Writing them into column form with the larger one at the top and subtracting, we get:
   $$ 52.60 $$
$$ -36.74 $$
__________
    $$ 15.86 $$
Hence $$ ( 36.74 - 52.6) = 15.86 $$


Add :
$$ 6.606 , 66.6, 666, 0.066, 0.66  $$

First convert the given decimals into like decimals.
we get,
$$ 6.606 , 66.600, 666.000 , 0.066 , 0.660 $$
Write the addends on under the other in column form, keeping the decimal points of all the addends in the same column and the digits of the same place in the same column,
Writing these decimals in column from and adding, we get,
    $$ 6.606 $$
  $$ 66.600 $$
$$ 666.000 $$
    $$ 0.066 $$
     $$ 0.660 $$
_________
$$ 739.932 $$
Hence, the sum of the given decimals is $$  122.085 $$


Subtract :
$$ 13.876 $$ from $$ 22 $$ 

Converting the decimals into like decimals, we get $$ 13.876 $$ and $$ 22.000 $$
Writing them into column form with the larger one at the top and subtracting, we get:
   $$ 22.000 $$
$$ -13.876 $$
__________
     $$ 8.124 $$
Hence $$ ( 13.876 - 22) = 8.124 $$ 


Subtract :
$$ 14.79 $$ from $$ 72.43 $$

Writing them into column form with the larger one at the top and subtracting, we get:
    $$ 72.43 $$
$$ -14.79 $$
__________
   $$ 57.64 $$
Hence $$ ( 14.79 - 72.43 ) = 57.64 $$


Namita travels $$20\ km\ 50\ m$$ every day. Out of this she travels $$10\ km\ 200\ m$$ by bus and the rest by auto. How much distance does she travels by auto?

Distance traveled everyday
$$=20\ km\ 50\ m=20\ km +50\ m$$
$$=20\ km+\dfrac {50}{1000}km$$     $$\left[\because \dfrac {1}{1000}km =0.001\ km \right]$$
$$=20\ km+0.050\ km$$
$$=(20+0.050)km=20.050\ km$$
Distance traveled by bus
$$=10\ km\ 200\ m=10\ km+200\ m$$
$$=10\ km +\dfrac {200}{1000}km$$     $$\left[\because \dfrac {1}{1000}km =0.001\ km\right]$$
$$=10\ km +0.200\ km $$
$$=(10+0.200)km=10.200\ km$$
$$\therefore $$ Distance traveled by auto
$$=20.050\ km-10.200\ km=9.850\ km$$


By how much does the sum of $$15.453$$ and $$31.647$$ exceed the sum of $$18.47$$ and $$19.506$$?

Sum of  $$\dfrac {\ \ \ \ 15.453\\ +31.647}{\underline{\ \ \ 47.100}}$$

Sum of  $$\dfrac {\ \ \ \ 18.470\\ +19.506}{\underline{\ \ \ 37.976}}$$

Difference  $$=\dfrac {\ \ \ \ 47.100\\ -37.976}{\underline{\ \ \ \ 9.124}}$$




Ravi purchase $$5\ kg\ 400\ g$$ rice, $$2\ kg\ 20\ g$$ sugar and $$10\ kg\ 850\ g$$ flour (aata). Find the total weight of his purchases.

Weight of rice purchase
$$=5\ kg 400\ g=5\ kg+400\ g$$
$$=4\ kg+\dfrac{400}{1000}\ kg \left[\because 1\ g=\dfrac {1}{1000}kg \right]$$
$$=5\ kg+0.400\ kg$$
$$=(5+0.400)\ kg=5.400\ kg$$

Weight of sugar purchase
$$=2\ kg 20\ g=2\ kg+20\ g$$
$$=2\ kg+\dfrac{20}{1000}\ kg \left[\because 1\ g=\dfrac {1}{1000}kg \right]$$
$$=2\ kg+0.020\ kg=2.020\ kg$$

Weight of flour purchase
$$=10\ kg 850\ g=10\ kg+850\ g$$
$$=10\ kg+\dfrac {850}{1000}kg \left[\because 1\ g=\dfrac {1}{1000}kg \right]$$
$$=10\ kg+0.850\ kg$$
$$=(10+0.850) kg=10.850\ kg$$

$$\therefore \ Total weight of his purchase is =5.400\ kg+2.020\ kg+10.850\ kg$$
$$=18.270\ kg$$

1757473_1786928_ans_c8dc69a3b2134e4a9ca39314bac3b5c8.png


Sunita travelled $$15\ km\ 268\ m$$ by bus, $$7\ km\ 7\ m$$ by car and $$500\ m$$ on foot in order to reach her school. how far is her school from her residence?

Distance travelled by bus
$$15\ km\ 268\ m = 15\ km + 268\ m$$
$$15\ km + \dfrac {268}{1000}km$$
$$15\ km + 0.268\ km$$ $$[\because 1\ m = \dfrac {1}{1000}km]$$
$$(15 + 0.268)\ km = 15.268\ km$$
Distance travelled by car
$$7\ km\ 7\ m = 7\ km +7\ m$$
$$7\ km + \dfrac {7}{1000}km$$
$$7\ km + 0.007\ km$$ $$[\because 1\ m= \dfrac {1}{1000}km]$$
$$(7 + 0.007)\ km = 7.007\ km$$
Distance travelled by foot
$$500\ m = \dfrac {500}{1000}km = 0.500\ km$$ $$[\because 1\ m = \dfrac {1}{1000}km]$$
$$\therefore$$ Distance of school from residence
$$15.268\ km + 7.007\ km + 0.500\ km$$ $$=22.775\ km$$

$$\begin{matrix}  & 1 &  &  &  & 1 &  &  \\  & 1 & 5 & \cdot  & 2 & 6 & 8 & km \\ + &  & 7 & \cdot  & 0 & 0 & 7 & km \\ + &  & 0 & \cdot  & 5 & 0 & 0 & km \\ = & 2 & 2 & \cdot  & 7 & 7 & 5 & km \end{matrix}$$


Rahul bought $$4\ kg\ 90\ g$$ apples, $$2\ kg\ 60\ g$$ grapes and $$5\ kg\ 300\ g$$ mangoes. Find the total weight of all the fruits he bought.

Weight of apples $$= 4\ kg\ 90\ g$$
$$4\ kg + \dfrac {90}{1000}kg\quad \left(\because 1\ g = \dfrac {1}{1000}kg\right)$$
$$=4\ kg + 0.09\ kg$$
$$=(4 + 0.09)kg = 4.09\ kg$$

Weight of grapes $$=2\ kg\ 60\ g$$
$$2kg + \dfrac {60}{1000} \quad \left(\because 1g = \dfrac {1}{1000}kg\right)$$
$$=2\ kg + 0.006\ kg$$
$$=(2 + 0.06)kg = 20.6\ kg$$

Weight of mangoes $$=5\ kg\ 300\ g$$
$$2\ kg + \dfrac {300}{1000}kg\ (\because 1g = \dfrac {1}{1000}kg)$$
$$=5\ kg +\ 0.3\ kg$$
$$=(5+0.3)kg=5.3\ kg$$

Total weight of his purchases is
$$=4.090\ kg + 2.060\ kg + 5.300\ kg$$
$$=11.450\ kg$$


$$ 4.55 + 9.73  $$ = _______ 

$$ 4.55 +9.73 = 14.28 $$


$$ 3.25.....3.4 $$

Since convert the $$ 3.25 $$ and $$ 3.4 $$ in like decimal . its become $$ 3.25 $$ and $$ 3.40 $$
$$ \because $$ compare the place value of $$ 3.25 $$ and $$ 3.40 $$ we get tenth place of $$ 3.25 $$ and the tenth place of $$ 3.40 $$ is $$4 $$
$$ \therefore 3.25 < 3.4 $$


$$ 8.76 - 2.68 $$ = _____.

$$ 8.76 - 2.68 = 6.08 $$


Measurement made in science lab must be as accurate as possible. Ravi measured the length of an iron rod and said it was 19.34 cm long; Kamal said 19.25 cm; and Tabish said 19.27 cm. The correct length was 19.33 cm. How much of error was made by each of the boys?


1903440_1790260_ans_923dd4be29514c72960989e2097bab43.jpeg


What should be added to $$ 25.5 $$ to get $$50$$? 

$$ \Rightarrow  25.5 + x = 50 $$
$$ \Rightarrow  x = 50 - 25.5 = 24.5 $$
$$ \therefore $$ The required number is $$ 24.5 $$


Alok purchased $$1kg 200g $$ potatoes, $$ 250g $$ dhania, $$ 5kg 300g $$ onion, $$ 500g $$ palak, and $$ 2kg 600g $$ tomatoes. Find the total weight of his purchases in kilograms.

Convert all the data in a signal unit , kg
Alok pucharsed $$ 1 kg  200 g $$ potatoes, $$ 250 g $$, $$ 5 kg 300 g $$ onion, $$ 500 g $$ palak , and $$ 2 kg  600 g $$ tomatoes are in kg
$$ = 1 kg  200 g $$ = $$1kg + \dfrac {200}{1000} kg $$ = $$ 1.200 kg $$ of potatoes

$$ = 0 kg 250 g  = 0 kg + \dfrac {250}{1000} kg = 0.250 kg  $$ of dhania 

$$ = 5kg  300 g = 5 kg + \dfrac {300}{1000} kg = 5.300 kg $$ of onion

$$ = 0 kg 500 g = 0 kg + \dfrac { 500}{1000} kg = 0.500 kg  $$ of palak 

$$ = 2 kg 600 g $$ = $$ 2 kg  + \dfrac  {600}{1000} kg $$ = $$ 2.600 kg $$ of tomatoes

$$ \therefore $$ total weight of the purchase = $$ 9.850 kg $$


Heenas father paid an electric bill of ` 385.70 out of a 500 rupee note. How much change should he have received?


1903463_1790254_ans_97845599711f4bc99ed5159ac0d31f88.jpeg


Imagine that a $$10 \times 10$$ grid has value $$300$$ and that this value is divided evenly among the small squares. In other words, each small square is worthUse a new grid for each part of this problem, and label each grid "Value : 300."
(a) Shade $$25\%$$ of the grid. What is $$25\%$$ of $$300$$ ?
Compare the two answers.
(b) What is the value of $$25$$ squares.
(c) Shade $$17\%$$ of the grid. What is $$17\%$$ of $$300$$ ?
Compare the two answers.
(d) What is the value of $$\dfrac{1}{10}$$ of the grid ?
1790851_8de29ec93dc347748518711045486a65.png

(a) $$25\%$$ of $$300 = \dfrac{25}{100} \times 300 = 75$$
Now, each small square is worth $$3$$
Hence, worth of $$25$$ squares $$= 25 \times 3 = 75$$
Both volume are same.
(b) From part (a) of the solution the values of small squares is $$75.$$
(c) $$17\%$$ of $$300 = \dfrac{17}{100} \times 300 = 51$$
Now, each small square is worth $$3$$
Hence, worth of small squares $$17 \times 3 = 51$$
Both the values are same.
(d) Total number in grid $$= 10 \times 10 = 100$$
$$\therefore \dfrac{1}{10}$$ of $$100 = \dfrac{1}{10} \times 100 = 10$$
Now, each small square is worth $$3$$
Hence, worth of $$10$$ small squares $$= 10 \times 3 = 30$$

1653262_1790851_ans_c8ba4061c9bc4b968a221e728b922758.png


Add the following: $$ 20.02 $$ and $$ 2.002 $$

Convert all decimal are in like from as $$ 20.020 $$ and $$ 2.002 $$ 
$$ \therefore  \quad 20.020 $$
       $$ + 2.002 $$
_____________
        $$ 22.022 $$


$$ 6.25 ..... \dfrac{25}{4} $$

Since convert $$ 1.3 $$ into fraction from, we get $$ \dfrac { 625}{100} $$

$$ \Rightarrow \dfrac { 625}{100} = \dfrac  { 625 \div  25}{ 100 \div  25} = \dfrac {25}{4} $$

$$ \dfrac {25}{4}..... \dfrac {25}{4} $$

$$ \dfrac {25}{4} = \dfrac {25}{4}$$ so$$ 6.25 = \dfrac { 25}{4} $$


A piece of rope is $$10 m$$ $$67 cm$$ long. Another rope is $$16 m$$ $$32 cm$$ long. By how much is the second rope longer than the first one?

Given
Length of one rope $$= 10 m 67 cm$$
Another rope length $$= 16 m 32 cm$$
The difference between the two rope lengths can be calculated as below
$$= 16 m 32/ 100 cm – 10 m 67/100 cm$$
$$= 16.32 m – 10.67 m$$
We get,
$$= 5.65 m$$
$$= 5 m 65 cm$$
Therefore, the length of second rope longer than the first rope by $$5.65 m$$


Subtract:
$$Rs 35.74$$ from $$Rs 63.22$$

Rs35.74Rs35.74 from Rs63.22Rs63.22
 63.2263.22
-35.7435.74
________
27.4827.48
________
∴∴ The subtraction of Rs35.74Rs35.74 from Rs63.22Rs63.22 is Rs27.48


Add (giving answer in rupees):
$$Rs 5.37$$ and $$Rs 12$$

$$RS 5.37$$ and $$Rs 12$$
     $$ 5.37$$
$$+12.00  $$
__________
$$Rs 17.37$$
__________
$$\therefore$$ $$Rs 5.37 + Rs 12 = Rs 17.37$$


What least number must be added to $$89.376$$ to get $$1000?$$

The number to be added to $$89.376$$ to get $$1000$$
Subtract $$89.376$$ from $$1000$$
Convert the decimals into like decimal numbers
Like decimals are $$89.376$$ and $$1000.000$$
$$1000.000$$
$$–$$ $$89.376$$ 
__________
$$910.624$$
___________
Therefore, the number to be added to $$89.376$$ to obtain $$1000$$ is $$910.624$$


Add the following:
$$1.01, 257$$ and $$0.200$$

To add $$1.01, 257$$ and $$0.200$$
Convert the decimals into like decimal by adding zeros
Like decimals are $$1.010, 257.000$$ and $$0.200$$
$$1.010$$
$$257.000$$ $$+$$
$$0.200$$ $$+$$
____________
$$258.210$$
____________
Hence, the addition of the given decimal numbers is $$258.210$$


add $$2.06 kg$$ and $$57.864 kg$$

$$2.06 kg$$ and $$57.864 kg$$
$$= 2.06 kg + 57.864 kg$$
Converting the decimals into like decimals
We get,
$$= 2.060 kg + 57.864 kg$$
$$= 59.924 kg$$
$$\therefore$$ The addition of $$2.06 kg$$ and $$57.86 kg$$ is $$59.924 kg$$


Subtract (giving answer in kg):
$$9.462 kg$$ from $$15.6 kg$$

9.462kg9.462kg from 15.6kg
=15.6kg-9.462kg=15.6kg9.462kg
Converting the decimals into like decimals
We get,
=15.600kg-9.462kg
=6.138kg
∴∴ The subtraction of 9.462kg9.462kg from 15.6kgis 6.138kg


Add the following:
$$18, 200.35, 11.72$$ and $$2.3$$

To add $$18, 200.35, 11.72$$ and $$2.3$$
Convert the decimals into like decimals by adding zeros
Like decimals are $$18.00, 200.35, 11.72$$ and $$2.30$$
    $$18.00$$
 $$200.35$$ 
   $$11.72$$ 
 $$+$$ $$2.30$$
____________

    $$232.37$$

___________

Hence, the addition of the given decimal numbers is $$232.37$$



Subtract the first number from the second:
$$41.03,59.46$$


1887845_1826196_ans_bd0c8e5f716d4116915cac9612715eda.jpg


Subtract (giving answer in kg):
$$0.798 kg$$ from $$4169 gm$$

$$0.798 kg$$ from $$4169 gm$$
Converting the $$4169 gm$$ into kg, we get
$$\dfrac{4169} { 1000 }kg – 0.798 kg$$
$$= 4.169 kg – 0.798 kg$$
$$= 3.371kg$$
$$\therefore$$ The subtraction of $$0.798 kg$$ from $$4169 gm$$ is $$3.371 kg$$


Add (giving answer in kg):
$$2.06 kg$$ and $$57.864 kg$$

$$2.06 kg$$ and $$57.864 kg$$
$$= 2.06 kg + 57.864 kg$$
Converting the decimals into like decimals
We get,
$$= 2.060 kg + 57.864 kg$$
$$= 59.924 kg$$
$$\therefore$$ The addition of $$2.06 kg$$ and $$57.86 kg$$ is $$59.924 kg$$


If $$ A=237.98 $$ and $$ B=83.47 $$
Find:
$$ \mathbf{A}-\mathbf{B} $$

$$ \mathrm{A}-\mathrm{B} $$
It is given that $$ A=237.98 $$ and $$ B=83.47 $$ 
Substituting the values $$ A-B=237.98-83.47 $$
$$ A-B=154.51 $$

     $$ 237.98 $$
    $$-83.47 $$
$$ \begin{array}{l l}\hline & 154.51 \end{array}$$


Subtract:-
$$2.051 \,km$$ from $$5.20\,km$$

  $$5.206$$
$$-2.051$$
$$.......$$
$$3.155$$
$$.......$$


The cost of one kg of sugar increases from 28.47 to 32.Find the increase in cost.

Cost of sugar $$ =₹ 28.47 $$ 
Cost of sugar is raised $$ =₹ 32.65 $$ 
Increase in the cost of sugar $$ =₹ 32.65-₹ 28.47=₹ 4.18 $$
$$ \begin{array}{l l}& 32.65 \\-&28.47 \\\hline & 4.18 \end{array}$$


What should be added to $$39.587$$ to give $$ 80.375 ? $$

It is given that Sum of two numbers $$ =80.375 $$ 
One number $$ =39.587 $$ 
So the other number $$ =80.375-39.587=40.788 $$
$$ \begin{array}{l l}& 80.375 \\-&39.587 \\\hline & 40.788 \end{array}$$


Subtract the first number from the second:
$$3.71,0.845$$



1744442_1826204_ans_96060c022adf424c93c08b890f5c2416.jpg


Radhika's mother gave her $$Rs.10.50$$ and her father gave her $$Rs.15.80,$$ Find the total amount given to Radhika by the parents.

Amount given by Radhika's mother         $$= Rs.10.50$$
Amount given by Radhika's Father         $$= Rs.15.80$$
                                                                        $$+.......$$
Total Amount given Radhika's Father    $$= Rs.26.30$$
                                                                      $$.......$$
Therefore, the amount given by her parents is $$Rs.26.30.$$
                                                                



Class 6 Maths Extra Questions